Im working with Data actory this time this why i ask lot of question about that
My new problem is that my SOURCE(CSV file contains a column DeleveryDate full of Date dd/MM/YYYY) and my table SQl where i specify DElevry date as DateTime but when I map btw source and sink in Data preview source
duplicate columns like in the picture below but in data preview sink the columns always NULL the same in my table NULL.
Thanks
You said column DeleveryDate full of Date dd/MM/YYYY), can you tell me why the column DeleveryDate has the values like '3', '1' in your screenshot? String '3' or '1' are not the date string with format dd/MM/YYYY.
If you want to do some data convert in Data Factory, I still suggest your to learn more about Data Flow.
For now, we can not convert date format from dd/MM/YYYY to datetime yyyy-MM-dd HH:mm:ss.SSS directly, we must do some other converts.
Look at bellow, I have a csv file contained a column with date format dd/MM/YYYY string, I still using DerivedColumn this time:
Add DerivedColumn:
Firstly, using this bellow expression to substring and convert dd/MM/YYYY to YYYY-MM-dd:
substring(Column_2, 7, 4)+'-'+substring(Column_2, 4, 2)+'-'+substring(Column_2, 1,2)
Then using toTimestamp() to convert it:
toTimestamp(substring(Column_2, 7, 4)+'-'+substring(Column_2, 4, 2)+'-'+substring(Column_2, 1,2), 'yyyy-MM-dd')
Sink settings and preview：
My Sink table column tt data type is datetime:
Execute the pipeline:
Check the data in sink table:
Hope this helps.
Please try this-
This is a trick which was a blocker for me, but try this-
Go to sink
Mapping
Click on output format
Select the data format or time format you prefer to store the data into the sink.
Related
I am reading a file from ADLS location, in that one column Period_Ending_Date is having data type as STRING.
The Period_Ending_Date is having many dates in random order, I need to apply filter to get the latest date.
I'm trying this code:
select * from final_table
WHERE Period_Ending_Date = (SELECT MAX(Period_Ending_Date) FROM final_table)
But the problem is I'm getting the day with maximum, not the latest date. I can understand this is happening because of STRING data type. Please guide me how I can change this column to DATE data type or any other alternative to get the solution of this.
I'm working with Scala and SQL on Azure Databricks.
what about changing SELECT MAX(Period_Ending_Date) FROM final_table to SELECT MAX(cast(Period_Ending_Date as date)) FROM final_table - performing explicit casting to date if date format is ISO8601 (YYYY-MM-DD) or using the to_date function (doc) to convert non-standard dates.
I need help in figuring out the date conversion logic in Snowflake. The documentation isn't clear enough on this.
In SQL Server, I would try
SELECT CONVERT(DATE, '20200730', 101)
and it gives me '07/30/2020'.
If I try the following in Snowflake,
to_varchar('20200730'::date, 'mm/dd/yyyy')
it gives me '08/22/1970'. Why would it give an entire different date? Need help in getting the logic with the correct date.
The issue with what you are doing is that you are assuming that Snowflake is converting your string of '20200730'::DATE to 2020-07-03. It's not. You need to specify your input format of a date. So, 2 options based on your question being a bit vague:
If you have a string in a table and you wish to transform that into a date and then present it back as a formatted string:
SELECT TO_VARCHAR(TO_DATE('20200730','YYYYMMDD'),'MM/DD/YYYY');
--07/30/2020
If the field in the table is already a date, then you just need to apply the TO_VARCHAR() piece directly against that field.
Unlike SQL Server, Snowflake stores date fields in the same format regardless of what you provide it. You need to use the TO_VARCHAR in order to format that date in a different way...or ALTER SESSION SET DATE_OUTPUT_FORMAT will also work.
Try select to_varchar(TO_DATE( '20200730', 'YYYYMMDD' ), 'MM/DD/YYYY'); which produces 2020-07-30
You may need to refer to https://docs.snowflake.com/en/user-guide/date-time-input-output.html#timestamp-formats
I am trying to import data from CSV file in to Oracle Table.
One of the column is DATETIME,
with an example value- "6/26/2018 12:41:00 PM"
(With 2 spaces between date and time)
In Data Import Wizard --> Column Definition --> Data Type
I select "Data Type" as Timestamp.
What should select in the below fields-
Size/Precision- ?? (I tried different sizes like 15, 23, 25,50 )
Format- ?? (I tried various formats- MM/DD/YYYY HH:Mi:SS AM, MM/DD/YYYY HH:Mi:SS)
Please advise.
Thanks!
Try below format in database and also in excel
Import DB: while loading in table MM/DD/YYYY HH:MI:SS AM in sql developer using import.
CSV file : Also format the csv file date field with format using custom m/d/yyyy h:mm:ss AM/PM
Make sure it's stored as a date and not as a VARCHAR2.
Then put in a valid NLS_DATE_FORMAT, so we know how to properly insert the record. For your sample, this will do: MM/DD/YYYY HH:MI:SS AM
We validate the format, so you can see there's no warning next to the list of dates we are previewing below.
One might consider this question a duplicate of sorts...
But you're not dealing with the RAW INSERT statement, our GUI is, and this is how you tell us that same information.
For my .csv file with the date value as "6/26/2018 12:41:00 PM"
select the DATE (No timestamp) and used format- MM/DD/YYYY HH24:MI and it worked for me probably I have all 00 values in my time (SS).
I would love to know the best way to handle data that has been inputted incorrectly as dd/mm/yyyy into a sql database as TEXT and to have it converted into a new column of the table with the datatype as DATE so it is actually stored as yyyy-mm-dd.
Existing text date column name is called "olddate" with an empty column created called "truedate" to house the new data. Each row has the date field, but none are able to be sorted correctly because of this issue.
Any ideas how I can slice and dice the current date into a new DATE field friendly version?
Thanks in advance :-)
That is style 103. So use:
select convert(date, col, 103)
Are you using Oracle? If so, TO_DATE is what you want. You can take in a string that represents a date and convert it to a date using the format you pass it.
I have a table with two columns, all of them are datetime value
Such as, Column A with value ‘07/09/2012 14:13:34’
Now, I want to update column A to yyyymmdd by statement
Update Change_Date
SET A = CONVERT(VARCHAR(8),A,112)
It shows succsessful message but with no effect (no update value to 20120907) in my table Change_Date.
Any help will be greated, thank you!
A datetime fields saves a date time. How you see that date time is a result of the tool you're using to inspect the data, whether it is Management Studio, or your own software that's printing something from the database.
I strongly recommend keeping it as a datetime field. This will allow you to do date-related operations, such as subtractions and comparisons. If you want to change how your users see the date, then format your date at the presentation layer.
What's happening in the code you've posted is that you're setting the value of A to the same date that it already is. The fact that you're setting that value by means of a string in another format has no relation, SQL server will always have to parse your string input into a date that it can understand. This is why you're not getting an error message. The operation is working, only it's not changing anything.
You can select the date column in specified format or make a view which selects the column value in yyyymmdd format:
SELECT CONVERT(VARCHAR(8), A, 112) FROM Change_Date
It's because the datatype of the column is DATE or DATETIME and it has specific format. If you want to update the column with specific format, make another column and make its datatype VARCHAR. I believe 112 is yyyymmdd format.
I strongly suggest that you keep it AS IS. Database is the storage of data and not for viewing purposes. It is easy to perform task for dates if your data type is DATETIME or DATE. If for instance you want to retrieve the dates with specific format, that's the time you convert your date.
Hope this makes sense.