DateDiff for each month - sql

Question

My current query give my this as a result;
Address PK StartDate EndDate Rent Cost NoDays
1 water lane 3435 01/04/2018 12/02/2020 500 11210.95 682
7 get road 5456 14/06/2019 01/02/2020 700 5339.18 232
I want to outline how many days per month/ or how much per month spent.
this is what i want to see after NoDays or even on a new query result.
04/2018 05/2018 06/2018 07/2018 so on ....
30 31 30 31 so on ....
0 0 0 0 so on ....
or
04/2018 05/2018 06/2018 07/2018 so on ....
500 500 500 500 so on ....
0 0 0 0 so on ....

Answer 1

Here a solution which generates a calendar using recursion
then adding columns and updating them using cursor and dynamic script
set dateformat dmy
declare #table as table(pk int, startdate date,enddate date,rent int,cost float)
insert into #table values(3435,'01/04/2018','12/02/2020',500,11210.95),(5456,'14/06/2019','01/02/2020',700,5339.18)
declare #table2 as table(pk int)
insert into #table2 select distinct(pk) from #table
declare #calendar as table (date date)
declare #mindate as date
declare #maxdate as date
select #mindate=min(startdate) from #table
select #maxdate=max(enddate) from #table;
with cte as(select #mindate as mydate union all select dateadd(day,1,mydate) from cte
where mydate < #maxdate)
insert into #calendar select * from cte
option(maxrecursion 0);
declare #tabresultsrows as table(pk int,MO varchar(7),N int,M int,Y int);
declare #tabmonths as table(Mo varchar(7),M int,Y int);
with cal as(
select t2.pk,c.date ,t.startdate,t.enddate ,month(date) M, year(date) y ,concat(RIGHT('00' + CONVERT(NVARCHAR(2), month(date)), 2),'/', year(date)) Mo,
case when c.date >= t.startdate and c.date <=t.enddate then 1 else 0 end N from #calendar c
cross join #table2 t2
inner join #table t on t2.pk=t.pk),
caltab as(select pk,Mo,sum(N) N ,Y,M from cal group by pk,Y,M,Mo )
insert into #tabresultsrows select pk,MO,N,M,Y from caltab order by pk,Y,M
insert into #tabmonths select distinct(MO),M,Y from #tabresultsrows
IF OBJECT_ID('tempdb..#tabresultscolumns') IS NOT NULL DROP TABLE #tabresultscolumns
select * into #tabresultscolumns from #table
declare #script as varchar(max)
declare mycursor cursor for select mo from #tabmonths order by Y,M
declare #mo as varchar(7)
open mycursor
fetch mycursor into #mo
while ##fetch_status=0
begin
set #script='alter table #tabresultscolumns add ['+#mo+'] int'
print #script
exec(#script)
fetch mycursor into #mo
end
close mycursor
deallocate mycursor
declare secondcursor cursor for select pk,Mo,N from #tabresultsrows
declare #PK AS INT
declare #n as int
open secondcursor
fetch secondcursor into #pk,#mo,#n
while ##fetch_status=0
begin
set #script=concat('update #tabresultscolumns set ['+#mo+']=',#n,' where pk=',#pk )
print #script
exec(#script)
fetch secondcursor into #pk,#mo,#n
end
close secondcursor
deallocate secondcursor
select * from #tabresultscolumns

Answer 2

Try something like this:
-- You can set the variables to get as an input the StartDate, EndDate from your table
DECLARE #StartDate DATE = '20200101'
, #EndDate DATE = '20200331'
;with datecreator as (
SELECT DATEADD(DAY, nbr - 1, #StartDate) as dates
FROM ( SELECT ROW_NUMBER() OVER ( ORDER BY c.PK ) AS Nbr
FROM Test c
) nbrs
WHERE nbr - 1 <= DATEDIFF(DAY, #StartDate, #EndDate)
)
,CTE AS
(
select distinct Month(dates) rnk,Convert(char(3), dates, 0) MM from datecreator
)
,CTE3 AS
(
SELECT T.* , rnk
FROM Test T INNER JOIN CTE c ON C.Mm = T.Months
)
,CTE4 AS
(
SELECT Years,[1] Jan ,[2] Feb ,[3] Mar FROM CTE3
PIVOT
(SUM(Rent) FOR rnk IN ([1],[2],[3])) p
)
SELECT Years , SUM(Jan) Jan , SUM(Feb) Feb , SUM(Mar) Mar FROM CTE4 GROUP BY Years
You'll get the result :
Year1 Jan Feb Mar
2013 3000 3000 3000
2014 3500 3500 3500
As you can see above I used only the first Quarter (First 3 Months) but you can use the whole year.
Please let me know if you have any questions/Feedbacks :)