REGEX get all matched patterns by SQL DB2 - sql

Question

all.
I need to extract from the string by REGEX all that matching the pattern "TTT\d{3}"
For the string in example i would like to get:
TTT108,TTT109,TTT111,TTT110
The DB2 function i would like to use is REGEXP_REPLACE(str,'REGEX pattern', ',').
The number of matching can be 0,1,2,3... in each string.
Thank you.
The example:
TTT108(optional);TTT109(optional);TTT111(optional);TTT110optional);ENTITYLIST_2=(optional);ENTITYLIST_3=(optional);Containment_Status=(optional)

Answer 1

If you want to extract the valid instead of replacing the invalid characters, please check if this helps:
with data (s) as (values
('TTT108(optional);TTT109(optional);TTT111(optional);TTT110optional);ENTITYLIST_2=(optional);ENTITYLIST_3=(optional);Containment_Status=(optional)')
)
select listagg(sst,', ') within group (order by n)
from (
select n,
regexp_substr(s,'(TTT[0-9][0-9][0-9])', 1, n)
from data
cross join (values (1),(2),(3),(4),(5)) x (n) -- any numbers table
where n <= regexp_count(s,'(TTT[0-9][0-9][0-9])')
) x (n,sst)

Answer 2

For any number of tokens & Db2 versions before 11.1:
select id, listagg(tok, ',') str
from
(
values
(1, 'TTT108(optional);TTT109(optional);TTT111(optional);TTT110optional);ENTITYLIST_2=(optional);ENTITYLIST_3=(optional);Containment_Status=(optional)')
) mytable (id, str)
, xmltable
(
'for $id in tokenize($s, ";") let $new := replace($id, "(TTT\d{3}).*", "$1") where matches($id, "(TTT\d{3}).*") return <i>{string($new)}</i>'
passing mytable.str as "s"
columns tok varchar(6) path '.'
) t
group by id;