I need to separate two columns into two rows in sql
I have this:
Column1 Column2 Column3
Car 2 5
Boat 4
Truck 6
And I want this:
Column1 Column2
Car 2
Car 5
Boat 4
Truck 6
How can I do this in SQL?
This operation is unpivoting. I would recommend apply:
select t.column1, v.col
from t cross apply
(values (col1), (col2)) v(col)
where v.col is not null;
This should do it
select Column1, Column2
from tbl where Column2 is not null and Column2 <> ''
union
select Column1, Column3
from tbl where Column3 is not null and Column3 <> ''
Related
using BigQuery, I would like to be able to divide one column, column1, into two separate columns, column2, and column3 with 50% of all records in column1 in column2 and 50% of all records in column1 in column 3. Ex column1 has 8 records of the number 2. I'd like to create a column2 with 4 records of the number 2 and column3 with 4 records of the number 2.
Is there a query to write this in BigQuery?
Column1
2
2
2
2
2
2
2
2
Column2
2
2
2
2
Column3
2
2
2
2
try:
SELECT
Column1 AS Column2
FROM `my-project.my-dataset.my-table`
WHERE 1=1
QUALIFY ROW_NUMBER() OVER (ORDER BY Column1) <= (
SELECT COUNT(*)/2
FROM `my-project.my-dataset.my-table`
);
SELECT
Column1 AS Column3
FROM `my-project.my-dataset.my-table`
WHERE 1=1
QUALIFY ROW_NUMBER() OVER (ORDER BY Column1) > (
SELECT COUNT(*)/2
FROM `my-project.my-dataset.my-table`
);
This will give you 2 results: One for each Column2 and Column3 with the first and second half of the data respectively order by Column1 (to use analytical functions you always have to specify an ORDER BY inside an OVER clause)
For random order try:
CREATE TEMP TABLE a AS (
SELECT Column1 as Column2
FROM `my-project.my-dataset.my-table`
WHERE 1=1
QUALIFY
ROW_NUMBER() OVER (ORDER BY RAND()) <= (SELECT COUNT(*)/2 FROM `my-project.my-dataset.my-table`)
);
SELECT Column1 as Column3
FROM `my-project.my-dataset.my-table`
WHERE Column1 NOT IN (SELECT * FROM a);
SELECT * FROM a
In this case you'll get 3 results: first one is the temporary table creation and the other 2 are the columns 2 and 3.
Good day
I have problem with my table and counting
TABLE1
COLUMN1 COLUMN2
3 jjd
5 jd
3 jjd
4 kg
5 jd
48 gjh
446 djj
… …
I need
TABLE1
COLUMN1 COLUMN2 COLUMN3
3 jj 2
5 jd 2
4 kg 1
48 gjh 1
446 djj 1
... ... …
Iam doing but not working well.
SELECT * , COUNT(Column1) as column3 FROM TABLE1
Thanks for help withh my counting
Use a GROUP BY and ORDER BY with DESC to put them in COUNT total order.
SELECT COLUMN1, COLUMN2, COUNT(Column1) AS COLUMN3
FROM Table1
GROUP BY COLUMN1, COLUMN2
ORDER BY COUNT(Column1) DESC
Output
COLUMN1 COLUMN2 COLUMN3
5 jd 2
3 jjd 2
4 kg 1
446 djj 1
48 gjh 1
SQL Fiddle: http://sqlfiddle.com/#!6/89f49/4/0
Try by using group by
SELECT COLUMN1 ,
COLUMN2 ,
COUNT(Column1) As COLUMN3 FROM cte_TABLE1
Group by COLUMN1 ,COLUMN2
Order by COLUMN1
By using Window function
SELECT DISTINCT COLUMN1 ,
COLUMN2 ,
COUNT(Column1)OVER(Partition by COLUMN1,COLUMN2 ORder by COLUMN1 ) As COLUMN3 FROM cte_TABLE1
Result
COLUMN1 COLUMN2 column3
-----------------------
3 jjd 2
4 kg 1
5 jd 2
48 gjh 1
446 djj 1
Using OVER we can achieve it easily
SELECT COLUMN1 ,
COLUMN2 ,
COUNT(Column1)OVER(Partition by COLUMN1,COLUMN2 ORder by COLUMN1 ) As COLUMN3 FROM cte_TABLE1
Group By COLUMN1,COLUMN2
I have 3 columns as
Column1 column2 column3
GU1 1 a
GU1 2 a
GU1 3 a
GU2 4 b
GU3 5 c
GU4 6 a
GU4 7 b
I would like to filter out the column1 where the values are having multiple column3 values
In this example, I want to pull GU4 where it is having both a & b in the column3.
Use distinct in your count
select column1
from your_table
group by column1
having count(distinct column3) = 1
I want have a query on the table values
Column1 Column2 Column3
-----------------------
a b c
d e f
Result should be
Column1 a
Column2 b
Column3 c
Column1 d
Column2 e
Column3 f
Basically a key value pairs. Is it possible in Oracle?
Thanks for the help in advance
You can do it with UNION ALL, like this:
SELECT 'Column1' as Name, Column1 as Value FROM my_table
UNION ALL
SELECT 'Column2' as Name, Column2 as Value FROM my_table
UNION ALL
SELECT 'Column3' as Name, Column3 as Value FROM my_table
Here is a demo on sqlfiddle.
I have a question related to select query. here I am explaining down below.
I have a table with the following data
**Column1(Primary Key) Column2 Column3**
------ --------- --------------
1 C
2 C
3 Null
4 H
5 L
6 H
my problem is I have to replace the value of Column3 with the corresponding value of Column1 for every occurrence of data "C", "H" and "L". Please provide me query related to this problem. How can I solve this using query or stored procedure. Please elaborate the same.
I need final select query result as follows
**Column1(Primary Key) Column2 Column3**
------ --------- --------------
1 C 1
2 C 2
3 Null
4 H 4
5 L 5
6 H 6
Select Column1, Column2,
CASE
WHEN Column2 is not null THEN Column1
ELSE null --or whatever value you want for blank
END as Column3
From TableName t1
Alternatively you could it it like this:
Select Column1, Column2,
CASE
WHEN Column2 = 'L' or Column2 = 'H' or Column2 = 'C' THEN Column1
ELSE null --or whatever value you want for blank
END as Column3
From TableName t1
Do you mean UPDATE?
UPDATE tbl SET Column3 = Column1 WHERE Column2 IN ('C', 'H', 'L', 'F')
Or for all;
UPDATE tbl SET Column3 = Column1 WHERE Column2 IS NOT NULL
UPDATE mytable
SET Column3 = Column1
WHERE Column2 in ('C', 'H', 'L')
like this?
select Column1, Column2, Column1 as Column3 from table
Or I'm not sure what you are actually asking for ..?
Ah, sorry. Dind't read all of the question there ...
Most SQL dialects have a way to do conditional subselects, but they are different in differend dialects. So which SQL are you using?