XML Comparison(String) in SQL server - sql

Question

I have two XML strings in two separate tables.
**ROOT**
**Node ID=** 1
**name** vignesh **/name**
**street** 1211 **/street**
**/Node**
**Node ID=** 2
**name** ram **/name**
**street** 333 **/street**
**/Node**
**/ROOT**
**ROOT**
**Node ID=** 1
**name** newbie **/name**
**street** 121223 **/street**
**/Node**
**Node ID=** 2
**name** pro **/name**
**street** 445**/street**
**/Node**
**/ROOT**
Please help me to find the comparison between these two XMLs in SQL Server and give result as Old value and New value for both ID1 and ID2(Node).

Answer 1

I believe this will help you out . i build a proper XML structure by considering your XML data.
DECLARE #XMLString1 XML =
'<ROOT>
<Nodes>
<NodeID>1</NodeID>
<name>vignesh </name>
<street>1211</street>
</Nodes>
<Nodes>
<NodeID>2</NodeID>
<name>ram</name>
<street>333</street>
</Nodes>
</ROOT>' ,
#XMLString2 XML =
'<ROOT>
<Nodes>
<NodeID>1</NodeID>
<name>newbie </name>
<street>121223</street>
</Nodes>
<Nodes>
<NodeID>2</NodeID>
<name>pro</name>
<street>445</street>
</Nodes>
</ROOT>'
SELECT #XMLString1,#XMLString2
;WITH XMLDATA1 AS
(
SELECT T.X.value('NodeID[1]','varchar(50)') AS NODEID,
T.X.value('name[1]','varchar(50)') AS NAME,
T.X.value('street[1]','varchar(50)') AS STREET
FROM #XMLString1.nodes('/ROOT/Nodes')T(X)
)
,XMLDATA2 AS
(
SELECT T.X.value('NodeID[1]','varchar(50)') AS NODEID,
T.X.value('name[1]','varchar(50)') AS NAME,
T.X.value('street[1]','varchar(50)') AS STREET
FROM #XMLString2.nodes('/ROOT/Nodes')T(X)
)
SELECT X1.NODEID,X1.NAME AS OLD_NAME,X2.NAME AS NEW_NAME , X1.STREET AS OLD_STREET , X2.STREET AS NEW_STREET
FROM XMLDATA1 X1
INNER JOIN XMLDATA2 X2 ON X1.NODEID=X2.NODEID