I am trying to write a SQL statement that will return a set of Distinct set of CompanyNames from a table based on the most recent SaleDate withing a specified date range from another table.
T01 = Account
T02 = TransHeader
The fields of importance are:
T01.ID, T01.CompanyName
T02.AccountID, T02.SaleDate
T01.ID = T02.AccountID
What I want to return is the Max SaleDate for each CompanyName without any duplicate CompanyNames and only the Max(SaleDate) as LastSale. I will be using a Where Clause to limit the SaleDate range.
I tried the following but it returns all the records for all SalesDates in the range. This results in the same company being listed multiple times.
Current MS-SQL Query
SELECT T01.CompanyName, T02.LastSale
FROM
(SELECT DISTINCT ID, IsActive, ClassTypeID, CompanyName FROM Account) T01
FULL OUTER JOIN
(SELECT DISTINCT AccountID, TransactionType, MAX(SaleDate) LastSale FROM TransHeader group by AccountID, TransactionType, SaleDate) T02
ON T01.ID = T02.AccountID
WHERE ( ( T01.IsActive = 1 )AND
( (Select Max(SaleDate)From TransHeader Where AccountID = T01.ID AND TransactionType in (1,6) AND SaleDate is NOT NULL)
BETWEEN '01/01/2016' AND '12/31/2018 23:59:00' AND (Select Max(SaleDate)From TransHeader Where AccountID = T01.ID AND TransactionType in (1,6) AND SaleDate is NOT NULL) IS NOT NULL
)
)
ORDER BY T01.CompanyName
I thought the FULL OUTER JOIN was the ticket but it did not work and I am stuck.
Sample data Account Table (T01)
ID CompanyName IsActive ClassTypeID
1 ABC123 1 1
2 CDE456 1 1
3 EFG789 1 1
4 Test123 0 1
5 Test456 1 1
6 Test789 0 1
Sample data Transheader table (T02)
AccountID TransactionType SaleDate
1 1 02/03/2012
2 1 03/04/2013
3 1 04/05/2014
4 1 05/06/2014
5 1 06/07/2014
6 1 07/08/2015
1 1 08/09/2016
1 1 01/15/2016
2 1 03/20/2017
2 1 03/21/2017
3 1 03/04/2017
3 1 04/05/2018
3 1 05/27/2018
4 1 06/01/2018
5 1 07/08/2018
5 1 08/01/2018
5 1 10/11/2018
6 1 11/30/2018
Desired Results
CompanyName LastSale (Notes note returned in the result)
ABC123 01/15/2016 (Max(SaleDate) LastSale for ID=1)
CDE456 03/21/2017 (Max(SaleDate) LastSale for ID=2)
EFG789 05/27/2018 (Max(SaleDate) LastSale for ID=3)
Testing456 10/11/2018 (Max(SaleDate) LastSale for ID=5)
ID=4 & ID=6 are note returned because IsActive = 0 for these records.
One option is to select the maximum date in the select clause.
select
a.*,
(
select max(th.saledate)
from transheader th
where th.accountid = a.id
and th.saledate >= '2016-01-01'
and th.saledate < '2019-01-01'
) as max_date
from account a
where a.isactive = 1
order by a.id;
If you only want to show transaction headers with sales dates in the given date range, then you can just inner join the maximum dates with the accounts. In order to do so, you must group your date aggregation per account:
select a.*, th.max_date
from account a
join
(
select accountid, max(saledate) as max_date
from transheader
and saledate >= '2016-01-01'
and saledate < '2019-01-01'
group by accountid
) th on th.accountid = a.id
where a.isactive = 1
order by a.id;
select CompanyName,MAX(SaleDate) SaleDate from Account a
inner join Transheader b on a.id = b.accountid
group by CompanyName
order by 1
Related
let's say there's a table have data like below
id
status
date
1
4
2022-05
2
3
2022-06
I want find count of id of each month by their status. Something like this below
date
count(status1) = 4
count(status2) =3
2022-05
1
null
2022-06
null
1
I tried doing
-- select distinct (not working)
select date, status1, status2 from
(select date, count(id) as "status1" from myTable
where status = 4 group by date) as myTable1
join
(select date, count(id) as "status2" from myTable
where status = 3 group by date) as myTable2
on myTable1.date = myTable2.date;
-- group by (not working)
but it does duplicate the data needed.
and I am using SQL Server.
select d.date,
sum
(
case
when d.status=4 then 1
else 0
end
)count_status_4,
sum
(
case
when d.status=5 then 1
else 0
end
)count_status_5
from your_table as d
group by d.date
I'm working on a service that needs to calculate how much a customer owes, according to a total invoice value and the partial payments that the customer has made.
So, in a tableA I have a row with the invoice total value:
[dbo].[TableA]
ID CustomerId InvoiceVal
1 12 1000
2 11 2000
3 10 5000
4 14 15000
5 12 100
6 16 8000
7 18 3200
In a TableB I have the record of each customer's partial payments they have made to each invoice:
[dbo].[TableB]
ID InvoiceId Payment
1 1 150
2 3 50
3 1 120
4 1 100
5 5 90
6 4 7500
So, as you can see, the customer 12 has an invoice for $1000 and has made 3 payment that sum $370
I need to be able to se the partial total owed in each row, this is the expected result:
No. InoviceId CustomerId Payment Owed
1 1 12 150 850
2 1 12 120 730
3 1 12 100 630
So far, this is my code:
DECLARE #invid int = '1'
DECLARE #invoicetotal numeric(18,2)
SET #invoicetotal =
(
SELECT
[dbo].[TableA].[InvoiceVal]
FROM [dbo].[TableA]
WHERE
([dbo].[TableA].[ID] = #invid)
)
SELECT
*,
SUM(#invoicetotal - [dbo].[TableB].[Payment]) OVER(ORDER BY [dbo].[TableB].[ID] ROWS BETWEEN UNBOUNDED PRECEDING AND 1 PRECEDING) AS [Owed]
FROM [dbo].[TableB]
WHERE
([dbo].[TableB].[InvoiceId] = #invid)
But this is what I get:
ID InvoiceId Payment Owed
1 1 150.00 NULL
3 1 120.00 850.00
4 1 100.00 1730.00
I need to sum the previous payment on each row.
Thanks!
Something like this would help
SELECT
ROW_NUMBER() OVER (ORDER BY TableB.ID ASC) NO,
CustomerId,
Payment,
InvoiceVal - SUM(Payment) OVER (PARTITION BY TableA.ID ORDER BY TableB.Id ASC) Owed
FROM TableA
INNER JOIN TableB
ON TableA.Id = TableB.InvoiceId
WHERE
CustomerId = 12
Working Fiddle
Your query will depend on what you are trying to make as your final output.
If you want just ONE CustomerID, go with:
SELECT a.ID AS InvoiceID, a.CustomerID, a.InvoiceVal AS StartInvoice
, b.ID AS bid, b.Payment
, a.InvoiceVal - ISNULL(SUM(b.Payment) OVER (PARTITION BY a.ID ORDER BY b.id),0) AS owed
FROM TableA a
LEFT OUTER JOIN TableB b ON a.ID = b.InvoiceID
WHERE a.CustomerID = 12
And if that CustomerID doesn't have any payments, you want to use a LEFT JOIN so that you don't eliminate an amount owed.
SELECT a.ID AS aid, a.CustomerID, a.InvoiceVal AS StartInvoice
, b.ID AS bid, b.Payment
, a.InvoiceVal - ISNULL(SUM(b.Payment) OVER (PARTITION BY a.ID ORDER BY b.id),0) AS owed
FROM TableA a
LEFT OUTER JOIN TableB b ON a.ID = b.InvoiceID
WHERE a.CustomerID = 11
I also added an ISNULL() around Payment to keep from nulling out your owed amount. It could also be added to the InvoiceVal to account for a CustomerID who hasn't been invoiced yet, if that was needed (or possible from other tables).
IF you want to get ALL CustomerIDs, you'll have to account for that in your partition.
SELECT s1.CustomerID, aid AS InvoiceID, s1.bid, s1.Payment
, (s1.StartInvoice - s1.runningPayment) AS Owed
FROM (
SELECT a.ID AS aid, a.CustomerID, a.InvoiceVal AS StartInvoice
, b.ID AS bid, b.Payment
, ISNULL(SUM(b.Payment) OVER (PARTITION BY a.CustomerID, a.ID ORDER BY b.id),0) AS runningPayment
FROM TableA a
LEFT OUTER JOIN TableB b ON a.ID = b.InvoiceID
) s1
ORDER BY s1.CustomerID, s1.aid, s1.bid
Fiddle demonstrates overpayment or paying total balance for 0 owed.
I need to make a query where only the last line of each user that has a car gets a license plate number.
ID UserId LicensePlate HasCar
1 1 ABC123 1
2 1 ABC123 1
3 2 NULL 0
4 3 UVW789 1
5 3 UVW789 1
Should become:
ID UserId LicensePlate HasCar
1 1 NULL 1
2 1 ABC123 1
3 2 NULL 0
4 3 NULL 1
5 3 UVW789 1
So I basically need to find all users with a licenseplate and change all but the last one and make the LicensePlate NULL
Assuming the ID column is an identity column so it can provide the ordering, something like this should do the trick:
;WITH CTE AS
(
SELECT Id,
UserId,
LicensePlate,
ROW_NUMBER() OVER(PARTITION BY UserId ORDER BY Id DESC) rn
FROM Table
WHERE HasCar = 1
)
UPDATE CTE
SET LicensePlate = NULL
WHERE rn > 1
You can try this
UPDATE l
SET l.LicensePlate = null
FROM Car l
INNER JOIN (SELECT UserId, Max(Id) AS max_id
FROM Car
GROUP BY UserId) m ON m.UserId = l.UserId
AND m.max_id <> l.id
You can do it with a join on the table itself like that :
UPDATE car c
INNER JOIN car c2 ON c.userId = c2.userId AND c.id < c2.id AND c.HasCar = 1 AND c2.HasCar = 1
SET c.LicensePlate = NULL
The condition c.id < c2.id will avoid to select the last line
By using LAG Function also you can achieve it.
;WITH License(ID,UserId,LicensePlate,HasCar)
as
(
SELECT 1,1,'ABC123',1 UNION ALL
SELECT 2,1,'ABC123',1 UNION ALL
SELECT 3,2,NULL ,0 UNION ALL
SELECT 4,3,'UVW789',1 UNION ALL
SELECT 5,3,'UVW789',1
)
SELECT ID,UserId,LAG(LicensePlate,1,NULL) OVER(PARTITION BY UserId ORDER BY LicensePlate),HasCar FROM License
The GROUP BY and HAVING isn't the hard part. This query results the summary:
SELECT date, account, amount, COUNT(1) AS num
FROM "transactions"
GROUP BY date, account, amount
HAVING num > 1
Something like:
date account amount num
2011-02-07 580416690 -6.4 2
2011-07-19 -50.0 2
2011-08-29 2445588 -22.0 2
2011-12-16 265113334 -0.1 3
But I dont want the summary (4 records). I want all the relevant records (so 2 + 2 + 2 + 3 = 9 records). If the GROUP BY was on 1 column, that wouldn't be hard either, but with 3 columns...
How do I get the actual records with those values? 1 query must be possible. Do I need 3 subqueries?
One way to do it is to join back to transactions
SELECT *
FROM transactions t JOIN
(
SELECT date, account, amount
FROM transactions
GROUP BY date, account, amount
HAVING COUNT(*) > 1
) d
ON (t.date = d.date
AND t.account = d.account
AND t.amount = d.amount) OR
(t.date = d.date
AND t.account IS NULL AND d.account IS NULL
AND t.amount = d.amount)
Here is a SQLFiddle demo
I'm working with a table that has dozens of rows per customer, each with a date and several columns representing various statuses. I'm only interested in pulling the rows where a change took place in one particular column (specifically 0 to 1 or 1 to 0, see status column below).
I can't simply use row_number() over (partition by customer_id, status order by date) because the status can go back and forth between 0 and 1.
Here's a sample of what I'm trying to do (note that there are two different Customer IDs in this example):
Original Table
Row CustomerID Status Date
1 ABC 0 3/12/2013
2 ABC 0 3/31/2013
3 ABC 1 4/13/2013
4 ABC 1 4/15/2013
5 ABC 1 5/17/2013
6 ABC 0 6/25/2013
7 ABC 0 6/28/2013
8 XYZ 0 8/2/2013
9 XYZ 1 5/10/2013
10 XYZ 0 5/18/2013
11 XYZ 1 8/23/2013
12 XYZ 1 9/7/2013
Desired Query Output
Customer ID Status Date
ABC 1 4/13/2013
ABC 0 6/25/2013
XYZ 1 5/10/2013
XYZ 0 5/18/2013
XYZ 1 8/23/2013
You were on the right track with ROW_NUMBER. It can be especially helpful in joining the table to itself in cases such as yours.
The following should get you what you're looking for:
WITH CTE AS (
SELECT Row,
CustomerID,
Status,
Date,
ROW_NUMBER() OVER(PARTITION BY CustomerID ORDER BY Row) AS N
FROM OriginalTable
)
SELECT A.CustomerID,
A.Status,
A.Date
FROM CTE A
JOIN CTE B
ON A.N = B.N+1
AND A.CustomerID = B.CustomerID
WHERE A.Status <> B.Status
ORDER BY
A.Row
select distinct b.CustomerID, b.status, min(b.date)
From customer a, customer b
where a.CustomerID = b.CustomerID and a.status <> b.status and a.date < b.date
group by b.CustomerID, b.status, a.date;