I have this df:
ID Date XXX 123_Var 456_Var 789_Var 123_P 456_P 789_P
A 07/16/2019 1 987 551 313 22 12 94
A 07/16/2019 9 135 748 403 92 40 41
A 07/18/2019 8 376 938 825 14 69 96
A 07/18/2019 5 259 176 674 52 75 72
B 07/16/2019 9 690 304 948 56 14 78
B 07/16/2019 8 819 185 699 33 81 83
B 07/18/2019 1 580 210 847 51 64 87
I want to group the df by ID and Date, aggregate the XXX column by the maximum value, and aggregate 123_Var, 456_Var, 789_Var columns by the minimum value.
* Note: The df contains many of these columns. The shape is: {some int}_Var.
This is the current code I've started to write:
df = (df.groupby(['ID','Date'], as_index=False)
.agg({'XXX':'max', list(df.filter(regex='_Var')): 'min'}))
Expected result:
ID Date XXX 123_Var 456_Var 789_Var
A 07/16/2019 9 135 551 313
A 07/18/2019 8 259 176 674
B 07/16/2019 9 690 185 699
B 07/18/2019 1 580 210 847
Create dictionary dynamic with dict.fromkeys and then merge it with {'XXX':'max'} dict and pass to GroupBy.agg:
d = dict.fromkeys(df.filter(regex='_Var').columns, 'min')
df = df.groupby(['ID','Date'], as_index=False).agg({**{'XXX':'max'}, **d})
print (df)
ID Date XXX 123_Var 456_Var 789_Var
0 A 07/16/2019 9 135 551 313
1 A 07/18/2019 8 259 176 674
2 B 07/16/2019 9 690 185 699
3 B 07/18/2019 1 580 210 847
Related
I have a data table derived via unstacking an existing dataframe:
Day 0 1 2 3 4 5 6
Hrs
0 223 231 135 122 099 211 217
1 156 564 132 414 156 454 157
2 950 178 121 840 143 648 192
3 025 975 151 185 341 145 888
4 111 264 469 330 671 201 345
-- -- -- -- -- -- -- --
I want to simply change the column titles so I have the days of the week displayed instead of numbered. Something like this:
Day Mon Tue Wed Thu Fri Sat Sun
Hrs
0 223 231 135 122 099 211 217
1 156 564 132 414 156 454 157
2 950 178 121 840 143 648 192
3 025 975 151 185 341 145 888
4 111 264 469 330 671 201 345
-- -- -- -- -- -- -- --
I've tried .rename(columns = {'original':'new', etc}, inplace = True) and other similar functions, none of which have worked.
I also tried going to the original dataframe and creating a dt.day_name column from the parsed dates, but it come out with the days of the week mixed up.
I'm sure it's a simple fix, but I'm living off nothing but caffeine, so help would be appreciated.
You can try:
import pandas as pd
df = pd.DataFrame(columns=[0,1,2,3,4,5,6])
df.columns = ["Mon", "Tue", "Wed", "Thu", "Fri", "Sat", "Sun"]
I have just started with python and need some help. I have a dataframe which looks like "Input Data", What I want is stack by every nth column. In other words, I want a dataframe where every nth Column is appended below to first m rows
id
city
Col 1
Col 2
Col 3
Col 4
Col 5
Col 6
Col 7
Col 8
Col 9
Col 10
1
1
51
155
255
355
455
666
777
955
55
553
2
0
52
155
255
355
455
666
777
595
55
553
3
NAN
53
155
255
355
455
666
777
559
55
535
4
1
54
155
255
355
545
666
777
559
55
535
5
7
55
155
255
355
455
666
777
955
55
535
Required Output
id
city
Col 1
Col 2
Col 3
Col 4
Col 5
1
1
51
155
255
355
455
2
0
52
155
255
355
455
3
NAN
53
155
255
355
455
4
1
54
155
255
355
545
5
7
55
155
255
355
455
1
1
666
777
955
55
553
2
0
666
777
595
55
553
3
NAN
666
777
559
55
535
4
1
666
777
559
55
535
5
7
666
777
955
55
535
I am trying to do something opposite of this
Input & required Output
In [74]: column_list = [df.columns[k:k+5] for k in range(2, len(df.columns), 5)]
In [75]: column_list
Out[75]:
[Index(['Col 1', 'Col 2', 'Col 3', 'Col 4', 'Col 5'], dtype='object'),
Index(['Col 6', 'Col 7', 'Col 8', 'Col 9', 'Col 10'], dtype='object')]
In [76]: dfs = [df[['id', 'city'] + columns.tolist()].rename(columns=dict(zip(columns, range(5)))) for columns in column_list]
In [77]: dfs
Out[77]:
[ id city 0 1 2 3 4
0 1 1.0 51 155 255 355 455
1 2 0.0 52 155 255 355 455
2 3 NaN 53 155 255 355 455
3 4 1.0 54 155 255 355 545
4 5 7.0 55 155 255 355 455,
id city 0 1 2 3 4
0 1 1.0 666 777 955 55 553
1 2 0.0 666 777 595 55 553
2 3 NaN 666 777 559 55 535
3 4 1.0 666 777 559 55 535
4 5 7.0 666 777 955 55 535]
In [78]: pd.concat(dfs, ignore_index=True)
Out[78]:
id city 0 1 2 3 4
0 1 1.0 51 155 255 355 455
1 2 0.0 52 155 255 355 455
2 3 NaN 53 155 255 355 455
3 4 1.0 54 155 255 355 545
4 5 7.0 55 155 255 355 455
5 1 1.0 666 777 955 55 553
6 2 0.0 666 777 595 55 553
7 3 NaN 666 777 559 55 535
8 4 1.0 666 777 559 55 535
9 5 7.0 666 777 955 55 535
To explain :
First generate the required columns for each slice
pd.concat requires the column names of all the dataframes in the list to be the same, hence the renames in rename(columns=dict(zip(columns, range(5)))). We are just renaming the sliced columns to 0,1,2,3,4
Last step is to concat everything.
EDIT
Based on the comments by OP:
Sorry #Asish M. but how to add a column for dataset number in each dataset of dfs, eg- here we split our dataset into 2, so I need one column which says for first 1 to 5 ids - 'first' (or 1), then again for another 1 to 5 ids - 'second' (or 2) in the output. I hope it's making scenes
dfs = [df[['id', 'city'] + columns.tolist()].assign(split_group=idx).rename(columns=dict(zip(columns, range(5)))) for idx, columns in enumerate(column_list)]
df.assign(split_group=idx) creates a column 'split_group' with value = idx. You get the idx from enumerating the column_list
I am working with the following code:
url = 'https://raw.githubusercontent.com/dothemathonthatone/maps/master/fertility.csv'
df = pd.read_csv(url)
year regional_schlüssel Aus15 Deu15 Aus16 Deu16 Aus17 Deu17 Aus18 Deu18 ... aus36 aus37 aus38 aus39 aus40 aus41 aus42 aus43 aus44 aus45
0 2000 5111000 0 4 8 25 20 45 56 89 ... 935 862 746 732 792 660 687 663 623 722
1 2000 5113000 1 1 4 14 13 33 19 48 ... 614 602 498 461 521 470 393 411 397 400
2 2000 5114000 0 11 0 5 2 13 7 20 ... 317 278 265 235 259 228 204 173 213 192
3 2000 5116000 0 2 2 7 3 28 13 26 ... 264 217 206 207 197 177 171 146 181 169
4 2000 5117000 0 0 3 1 2 4 4 7 ... 135 129 118 116 128 148 89 110 124 83
I would like to create a new set of columns fertility_deu15, ..., fertility_deu45 and fertility_aus15, ..., fertility_aus45 such that aus15 / Aus15 = fertiltiy_aus15 and deu15/ Deu15 = fertility_deu15 for each ausi and Ausj where j == i \n [15-45] and deui:Deuj where j == i \n [15-45]
I'm not sure what is up with that data but we need to fix it to make it numeric. I'll end up doing that while filtering
numerator = df.filter(regex='^[a-z]+\d+$') # Lower case ones
numerator = numerator.apply(pd.to_numeric, errors='coerce') # Fix numbers
denominator = df.filter(regex='^[A-Z][a-z]+\d+$').rename(columns=str.lower)
denominator = denominator.apply(pd.to_numeric, errors='coerce')
numerator.div(denominator).add_prefix('fertility_')
I have this data frame:
ID Date X 123_Var 456_Var 789_Var
A 16-07-19 3 777 250 810
A 17-07-19 9 637 121 529
A 18-07-19 7 878 786 406
A 19-07-19 4 656 140 204
A 20-07-19 2 295 272 490
A 21-07-19 3 778 600 544
A 22-07-19 6 741 792 907
B 01-07-19 4 509 690 406
B 02-07-19 2 732 915 199
B 03-07-19 2 413 725 414
B 04-07-19 2 170 702 912
B 09-08-19 3 851 616 477
B 10-08-19 9 475 447 555
B 11-08-19 1 412 403 708
B 12-08-19 2 299 537 321
B 13-08-19 4 310 119 125
C 01-12-18 4 912 755 657
C 02-12-18 4 586 771 394
C 04-12-18 9 498 122 193
C 05-12-18 2 500 528 764
C 06-12-18 1 982 383 654
C 07-12-18 1 299 496 488
C 08-12-18 3 336 691 496
C 09-12-18 3 206 433 263
C 10-12-18 2 373 319 111
I want to show the minimum value between current row and previous row values, for each column in 123_Var 456_Var 789_Var set.
That should be applied separately for each ID. (Groupby.)
The first row of each ID, will show the current value. (Since there's no "previous" value to compare.)
Expected result:
ID Date X 123_Var 456_Var 789_Var 123_Min2 456_Min2 789_Min2
A 16-07-19 3 777 250 810 777 250 810
A 17-07-19 9 637 121 529 637 121 529
A 18-07-19 7 878 786 406 637 121 406
A 19-07-19 4 656 140 204 656 140 204
A 20-07-19 2 295 272 490 295 140 204
A 21-07-19 3 778 600 544 295 272 490
A 22-07-19 6 741 792 907 741 600 544
B 01-07-19 4 509 690 406 509 690 406
B 02-07-19 2 732 915 199 509 690 199
B 03-07-19 2 413 725 414 413 725 199
B 04-07-19 2 170 702 912 170 702 414
B 09-08-19 3 851 616 477 170 616 477
B 10-08-19 9 475 447 555 475 447 477
B 11-08-19 1 412 403 708 412 403 555
B 12-08-19 2 299 537 321 299 403 321
B 13-08-19 4 310 119 125 299 119 125
C 01-12-18 4 912 755 657 912 755 657
C 02-12-18 4 586 771 394 586 755 394
C 04-12-18 9 498 122 193 498 122 193
C 05-12-18 2 500 528 764 498 122 193
C 06-12-18 1 982 383 654 500 383 654
C 07-12-18 1 299 496 488 299 383 488
C 08-12-18 3 336 691 496 299 496 488
C 09-12-18 3 206 433 263 206 433 263
C 10-12-18 2 373 319 111 206 319 111
IIUC, We use groupby.shift to select the previous var for each ID, then we can use DataFrame.where
to leave only the cells where the previous value is lower than the current value and fill with the current value in the rest. We use DataFrame.add_suffix to add _Min2 and we join with df with DataFrame.join
df_vars = df[['123_Var','456_Var','789_Var']]
df = df.join(df.groupby('ID')['123_Var','456_Var','789_Var']
.shift()
.fillna(df_vars)
.where(lambda x: x.le(df_vars),df_vars)
.add_suffix('_Min2')
)
print(df)
Output
ID Date X 123_Var 456_Var 789_Var 123_Var_Min2 456_Var_Min2 789_Var_Min2
0 A 16-07-19 3 777 250 810 777.0 250.0 810.0
1 A 17-07-19 9 637 121 529 637.0 121.0 529.0
2 A 18-07-19 7 878 786 406 637.0 121.0 406.0
3 A 19-07-19 4 656 140 204 656.0 140.0 204.0
4 A 20-07-19 2 295 272 490 295.0 140.0 204.0
5 A 21-07-19 3 778 600 544 295.0 272.0 490.0
6 A 22-07-19 6 741 792 907 741.0 600.0 544.0
7 B 01-07-19 4 509 690 406 509.0 690.0 406.0
8 B 02-07-19 2 732 915 199 509.0 690.0 199.0
9 B 03-07-19 2 413 725 414 413.0 725.0 199.0
10 B 04-07-19 2 170 702 912 170.0 702.0 414.0
11 B 09-08-19 3 851 616 477 170.0 616.0 477.0
12 B 10-08-19 9 475 447 555 475.0 447.0 477.0
13 B 11-08-19 1 412 403 708 412.0 403.0 555.0
14 B 12-08-19 2 299 537 321 299.0 403.0 321.0
15 B 13-08-19 4 310 119 125 299.0 119.0 125.0
16 C 01-12-18 4 912 755 657 912.0 755.0 657.0
17 C 02-12-18 4 586 771 394 586.0 755.0 394.0
18 C 04-12-18 9 498 122 193 498.0 122.0 193.0
19 C 05-12-18 2 500 528 764 498.0 122.0 193.0
20 C 06-12-18 1 982 383 654 500.0 383.0 654.0
21 C 07-12-18 1 299 496 488 299.0 383.0 488.0
22 C 08-12-18 3 336 691 496 299.0 496.0 488.0
23 C 09-12-18 3 206 433 263 206.0 433.0 263.0
24 C 10-12-18 2 373 319 111 206.0 319.0 111.0
Case 2: If you want check the n previous use groupby.rolling
df_vars = df[['123_Var','456_Var','789_Var']]
n = 3
df = df.join(df.groupby('ID')['123_Var','456_Var','789_Var']
.rolling(n,min_periods = 1).min()
.reset_index(drop=True)
.add_suffix(f'_Min{n}')
)
print(df)
ID Date X 123_Var 456_Var 789_Var 123_Var_Min3 456_Var_Min3 789_Var_Min3
0 A 16-07-19 3 777 250 810 777.0 250.0 810.0
1 A 17-07-19 9 637 121 529 637.0 121.0 529.0
2 A 18-07-19 7 878 786 406 637.0 121.0 406.0
3 A 19-07-19 4 656 140 204 637.0 121.0 204.0
4 A 20-07-19 2 295 272 490 295.0 121.0 204.0
5 A 21-07-19 3 778 600 544 295.0 140.0 204.0
6 A 22-07-19 6 741 792 907 295.0 140.0 204.0
7 B 01-07-19 4 509 690 406 509.0 690.0 406.0
8 B 02-07-19 2 732 915 199 509.0 690.0 199.0
9 B 03-07-19 2 413 725 414 413.0 690.0 199.0
10 B 04-07-19 2 170 702 912 170.0 690.0 199.0
11 B 09-08-19 3 851 616 477 170.0 616.0 199.0
12 B 10-08-19 9 475 447 555 170.0 447.0 414.0
13 B 11-08-19 1 412 403 708 170.0 403.0 477.0
14 B 12-08-19 2 299 537 321 299.0 403.0 321.0
15 B 13-08-19 4 310 119 125 299.0 119.0 125.0
16 C 01-12-18 4 912 755 657 912.0 755.0 657.0
17 C 02-12-18 4 586 771 394 586.0 755.0 394.0
18 C 04-12-18 9 498 122 193 498.0 122.0 193.0
19 C 05-12-18 2 500 528 764 498.0 122.0 193.0
20 C 06-12-18 1 982 383 654 498.0 122.0 193.0
21 C 07-12-18 1 299 496 488 299.0 122.0 193.0
22 C 08-12-18 3 336 691 496 299.0 383.0 488.0
23 C 09-12-18 3 206 433 263 206.0 383.0 263.0
24 C 10-12-18 2 373 319 111 206.0 319.0 111.0
A quite elegant solution is to apply rolling(2).min() to each group,
but to avoid the first row of NaN in each group, this first row
should be "replicated" from the source group.
To do your task, start from defining the following function:
def fnMin2(grp):
rv = pd.concat([pd.DataFrame([grp.iloc[0, -3:]]),
grp[['123_Var', '456_Var', '789_Var']].rolling(2).min().iloc[1:]])\
.astype('int')
rv.columns = [ it.replace('Var', 'Min2') for it in rv.columns ]
return grp.join(rv)
Then apply it to each group:
df.groupby('ID').apply(fnMin2)
Note that column names assigned to new columns in my solution are
just as you wish, contrary to the solution you accepted.
#this compares the next row to the previous row
ext = df.iloc[:,3:].gt(df.iloc[:,3:].shift(1))
#simply renamed the columns here
ext.columns=['123_min','456_min','789_min']
#join the two dataframes by columns
M = pd.concat([df,ext],axis=1)
#based on the conditions, if it is False,
#use value from current row,
#else use value from previous row
M['123_min']=np.where(M['123_min']==0,
M['123_Var'],
M['123_Var'].shift(1)
)
M['456_min']=np.where(M['456_min']==0,
M['456_Var'],
M['456_Var'].shift(1)
)
M['789_min']=np.where(M['789_min']==0,
M['789_Var'],
M['789_Var'].shift(1)
)
I have a dataframe named nf as below :
A B C D E A.1 B.1 C.1 D.1 E.1 A.2 B.2 C.2 D.2 E.2 F.2
122 434 345 435 566 657 466 762 123 645
434 453 786 654 980 424 786 897 564 243 345 455 432 435 432
234 553 588 899 533
123 875 789 456 876 667 988 887 234 342
and so on ....
where the values repeat every 5th column and in the 3rd row I have no values for the second half.
The above provided values are just a sample of the original values I have. In original I have 50 columns with values repeating columnwise every 10th. And rows i have alomst 120k. I want to reshape the values so that there are only 10 columns in such a way that values append at the last as below.
Desired output is :
A B C D E
122 434 345 435 566
434 453 786 654 980
234 553 588 899 533
123 875 789 456 876
657 466 762 123 645
424 786 897 564 243
667 988 887 234 342
345 455 432 435 432
All the values by columns should append at the bottom in the rows.
You can using stack and groupby
df.stack().groupby(level=1).apply(list).apply(pd.Series).T
Out[1178]:
A B C D E
0 122.0 434.0 345.0 435.0 566.0
1 657.0 466.0 762.0 123.0 645.0
2 434.0 453.0 786.0 654.0 980.0
3 424.0 786.0 897.0 564.0 243.0
4 345.0 455.0 432.0 435.0 432.0
5 234.0 553.0 588.0 899.0 533.0
6 123.0 875.0 789.0 456.0 876.0
7 667.0 988.0 887.0 234.0 342.0
Update
df.apply(lambda x : ','.join(x[x.notnull()].astype(str))).groupby(level=0).apply(','.join).str.split(',',expand=True).T
Out[1203]:
A B C D E F
0 122.0 434.0 345.0 435.0 566.0
1 434.0 453.0 786.0 654.0 980.0 None
2 234.0 553.0 588.0 899.0 533.0 None
3 123.0 875.0 789.0 456.0 876.0 None
4 657.0 466.0 762.0 123.0 645.0 None
5 424.0 786.0 897.0 564.0 243.0 None
6 667.0 988.0 887.0 234.0 342.0 None
7 345.0 455.0 432.0 435.0 432.0 None