Separate a String into Two parts 'name' and 'number' using VBA - vba

I need to separate following strings into Name and Number: e.g.
evil333 into evil and 333
bili454 into bili and 454
elvis04 into elvis and 04
Split(String, "#") ' don't work here because numbers are unknown
similarly
Mid(String, 1, String - #) ' don't work because Numbers length is unknown
so what should be the best way to start? Just want to keep it simple as possible
Update:
For further info follow - https://youtu.be/zjF7oLLgtms

Two more ways for solving this:
Sub test()
Dim sInputString As String
Dim i As Integer
Dim lFirstNumberPos As Long
sInputString = "evil333"
'loop through text in input string
'if value IsNumeric (digit), stop looping
For i = 1 To Len(sInputString)
If IsNumeric(Mid(sInputString, i, 1)) Then
lFirstNumberPos = i
Exit For
End If
Next i
Dim Name As String
Dim Number As String
'return result
Name = Left$(sInputString, lFirstNumberPos - 1)
Number = Mid$(sInputString, lFirstNumberPos)
End Sub
Or another method:
Sub test2()
'if you are going to have too long string it would maybe better to use "instr" method
Dim sInputString As String
Dim lFirstNumberPos As Long
Dim i As Integer
sInputString = "evil333"
Dim lLoopedNumber as Long
LoopedNumber = 0
lFirstNumberPos = Len(sInputString) + 1
'loop through digits 0-9 and stop when any of the digits will be found
For i = 0 To 9
LoopedNumber = InStr(1, sInputString, cstr(i), vbTextCompare)
If LoopedNumber > 0 Then
lFirstNumberPos = Application.Min(LoopedNumber,lFirstNumberPos)
End If
Next i
Dim Name As String
Dim Number As String
'return result
Name = Left$(sInputString, lFirstNumberPos - 1)
Number = Mid$(sInputString, lFirstNumberPos)
End Sub

You should regular expressions (regex) to match the two parts of your strings. The following regex describes how to match the two parts:
/([a-z]+)([0-9]+)/
Their use in VBA is thorougly explained in Portland Runner's answer to How to use Regular Expressions (Regex) in Microsoft Excel both in-cell and loops

Related

Read all unique values from cells in a range and create a comma separated string from them?

I have written the following function to read all unique values from cells in a range and create a comma separated string from them? Is there a better, simpler way to do this?
Private Sub CsvUniqueValues(r As Excel.Range)
Dim c As Excel.Range
Dim s As String = ""
For Each c In r.Cells
If ExcelApp.WorksheetFunction.CountIf(r, c.Value) = 1 Then
s = s & ","
End If
Next
If s.Length > 0 Then
s = s.Substring(0, s.Length - 1)
End If
End Sub
You could use LINQ to get a list of only the unique values, like this:
Dim uniqueValues As IEnumerable = r.Cells.Where(Function(x) ExcelApp.WorksheetFunction.CountIf(r, x.Value) = 1))
Then, you could use LINQ to convert all of those unique values to strings:
Dim uniqueStrings As IEnumerable(Of String) = uniqueValues.Select(Of String)(Function(x) x.ToString())
Then you can use LINQ to convert the resulting list to an array:
Dim uniqueArray() As String = uniqueStrings.ToArray()
Then, you could use the String.Join method to combine them into a single CSV string:
Dim csv As String = String.Join(",", uniqueArray)
You could, of course, do all of this in a single command, like this:
Dim csv As String = String.Join(",",
r.Cells.Where(Function(x) ExcelApp.WorksheetFunction.CountIf(r, x.Value) = 1))
.Select(Of String)(Function(x) x.ToString())
.ToArray())
The question, though, is whether or not you would call that "easier". LINQ is useful because it makes code easier to to read and write, but when it's taken too far, it can become less readable, thereby defeating the purpose of using it. At the very least, to make your code more clear, I would move the first part into a named function so it's more self-documenting:
Public Function GetUniqueCellValuesAsString(r As Excel.Range) As IEnumerable(Of String)
Return r.Cells.Where(
Function(x) ExcelApp.WorksheetFunction.CountIf(r, x.Value) = 1))
.Select(Of String)(Function(x) x.ToString())
End Function
Then you could just build the CSV string like this:
Dim csv As String = String.Join(",", GetUniqueCellValuesAsString(r).ToArray())
I would make use of the collection object. Since collections can only contain unique values, trying to add all of your input data to a collection will result in an array of unique values. The following modification lets CsvUniqueValues return a comma separated string from the values in any given range.
'Test function and return result in MsgBox
Sub ReturnUnique()
MsgBox CsvUniqueValues(Selection)
End Sub
'Function will return csv-string from input range
Function CsvUniqueValues(r As Range) As String
Dim Cell As Range
Dim i As Integer
Dim DistCol As New Collection
Dim s As String
'Add all distinct values to collection
On Error Resume Next
For Each Cell In r
DistCol.Add Cell.Value, Cell.Value
Next Cell
On Error GoTo 0
'Write collection to comma seperated list
For i = 1 To DistCol.Count
s = s & DistCol.Item(i) & "; "
Next i
s = Left(s, Len(s) - 2)
CsvUniqueValues = s
End Function

What code will help me check a string for at least 2 numericals characters?

Basically, I am trying to create a random password generator using VB. However I am stumped at one certain place. I do not know how to check the string to see if at least 2 numerical characters have been inserted. I thought maybe a contain would help but I can only check for one character. Can anyone help me? The code at the moment is placed below:
Dim sChars As String="qwertyuiopasdfghjklzxcvbnmMNBVCXZLKJHGFDSAPOIUYTREWQ1234567890"
Dim sPassword As String = ""
Dim iLength As Integer
Do Until iLength >= 10 And sPassword.Contains(???)
Loop
You can use the following scenario
Dim sChars As String = "qwertyuiopasdfghjklzxcvbnmMNBV1CXZLKJHGFDSAPOIUYTREWQ"
Dim output As String = New String((From c As Char In sChars Select c Where Char.IsDigit(c)).ToArray())
If output.Length >= 2 Then
MsgBox("success")
Else
MsgBox("Doesn't meet the requirement") ' for this input this message will displayed
End If
suppose the input will be
Dim sChars As String="qwertyuiopasdfghjklzxcvbnmMNBVCXZLKJHGFDSAPOIUYTREWQ1234567890" then it will display Success
You can use the below code for matching the regex expressions:
Imports System.Text.RegularExpressions
Module Module1
Sub Main()
Dim regex As Regex = New Regex("\d{2}")
Dim match As Match = regex.Match("Dot 77 Perls")
If match.Success Then
Console.WriteLine(match.Value)
End If
End Sub
End Module
This will match for two numerical occurrences in the string and return the result. You can use the regex match in your web/console application and not execute the entire module
A little faster version than the regex approach:
Dim password As String = "somePasswordToTest24hehe6"
Dim numberCounter As Integer
Dim counterLimit As Integer = 2
Dim hasValidCountOfNumbers As Boolean
For Each ch As Char In password
If Char.IsDigit(ch) Then
numberCounter += 1
End If
If numberCounter >= counterLimit Then
hasValidCountOfNumbers = True
Exit For
End If
Next
If hasValidCountOfNumbers Then
'do probably nothing
Else
'notify that password validation failed
End If

optimal code for detecting formatting differences?

I need to compare two formatted strings. The text in the two of them is the same, only the formatting differs, meaning that some words are bold. The code should tell me if the location of the bold substrings are different e.g. the strings are formatted differently.
So far I tried a char-to-char approach, but it is far too slow.
It's a plain legal current text in MS Word, with cca 10-500 chars per string. Two people independently formatted the strings.
my code so far:
Function collectBold(r As Range) As String
Dim chpos As Integer
Dim ch As Variant
Dim str, strTemp As String
chpos = 1
Do
If r.Characters(chpos).Font.Bold Then
Do
Dim boold As Boolean
strTemp = strTemp + r.Characters(chpos)
chpos = chpos + 1
If (chpos < r.Characters.Count) Then boold = r.Characters(chpos).Font.Bold
Loop While (boold And chpos < r.Characters.Count)
str = str + Trim(strTemp) + "/"
strTemp = ""
Else: chpos = chpos + 1
End If
Loop While (chpos < r.Characters.Count)
collectBold = str
End Function
This code collect all bold substrings (strTemp) and merges them into one string (str), separating them with "/". The function runs for both strings to compare, and then checks if the outputs are the same.
If you only need to see if they are different, this function will do it:
Function areStringsDifferent(range1 As Range, range2 As Range) As Boolean
Dim i As Integer, j As Integer
For i = 1 To range1.Words.Count
'check if words are different formatted
If Not range1.Words(i).Bold = range2.Words(i).Bold Then
areStringsDifferent = True
Exit Function
'words same formatted, but characters may not be
ElseIf range1.Words(i).Bold = wdUndefined Then
For j = 1 To range1.Words(i).Characters.Count
If Not range1.Words(i).Characters(j).Bold = range2.Words(i).Characters(j).Bold Then
areStringsDifferent = True
Exit Function
End If
Next
End If
Next
areStringsDifferent = False
End Function
It first looks if the words are different formatted... If they have the same format but the format is undefinied, it looks into the characters of the word.

How to check what sub-string follows follows a string matched by InStr

I am trying to use the function InStr to find a specific string in another string.
When I find it, I would like to check what directly follows this string (for example End-user) and return this portion. So far I Have managed to write this:
If InStr(LCase(analysis), "End-user:") > 1 Then Range("AE" & i).Value = "OK"
which marks the relevant cell as OK once this string has been detected.
Could anyone help me please?
InStr returns the first index of the string to search ("End-user:") into the target string (Analysis). You should take it, together with the lengths to calculate the substring you want. Also bear in mind that you are using LCase in one part but not in the other one (what provokes that the string to search will never be found as far as it contains a capital letter). A code delivering what you want:
Dim analysis As String : analysis = "End-user: anyone"
Dim stringToSearch as String : stringToSearch = "End-user:"
Dim finalBit As String
Dim startIndex As Integer: startIndex = InStr(LCase(analysis), LCase(stringToSearch))
If (startIndex > 0 And InStr(LCase(analysis), LCase(stringToSearch)) < Len(analysis)) Then
Dim endIndex As Integer: endIndex = startIndex + Len(stringToSearch)
finalBit = Mid(analysis, endIndex, Len(analysis) - endIndex + 1)
End If
'finalBit -> " anyone"
More directly:
Dim StrMain As String
Dim StrSearch As String
Dim LngPos As Long
StrMain = "sample text End-user:kilroy"
StrSearch = "End-user:"
LngPos = InStr(StrMain, StrSearch)
If LngPos > 0 Then MsgBox Right$(StrMain, Len(StrMain) - LngPos - Len(StrSearch) + 1)

get string between other string vb.net

I have code below. How do I get strings inside brackets? Thank you.
Dim tmpStr() As String
Dim strSplit() As String
Dim strReal As String
Dim i As Integer
strWord = "hello (string1) there how (string2) are you?"
strSplit = Split(strWord, "(")
strReal = strSplit(LBound(strSplit))
For i = 1 To UBound(strSplit)
tmpStr = Split(strSplit(i), ")")
strReal = strReal & tmpStr(UBound(tmpStr))
Next
Dim src As String = "hello (string1) there how (string2) are you?"
Dim strs As New List(Of String)
Dim start As Integer = 0
Dim [end] As Integer = 0
While start < src.Length
start = src.IndexOf("("c, start)
If start <> -1 Then
[end] = src.IndexOf(")"c, start)
If [end] <> -1 Then
Dim subStr As String = src.Substring(start + 1, [end] - start - 1)
If Not subStr.StartsWith("(") Then strs.Add(src.Substring(start + 1, [end] - start - 1))
End If
Else
Exit While
End If
start += 1 ' Increment start to skip to next (
End While
This should do it.
Dim result = Regex.Matches(src, "\(([^()]*)\)").Cast(Of Match)().Select(Function(x) x.Groups(1))
Would also work.
This is what regular expressions are for. Learn them, love them:
' Imports System.Text.RegularExpressions
Dim matches = Regex.Matches(input, "\(([^)]*)\)").Cast(of Match)()
Dim result = matches.Select(Function (x) x.Groups(1))
Two lines of code instead of more than 10.
In the words of Stephan Lavavej: “Even intricate regular expressions are easier to understand and modify than equivalent code.”
Use String.IndexOf to get the position of the first opening bracket (x).
Use IndexOf again the get the position of the first closing bracket (y).
Use String.Substring to get the text based on the positions from x and y.
Remove beginning of string up to y+1.
Loop as required
That should get you going.
This may also work:
Dim myString As String = "Hello (FooBar) World"
Dim finalString As String = myString.Substring(myString.IndexOf("("), (myString.LastIndexOf(")") - myString.IndexOf("(")) + 1)
Also 2 lines.