sum last values and group by - sql

Question

I have "steps" table like this
id | points | game_id | price | user_id | timestamp | some | additional | fields
it contains game information.
I have a code which can group by game_id
SELECT game_id, MIN(timestamp),
(SELECT points FROM steps as t2 WHERE t2.game_id = t1.game_id ORDER BY t2.id DESC LIMIT 1) as last_point
WHERE user_id = 1
GROUP BY game_id
but I want to group by price and summarize each last point of the game. my query is
SELECT COUNT(DISTINCT game_id) as game_count, COUNT(id) as step_count, SUM(points), price
FROM steps WHERE user_id = 1
GROUP BY price
But this query returns a sum of all points while I need a sum of the last point in each game.
Please point me to the right way
Example result
last_points_sum | game_count | step_count | price
200 | 2 | 3 | 100
400 | 3 | 4 | 200
where table is
id | points | game_id | price | user_id | timestamp
1 | 10 | 5 | 100 | 1 | 100000001
2 | 200 | 5 | 100 | 1 | 100000002
3 | 200 | 6 | 200 | 1 | 100000003
4 | 0 | 6 | 200 | 1 | 100000004
5 | 400 | 6 | 200 | 1 | 100000005

Answer 1

Is this what you're looking for?
This assumes that timestamp is unique, at least for each instance of game_id.
SELECT
COUNT(DISTINCT game_id) AS game_count,
COUNT(id) AS step_count,
SUM(COALESCE(ltIsLastPoints, 0.0) * points),
price
FROM
(SELECT
game_id ltGameID,
MAX(timestamp) ltTimestamp,
1.0 ltIsLastPoints
FROM
steps
GROUP BY
game_id
) lt RIGHT JOIN
steps
ON ltGameID = game_id
AND ltTimestamp = timestamp
WHERE
user_id = 1
GROUP BY
price;
Your description says you want to group by points but your example query groups by price. I went with price.