SQL select records based on not existing record - sql

I have a table with records like this:
ID | NAME | PHASE_ID | OPERATION_ID | EXT_ID |
---+------+----------+--------------+--------+
1 | john | 5 | 5019 | aa-aaa |
2 | ann | 1 | 5048 | aa-aaa |
3 | mary | 1 | 5048 | bb-bbb |
4 | zack | 5 | 5019 | cc-ccc |
5 | paul | 1 | 5048 | cc-ccc |
6 | zoe | 2 | 5555 | aa-aaa |
7 | luke | 3 | 6666 | bb-bbb |
and I want to select all names from records having PHASE_ID=1 and OPERATION_ID=5048 for which there is no record with the same EXT_ID that have PHASE_ID=5 and OPERATION_ID=5019. In this table there is many combinations of PHASE_ID and OPERATION_ID for the same EXT_ID.
In this table name that fulfill this select would be only mary.
Any help composing that select would be appreciated.


Sounds like not exists:
select distinct name
from t
where phase_id = 1 and operation_id = 5048 and
not exists (select 1
from t t2
where t2.ext_id = t.ext_id and
t2.phase_id = 5 and t2.operation_id = 5019
);

Related

SQL Count depending on certain conditions

I have two tables.
One have userid and email (users table). The other have payments information (payments table) from the userid in users.
users
+--------+------------+
| Userid | Name |
+--------+------------+
| 1 | Alex T |
| 2 | Jeremy T |
| 3 | Frederic A |
+--------+------------+
payments
+--------+-----------+------------+----------+
| Userid | ValuePaid | PaidMonths | Refunded |
+--------+-----------+------------+----------+
| 1 | 1 | 12 | null |
| 1 | 20 | 12 | null |
| 1 | 20 | 12 | null |
| 1 | 20 | 1 | null |
| 2 | 1 | 1 | null |
| 2 | 20 | 12 | 1 |
| 2 | 20 | 12 | null |
| 2 | 20 | 1 | null |
| 3 | 1 | 12 | null |
| 3 | 20 | 1 | 1 |
| 3 | 20 | 1 | null |
+--------+-----------+------------+----------+
I want to count the PaidMonths taking in consideration the following rules:
If ValuePaid < 10 PaidMonths should be = 0.23 (even if in the column the value seen is any other mumber).
If Refund=1 the PaidMonths should be = 0.
Based on this when i join both tables by userid, and sum the PaidMonths based in the previousrules, i expect to see as result:
+--------+------------+------------+
| userid | Name | paidMonths |
+--------+------------+------------+
| 1 | Alex T | 25.23 |
| 2 | Jeremy T | 13.23 |
| 3 | Frederic A | 1.23 |
+--------+------------+------------+
Can you help me to achieve this in the most elegant way? Should a temporary table be used?

The following gives your desired results, using apply with case expression to map your values:
select u.UserID, u.Name, Sum(pm) PaidMonths
from users u join payments p on p.userid=u.userid
cross apply (values(
case
when valuepaid <10 then 0.23
when Refunded=1 then 0
else PaidMonths end
))x(pm)
group by u.UserID, u.Name
See Working Fiddle

Get Field Hierachy

I have the following tables and I want to get the quantity of users by country:
+--------+------+:
| user | zone |
+--------+------+
| Paul | 7 |
+--------+------+
| John | 5 |
+--------+------+
| Peter | 6 |
+--------+------+
| Frank | 5 |
+--------+------+
| Silvia | 2 |
+--------+------+
| Carl | 4 |
+--------+------+
| Mark | 3 |
+--------+------+
Regions
+---------+-----------------+----------+--+
| zone_id | zone_name | idUpzone | |
+---------+-----------------+----------+--+
| 1 | Global | null | |
+---------+-----------------+----------+--+
| 2 | US | 1 | |
+---------+-----------------+----------+--+
| 3 | Florida | 2 | |
+---------+-----------------+----------+--+
| 4 | Orlando | 3 | |
+---------+-----------------+----------+--+
| 5 | China | 1 | |
+---------+-----------------+----------+--+
| 6 | Orlando Sector | 4 | |
+---------+-----------------+----------+--+
| 7 | Beijing | 5 | |
+---------+-----------------+----------+--+
so I get something like this
+---------+-----+
| Country | QTY |
+---------+-----+
| US | 4 |
+---------+-----+
| China | 3 |
+---------+-----+

Use a recursive CTE to get the highest level and then join:
with cte as (
select zone_id, zone_id as top_zone_id, zone_name as top_zone_name, 1 as lev
from regions
where parent_zone_id = 1
union all
select r.zone_id, cte.top_zone_id, top_zone_name, lev + 1
from cte join
regions r
on r.idUpzone = cte.zone_id
)
select cte.top_zone_name, count(*)
from users u join
cte
on u.zone = cte.zone_id
group by cte.top_zone_name;

Try this out:
SELECT
r.zone_name AS Contry, COUNT(*) QTY
FROM (
SELECT * FROM users u
INNER JOIN regions r ON u.zone = r.zone_id
) a
GROUP BY r.zone_name

How to remove duplicate values from oracle join?

I want to create a view that present only the results and not present the duplicates, I have 3 tables in oracle database:
The first table contain general information about a person
+-----------+-------+-------------+
| ID | Name | Birtday_date|
+-----------+-------+-------------+
| 1 | Byron | 12/10/1998 |
| 2 | Peter | 01/11/1973 |
| 4 | Jose | 05/02/2008 |
+-----------+-------+-------------+
The second table contain information about a telephone of the people in the first table.
+-------+----------+----------+----------+
| ID |ID_Person |CELL_TYPE | NUMBER |
+-------+- --------+----------+----------+
| 1221 | 1 | 3 | 099141021|
| 2221 | 1 | 2 | 099091925|
| 3222 | 1 | 1 | 098041013|
| 4321 | 2 | 1 | 088043153|
| 4561 | 2 | 2 | 090044313|
| 5678 | 4 | 1 | 092049013|
| 8990 | 4 | 2 | 098090233|
+----- -+----------+----------+----------+
The Third table contain information about a email of the people in the first table.
+------+----------+----------+---------------+
| ID |ID_Person |MAIL_TYPE | Email |
+------+- --------+----------+---------------+
| 221 | 1 | 1 |jdoe#aol.com |
| 222 | 1 | 2 |jdoe1#aol.com |
| 421 | 2 | 1 |xx12#yahoo.com |
| 451 | 2 | 2 |dsdsa#gmail.com|
| 578 | 4 | 1 |sasaw1#sdas.com|
| 899 | 4 | 2 |cvcvsd#wew.es |
+------+----------+----------+---------------+
if i do a inner join with this tables the result will do something like that
+-----+-------+-------------+----------+----------+----------+----------------+
| ID | Name | Birtday_date| CELL_TYPE| NUMBER |MAIL_TYPE|Email |
+-----+-------+-------------+----------+----------+----------+----------------+
| 1 | Byron | 12/10/1998 | 3 | 099141021|1 |jdoe#aol.com |
| 1 | Byron | 12/10/1998 | 3 | 099141021|2 |jdoe1#aol.com |
| 1 | Byron | 12/10/1998 | 2 | 099091925|1 |jdoe#aol.com |
| 1 | Byron | 12/10/1998 | 2 | 099091925|2 |jdoe1#aol.com |
| 1 | Byron | 12/10/1998 | 1 | 098041013|1 |jdoe#aol.com |
| 1 | Byron | 12/10/1998 | 1 | 098041013|2 |jdoe1#aol.com |
| 2 | Peter | 01/11/1973 | 1 | 088043153|1 |xx12#yahoo.com |
| 2 | Peter | 01/11/1973 | 1 | 088043153|2 |dsdsa#gmail.com |
| 2 | Peter | 01/11/1973 | 2 | 090044313|1 |xx12#yahoo.com |
| 2 | Peter | 01/11/1973 | 2 | 090044313|2 |dsdsa#gmail.com |
| 4 | Jose | 05/02/2008 | 1 | 088043153|1 |sasaw1#sdas.com |
| 4 | Jose | 05/02/2008 | 1 | 088043153|2 |cvcvsd#wew.es |
| 4 | Jose | 05/02/2008 | 2 | 088043153|1 |sasaw1#sdas.com |
| 4 | Jose | 05/02/2008 | 2 | 088043153|2 |cvcvsd#wew.es |
+-----+-------+-------------+----------+----------+----------+----------------+
So the result that i will to present in a view is the next
+-----+-------+-------------+----------+----------+----------+----------------+
| ID | Name | Birtday_date| CELL_TYPE| NUMBER |MAIL_TYPE|Email |
+-----+-------+-------------+----------+----------+----------+----------------+
| 1 | Byron | 12/10/1998 | 3 | 099141021|1 |jdoe#aol.com |
| 1 | Byron | 12/10/1998 | | |2 |jdoe1#aol.com |
| 1 | Byron | 12/10/1998 | 2 | 099091925| | |
| 1 | Byron | 12/10/1998 | 1 | 098041013| | |
| 2 | Peter | 01/11/1973 | 1 | 088043153|1 |xx12#yahoo.com |
| 2 | Peter | 01/11/1973 | | |2 |dsdsa#gmail.com |
| 2 | Peter | 01/11/1973 | 2 | 090044313| | |
| 4 | Jose | 05/02/2008 | 1 | 092049013|1 |sasaw1#sdas.com |
| 4 | Jose | 05/02/2008 | | |2 |cvcvsd#wew.es |
| 4 | Jose | 05/02/2008 | 2 | 098090233| | |
+-----+-------+-------------+----------+----------+----------+----------------+
I tried to achieve a similar output using
case
when row_number() over (partition by table1.id order by table2.type) = 1
then table1.value
end
as "VALUE"
But the result is nothing that I expect and some rows they repeats

What you need to do is enumerate the rows and then join on those enumerations. This is tricky, because you don't know how many are in each list. Well, there is another method using conditional aggregation:
select p.id, p.name, p.birthday,
max(cell_type) as cell_type, max(number) as number,
max(mail_type) as mail_type, max(email) as email
from person p left join
((select id_person, cell_type, number,
null as mail_type, null as email,
row_number() over (partition by id_person order by number) as seqnum
from phones
) union all
(select id_person, null as cell_type, null as number,
mail_type, email,
row_number() over (partition by id_person order by email) as seqnum
from emails
)
) pe
on pe.id_person = p.id_person
group by p.id, p.name, p.birthday, pe.seqnum

Hope this helps.
Create table person(ID int ,Name varchar(20), Birtday_date date)
Insert into person values
(1,'Byron' ,'12/10/1998'),
(2,'Peter' ,'01/11/1973'),
(4,'Jose ' ,'05/02/2008')
Create table phones (ID int,ID_Person int,CELL_TYPE int,NUMBER float)
Insert into phones values
(1221, 1 , 3,099141021),
(2221, 1 , 2,099091925),
(3222, 1 , 1,098041013),
(4321, 2 , 1,088043153),
(4561, 2 , 2,090044313),
(5678, 4 , 1,092049013),
(8990, 4 , 2,098090233)
Create table emails(ID int,ID_Person int, MAIL_TYPE int, Email varchar(100))
Insert into emails values
(221, 1 , 1, 'jdoe#aol.com '),
(222, 1 , 2, 'jdoe1#aol.com '),
(421, 2 , 1, 'xx12#yahoo.com '),
(451, 2 , 2, 'dsdsa#gmail.com'),
(578, 4 , 1, 'sasaw1#sdas.com'),
(899, 4 , 2, 'cvcvsd#wew.es ')
select p.id, p.name, p.Birtday_date,
case when Lag(number) over(partition by p.id order by p.id,pe.id) = number then null else cell_type end as cell_type,
case when Lag(number) over(partition by p.id order by p.id,pe.id) = number then null else number end as number,
mail_type as mail_type, email as email
from person p left join
(select pp.ID_Person, cell_type, number, mail_type, email,pp.id from
(select ID_Person, cell_type, number,id,
row_number() over (partition by ID_Person order by id ) as seqnum
from phones
) pp left join
(select ID_Person,
mail_type, email, 1 as seqnum
from emails
)e on pp.ID_Person = e.ID_Person and pp.seqnum = e.seqnum
) pe
on pe.ID_Person = p.Id
order by p.id, pe.id

How to (recursively) update a table based on available hierarchy?

Given these 3 column values, how can i update a table with the top level head for each employee?
| EmpID | EmpName | SupervisorID | DeptHeadID |
|:-----:|:-------:|:------------:|:----------:|
| 3 | Adam | null | |
| 1 | Sam | 5 | |
| 6 | Mike | 2 | |
| 5 | Jack | 3 | |
| 2 | Steph | 5 | |
| 8 | Rob | 2 | |
The result should be like this
| EmpID | EmpName | SupervisorID | DeptHeadID |
|:-----:|:-------:|:------------:|:----------:|
| 3 | Adam | null | null |
| 1 | Sam | 5 | 3 |
| 6 | Mike | 2 | 3 |
| 5 | Jack | 3 | 3 |
| 2 | Steph | 3 | 3 |
| 8 | Rob | 2 | 3 |

Example
;with cteP as (
Select EmpID,SupervisorID,TopLvl=EmpID
From YourTable
Where SupervisorID is null
Union All
Select r.EmpID,r.SupervisorID,TopLvl=p.TopLvl
From YourTable r
Join cteP p on r.SupervisorID = p.EmpID)
Update YourTable
set DeptHeadID = nullIf(TopLvl,A.EmpID)
From YourTable A
Join cteP B on A.EmpID=B.EmpID
-- Show Updated Table
Select * From YourTable
Updated Table
EmpID EmpName SupervisorID DeptHeadID
3 Adam NULL NULL
1 Sam 5 3
6 Mike 2 3
5 Jack 3 3
2 Steph 5 3
8 Rob 2 3

SQL Query in MANY- MANY RELATIONSHIP exactly one record with matching criteria

I have 3 like with many - many relationship
As:
TABLE 1 : select * from student;
| id | name |
| 1 | sone |
| 2 | stwo |
| 3 | sthree |
| 4 | sfour |
| 6 | ssix |
TABLE 2 : select * from course;
| id | name |
| 100 | CSE |
| 101 | ECE |
| 102 | ITI |
RELATION_SHIP TABLE : select * from student_course
| id | stu_id | cou_id |
| 1 | 1 | 101 |
| 2 | 2 | 102 |
| 3 | 2 | 100 |
| 4 | 3 | 100 |
| 5 | 3 | 101 |
| 6 | 1 | 101 |
| 1 | 6 | 101 |
I need to write a query to select a student with exactly one course 'CSE' and he should not have any other courses.
Thanks in advance

Use query:
SELECT
sc.`stu_id`,
COUNT(sc.`cou_id`) AS cnt
FROM
student_course sc
GROUP BY sc.`stu_id`
HAVING cnt = 1
AND GROUP_CONCAT(cou_id) LIKE
(SELECT
id
FROM
course
WHERE NAME = 'CSE')