I need the sum of all positions from one year for every customer.
In the subquery i've hardcoded the customernumber (mark 1) but it needs to be another customernumber for every row.
The values in mark 2 are wrong.
SELECT CustomerNumber AS Kundennummer,
cont.CompanyName AS Firmenname,
(SELECT SUM(SumPositions) FROM OP_Invoices JOIN BAS_Customers ON OP_Invoices.Contact = BAS_Customers.Contact WHERE YEAR(DocumentDate) = 2018 AND BAS_Customers.CustomerNumber = '28673') AS '2018'
FROM BAS_Customers AS cust
JOIN BAS_Contacts AS cont
ON cust.Contact = cont.GUID
Thanks for your help!
If BAS_Customers and BAS_Contacts have a one-to-one relationship, then you should be able to use something like this:
SELECT BAS_Customers.CustomerNumber AS Kundennummer,
cont.CompanyName AS Firmenname,
SUM(SumPositions)
FROM OP_Invoices
JOIN BAS_Customers
ON OP_Invoices.Contact = BAS_Customers.Contact
JOIN BAS_Contacts AS cont
ON cust.Contact = cont.GUID
WHERE YEAR(DocumentDate) = 2018
GROUP BY BAS_Customers.CustomerNumber,
cont.CompanyName
Answering your follow up question in the comments:
SELECT BAS_Customers.CustomerNumber AS Kundennummer,
cont.CompanyName AS Firmenname,
SUM(case when YEAR(DocumentDate) = 2018 then SumPositions else 0 end) AS sum_2018,
SUM(case when YEAR(DocumentDate) = 2019 then SumPositions else 0 end) AS sum_2019
FROM OP_Invoices
JOIN BAS_Customers
ON OP_Invoices.Contact = BAS_Customers.Contact
JOIN BAS_Contacts AS cont
ON cust.Contact = cont.GUID
GROUP BY BAS_Customers.CustomerNumber,
cont.CompanyName
Related
Hi I try to need to sum values and if there is more than 20 there shouldbe written 20 else should be number.
I don't know what i make wrong:
SELECT
ta6.product_product_id AS ID,
ta6.product_manufacture_code AS Code,
SUM(CASE WHEN ta3.stock_quantity >= 20 THEN 20 ELSE ta3.stock_quantity END) AS Quantity,
ta4.price_value AS Price,
ta5.Attribute_Value AS Sizer,
ta6.Procut_product_name AS Name,
ta7.Attribute_Value AS produce
FROM
product ta6
LEFT JOIN stock ta3 ON
ta3.stock_id = ta6.product_id
LEFT JOIN price ta4 ON
ta4.price_id = ta6.product_id
AND ta4.price_type = 2
LEFT JOIN Attributes ta5 ON
ta5.Attributes_product_Id = ta6.product_id
LEFT JOIN Attributes ta7 ON
ta7.Attributes_product_Id = ta6.product_id
WHERE
( ta3.stock_wharehouse_id = 1
AND ta5.Attrib_id = 54
AND ta7.Attrib_id = 25 )
GROUP BY
ta6.product_manufacture_code,
ta6.product_product_id
ta4.price_value,
ta5.Attribute_Value,
ta6.product_product_name ,
ta7.Attribute_Value;
Table stock_quantity looks like:
Stock_table image
How to sum it ??
Like this?
CASE WHEN SUM(ta3.stock_quantity) >= 20
THEN 20
ELSE SUM(ta3.stock_quantity)
END AS Quantity
I've been trying hopelessly to get the following SQL statement to return the query results and default to 0 if there are no rows matching the query.
This is the intended result:
vol | year
-------+------
0 | 2018
Instead I get:
vol | year
-----+------
(0 rows)
Here is the sql statement:
select coalesce(vol,0) as vol, year
from (select sum(vol) as vol, year
from schema.fact_data
join schema.period_data
on schema.fact_data.period_tag = schema.period_data.tag
join schema.product_data
on schema.fact_data.product_tag =
schema.product_data.tag
join schema.market_data
on schema.fact_data.market_tag = schema.market_data.tag
where "retailer"='MadeUpRetailer'
and "product_tag"='FakeProductTag'
and "year"='2018' group by year
) as DerivedTable;
I know the query works because it returns data when there is data. Just doesn't default to 0 as intended...
Any help in finding why this is the case would be much appreciated!
Using your subquery DerivedTable, you could write:
SELECT coalesce(DerivedTable.vol, 0) AS vol,
y.year
FROM (VALUES ('2018'::text)) AS y(year)
LEFT JOIN (SELECT ...) AS DerivedTable
ON DerivedTable.year = y.year;
Remove the GROUP BY (and the outer query):
select 2018 as year, coalesce(sum(vol), 0) as vol
from schema.fact_data f join
schema.period_data p
on f.period_tag = p.tag join
schema.product_data pr
on f.product_tag = pr.tag join
schema.market_data m
on fd.market_tag = m.tag
where "retailer" = 'MadeUpRetailer' and
"product_tag" = 'FakeProductTag' and
"year" = '2018';
An aggregation query with no GROUP BY always returns exactly one row, so this should do what you want.
EDIT:
The query would look something like this:
select v.yyyy as year, coalesce(sum(vol), 0) as vol
from (values (2018), (2019)) v(yyyy) left join
schema.fact_data f
on f.year = v.yyyy left join -- this is just an example. I have no idea where year is coming from
schema.period_data p
on f.period_tag = p.tag left join
schema.product_data pr
on f.product_tag = pr.tag left join
schema.market_data m
on fd.market_tag = m.tag
group by v.yyyy
However, you have to move the where conditions to the appropriate on clauses. I have no idea where the columns are coming from.
From the code you posted it is not clear in which table you have the year column.
You can use UNION to fetch just 1 row in case there are no rows in that table for the year 2018 like this:
select sum(vol) as vol, year
from schema.fact_data innrt join schema.period_data
on schema.fact_data.period_tag = schema.period_data.tag
inner join schema.product_data
on schema.fact_data.product_tag = schema.product_data.tag
inner join schema.market_data
on schema.fact_data.market_tag = schema.market_data.tag
where
"retailer"='MadeUpRetailer' and
"product_tag"='FakeProductTag' and
"year"='2018'
group by "year"
union
select 0 as vol, '2018' as year
where not exists (
select 1 from tablename where "year" = '2018'
)
In case there are rows for the year 2018, then nothing will be fetched by the 2nd query,
OK, I've looked this up and tried a number of solutions, but can't get it to work. I'm a bit of a novice. Here's my original query - how can I get it to return 0 for an account when there are no results in the student table?
SELECT a.NAME
,count(s.student_sid)
FROM account a
JOIN inst i ON a.inst_sid = i.root_inst_sid
JOIN inst_year iy ON i.inst_sid = iy.inst_sid
JOIN student s ON iy.inst_year_sid = s.inst_year_sid
WHERE s.demo = 0
AND s.STATE = 1
AND i.STATE = 1
AND iy.year_sid = 16
AND a.account_sid IN (
20187987
,20188576
,20188755
,52317128
,20189249
)
GROUP BY a.NAME;
Use an outer join, moving the condition on that table into the join:
select a.name, count(s.student_sid)
from account a
join inst i on a.inst_sid = i.root_inst_sid
join inst_year iy on i.inst_sid = iy.inst_sid
left join student s on iy.inst_year_sid = s.inst_year_sid
and s.demo = 0
and s.state = 1
where i.state = 1
and iy.year_sid = 16
and a.account_sid in (20187987, 20188576, 20188755, 52317128, 20189249)
group by a.name;
count() does not count null values, which s.student_sid will be if no rows join from student.
You need to LEFT JOIN and then SUM() over the group where s.student_sid is not null:
select
a.name,
sum(case when s.student_sid is null then 0 else 1 end) as student_count
from account a
join inst i on a.inst_sid = i.root_inst_sid
join inst_year iy on i.inst_sid = iy.inst_sid
left join student s
on iy.inst_year_sid = s.inst_year_sid
and s.demo = 0
and s.state = 1
where i.state = 1
and iy.year_sid = 16
and a.account_sid in (20187987, 20188576, 20188755, 52317128, 20189249)
group by a.name;
This is assuming that all of the fields in the student table that you are filtering on are optional. If you don't want to enforce removal of records where, say, s.state does not equal 1, then you need to move the s.state=1 predicate into the WHERE clauses.
If, for some reason, you are getting duplicate student IDs and students are being counted twice, then you can change the aggregate function to this:
count(distinct s.student_id) as student_count
...which is safe to do as count(distinct ...) ignores null values.
I have a sql statement with many inner join tables, as you can see below I have many conditional SUM statements , these sums are giving me wrong (very large) numbers as the inner join is repeating the same values in my source select pool. I was wondering id there is a way to limit these sum conditions lets say to EMPLIDs. The code is :
SELECT
A.EMPL_CTG,
B.DESCR AS PrName,
SUM(A.CURRENT_COMPRATE) AS SALARY_COST_BUDGET,
SUM(A.BUDGET_AMT) AS BUDGET_AMT,
SUM(A.BUDGET_AMT)*100/SUM(A.CURRENT_COMPRATE) AS MERIT_GOAL,
SUM(C.FACTOR_XSALARY) AS X_Programp,
SUM(A.FACTOR_XSALARY) AS X_Program,
COUNT(A.EMPLID) AS EMPL_CNT,
COUNT(D.EMPLID),
SUM(CASE WHEN A.PROMOTION_SECTION = 'Y' THEN 1 ELSE 0 END) AS PRMCNT,
SUM(CASE WHEN A.EXCEPT_IND = 'Y' THEN 1 ELSE 0 END) AS EXPCNT,
(SUM(CASE WHEN A.PROMOTION_SECTION = 'Y' THEN 1 ELSE 0 END)+SUM(CASE WHEN A.EXCEPT_IND = 'Y' THEN 1 ELSE 0 END))*100/(COUNT(A.EMPLID)) AS PEpercent
FROM
EMP_DTL A INNER JOIN EMPL_CTG_L1 B ON A.EMPL_CTG = B.EMPL_CTG
INNER JOIN
ECM_PRYR_VW C ON A.EMPLID=C.EMPLID
INNER JOIN ECM_INELIG D on D.EMPL_CTG=A.EMPL_CTG and D.YEAR=YEAR(getdate())
WHERE
A.YEAR=YEAR(getdate())
AND B.EFF_STATUS='A'
GROUP BY
A.EMPL_CTG,
B.DESCR
ORDER BY B.DESCR
I already tried moving D.YEAR=YEAR(getdate()) to the where clause. Any help would be greatly appereciated
The probable reason of your very large numbers is probably due to the result of Cartesian product of joining A -> B, A -> C and A -> D where tables C and D appear to have multiple records. So, just example... if A has 10 records, and C has 10 for each of the A records, you now have 10 * 10 records... Finally, join that to D table with 10 records, you now have 10 * 10 * 10 for each "A", thus your bloated answers.
Now, how to resolve. I have taken your "C" and "D" tables and "Pre-Aggregated" those counts based on the join column basis. This way, they will each have only 1 record with the total already computed at that level, joined back to A table and you lose your Cartesian issue.
Now, for table B, it appears that is a lookup table only and would only be a single record result anyhow.
SELECT
A.EMPL_CTG,
B.DESCR AS PrName,
SUM(A.CURRENT_COMPRATE) AS SALARY_COST_BUDGET,
SUM(A.BUDGET_AMT) AS BUDGET_AMT,
SUM(A.BUDGET_AMT)*100/SUM(A.CURRENT_COMPRATE) AS MERIT_GOAL,
PreAggC.X_Programp,
SUM(A.FACTOR_XSALARY) AS X_Program,
COUNT(A.EMPLID) AS EMPL_CNT,
PreAggD.DCount,
SUM(CASE WHEN A.PROMOTION_SECTION = 'Y' THEN 1 ELSE 0 END) AS PRMCNT,
SUM(CASE WHEN A.EXCEPT_IND = 'Y' THEN 1 ELSE 0 END) AS EXPCNT,
( SUM( CASE WHEN A.PROMOTION_SECTION = 'Y' THEN 1 ELSE 0 END
+ CASE WHEN A.EXCEPT_IND = 'Y' THEN 1 ELSE 0 END ) *
100 / COUNT(A.EMPLID) AS PEpercent
FROM
EMP_DTL A
INNER JOIN EMPL_CTG_L1 B
ON A.EMPL_CTG = B.EMPL_CTG
AND B.EFF_STATUS='A'
INNER JOIN ( select
C.EMPLID,
SUM(C.FACTOR_XSALARY) AS X_Programp
from
ECM_PRYR_VW C
group by
C.EMPLID ) PreAggC
ON A.EMPLID = PreAggC.EMPLID
INNER JOIN ( select
D.EMPLID,
COUNT(*) AS DCount
from
ECM_INELIG D
where
D.Year = YEAR( getdate())
group by
D.EMPLID ) PreAggD
ON A.EMPLID = PreAggD.EMPLID
WHERE
A.YEAR=YEAR(getdate())
GROUP BY
A.EMPL_CTG,
B.DESCR
ORDER BY
B.DESCR
I'm using PostgreSQL 8.4.
I have the following sql-query:
SELECT p.partner_id,
CASE WHEN pa.currency_id = 1 THEN SUM(amount) ELSE 0 END AS curUsdAmount,
CASE WHEN pa.currency_id = 2 THEN SUM(amount) ELSE 0 END AS curRubAmount,
CASE WHEN pa.currency_id = 3 THEN SUM(amount) ELSE 0 END AS curUahAmount
FROM public.player_account AS pa
JOIN player AS p ON p.id = pa.player_id
WHERE p.partner_id IN (819)
GROUP BY p.partner_id, pa.currency_id
The thing is that query does not what I expected. I realize that, but now I want to understand what exactly that query does. I mean, what SUM will be counted after the query executed. Could you clarify?
I think you have the conditions backwards in the query:
SELECT p.partner_id,
SUM(CASE WHEN pa.currency_id = 1 THEN amount ELSE 0 END) AS curUsdAmount,
SUM(CASE WHEN pa.currency_id = 2 THEN amount ELSE 0 END) AS curRubAmount,
SUM(CASE WHEN pa.currency_id = 3 THEN amount ELSE 0 END) AS curUahAmount
FROM public.player_account pa JOIN
player p
ON p.id = pa.player_id
WHERE p.partner_id IN (819)
GROUP BY p.partner_id;
Note that I also removed currency_id from the group by clause.
Maybe one row per (partner_id, currency_id) does the job. Faster and cleaner that way:
SELECT p.partner_id, pa.currency_id, sum(amount) AS sum_amount
FROM player_account pa
JOIN player p ON p.id = pa.player_id
WHERE p.partner_id = 819
AND pa.currency_id IN (1,2,3) -- may be redundant if there are not other
GROUP BY 1, 2;
If you need 1 row per partner_id, you are actually looking for "cross-tabulation" or a "pivot table". In Postgres use crosstab() from the additional module tablefunc , which is very fast. (Also available for the outdated version 8.4):
SELECT * FROM crosstab(
'SELECT p.partner_id, pa.currency_id, sum(amount)
FROM player_account pa
JOIN player p ON p.id = pa.player_id
WHERE p.partner_id = 819
AND pa.currency_id IN (1,2,3)
GROUP BY 1, 2
ORDER BY 1, 2'
,VALUES (1), (2), (3)'
) AS t (partner_id int, "curUsdAmount" numeric
, "curRubAmount" numeric
, "curUahAmount" numeric); -- guessing data types
Adapt to your actual data types.
Detailed explanation:
PostgreSQL Crosstab Query