I have one dataframe called df and I need to drop one column amount from df and assign it to a new data frame called df1 but I get an error below. How can I fix this? Please note that below is a small example. In my real dataset I do have 28 columns and I can't type their names to create a new one
Thank you.
df= [['A',100,10000]
,['A',120,15000]
,['A',300,50000]
,['B',100,180000]
,['B',80,200000]]
df = pd.DataFrame(df, columns = ['group','size','amount'])
df1=df.drop('amount',axis=1,inplace=True)
df1.head()
"AttributeError: 'NoneType' object has no attribute 'head'"
inplace operations return None, so need omit assign back:
df.drop('amount',axis=1,inplace=True)
df.head()
Or remove inpalce=True and assign back:
df = df.drop('amount',axis=1)
df.head()
Related
I am extracting tables from pdf using Camelot. Two of the columns are getting merged together with a newline separator. Is there a way to separate them into two columns?
Suppose the column looks like this.
A\nB
1\n2
2\n3
3\n4
Desired output:
|A|B|
|-|-|
|1|2|
|2|3|
|3|4|
I have tried df['A\nB'].str.split('\n', 2, expand=True) and that splits it into two columns however I want the new column names to be A and B and not 0 and 1. Also I need to pass a generalized column label instead of actual column name since I need to implement this for several docs which may have different column names. I can determine such column name in my dataframe using
colNew = df.columns[df.columns.str.contains(pat = '\n')]
However when I pass colNew in split function, it throws an attribute error
df[colNew].str.split('\n', 2, expand=True)
AttributeError: DataFrame object has no attribute 'str'
You can take advantage of the Pandas split function.
import pandas as pd
# recreate your pandas series above.
df = pd.DataFrame({'A\nB':['1\n2','2\n3','3\n4']})
# first: Turn the col into str.
# second. split the col based on seperator \n
# third: make sure expand as True since you want the after split col become two new col
test = df['A\nB'].astype('str').str.split('\n',expand=True)
# some rename
test.columns = ['A','B']
I hope this is helpful.
I reproduced the error from my side... I guess the issue is that "df[colNew]" is still a dataframe as it contains the indexes.
But .str.split() only works on Series. So taking as example your code, I would convert the dataframe to series using iloc[:,0].
Then another line to split the column headers:
df2=df[colNew].iloc[:,0].str.split('\n', 2, expand=True)
df2.columns = 'A\nB'.split('\n')
I am trying to apply value_counts method to a Dataframe based on the columns selected dynamically in the Streamlit app
This is what I am trying to do:
if st.checkbox("Select Columns To Show"):
all_columns = df.columns.tolist()
selected_columns = st.multiselect("Select", all_columns)
new_df = df[selected_columns]
st.dataframe(new_df)
The above lets me select columns and displays data for the selected columns. I am trying to see how could I apply value_counts/groupby method on this output in Streamlit app
If I try to do the below
st.table(new_df.value_counts())
I get the below error
AttributeError: 'DataFrame' object has no attribute 'value_counts'
I believe the issue lies in passing a list of columns to a dataframe. When you pass a single column in [] to a dataframe, you get back a pandas.Series object (which has the value_counts method). But when you pass a list of columns, you get back a pandas.DataFrame (which doesn't have value_counts method defined on it).
Can you try st.table(new_df[col_name].value_counts())
I think the error is because value_counts() is applicable on a Series and not dataframe.
You can try Converting ".value_counts" output to dataframe
If you want to apply on one single column
def value_counts_df(df, col):
"""
Returns pd.value_counts() as a DataFrame
Parameters
----------
df : Pandas Dataframe
Dataframe on which to run value_counts(), must have column `col`.
col : str
Name of column in `df` for which to generate counts
Returns
-------
Pandas Dataframe
Returned dataframe will have a single column named "count" which contains the count_values()
for each unique value of df[col]. The index name of this dataframe is `col`.
Example
-------
>>> value_counts_df(pd.DataFrame({'a':[1, 1, 2, 2, 2]}), 'a')
count
a
2 3
1 2
"""
df = pd.DataFrame(df[col].value_counts())
df.index.name = col
df.columns = ['count']
return df
val_count_single = value_counts_df(new_df, selected_col)
If you want to apply for all object columns in the dataframe
def valueCountDF(df, object_cols):
c = df[object_cols].apply(lambda x: x.value_counts(dropna=False)).T.stack().astype(int)
p = (df[object_cols].apply(lambda x: x.value_counts(normalize=True,
dropna=False)).T.stack() * 100).round(2)
cp = pd.concat([c,p], axis=1, keys=["Count", "Percentage %"])
return cp
val_count_df_cols = valueCountDF(df, selected_columns)
And Finally, you can use st.table or st.dataframe to show the dataframe in your streamlit app
So I learned from this answer to this question that in pandas 0.20.3 and above reassigning the values of a dataframe works without giving the SettingWithCopyWarning in many ways as follows:
df = pd.DataFrame(np.ones((5,6)),columns=['one','two','three',
'four','five','six'])
df.one *=5
df.two = df.two*5
df.three = df.three.multiply(5)
df['four'] = df['four']*5
df.loc[:, 'five'] *=5
df.iloc[:, 5] = df.iloc[:, 5]*5
HOWEVER
If I were to take a part of that dataframe like this for example:
df1 = df[(df.index>1)&(df.index<5)]
And then try one of the above methods for reassigning a column like so:
df.one *=5
THEN I will get the SettingWithCopyWarning.
So is this a bug or am I just missing something about the way pandas expects for this kind of operation to work?
I have a Dataframe (called df) that has list of tickets worked for a given date. I have a script that runs each day where this df gets generated and I would like to have a new master dataframe (lets say df_master) that appends values form df to a new Dataframe. So anytime I view df_master I should be able to see all the tickets worked across multiple days. Also would like to have a new column in df_master that shows date when the row was inserted.
Given below is how df looks like:
1001
1002
1003
1004
I tried to perform concat but it threw an error
TypeError: first argument must be an iterable of pandas objects, you passed an object of type "Series"
Update
df_ticket = tickets['ticket']
df_master = df_ticket
df_master['Date'] = pd.Timestamp('now').normalize()
L = [df_master,tickets]
master_df = pd.concat(L)
master_df.to_csv('file.csv', mode='a', header=False, index=False)
I think you need pass sequence to concat, obviously list is used:
objs : a sequence or mapping of Series, DataFrame, or Panel objects
If a dict is passed, the sorted keys will be used as the keys argument, unless it is passed, in which case the values will be selected (see below). Any None objects will be dropped silently unless they are all None in which case a ValueError will be raised
L = [s1,s2]
df = pd.concat(L)
And it seems you pass only Series, so raised error:
df = pd.concat(s)
For insert Date column is possible set pd.Timestamp('now').normalize(), for master df I suggest create one file and append each day DataFrame:
df_ticket = tickets[['ticket']]
df_ticket['Date'] = pd.Timestamp('now').normalize()
df_ticket.to_csv('file.csv', mode='a', header=False, index=False)
df_master = pd.read_csv('file.csv', header=None)
I want to add a Series (s) to a Pandas DataFrame (df) as a new column. The series has more values than there are rows in the dataframe, so I am using the concat method along axis 1.
df = pd.concat((df, s), axis=1)
This works, but the new column of the dataframe representing the series is given an arbitrary numerical column name, and I would like this column to have a specific name instead.
Is there a way to add a series to a dataframe, when the series is longer than the rows of the dataframe, and with a specified column name in the resulting dataframe?
You can try Series.rename:
df = pd.concat((df, s.rename('col')), axis=1)
One option is simply to specify the name when creating the series:
example_scores = pd.Series([1,2,3,4], index=['t1', 't2', 't3', 't4'], name='example_scores')
Using the name attribute when creating the series is all I needed.
Try:
df = pd.concat((df, s.rename('CoolColumnName')), axis=1)