Join tables with same keys, second table has multiple values for key and rows of second table must have same column value - sql

I have two tables with shared key and I'm trying to join them to filter data based on few conditions
tbl1
id | OutPutValue |
1 | 2019 |
2 | 2018 |
tbl2
object_id | status | type |
1 | 22 | a |
1 | 22 | c |
1 | 33 | b |
2 | 33 | c |
2 | 33 | c |
2 | 33 | c |
What I'm trying to get is : it must select all 'OutPutValue' from tbl1 where, in tbl2 column 'type' should be c, and column 'status' must have same value for all rows i.e. 33. Note that Primary key (id) of tbl1 is foreign key (object_id) in tbl2.
Select column from tbl1 if, All rows in tbl2 (id of tbl1 have multiple rows (based on object_id) in tbl2) have same status value i.e. 33 and Type should be 'c'.
OutPutValue | Type | status |
2018 | c | 33 |
I have tried with following solution, but it's not returning desired output :
SELECT a.OutPutValue FROM tbl1 a JOIN tbl2 b ON a.id = b.object_id WHERE b.Type =c
GROUP BY a.OutPutValue, b.status HAVING b.STATUS IN(33)

You can try using correlated subquery
DEMO
select distinct OutPutValue,type, status
from t2 a inner join t1 b on a.object_id=b.id
where type='c' and not exists
(select 1 from t2 a1 where a.object_id=a1.object_id and status<>33 and type='c')
OUTPUT:
OutPutValue type status
2018 c 33

Another solution could be the following :
SELECT T1.id, T1.outputvalue FROM tbl1 T1
JOIN (
SELECT tbl2.*, MAX(type), MAX(status)
FROM tbl2
GROUP BY object_id
HAVING
MIN(status) = MAX(status) AND
MIN(type) = MAX(type)
) T2 ON T1.id = T2.object_id
WHERE T2.type = 'c'
EDIT: I have updated my query to match a particular case which make it quite similar to another answer.
FIND A DEMO HERE

Try a join combined with an aggregation:
SELECT
t1.OutPutValue,
MAX(t2.type) AS type,
MAX(t2.status) AS status
FROM tbl1 t1
INNER JOIN tbl2 t2
ON t1.id = t2.object_id
GROUP BY
t1.id,
t1.OutPutValue
HAVING
MIN(t2.status) = MAX(t2.status) AND
MAX(t2.status) = 33 AND
MIN(t2.type) = MAX(t2.type) AND
MAX(t2.type) = 'c';

Related

How to populate a table based on a value from a different table

I have two tables of data which I can join using a left join linked on the ID in both tables. Where the course and the person are the same, I need to populate the RegNumber as the same as the RegNumber which is already there for 1 row:
How it is currently: if I join table 1 and table 2 with a left join.
Table 1
ID | Course| Person
67705 | A | 1
68521 | A | 1
85742 | A | 1
89625 | A | 1
67857 | B | 2
86694 | B | 2
88075 | B | 2
88710 | C | 3
47924 | C | 3
66981 | C | 3
12311 | B | 1
12312 | B | 1
12313 | B | 1
Table 2
ID | RegNumber
67705 | N712316
NULL | NULL
NULL | NULL
NULL | NULL
67857 | N712338
NULL | NULL
NULL | NULL
NULL | NULL
47924 | M481035
NULL | NULL
12311 | N645525
NULL | NULL
NULL | NULL
I need table 2 to look like this:
ID | RegNumber
67705 | N712316
68521 | N712316
85742 | N712316
89625 | N712316
67857 | N712338
86694 | N712338
88075 | N712338
88710 | N712338
47924 | M481035
66981 | M481035
12311 | N645525
12312 | N645525
12313 | N645525
That is, I need to insert new rows into Table 2
Can anyone help me please? This is Totally beyond my capability!
insert into table2 (ID,RegNumber)
select t1.ID,reg.regNumber
from table1 t1
cross join (select top 1 regNumber from table2 r2 join table1 r1
on r1.Id = r2.Id
and r1.Course = t1.Course
and r1.Person = t1.person
order by id) reg
where not exists (select 1 from table2 t2 where t1.ID = t2.ID)
you can improve performance a little bit by loading data into temp table first :
select t1.ID , Course,Person,regNumber
into #LoadedData
from table1 t1
join table2 t2 on t1.Id = t2.ID
insert into table2 (ID,RegNumber)
select t1.ID,reg.regNumber
from table1 t1
cross join (select top 1 regNumber from #LoadedData l
where l.Course = t1.Course
and l.Person = t1.person
order by id) reg
where not exists (select 1 from #LoadedData l where t1.ID = l.ID)
in either case having an index on (ID, Course, Person) will help with performance
Assuming:
You are missing items in table 2 that inherit data from other records in table 1.
What makes two different IDs share the same Regnumber is to have BOTH course and person number in common.
You really need to join table 1 to itself to create the mapping that associates ID 67705 with ID 68521, then you can join in table 2 to pick up the Regnumber.
Try this:
Insert into table2 (ID,RegNumber)
Select right1.ID, left2.RegNumber
From (
(table2 left2 INNER JOIN
table1 left1 On (left1.ID=left2.ID)
INNER JOIN table1 right1 On (left1.Course=right1.Course AND left1.Person=right1.Person)
) LEFT OUTER JOIN table2 right2 On (right1.ID=right2.ID)
WHERE right2.ID Is Null
The 4th table join (alias right2) is purely defensive, to handle two records in table2 having identical Person & Course in table1.
I have solved this myself.
I concatenated the person and course columns and then joined them using that new concatenated field
insert into table 2 (ID,RegNumber)
select X1.ID,X2.Regnumber
from (select concat(course,person) as X,ID from table1) X1
join (select concat(t1.course,t1.person) as X, t2.RegNumber
from table1 t1
join table2 t2 on t1.ID = t2.ID) X2
on X1.X = X2.X
where X1.ID not in (select ID from table2)

Take data from two tables and show in one row without duplicates with a where condition

I want to take the data from two tables and output them in one row .
output will have two columns "to" and "from" where the condition is "from" will be having data from second table where type is true and "to" column will have data from second table where type is false . FK_ID in second table is linked to ID on the first table . Please help with the query.
I was trying to do with inner joins and union was not able to make it work . Thanks in advance .
TABLE 1
ID | PATH|
1 | ABC |
2 | EFG |
TABLE 2
ID | FK_ID | NUMBER | TYPE
20 | 1 | 123 | TRUE
21 | 1 | 456 | FALSE
28 | 2 | 888 | FALSE
29 | 2 | 939 | TRUE
OUTPUT SHOULD BE:
ID | PATH | TO | FROM
1 | ABC | 456 | 123
2 | EFG | 888 | 939
Use aggregation with pivoting logic to identify the "to" and "from" components of each path:
SELECT
t1.ID,
t1.PATH,
MAX(CASE WHEN t2.TYPE = 'FALSE' THEN t2.NUMBER END) AS "TO",
MAX(CASE WHEN t2.TYPE = 'TRUE' THEN t2.NUMBER END) AS "FROM"
FROM table1 t1
LEFT JOIN table2 t2
ON t1.ID = t2.FK_ID
GROUP BY
t1.ID,
t1.PATH
ORDER BY
t1.ID;
If performance is an issue, you might find a lateral join to be faster:
SELECT t1.*, t2.*
FROM table1 t1 LEFT JOIN LATERAL
(SELECT SUM(T2.NUMBER) FILTER (WHERE NOT t2.TYPE) as num_to,
SUM(T2.NUMBER) FILTER (WHERE t2.TYPE) as num_from
FROM table2 t2
WHERE t1.ID = t2.FK_ID
) t2
ORDER BY t1.ID;
This avoids the outer GROUP BY and probably the sorting as well (assuming that ID is the primary key).
It also assumes that TYPE is a Postgres boolean type. If not, use string comparisons for the WHERE clauses.

How to do an outer join with full result between two tables

I have two tables:
TABLE1
id_attr
-------
1
2
3
TABLE2
id | id_attr | val
----------------------
10 | 1 | A
10 | 2 | B
As a result I want a table that show:
RESULT
id | id_attr | val
----------------------
10 | 1 | A
10 | 2 | B
10 | 3 | NULL
So I want the row with id=10 and id_attr=3 also when id_Attr=3 is missing in TABLE2 (and I know that because I have a NULL value (or something else) in the val column of RESULT.
NB: I could have others ids in table2. For example, after insert this row on table2: {11,1,A}, as RESULT I want:
id | id_attr | val
----------------------
10 | 1 | A
10 | 2 | B
10 | 3 | NULL
11 | 1 | A
11 | 2 | NULL
11 | 3 | NULL
So, for every id, I want always the match with all id_attr.
Your specific example only has one id, so you can use the following:
select t2.id, t2.id_attr, t2.val
from table2 t2
union all
select 10, t1.id_attr, NULL
from table1 t1
where not exists (select 1 from table2 t2 where t2.id_attr = t1.id_attr);
EDIT:
You can get all combinations of attributes and ids in the following way. Use a cross join to create all the rows you want and then a left join to bring in the data you want:
select i.id, t1.id_attr, t2.val
from (select distinct id from table2) i cross join
table1 t1 left join
table2 t2
on t2.id = i.id and t2.id_attr = t1.id_attr;
It sounds like you want to do just an outer join on id_attr instead of id.
select * from table2 t2
left outer join table1 t1 on t2.id_attr = t1.id_attr;

ORACLE - remove from result set if two or more "same" records found

ID | NAME | REFERENCE | STATUS
-------------------------------
1 | name1 | 123 | 0
2 | name1 | 123 | 1
3 | name2 | 111 | 0
4 | name3 | 222 | 0
5 | name5 | 555 | 1
Let's say I have this table TABLE1. I need a select statement that will only find records with STATUS=0, but if "same" record exists with STATUS=1 (like those records with ID 1 and 2)
So, query must find only third and fourth record.
Based on your suggested results, I am reading your question as "find only records with status = 0 where the same name/reference combination doesn't have a record with status = 1".
One way you can do this is with a not exists clause:
select t.*
from table t
where status = 0 and
not exists (select 1
from table t2
where t2.name = t.name and
t2.reference = t.reference and
t2.status = 1
);
Try this query out:
SELECT A.*
FROM TABLE1 A
LEFT JOIN TABLE1 B ON
A.ID = B.ID AND
A.NAME = B.NAME AND
A.REFERENCE = B.REFERENCE AND
B.STATUS = 1
WHERE A.STATUS = 0
AND B.REFERENCE IS NULL
The NULL check on B.REFERENCE in the WHERE clause basically ensures that there was no matching record found in the LEFT JOIN (you could just use B.ID or B.NAME also).
MINUS can be used to get the value with Status both 0 but not 1.
SELECT ID, Name, Reference, Status
FROM Table1
WHERE (Name, Reference) IN (SELECT Name, Reference
FROM Table1
WHERE Status = 0
MINUS
SELECT Name, Reference
FROM Table1
WHERE Status = 1)
SELECT * FROM TABLE WHERE NAME NOT IN
(
SELECT NAME FROM
TABLE
GROUP BY NAME
HAVING COUNT(DISTINCT STATUS)>1
) AND STATUS='0';

MySQL: Typecasting NULL to 0

Let us suppose the following table (e.g. a result of several inner join statements):
id | column_1 | column_2
------------------------
1 | 1 |
2 | 2 | 2
3 | | 3
Which you could for example get from the following statement:
select a.id, t1.column_1, t2.column_2
from a
left join t1 on a.id = t1.id
left join t2 on a.id = t2.id
Now, if i'd like to sum up t1.column_1 and t2.column_2 as follows
select
a.id,
t1.column_1,
t2.column_2,
(t1.column_1 + t2.column_2) as cumulated
from a
left join t1 on a.id = t1.id
left join t2 on a.id = t2.id
The result will look as follows:
id | column_1 | column_2 | cumulated
------------------------------------
1 | 1 | NULL | NULL
2 | 2 | 2 | 4
3 | NULL | 3 | NULL
My question basically is: is there a way to typecast NULL into 0 in order to do some math?
I have tried CONVERT(t1.column_1, SIGNED) and CAST(t1.column_1 as SIGNED), but a NULL stays a NULL.
Use IFNULL(column, 0) to convert the column value to zero.
Alternatively, the COALESCE function will do the same thing: COALESCE(column, 0), except
COALESCE is ANSI-compliant, IFNULL is not
COALESCE takes an arbitrary number of columns/values and will return the first non-null value passed to it.