CREATE TABLE CHARGES
(
ChrgCode CHAR(7) PRIMARY KEY,
ChrgDescription NVARCHAR(80) NOTNULL,
Duration NUMBER(2) NOTNULL (DURATION <= 60),
HourlyRate NUMBER(3) (HourlyRate <= 399)
)
This one should work,
CREATE TABLE CHARGES (
ChrgCode CHAR(7) PRIMARY KEY,
ChrgDescription NVARCHAR(80) NOT NULL,
Duration NUMBER(2) NOT NULL check (Duration <=60),
HourlyRate NUMBER(3) check(HourlyRate <=399)
)
The reason that it has syntax error in OP's case is that the missing check keyword. (I assume the missing blank between NOT and NULL are copy / paste errors).
As pointed out in the comment, yes, varchar2 and nvarchar2 should be preferred these days.
Related
CREATE TABLE residents
(
R_ID NUMBER(4), CONSTRAINTS pk_residents_R_ID PRIMARY KEY,
R_FN VARCHAR2(15), NOT NULL,
R_LN VARCHAR2(15), NOT NULL,
R_Contact NUMBER(10), NOT NULL,
DoB DATE, NOT NULL
);
Tried a few changes but I'm unable to resolve this error. Any help would be appreciated!
It works for Oracle in this way:
CREATE TABLE residents(
R_ID NUMBER(4),
R_FN VARCHAR2(15) NOT NULL,
R_LN VARCHAR2(15) NOT NULL,
R_Contact NUMBER(10) NOT NULL,
DoB DATE NOT NULL,
pk_residents_R_ID NUMBER(4) PRIMARY KEY
);
Code which is the closest to your attempt is:
SQL> CREATE TABLE residents
2 (
3 r_id NUMBER (4) CONSTRAINT pk_residents_r_id PRIMARY KEY,
4 r_fn VARCHAR2 (15) NOT NULL,
5 r_ln VARCHAR2 (15) NOT NULL,
6 r_contact NUMBER (10) NOT NULL,
7 dob DATE NOT NULL
8 );
Table created.
SQL>
keyword is constraint, not constraintS
don't separate NOT NULL (or any other constraint) from its column with a comma
Also, using mixed letter case is irrelevant as Oracle - by default - stores object names in UPPERCASE. That's so unless you decide to enclose names into double quotes, but then you'll always have to use double quotes and exactly match letter case so - that's not what anyone should do, not in Oracle.
First of all, I apologize for asking the same question again but the information on the old topics did not work in my oraclesql code and secondly there may be some syntax errors, I learned mysql in school last semester, but now we are learning oraclesql with old mysql information in the lesson, so i am a bit confused.
So my question is i want to create 3 related table (movie-casts-actor) but i am getting missing right parenthesis. trying to connect casts table to movie table with foreign key and actor table to casts table. what am i doing wrong? how spagetti is it?
CREATE TABLE Movie (
movie_id NUMBER(7) NOT NULL,
movie_name varchar2(50) NOT NULL ,
movie_director varchar2(50) NOT NULL ,
movie_year INT(4) NOT NULL ,
movie_duration INT(3) ,
movie_language varchar2(15) ,
movie_rating number(4,2) ,
PRIMARY KEY(movie_id),
CONSTRAINT is_unique UNIQUE(movie_id),
CONSTRAINT movie_id_checker CHECK(movie_id>0 and movie_id<=9999999)
);
CREATE TABLE Casts (
movie_id_fk INT(7) FOREIGN KEY REFERENCES Movie(movie_id) ,
cast_id INT(7) NOT NULL,
actor_fullname varchar2(50) NOT NULL ,
actor_role varchar2(50) ,
PRIMARY KEY(cast_id),
CONSTRAINT is_unique UNIQUE(cast_id),
CONSTRAINT cast_id_checker CHECK(cast_id>0 and cast_id<=9999999)
);
CREATE TABLE Actor (
cast_id_fk INT(7) FOREIGN KEY REFERENCES Casts(cast_id) ,
actor_id INT(7) NOT NULL,
actor_name CHAR(30) ,
actor_surname CHAR(25) ,
actor_gender CHAR(5) ,
actor_age CHAR(3) CONSTRAINT real_age_check CHECK(actor_age>0 AND actor_age<=150),
PRIMARY KEY(actor_id),
CONSTRAINT is_unique UNIQUE(actor_id),
CONSTRAINT actor_id_checker CHECK(actor_id>0 and actor_id<=9999999)
)
The errors are:
INT or NUMBER(4,0) and not INT(4)
You cannot have a unique key and a primary key on the same column.
An inline foreign key just need the REFERENCES keyword and does not need FOREIGN KEY.
Other issues:
You probably don't want actor name/surname as fixed-length CHAR strings and want to us variable-length VARCHAR2.
You probably want gender to be a code from a fixed list (which can be as long or as short as you find appropriate to describe the actors) rather than as a string.
You probably don't want to have an AGE column as that will be out of date as soon as the first birthday of an actor occurs; instead have a DATE_OF_BIRTH column that is a DATE data type and then you can calculate the age as and when necessary.
Using the table name as a prefix for every column is a waste of key strokes; you would be better to just name the columns for what they are without the prefix. Similar with fk as a suffix.
If you are using a NUMBER(7,0) for id values then you don't need to check that it is less than or equal to 9999999 as it is impossible to be a greater value; however, you can have zero or negative values so the check constraint for the lower bound may still be valid.
If you are using Oracle 12c or later then you should probably be using an IDENTITY column for the id values unless you are taking the id values from a 3rd party.
CREATE TABLE Movie (
id NUMBER(7,0) NOT NULL,
name varchar2(50) NOT NULL ,
director varchar2(50) NOT NULL ,
year NUMBER(4,0) NOT NULL ,
duration NUMBER(3,0),
language varchar2(15) ,
rating number(4,2) ,
PRIMARY KEY(id),
CONSTRAINT movie_id_checker CHECK(id>0)
);
CREATE TABLE Casts (
movie_id INT REFERENCES Movie(id) ,
id NUMBER(7,0) NOT NULL,
fullname varchar2(50) NOT NULL ,
role varchar2(50) ,
PRIMARY KEY(id),
CONSTRAINT cast_id_checker CHECK(id>0)
);
CREATE TABLE Actor (
cast_id NUMBER(7,0) REFERENCES Casts(id) ,
id NUMBER(7,0) NOT NULL,
name VARCHAR2(30) ,
surname VARCHAR2(25) ,
gender CHAR(1)
CHECK ( gender IN ( 'M', 'F', 'X', 'Y', 'Z' ) ),
date_of_birth DATE
CONSTRAINT real_age_check CHECK(date_of_birth >= DATE '1870-01-01' ),
PRIMARY KEY(id),
CONSTRAINT actor_id_checker CHECK(id>0)
);
db<>fiddle here
condition for the problem to be solved:
The code i tried to do is
create table article (
ArCode CHAR(5),
ArName VARCHAR(30) NOT NULL ,
Rate Number(8,2) ,
Quantity NUMBER(4) CHECK (Quantity>0) DEFAULT 0 ,
Class CHAR(1)
);
I couldn't solve the first condition and so i am getting right parenthesis missing for final condition
I would translate your requirement as follows:
CREATE TABLE article (
ArCode CHAR(5) PRIMARY KEY CHECK(ArCode like 'A%'),
ArName VARCHAR(30) NOT NULL,
Rate NUMERIC(8,2),
Quantity NUMERIC(4) DEFAULT 0 CHECK (Quantity >= 0),
Class CHAR(1) CHECK(Class in ('A', 'B', 'C'))
);
Changes to your original code:
you want NUMERIC rather than NUMBER
ArCode must be declared as PRIMARY KEY, and needs a check constraint to enfore the "Must begin with A" requirement
the check constraint on Quantity should allow 0 value (that's the default!)
Class needs a check constraint on the list of allowed values
I have tried editing the command and looking at other questions in order to answer this question, but I still get the dreaded
ORA-00907: missing right parenthesis.
Here is my code. Is there any key word that I may need to drop here? Thanks
CREATE TABLE Loan
(
LoanID INT IDENTITY ( 1, 1 ) UNIQUE,
BranchID INT NOT NULL REFERENCES Branch(BranchID) ON DELETE CASCADE,
LoanNumber CHAR(20) NOT NULL UNIQUE,
LoanType VARCHAR(30) NOT NULL,
Amount MONEY NOT NULL,
ModifiedDate DATETIME DEFAULT (getdate()),
PRIMARY KEY ( LoanID )
);
The following ddl is syntactically correct. Of course, you have to check whether that statement really produces what you want ( in particular the IDENTITY keyword in your original statement is not accounted for ):
CREATE TABLE Loan
(
LoanID INTEGER NOT NULL PRIMARY KEY
, BranchID INTEGER NOT NULL CONSTRAINT tl_fk_branchid REFERENCES Branch(BranchID) ON DELETE CASCADE
, LoanNumber CHAR(20) NOT NULL CONSTRAINT tl_u_loannumber UNIQUE
-- right padded to length of 20 with blanks
, LoanType VARCHAR2(30) NOT NULL
, Amount Number(*,4) NOT NULL
-- cf. http://stackoverflow.com/a/29014422, changed per #BobJarvis' comment
, ModifiedDate DATE DEFAULT SYSDATE
);
The syntax deviations are as follows:
IDENTITYkeyword
inline constraint specification
datatype to represent date and time
datatype for string content
stand-in for money datatype
current datetime
I try to Write the SQL code to create the table named ‘EMP_1’. This table is a subset of the EMPLOYEE table, and the structure of the table is summarized as shown below.
This is the information:
Attribute Name Data Type Remarks
EMP_NUM CHAR(3) PK
EMP_LNAME VARCHAR(15) Not Null
EMP_FNAME VARCHAR(15) Not Null
EMP_INITIAL CHAR(1)
EMP_HIREDATE DATE
JOB_CODE CHAR(3) FK (from JOB table)
My code:
CREATE TABLE EMP_1
(
EMP_NUM CHAR(3) PRIMARY KEY,
EMP_LNAME VARCHAR(15) Not Null,
EMP_FNAME VARCHAR(15) Not Null,
EMP_INITIAL CHAR(1) ,
EMP_HIREDATE DATETIME,
JOB_CODE CHAR(3) FOREIGN KEY (JOB_CODE) REFERENCES JOB(JOB_CODE)
);
I keep getting CONSTRAINT error
I think you might be missing a comma before the constraint. This worked when I tried it:
CREATE TABLE EMP_1
(
EMP_NUM CHAR(3) PRIMARY KEY,
EMP_LNAME VARCHAR(15) Not Null,
EMP_FNAME VARCHAR(15) Not Null,
EMP_INITIAL CHAR(1),
EMP_HIREDATE DATETIME,
JOB_CODE CHAR(3),
CONSTRAINT FK_JOBS FOREIGN KEY (JOB_CODE) REFERENCES JOB(JOB_CODE)
);
Make sure your PRIMARY KEY and FOREIGN KEY have the same DATA TYPE.
I've not scrpited a FK for a while, but my recollection is that you can EITHER use:
JOB_CODE CHAR(3) FOREIGN KEY REFERENCES JOB(JOB_CODE)
which will create an FK named JOB_CODE,
OR:
split the line so you create the field and add the constraint separately as per JPW's response.
Your original code tries to combine the 2 approaches which will throw the error you describe.