This question already has answers here:
Simulating group_concat MySQL function in Microsoft SQL Server 2005?
(12 answers)
SQL Server: Combine multiple rows into one row from a join table?
(1 answer)
ListAGG in SQLSERVER
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how to stuff date and time in SQL
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Query to get multiple row into single row
(3 answers)
Closed 3 years ago.
I have the below data and I have to concatenate the long text column and make it as a single row. The challenge part is only one row has the notification number and other rows are null. You cannot group by the notification number.
I need the output as 2 rows
row number Notification Number Plant Creation Date Language Lineno Tag Long Text
1 10014354914 A057 43466 EN 1 >X aaabbbcccdddeeefffggghhhjjjkkklll
2 10014354915 A057 43466 EN 1 >X aaabbbcccdddeeefffgggpppqqqrrrsss
I have used cursor for this. But it is taking much time.
If you are using oracle:
with data("row number", "Notification Number","Plant","Creation Date","Language","Lineno","Tag","Long Text") as (
select 1,10014354914,'A057',43466,'EN',1,'>X','aaabbbcccdddeeefffggghhhjjjkkklll' from dual
union all
select 2,10014354915,'A057',43466,'EN',1,'>X','aaabbbcccdddeeefffgggpppqqqrrrsss' from dual)
select LISTAGG("Long Text",'') within group (order by "row number") from data;
if you are using ms-sql maybe try this:
SELECT u.[Long Text] AS [text()]
FROM yourtable u
ORDER BY u.[row number]
FOR XML PATH ('')
Related
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Get top results for each group (in Oracle)
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How to extract the first 5 rows for each id user in Oracle? [duplicate]
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First two salaries in each department [duplicate]
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Limit SQL query to only the top two counts per group [duplicate]
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Closed 12 months ago.
User requirement:- 2 policies in each product code with Highest (Maximum) SUM INSURED
How do I get 2 policies in each product code with Highest (Maximum) SUM INSURED
SELECT
PROD.MV_PREMIUM_REGISTER.T_DATE_DESC,
PROD.MV_PREMIUM_REGISTER.P_POLICY_NUMBER,
PROD.MV_PREMIUM_REGISTER.P_POLICY_STATUS,
PROD.MV_PREMIUM_REGISTER.VERSION,
PROD.MV_PREMIUM_REGISTER.P_RISK_INC_DATE,
PROD.MV_PREMIUM_REGISTER.P_OFFICE_LOC_ID,
PROD.MV_PREMIUM_REGISTER.LOCATION_DESC,
PROD.MV_PREMIUM_REGISTER.ZONE_DESC,
PROD.MV_PREMIUM_REGISTER.I_IMD_DESC,
PROD.MV_PREMIUM_REGISTER.P_SUB_IMD,
PROD.MV_PREMIUM_REGISTER.P_PRODUCT_ID,
PROD.MV_PREMIUM_REGISTER.P_RISK_EXPIRY_DATE,
PROD.MV_PREMIUM_REGISTER.P_GC_PLAN,
PROD.MV_PREMIUM_REGISTER.IMD_CHANNEL,
PROD.MV_PREMIUM_REGISTER.P_PRODUCT_DESC,
(PROD.MV_PREMIUM_REGISTER.SUM_INSURED) AS SUM_INSURED,
(PROD.MV_PREMIUM_REGISTER.GROSS_PREMIUM) AS GROSS_PREMIUM,
(PROD.MV_PREMIUM_REGISTER.STAMP_DUTY) AS STAMP_DUTY
FROM
PROD.MV_PREMIUM_REGISTER
WHERE
T_DATE_DESC BETWEEN '27-FEB-2022' AND '28-FEB-2022'
AND VERSION NOT LIKE '%E%'
AND LT_POLICY_YEAR = 1;
SELECT P_PRODUCT_ID,P_POLICY_NUMBER,SUM_INSURED from(
SELECT
PROD.MV_PREMIUM_REGISTER.P_PRODUCT_ID,
PROD.MV_PREMIUM_REGISTER.P_POLICY_NUMBER,
(PROD.MV_PREMIUM_REGISTER.SUM_INSURED) AS SUM_INSURED,
RANK() OVER(PARTITION BY P_PRODUCT_ID ORDER BY SUM_INSURED DESC) AS
RANK_COUNT
FROM
PROD.MV_PREMIUM_REGISTER
WHERE
T_DATE_DESC BETWEEN '27-FEB-2022' AND '28-FEB-2022'
AND VERSION NOT LIKE '%E%'
AND LT_POLICY_YEAR = 1) MVP where MVP.RANK_COUNT <3;
This question already has answers here:
Fetch the rows which have the Max value for a column for each distinct value of another column
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Closed 2 years ago.
I have a database table where there is a column hostname and few other columns.
in hostname, there are many instances of rows with same hostnames.
Ex. 192.0.0.1 has 40 entries and 192.0.0.2 has 35 entries and so on.
Is it possible to get the list of latest entries for each hostname? meaning in the result i should get one latest for 192.0.0.1 and one latest for 192.0.0.2 and so on.
I tried with
SELECT host,cluster,region,service
FROM system
WHERE host IN ("171.33.64.158","171.33.64.159")
ORDER BY id DESC LIMIT 1;
but the output contains only one row which is probably the first row of the entire result.
Can anyone please help me in this requirement?
Thanks,
Swapnil
Try this:
select host,cluster,region,service
from (
SELECT host,cluster,region,service, row_number() over (partition by host order by id
desc) as r_num
FROM system
WHERE host IN ("171.33.64.158","171.33.64.159"))
where r_num = 1;
Thanks
For proper ordering you need to convert the IP address into decimal equivalent. I would suggest a function like this:
FUNCTION IP2Decimal(IP IN VARCHAR2) RETURN NUMBER DETERMINISTIC IS
DecimalIp NUMBER;
BEGIN
SELECT SUM(REGEXP_SUBSTR(IP, '\d+', 1, LEVEL) * POWER(256, 4-LEVEL))
INTO DecimalIp
FROM dual
CONNECT BY LEVEL <= 4;
RETURN DecimalIp;
END IP2Decimal;
Then your query could be this:
SELECT hostname,
FIRST_VALUE(host) OVER (ORDER BY IP2Decimal(host)),
FIRST_VALUE(cluster) OVER (ORDER BY IP2Decimal(host)),
FIRST_VALUE(region) OVER (ORDER BY IP2Decimal(host)),
FIRST_VALUE(service) OVER (ORDER BY IP2Decimal(host))
FROM system
GROUP BY hostname;
This question already has answers here:
SQL Query to concatenate column values from multiple rows in Oracle
(10 answers)
Closed 4 years ago.
I have a very simple query:
select date,route,employee
from information
where date=Trunc(Sysdate)
however, since for some routes, there are more than 2 employees are assigned, so the query will return two rows
But I want get one route for one row, so the ideal output should be:
so the two names are in the same row, and combine with "|", so how can I achieve this goal in PL/SQL?
You can use listagg function, but you have to add Date and Route to grouping functions as well
SELECT LISTAGG(emp, ' | ')
WITHIN GROUP (ORDER BY emp) "Emp",
MAX(date) "Date",
MAX(route) "Route"
FROM information
WHERE date=Trunc(Sysdate);
This question already has answers here:
How can I compute TF/IDF with SQL (BigQuery)
(3 answers)
Closed 4 years ago.
In BigQuery I would like to create a query to count the occurrence of words in a comments field and group by a count of each occurrence. This would me get a sense of what words were used more than others and get a sense of user behavior and moods. Pretty new to bigquery so any ideas will be helpful.
What I ended up doing was using the split function...
SELECT
COUNT(JJ) AS STUFF, JJ
FROM
(SELECT SPLIT(text, ' ') AS JJ FROM [bigquery-public-
data:hacker_news.comments] LIMIT 1000 )
GROUP BY JJ
ORDER BY STUFF DESC
LIMIT 5
Obviously it can be manipulated more by using replace to remove other characters before splitting.
This question already has an answer here:
How can I get a number with a thounds separator on top?
(1 answer)
Closed 5 years ago.
SELECT count(id) FROM table a
it gives me a number lets say 36136, how can i make thousand separator on top?
Try (MSSQL)
SELECT REPLACE(REPLACE(
CONVERT(VARCHAR,CONVERT(MONEY, COUNT(ID)),1)
,'.00','') ,',','''')
FROM TABLE A
Example
SELECT REPLACE(REPLACE(CONVERT(VARCHAR,CONVERT(MONEY, 1000),1),'.00','') ,',','''') X
Output
X
----
1'000
Use TOP statement in SQL server :
SELECT TOP 1000 * FROM table a