enter code hereI want to show a toast when my modal is visible in my react native project.
I use react-native-modal.
I have a button in modal when i press it should show up a toast
I don't want to put my toast tag inside the modal tag
what should i do???
render(){
return(
<>
<Modal visible={this.state.visible}>
<Toast
ref="toast"
style={{backgroundColor:'red'}}
position='bottom'
positionValue={100}
fadeInDuration={1000}
fadeOutDuration={1000}
opacity={0.8}
textStyle={{color:'blue'}}
/>
<SafeAreaView style={{flex:1}}>
<View style={{flex:1,justifyContent:'center',alignItems:'center'}}>
<TouchableOpacity onPress={()=>this.refs.toast.show('hello world!')} style={{height:200,width:100,justifyContent:'center',alignItems:'center',backgroundColor:'blue'}}>
<Text>Modal Button</Text>
</TouchableOpacity>
</View>
</SafeAreaView>
</Modal>
<SafeAreaView style={{flex:1}}>
<View style={{flex:1,justifyContent:'center',alignItems:'center'}}>
<TouchableOpacity onPress={()=>{this.setState({visible:true})}} style={{height:100,width:100,justifyContent:'center',alignItems:'center',backgroundColor:'red'}}>
<Text>button</Text>
</TouchableOpacity>
</View>
</SafeAreaView>
</>
)
}
Actually i wanna be my toast out of my Modal tag but it show in top of screen when modal is visible
react native modal is a native view, so impossible to be covered by a js component.
Related
I make check box list on Model Pop up by using react native multiple select
checkbox list listed but it take full screen height
i am not able to fix this issue
please Any body help me
Outer Element would be a modal, then make a view of a specific height inside that modal,
Example
<Modal transparent={true}
visible={this.state.showDialog}
animationType='fade'>
<View style={{opacity:.5, backgroundColor:'black',flex:1}}/>
<View
style={{position:'absolute',padding:16,top:0,bottom:0,left:0,right:0
,justifyContent:'center',alignContent:"center",
alignItems:'center'}}>
<View style={{backgroundColor:’red’,padding:16,borderRadius:5,
width:'60%',height:'10%',alignContent:'center',alignItems:'center',justifyContent:'center'}}>
<Text style={{fontSize:14,alignSelf:'center',textAlign:'center'}}>
Sorry!!
</Text>
<Text style={{marginTop:5,fontSize:12,alignSelf:'center',textAlign:'center',color:’black’}}>
{this.props.errorMessage}
</Text>
<Button title='close'
onPress={()=>this.setState({showDialog:false})}/>
</View>
</View>
</Modal>
I'm creating an application where I'm using a MaterialBottomTabBar and in the Home Screen I've a button which are supposed to open up a <Modal>.
After investigating this for quite some time I found out that I cannot present the modal when using the tabbar. I've tried to put the modal in all my tabbar-screens (without any success). And then moved the modal over to another screen which are not included in the tab-bar and the modal worked perfectly fine.
export default function Home({ route, navigation }){
const [modal, setModal] = useState(false)
return(
<View style={styles.container}>
<Modal visible={modal} transparent={true}>
<View style={{height: "100%", width: "80%", backgroundColor: "blue"}}>
<Text>TIFMNASIFAMNFISAMFIAOFMSAOFMAFOPSAMF</Text>
</View>
</Modal>
<TouchableOpacity style={styles.addNewButton} onPress={() => setModal(true)}>
<Text style={styles.addNewButtonText}>+</Text>
</TouchableOpacity>
</View>
)
}
As you can see i'm using the React Native Hooks useState(false) and refers to it inside the Modal. But whenever I tap the <TouchableOpacity> the modal is not being presented.
NOTE!
The modal is being presented if I replace the
<Modal visible={modal} transparent={true}>
to
<Modal visible={true} transparent={true}>
But would be runned instantly, which is not an option in my case.
Do you have any idea how I can run this modal inside the screen?
I have several modals in jsx
<View>
<Modal id="first" visible>
<View>
<Text>123</Text>
<Button onPress={() => this.setState({ secondVisible: true })}>Open Modal</Button>
</View>
</Modal>
<Modal id="second" visible={this.state.secondVisible}>
<View>
<Text>123</Text>
</View>
</Modal>
</View>
I open #first than inside it i press button and do #second visible.
Is it possible to give some zIndex to #second so it can be always on top.
Modal in Modal i cant do because its sharable so can be opened from several places
We have a FilterComponent which renders a Modal, but on iPhone X it's Header is in the Statusbar.
I tried to render it with SafeAreaView but seems like this is not working:
return (
<SafeAreaView>
<Modal
{ ...defaultModalProps }
onRequestClose={ close }
style={ styles.container }
visible={ visible }
>
<ModalNavbar close={ close }>
Filter
</ModalNavbar>
<View style={ styles.content }>
...
</View>
</Modal>
</SafeAreaView>
);
When FilterModal is openend on iPhoneX it still is in the Statusbar and you cant click on anything.
Any idea how to solve this?
thanks.
Put SafeAreaView inside the Modal component
return (
<Modal
{...defaultModalProps}
onRequestClose={close}
style={styles.container}
visible={visible}
>
<SafeAreaView style={{ flex: 1, backgroundColor: "transparent" }}>
<ModalNavbar close={close}>Filter</ModalNavbar>
<View style={styles.content}>...</View>
</SafeAreaView>
</Modal>
);
if you use react-native-safe-area-context and you have a problem with modal then
<Modal>
<SafeAreaProvider>
<SafeAreaView>
// your modal content
</SafeAreaView>
</SafeAreaProvider>
</Modal>
A Modal fill the entire screen, so you need to provide extra spacing inside the Modal. Margin / Padding will not effect on Modal if applied on parent of Modal.
<Modal {...}>
<TouchableWithoutFeedback onPress={closeModal}>
<SafeAreaView {...}>
{...}
</SafeAreaView>
</TouchableWithoutFeedback>
</Modal>
I’m writing a React Native app and I want to detect tap/clicks anywhere on the screen so I put an onClick handler on my <View> element but it doesn’t seem to be working. Here is my render function:
<View style={styles.container} onClick={this.onClick}>
<Text style={styles.welcome}>
Tap to change the background
</Text>
</View>
What do I need to do?
For making any element to handle touch/click events in a React-Native UI, you need to put the element inside a TouchableOpacity, TouchableWithoutFeedback, TouchableNativeFeedback or TouchableHighlight element:
<TouchableHighlight onPress = { this.onClick }>
<View style={styles.container}>
<Text style={styles.welcome}>
Tap to change the background
</Text>
</View>
</TouchableHighlight>
Hope that helps.
In React Native version > 55.3 you make check onPress events into your View if use onStartShouldSetResponder props.
Like example:
<View
style={{ flex: 1 }}
onStartShouldSetResponder={() => console.log('You click by View')}
>
<ScrollView
refreshControl={
<RefreshControl
refreshing={this.state.refreshing}
onRefresh={this.onRefresh} />
}
>
<Text>Awesome</Text>
</ScrollView>
</View>
In example I showed how you can get onPress event on View and not blocking other event behind them. Refresh control still work correct.
In my case the following works fine. You can use onTouchStart and onTouchEnd handlers on any View via props, for example:
<View onTouchStart={() => this.doSomething()} />
More information
This worked for me...
onTouchEnd={() => alert('TAPPED')}
The easiest way to do that:
<TouchableOpacity style={styles.container} onPress={()=> whateverFunc(parameter)}>
<Text style={styles.welcome}>
Tap to change the background
</Text>
</TouchableOpacity>
So, you need to replace the 'View' component to a 'TouchableOpacity' or any other Touchable component and you also need to replace the 'onClick' prop to 'onPress'. That's all. The wrapping of a view with a TouchableWhatever component is not necessary at all.