I have a big table with over 1 million rows and 96 columns.
Using SQL I want to find rows where every value is the same. The table doesn't have any primary key so I'm not sure how to approach this. I'm not permitted to change the table structure.
I've seen people use count(*) and group by but I'm not sure if this is effective for a table with 96 columns.
Using COUNT() as an analytic function we can try:
WITH cte AS (
SELECT *, COUNT(*) OVER (PARTITION BY col1, col2, ..., col96) cnt
FROM yourTable
)
SELECT col1, col2, ..., col96
FROM cte
WHERE cnt > 1;
you can use md5 function as primary key.
select count(1),md5_col,* from (
select md5(concat_ws('',col1,col2)) as md5_col,* from db_name.table_name) tt group by md5_col;
For convenience, use BINARY_CHECKSUM:
with cte as (
select *, BINARY_CHECKSUM(*) checksum
from mytable
), cte2 as (
select checksum
from cte
group by checksum
having count(*) > 1
)
select distinct t1.*
from cte t1
join cte t2 on t1.checksum = t2.checksum
and t1.col1 = t2.col2
and t1.col2 = t2.col2
-- etc
where t1.checksum in (select checksum from cte2)
cte2 will return (almost) only truly matching rows, so join condition won't have many rows to exhaustively compare every column.
Rather than trying to boil the ocean and solve the entire problem with a single sql query (which you certainly can do...), I recommend using any indexes or statistics on the tables to filter out as many rows as you can.
Start by finding the columns with the most / fewest unique values (assuming you have statistics, that is), and smash them up against each other to rapidly exclude as many rows as possible. Take the results, dump them to a temp table, index fields as needed, and repeat.
Or you could just do this:
Declare #sql nvarchar(max);
Select #sql='select column1 from schema.table where case ' + stuff((select 'when col1!=' + quotename(name) + ' then 0 ' from sys.columns where object_id=object_id('schema.table') for xml path(''),Type).value('.','nvarchar(max)'),1,11,'') + 'else 1 end = 1';
Exec sp_executesql #sql;
If you must run that horrorshow of a query in production, please use snapshot isolation or move it to a temp table first (unless no one ever updates the table.
(Honestly, I would probably use something like that query on the temp table containing my filtered-down dataset... but anything you can do to makes sure that the comparisons aren't naïve (e.g. taking statistics into account) can improve your performance significantly. If you want to do it all at once, you could always join sys.tables to a temp table that puts your field comparisons into a thoughtful order. After all, once a case statement if found to be true, all the others will be skipped for that record. )
I have the same table structure called "table1" under two different schemas "schema1" and "schema2". "table1" contains columns "col1, col2, col3". Initialy I want see whether there are records having the same entries of col1 and col2 in the table schema1.table1 and schema2.table1. But I had mistyped schema2.table1 as schema1.table1. And now I am confused by the query result.
SELECT COUNT(*) FROM schema1.table1 AS s1t, schema1.table1 AS s2t
WHERE s1t.col1 = s2t.col1 AND s1t.col2 = s2t.col2;
I got
count
-------
530
(1 row)
However, SELECT COUNT(*) FROM schema1.table1; shows that there are 17815 rows.
Why would the first query show there are only 530 satisfied records? Shouldn't it be 17815 as well?
You can try to use FULL OUTER JOIN to see even mismatched rows, including null values for columns(col1 and 2). This way, at least(more than or equal to) 17815 rows return
SELECT COUNT(*)
FROM schema1.table1 AS s1t
FULL OUTER JOIN schema1.table1 AS s2t
ON s1t.col1 = s2t.col1 AND s1t.col2 = s2t.col2
In your case, only matched rows return for those columns (col1 and 2).
You are joining the table to itself. That is really strange.
In any case, your join is going to filter out any rows where col1 or col2 are NULL.
In addition, the self-join might multiply the number of rows if there are duplicates (with respect to the two columns) in the table.
It is really unclear why you would be doing this, but the above explains the results you are seeing.
If you want to compare the results in the two schemas allowing for duplicates and missing values, I recommend union all/group by:
select col1, col2, sum(cnt1) as cnt1, sum(cnt2) as cnt2
from ((select col1, col2, count(*) as cnt1, 0 as cnt2
from schema1.table1
group by col1, col2
) union all
(select col1, col2, 0 as cnt1, count(*) as cnt2
from schema2.table1
group by col1, col2
)
) t12
group by col1, col2
having sum(cnt1) <> sum(cnt2);
This returns pairs where the counts are not the same in the two tables. It even works for NULL values. If you ran this on the same table, no rows would be returned.
I need to remove duplicate rows from a fairly large SQL Server table (i.e. 300,000+ rows).
The rows, of course, will not be perfect duplicates because of the existence of the RowID identity field.
MyTable
RowID int not null identity(1,1) primary key,
Col1 varchar(20) not null,
Col2 varchar(2048) not null,
Col3 tinyint not null
How can I do this?
Assuming no nulls, you GROUP BY the unique columns, and SELECT the MIN (or MAX) RowId as the row to keep. Then, just delete everything that didn't have a row id:
DELETE FROM MyTable
LEFT OUTER JOIN (
SELECT MIN(RowId) as RowId, Col1, Col2, Col3
FROM MyTable
GROUP BY Col1, Col2, Col3
) as KeepRows ON
MyTable.RowId = KeepRows.RowId
WHERE
KeepRows.RowId IS NULL
In case you have a GUID instead of an integer, you can replace
MIN(RowId)
with
CONVERT(uniqueidentifier, MIN(CONVERT(char(36), MyGuidColumn)))
Another possible way of doing this is
;
--Ensure that any immediately preceding statement is terminated with a semicolon above
WITH cte
AS (SELECT ROW_NUMBER() OVER (PARTITION BY Col1, Col2, Col3
ORDER BY ( SELECT 0)) RN
FROM #MyTable)
DELETE FROM cte
WHERE RN > 1;
I am using ORDER BY (SELECT 0) above as it is arbitrary which row to preserve in the event of a tie.
To preserve the latest one in RowID order for example you could use ORDER BY RowID DESC
Execution Plans
The execution plan for this is often simpler and more efficient than that in the accepted answer as it does not require the self join.
This is not always the case however. One place where the GROUP BY solution might be preferred is situations where a hash aggregate would be chosen in preference to a stream aggregate.
The ROW_NUMBER solution will always give pretty much the same plan whereas the GROUP BY strategy is more flexible.
Factors which might favour the hash aggregate approach would be
No useful index on the partitioning columns
relatively fewer groups with relatively more duplicates in each group
In extreme versions of this second case (if there are very few groups with many duplicates in each) one could also consider simply inserting the rows to keep into a new table then TRUNCATE-ing the original and copying them back to minimise logging compared to deleting a very high proportion of the rows.
There's a good article on removing duplicates on the Microsoft Support site. It's pretty conservative - they have you do everything in separate steps - but it should work well against large tables.
I've used self-joins to do this in the past, although it could probably be prettied up with a HAVING clause:
DELETE dupes
FROM MyTable dupes, MyTable fullTable
WHERE dupes.dupField = fullTable.dupField
AND dupes.secondDupField = fullTable.secondDupField
AND dupes.uniqueField > fullTable.uniqueField
The following query is useful to delete duplicate rows. The table in this example has ID as an identity column and the columns which have duplicate data are Column1, Column2 and Column3.
DELETE FROM TableName
WHERE ID NOT IN (SELECT MAX(ID)
FROM TableName
GROUP BY Column1,
Column2,
Column3
/*Even if ID is not null-able SQL Server treats MAX(ID) as potentially
nullable. Because of semantics of NOT IN (NULL) including the clause
below can simplify the plan*/
HAVING MAX(ID) IS NOT NULL)
The following script shows usage of GROUP BY, HAVING, ORDER BY in one query, and returns the results with duplicate column and its count.
SELECT YourColumnName,
COUNT(*) TotalCount
FROM YourTableName
GROUP BY YourColumnName
HAVING COUNT(*) > 1
ORDER BY COUNT(*) DESC
delete t1
from table t1, table t2
where t1.columnA = t2.columnA
and t1.rowid>t2.rowid
Postgres:
delete
from table t1
using table t2
where t1.columnA = t2.columnA
and t1.rowid > t2.rowid
DELETE LU
FROM (SELECT *,
Row_number()
OVER (
partition BY col1, col1, col3
ORDER BY rowid DESC) [Row]
FROM mytable) LU
WHERE [row] > 1
This will delete duplicate rows, except the first row
DELETE
FROM
Mytable
WHERE
RowID NOT IN (
SELECT
MIN(RowID)
FROM
Mytable
GROUP BY
Col1,
Col2,
Col3
)
Refer (http://www.codeproject.com/Articles/157977/Remove-Duplicate-Rows-from-a-Table-in-SQL-Server)
I would prefer CTE for deleting duplicate rows from sql server table
strongly recommend to follow this article ::http://codaffection.com/sql-server-article/delete-duplicate-rows-in-sql-server/
by keeping original
WITH CTE AS
(
SELECT *,ROW_NUMBER() OVER (PARTITION BY col1,col2,col3 ORDER BY col1,col2,col3) AS RN
FROM MyTable
)
DELETE FROM CTE WHERE RN<>1
without keeping original
WITH CTE AS
(SELECT *,R=RANK() OVER (ORDER BY col1,col2,col3)
FROM MyTable)
DELETE CTE
WHERE R IN (SELECT R FROM CTE GROUP BY R HAVING COUNT(*)>1)
To Fetch Duplicate Rows:
SELECT
name, email, COUNT(*)
FROM
users
GROUP BY
name, email
HAVING COUNT(*) > 1
To Delete the Duplicate Rows:
DELETE users
WHERE rowid NOT IN
(SELECT MIN(rowid)
FROM users
GROUP BY name, email);
Quick and Dirty to delete exact duplicated rows (for small tables):
select distinct * into t2 from t1;
delete from t1;
insert into t1 select * from t2;
drop table t2;
I prefer the subquery\having count(*) > 1 solution to the inner join because I found it easier to read and it was very easy to turn into a SELECT statement to verify what would be deleted before you run it.
--DELETE FROM table1
--WHERE id IN (
SELECT MIN(id) FROM table1
GROUP BY col1, col2, col3
-- could add a WHERE clause here to further filter
HAVING count(*) > 1
--)
SELECT DISTINCT *
INTO tempdb.dbo.tmpTable
FROM myTable
TRUNCATE TABLE myTable
INSERT INTO myTable SELECT * FROM tempdb.dbo.tmpTable
DROP TABLE tempdb.dbo.tmpTable
I thought I'd share my solution since it works under special circumstances.
I my case the table with duplicate values did not have a foreign key (because the values were duplicated from another db).
begin transaction
-- create temp table with identical structure as source table
Select * Into #temp From tableName Where 1 = 2
-- insert distinct values into temp
insert into #temp
select distinct *
from tableName
-- delete from source
delete from tableName
-- insert into source from temp
insert into tableName
select *
from #temp
rollback transaction
-- if this works, change rollback to commit and execute again to keep you changes!!
PS: when working on things like this I always use a transaction, this not only ensures everything is executed as a whole, but also allows me to test without risking anything. But off course you should take a backup anyway just to be sure...
This query showed very good performance for me:
DELETE tbl
FROM
MyTable tbl
WHERE
EXISTS (
SELECT
*
FROM
MyTable tbl2
WHERE
tbl2.SameValue = tbl.SameValue
AND tbl.IdUniqueValue < tbl2.IdUniqueValue
)
it deleted 1M rows in little more than 30sec from a table of 2M (50% duplicates)
Using CTE. The idea is to join on one or more columns that form a duplicate record and then remove whichever you like:
;with cte as (
select
min(PrimaryKey) as PrimaryKey
UniqueColumn1,
UniqueColumn2
from dbo.DuplicatesTable
group by
UniqueColumn1, UniqueColumn1
having count(*) > 1
)
delete d
from dbo.DuplicatesTable d
inner join cte on
d.PrimaryKey > cte.PrimaryKey and
d.UniqueColumn1 = cte.UniqueColumn1 and
d.UniqueColumn2 = cte.UniqueColumn2;
Yet another easy solution can be found at the link pasted here. This one easy to grasp and seems to be effective for most of the similar problems. It is for SQL Server though but the concept used is more than acceptable.
Here are the relevant portions from the linked page:
Consider this data:
EMPLOYEE_ID ATTENDANCE_DATE
A001 2011-01-01
A001 2011-01-01
A002 2011-01-01
A002 2011-01-01
A002 2011-01-01
A003 2011-01-01
So how can we delete those duplicate data?
First, insert an identity column in that table by using the following code:
ALTER TABLE dbo.ATTENDANCE ADD AUTOID INT IDENTITY(1,1)
Use the following code to resolve it:
DELETE FROM dbo.ATTENDANCE WHERE AUTOID NOT IN (SELECT MIN(AUTOID) _
FROM dbo.ATTENDANCE GROUP BY EMPLOYEE_ID,ATTENDANCE_DATE)
This is the easiest way to delete duplicate record
DELETE FROM tblemp WHERE id IN
(
SELECT MIN(id) FROM tblemp
GROUP BY title HAVING COUNT(id)>1
)
Use this
WITH tblTemp as
(
SELECT ROW_NUMBER() Over(PARTITION BY Name,Department ORDER BY Name)
As RowNumber,* FROM <table_name>
)
DELETE FROM tblTemp where RowNumber >1
Here is another good article on removing duplicates.
It discusses why its hard: "SQL is based on relational algebra, and duplicates cannot occur in relational algebra, because duplicates are not allowed in a set."
The temp table solution, and two mysql examples.
In the future are you going to prevent it at a database level, or from an application perspective. I would suggest the database level because your database should be responsible for maintaining referential integrity, developers just will cause problems ;)
I had a table where I needed to preserve non-duplicate rows.
I'm not sure on the speed or efficiency.
DELETE FROM myTable WHERE RowID IN (
SELECT MIN(RowID) AS IDNo FROM myTable
GROUP BY Col1, Col2, Col3
HAVING COUNT(*) = 2 )
Oh sure. Use a temp table. If you want a single, not-very-performant statement that "works" you can go with:
DELETE FROM MyTable WHERE NOT RowID IN
(SELECT
(SELECT TOP 1 RowID FROM MyTable mt2
WHERE mt2.Col1 = mt.Col1
AND mt2.Col2 = mt.Col2
AND mt2.Col3 = mt.Col3)
FROM MyTable mt)
Basically, for each row in the table, the sub-select finds the top RowID of all rows that are exactly like the row under consideration. So you end up with a list of RowIDs that represent the "original" non-duplicated rows.
The other way is Create a new table with same fields and with Unique Index. Then move all data from old table to new table. Automatically SQL SERVER ignore (there is also an option about what to do if there will be a duplicate value: ignore, interrupt or sth) duplicate values. So we have the same table without duplicate rows. If you don't want Unique Index, after the transfer data you can drop it.
Especially for larger tables you may use DTS (SSIS package to import/export data) in order to transfer all data rapidly to your new uniquely indexed table. For 7 million row it takes just a few minute.
By useing below query we can able to delete duplicate records based on the single column or multiple column. below query is deleting based on two columns. table name is: testing and column names empno,empname
DELETE FROM testing WHERE empno not IN (SELECT empno FROM (SELECT empno, ROW_NUMBER() OVER (PARTITION BY empno ORDER BY empno)
AS [ItemNumber] FROM testing) a WHERE ItemNumber > 1)
or empname not in
(select empname from (select empname,row_number() over(PARTITION BY empno ORDER BY empno)
AS [ItemNumber] FROM testing) a WHERE ItemNumber > 1)
Create new blank table with the same structure
Execute query like this
INSERT INTO tc_category1
SELECT *
FROM tc_category
GROUP BY category_id, application_id
HAVING count(*) > 1
Then execute this query
INSERT INTO tc_category1
SELECT *
FROM tc_category
GROUP BY category_id, application_id
HAVING count(*) = 1
Another way of doing this :--
DELETE A
FROM TABLE A,
TABLE B
WHERE A.COL1 = B.COL1
AND A.COL2 = B.COL2
AND A.UNIQUEFIELD > B.UNIQUEFIELD
I would mention this approach as well as it can be helpful, and works in all SQL servers:
Pretty often there is only one - two duplicates, and Ids and count of duplicates are known. In this case:
SET ROWCOUNT 1 -- or set to number of rows to be deleted
delete from myTable where RowId = DuplicatedID
SET ROWCOUNT 0
From the application level (unfortunately). I agree that the proper way to prevent duplication is at the database level through the use of a unique index, but in SQL Server 2005, an index is allowed to be only 900 bytes, and my varchar(2048) field blows that away.
I dunno how well it would perform, but I think you could write a trigger to enforce this, even if you couldn't do it directly with an index. Something like:
-- given a table stories(story_id int not null primary key, story varchar(max) not null)
CREATE TRIGGER prevent_plagiarism
ON stories
after INSERT, UPDATE
AS
DECLARE #cnt AS INT
SELECT #cnt = Count(*)
FROM stories
INNER JOIN inserted
ON ( stories.story = inserted.story
AND stories.story_id != inserted.story_id )
IF #cnt > 0
BEGIN
RAISERROR('plagiarism detected',16,1)
ROLLBACK TRANSACTION
END
Also, varchar(2048) sounds fishy to me (some things in life are 2048 bytes, but it's pretty uncommon); should it really not be varchar(max)?
DELETE
FROM
table_name T1
WHERE
rowid > (
SELECT
min(rowid)
FROM
table_name T2
WHERE
T1.column_name = T2.column_name
);
CREATE TABLE car(Id int identity(1,1), PersonId int, CarId int)
INSERT INTO car(PersonId,CarId)
VALUES(1,2),(1,3),(1,2),(2,4)
--SELECT * FROM car
;WITH CTE as(
SELECT ROW_NUMBER() over (PARTITION BY personid,carid order by personid,carid) as rn,Id,PersonID,CarId from car)
DELETE FROM car where Id in(SELECT Id FROM CTE WHERE rn>1)
I you want to preview the rows you are about to remove and keep control over which of the duplicate rows to keep. See http://developer.azurewebsites.net/2014/09/better-sql-group-by-find-duplicate-data/
with MYCTE as (
SELECT ROW_NUMBER() OVER (
PARTITION BY DuplicateKey1
,DuplicateKey2 -- optional
ORDER BY CreatedAt -- the first row among duplicates will be kept, other rows will be removed
) RN
FROM MyTable
)
DELETE FROM MYCTE
WHERE RN > 1