How to insert records based on another table value - sql

I have the following three tables:
Permission
| PermissionId | PermissionName |
+--------------+----------------+
| 1 | A |
| 2 | B |
| 3 | C |
| 100 | D |
Group
| GroupId | GroupLevel | GroupName |
+---------+------------+----------------------+
| 1 | 0 | System Administrator |
| 7 | 0 | Test Group 100 |
| 8 | 20 | Test Group 200 |
| 9 | 20 | test |
| 10 | 50 | TestGroup01 |
| 11 | 51 | TestUser02 |
| 12 | 52 | TestUser03 |
GroupPermission
| GroupPermissionId | FkGroupId | FkPermissionId |
+-------------------+-----------+----------------+
| 1 | 1 | 1 |
| 2 | 1 | 2 |
| 3 | 1 | 3 |
| 4 | 1 | 4 |
I need to insert records into GroupPermission table, if table Group, GroupLevel column have 0
then I need to take its GroupId and need to insert values to GroupPermission table as that particular id and 100.
In order to above sample table records, I need to insert the following two records to GroupPermission table,
| FkGroupId | FkPermissionId |
+-----------+----------------+
| 1 | 100 |
| 7 | 100 |
How can I do it

This question is not very clear and I can only assume the value 100 is a static value and that you don't actually have foreign keys as the names of the columns imply. Also, you really should avoid reserved words like "Group" for object names. It makes things more difficult and confusing.
The simple version of your insert might look like this.
insert GroupPermission
(
FkGroupId
, FkPermissionId
)
select g.GroupId
, 100
from [Group] g
where g.GroupLevel = 0
--EDIT--
Since you want to only insert those rows that don't already exist you can use NOT EXISTS like this.
select g.GroupId
, 100
from [Group] g
where g.GroupLevel = 0
AND NOT EXISTS
(
select *
from GroupPermission gp
where gp.FkGroupId = g.GroupId
and g.FkPermissionId = 100
)
Or you could use a left join like this.
select g.GroupId
, 100
from [Group] g
left join GroupPermission gp on gp.FkGroupId = g.GroupId
and gp.FkPermissionId = 100
where g.GroupLevel = 0
and gp.FkGroupId is null

Related

Select from a concatenation of two columns after a left join

Problem description
Let the tables C and V have those values
>> Table V <<
| UnID | BillID | ProductDesc | Value | ... |
| 1 | 1 | 'Orange Juice' | 3.05 | ... |
| 1 | 1 | 'Apple Juice' | 3.05 | ... |
| 1 | 2 | 'Pizza' | 12.05 | ... |
| 1 | 2 | 'Chocolates' | 9.98 | ... |
| 1 | 2 | 'Honey' | 15.98 | ... |
| 1 | 3 | 'Bread' | 3.98 | ... |
| 2 | 1 | 'Yogurt' | 8.55 | ... |
| 2 | 1 | 'Ice Cream' | 7.05 | ... |
| 2 | 1 | 'Beer' | 9.98 | ... |
| 2 | 2 | 'League of Legends RP' | 40.00 | ... |
>> Table C <<
| UnID | BillID | ClientName | ... |
| 1 | 1 | 'Alexander' | ... |
| 1 | 2 | 'Tom' | ... |
| 1 | 3 | 'Julia' | ... |
| 2 | 1 | 'Tom' | ... |
| 2 | 2 | 'Alexander' | ... |
Table C have the values of each product, which is associated with a bill number. Table V has the relationship between the client name and the bill number. However, the bill number has a counter that is dependent on the UnId, which is the store unity ID. That being said, each store has it`s own Bill number 1, number 2, etc. Also, the number of bills from each store are not equal.
Solution description
I'm trying to make select between the C left join V without sucess. Because each BillID is dependent on the UnID, I have to make the join considering the concatenation between those two columns.
I've used this script, but it gives me an error.
SELECT
SUM(C.Value),
V.ClientName
FROM
C
LEFT JOIN
V
ON
CONCAT(C.UnID, C.BillID) = CONCAT(V.UnID, V.BillID)
GROUP BY
V.ClientName
and SQL server returns me this 'CONCAT' is not a recognized built-in function name.
I'm using Microsoft SQL Server 2008 R2
Is the use of CONCAT wrong? Or is it the way I tried to SELECT? Could you give me a hand?
[OBS: The tables I've present you are just for the purpose of explaining my difficulties. That being said, if you find any errors in the explanation, please let me know to correct them.]
You should be joining on the equality of the UnID and BillID columns in the two tables:
SELECT
c.ClientName,
COALESCE(SUM(v.Value), 0) AS total
FROM C c
LEFT JOIN V v
ON c.UnID = v.UnID AND
c.BillID = v.BillID
GROUP BY
c.ClientName;
In theory you could try joining on CONCAT(UnID, BillID). However, you could run into problems. For example, UnID = 1 with BillID = 23 would, concatenated together, be the same as UnID = 12 and BillID = 3.
Note: We wrap the sum with COALESCE, because should a given client have no entries in the V table, the sum would return NULL, which we then replace with zero.
concat is only available in sql server 2012.
Here's one option.
SELECT
SUM(C.Value),
V.ClientName
FROM
C
LEFT JOIN
V
ON
cast(C.UnID as varchar(100)) + cast(C.BillID as varchar(100)) = cast(V.UnID as varchar(100)) + cast(V.BillID as varchar(100))
GROUP BY
V.ClientName

Only include grouped observations where event order is valid

I have a table of dates for eye exams and eye wear purchases for individuals. I only want to keep instances where individuals bought their eye wear following an eye exam. In the example below, I would want to keep person 1, events 2 and 3 for person 2, person 3, but not person 4. How can I do this in SQL server?
| Person | Event | Order |
| 1 | Exam | 1 |
| 1 | Eyewear| 2 |
| 2 | Eyewear| 1 |
| 2 | Exam | 2 |
| 2 | Eyewear| 3 |
| 3 | Exam | 1 |
| 3 | Eyewear| 2 |
| 4 | Eyewear| 1 |
| 4 | Exam | 2 |
The final result would look like
| Person | Event | Order |
| 1 | Exam | 1 |
| 1 | Eyewear| 2 |
| 2 | Exam | 2 |
| 2 | Eyewear| 3 |
| 3 | Exam | 1 |
| 3 | Eyewear| 2 |
Self join should work...
select
t.Person
,t.Event
,t.[Order]
from
yourTable t
inner join
yourTable t2 on t2.Person = t.Person
and t2.[Order] = (t.[Order] +1)
where
t2.Event = 'Eyewear'
and t.Event = 'Exam'
I haven't tried to optimize it but this seems to work:
create table t(
person varchar(10),
event varchar(10),
[order] varchar(10)
);
insert into t values
('1','Exam','1'),
('1','Eyewear','2'),
('2','Eyewear','1'),
('2','Exam','2'),
('2','Eyewear','3'),
('3','Exam','1'),
('3','Eyewear','2'),
('4','Eyewear','1'),
('4','Exam','2');
with xxx(person,event_a,seq_a,event_b,seq_b) as (
select a.person,a.event,a.[order],b.event,b.[order]
from t a join t b
on a.person = b.person
and a.[order] < b.[order]
and a.event like 'exam'
and b.event like 'eyewear'
)
select person,event_a event,seq_a [order] from xxx
union
select person,event_b event,seq_b [order] from xxx
order by 1,3

Counting on multiple columns

I have a table like this:
+------------+---------------+-------------+
|store_number|entrance_number|camera_number|
+------------+---------------+-------------+
| 1 | 1 | 1 |
| 1 | 1 | 2 |
| 2 | 1 | 1 |
| 2 | 2 | 1 |
| 2 | 2 | 2 |
| 3 | 1 | 1 |
| 4 | 1 | 1 |
| 4 | 1 | 2 |
| 4 | 2 | 1 |
| 4 | 3 | 1 |
+------------+---------------+-------------+
In summary the stores are numbered 1 and up, the entrances are numbered 1 and up for each store, and the cameras are numbered 1 and up for each entrance.
What I want to do is count how many how many entrances in total, and how many cameras in total for each store. Producing this result from the above table:
+------------+---------------+-------------+
|store_number|entrances |cameras |
+------------+---------------+-------------+
| 1 | 1 | 2 |
| 2 | 2 | 3 |
| 3 | 1 | 1 |
| 4 | 3 | 4 |
+------------+---------------+-------------+
How can I count on multiple columns to produce this result?
You can do this with a GROUP BY and a COUNT() of each item:
Select Store_Number,
Count(Distinct Entrance_Number) as Entrances,
Count(Camera_Number) As Cameras
From YourTable
Group By Store_Number
From what I can tell from your expected output, you're looking for the number of cameras that appear, whilst also looking for the DISTINCT number of entrances.
This will work as well,
DECLARE #store TABLE
( store_number INT,entrance_number INT,camera_number INT)
INSERT INTO #store VALUES(1,1,1),(1,1,2),(2,1,1),(2,2,1),
(2,2,2),(3,1,1),(4,1,1),(4,1,2),(4,2,1),(4,3,1)
SELECT AA.s store_number, BB.e entrances,AA.c cameras FROM (
SELECT s,COUNT(DISTINCT c) c FROM ( SELECT store_number s,
CONVERT(VARCHAR,store_number) + CONVERT(VARCHAR,entrance_number) +
CONVERT(VARCHAR,camera_number) c FROM #store ) A GROUP BY s ) AA
LEFT JOIN
( SELECT s,COUNT(DISTINCT e) e FROM ( SELECT store_number s,
CONVERT(VARCHAR,store_number) + CONVERT(VARCHAR,entrance_number) e
FROM #store ) B GROUP BY s ) BB ON AA.s = BB.s
Hope it helped. :)

Check if relation exists and return true or false

I have 3 tables, Category Step and CategoryStep, where CategoryStep relates the two other tables together. I want to return all categories with a true/false column whether or not the relation exists in CategoryStep based on a StepID.
The schema for the tables is simple,
Category:
CategoryID | CategoryName
Step:
StepID | StepName
CategoryStep:
CategoryStepID | CategoryID | StepID
When trying to get results based on StepID, I only get the relations that exist, and not ones that don't.
SELECT [CategoryID], [Category], CAST(CASE WHEN [CategoryStep].[CategoryStep] IS NULL THEN 0 ELSE 1 END AS BIT) AS related
FROM Category
LEFT JOIN CategoryStep ON Category.CategoryID = CategoryStep.CategoryID
INNER JOIN Step ON CategoryStep.StepID = Step.StepID
WHERE Step.StepID = 2
Step Table:
|StepID | StepName
|-------|---------
| 1 | StepOne
| 2 | StepTwo
| 3 | StepThree
Category Table:
| CategoryID | CategoryName
|------------|-------------
| 1 | Holidays
| 2 | States
| 3 | Cities
| 4 | Animals
| 5 | Food
CategoryStep Table
| CategoryStepID | CategoryID | StepID
|----------------|------------|-------
| 1 | 1 | 1
| 2 | 1 | 2 <--
| 3 | 2 | 1
| 4 | 2 | 3
| 5 | 3 | 2 <--
| 6 | 4 | 1
| 7 | 4 | 2 <--
| 8 | 4 | 3
| 9 | 5 | 1
| 10 | 5 | 3
So, if I was looking for StepID = 2 the result table I am looking for is:
| CategoryID | Category | Related
|------------|----------|--------
| 1 | Holidays | 1
| 2 | States | 0
| 3 | Cities | 1
| 4 | Animals | 1
| 5 | Food | 0
Try replacing the INNER JOIN with a LEFT JOIN.
Update:
The fatal flaw with your original attempt was the WHERE clause. You were performing the correct LEFT JOIN, but the WHERE clause was filtering off category records which did not match. In the query below, I moved the check for step ID into the join condition, where it belongs.
SELECT [CategoryID], [Category],
CAST(CASE WHEN [CategoryStep].[CategoryStep] IS NULL THEN 0 ELSE 1 END AS BIT) AS related
FROM Category
LEFT JOIN CategoryStep
ON Category.CategoryID = CategoryStep.CategoryID AND
CategoryStep.StepCodeID = 2
LEFT JOIN Step
ON CategoryStep.StepID = Step.StepID

Getting Sum of MasterTable's amount which joins to DetailTable

I have two tables:
1. Master
| ID | Name | Amount |
|-----|--------|--------|
| 1 | a | 5000 |
| 2 | b | 10000 |
| 3 | c | 5000 |
| 4 | d | 8000 |
2. Detail
| ID |MasterID| PID | Qty |
|-----|--------|-------|------|
| 1 | 1 | 1 | 10 |
| 2 | 1 | 2 | 20 |
| 3 | 2 | 2 | 60 |
| 4 | 2 | 3 | 10 |
| 5 | 3 | 4 | 100 |
| 6 | 4 | 1 | 20 |
| 7 | 4 | 3 | 40 |
I want to select sum(Amount) from Master which joins to Deatil where Detail.PID in (1,2,3)
So I execute the following query:
SELECT SUM(Amount) FROM Master M INNER JOIN Detail D ON M.ID = D.MasterID WHERE D.PID IN (1,2,3)
Result should be 20000. But I am getting 40000
See this fiddle. Any suggestion?
You are getting exactly double the amount because the detail table has two occurences for each of the PIDs in the WHERE clause.
See demo
Use
SELECT SUM(Amount)
FROM Master M
WHERE M.ID IN (
SELECT DISTINCT MasterID
FROM DETAIL
WHERE PID IN (1,2,3) )
What is the requirement of joining the master table with details when you have all your columns are in Master table.
Also, isnt there any FK relationhsip defined on these tables. Looking at your data it seems to me that there should be FK on detail table for MasterId. If that is the case then you do not need join the table at all.
Also, in case you want to make sure that you have records in details table for the records for which you need sum and there is no FK relationship. Then you could give a try for exists instead of join.