How to query duplicated rows according to column value? - sql

Question

I'm trying to figure out how to duplicate my rows based on the pass and fail column. Below is the table that I've done querying so far.
The code for the query is shown below. I'm querying from a json.
SELECT
to_date(LotSummary ->> 'Start', 'HH24:MI:SS DD/MM/YY')AS "Date",
Machine AS "Machine",
LotSummary ->> 'Pass' AS "Pass",
LotSummary ->> 'Fail' AS "Fail"
FROM
(
SELECT
CASE
WHEN jsonb_typeof(json_data->'OEESummary'->'LotSummary'->'Lot') = 'array'
THEN
jsonb_array_elements(cast(json_data->'OEESummary'->'LotSummary'->'Lot' AS JSONB))
ELSE
json_data->'OEESummary'->'LotSummary'->'Lot'
END
AS LotSummary,
json_data->'OEESummary'->>'MachineID' AS Machine
FROM
(
SELECT
jsonb_array_elements(cast(json_data->>'body' AS JSONB)) AS json_data
FROM data
)t
WHERE
json_data ->> 'file_name' = 'OEE.xml'
)a
WHERE
to_date(LotSummary ->> 'Start', 'HH24:MI:SS DD/MM/YY') IS NOT NULL
So let's say I want to query it as duplicates to separate Pass and Fail values just like:
+----------------------------+--------------+------+------+
| Date | Machine | Pass | Fail |
+----------------------------+--------------+------+------+
| "2019-08-04T16:00:00.000Z" | TRS1000i-082 | 5 | NULL |
| "2019-08-04T16:00:00.000Z" | TRS1000i-082 | NULL | 2 |
| "2019-07-01T16:00:00.000Z" | TRS1000i-001 | 0 | NULL |
| "2019-07-01T16:00:00.000Z" | TRS1000i-001 | NULL | 0 |
| "2019-07-01T16:00:00.000Z" | TRS1000i-001 | 20 | NULL |
| "2019-07-01T16:00:00.000Z" | TRS1000i-001 | NULL | 0 |
+----------------------------+--------------+------+------+
Just in case you need the json formats (Do note it's not the exact one, but the format is correct):
{
"body": [
{
"file_name": "OEE.xml",
"OEESummary": {
"MachineID": "TRS1000i-012",
"LotSummary": {
"Lot": [
{
"#i": "0",
"Start": "14:52:16 15/08/19",
"Pass": "3",
"Fail": "0"
},
{
"#i": "1",
"Start": "15:40:41 15/08/19",
"Pass": "3",
"Fail": "0"
}
]
},
"Utilisation": [
"0:01:42:48",
"19.04%"
],
"MTTR": "--",
"IdleTime": "0:07:16:39",
"MUBA": "57",
"OEE": "60.55%"
}
}
],
"header": {
"json_metadata_revision": "v1.0.0",
"json_metadata_datetime_creation": "14-OCT-2019_14:55:57",
"json_metadata_uuid": "14102019145557_65b425d8-09e5-48ec-be85-e69d9a50d2e3",
"json_metadata_type": "mvst_xml_to_json"
}
}
Do help if you know any techniques I could use to solve this issue. Your help is greatly appreciated! Thank youu.

Answer 1

With your table, you can use a lateral join:
select t.date, t.machine, v.pass, v.fail
from t cross join lateral
(values (t.pass, null), (null, t.fail)) v(pass, fail);
I'm not quite sure what your query has to do with the question. But you can define it as a CTE and then use the results for t.

Answer 2

In the top of your result set , its just union query:
WITH A AS(
Select 1 id , 'TRS1000i-082' as Machine , 5 pass, 2 fail union all
Select 2 id , 'TRS1000i-001' as Machine , 0 pass, 0 fail union all
Select 3 id , 'TRS1000i-001' as Machine , 20 pass, 0 fail
)
SELECT ID
,MACHINE
,pass
,null fail
FROM a
UNION ALL
SELECT ID
,MACHINE
,null pass
,fail fail
FROM a
order by ID