I have data like below
create table #Temp(Id int, FromDate date, ToDate date)
Insert into #Temp
values(1,'9/1/2019','9/1/2019'),
(2,'9/2/2019','9/3/2019'),
(3,'9/2/2019','9/3/2019'),
(4,'9/4/2019','9/6/2019'),
(5,'9/7/2019','9/7/2019')
I am trying to calculate the difference and create days i.e Day 1, Day 2-3 etc...
Expected result
Id FromDate ToDate Display
1 01/09/2019 01/09/2019 Day 1
2 02/09/2019 03/09/2019 Day 2-3
3 02/09/2019 03/09/2019 Day 2-3
4 04/09/2019 06/09/2019 Day 4-6
5 07/09/2019 07/09/2019 Day 7
I have tried below code using datediff, but not sure how to relate to previous row and get the date range
select *, DATEDIFF(DAY,FromDate,ToDate)
from #Temp
Use first_value
select *
, datediff(day, first_value(FromDate) over(order by FromDate), FromDate) + 1
, datediff(day, first_value(FromDate) over(order by FromDate), ToDate) + 1
from #Temp
You can try this if you want exactly the same output
Select
* ,
case
when (FromDate != ToDate)
then
'Day '+ DATEPART(Day,FromDate) + '-' + DATEPART(Day,ToDate)
else
'Day '+ DATEPART(Day,FromDate)
END AS Display
From #Temp
You don't want the previous row's value, you want the earliest fromdate, and then you can compare it to every row.
select id, min (fromdate) over (order by fromdate asc) as earliest_date,fromDate,todate,
datediff(day,min (fromdate) over (order by fromdate asc),fromdate)+1,
datediff(day,min (fromdate) over (order by fromdate asc),todate)+1
from
#temp
Fiddle
Related
Dear Stack Overflow community,
I am looking for the patient id where the two consecutive dates after the very first one are less than 7 days.
So differences between 2nd and 1st date <= 7 days
and differences between 3rd and 2nd date <= 7 days
Example:
ID Date
1 9/8/2014
1 9/9/2014
1 9/10/2014
2 5/31/2014
2 7/20/2014
2 9/8/2014
For patient 1, the two dates following it are less than 7 days apart.
For patient 2 however, the following date are more than 7 days apart (50 days).
I am trying to write an SQL query that just output the patient id "1".
Thanks for your help :)
You want to use lead(), but this is complicated because you want this only for the first three rows. I think I would go for:
select t.*
from (select t.*,
lead(date, 1) over (partition by id order by date) as next_date,
lead(date, 2) over (partition by id order by date) as next_date_2,
row_number() over (partition by id order by date) as seqnum
from t
) t
where seqnum = 1 and
next_date <= date + interval '7' day and
next_date2 <= next_date + interval '7' day;
You can try using window function lag()
select * from
(
select id,date,lag(date) over(order by date) as prevdate
from tablename
)A where datediff(day,date,prevdate)<=7
I have a temp table that has an entityID, a start date, an end date, and number of days. I get the number of days by getting the datediff between start and end dates and +1 day. The problem that I am having is when an entity has a second record that has the same start date as its previous end date, I get the number of days as 1 too many. ie.:
EntityID StartDate EndDate NumOfDays
-------- --------- ------- ---------
3414 02/01/2018 02/02/2018 2
3414 02/02/2018 02/10/2018 9
I need to make the StartDate of the second record to be 02/03/2018 and NumOfDays becomes 8 so that the whole range of days is 10 which would be correct. The temp table is ordered on EntityID, StartDate. There would be thousands of records in the table and maybe a few hundred that has this case. I only need to change the start date if that entity's previous end date is the same.
Should I do a loop? Cursor? Or is there a better way?
We are on SQL Server 2014
First, it seems that you should be calculating the number of days without the end date. That would solve the problem. But, that might not work.
You can use an updatable CTE:
with toupdate as (
select t.*, lag(end_date) over (partition by entityid order by start_date) as prev_end_date
from t
)
update toupdate
set numofdays = numofdays - 1
where prev_end_date = end_date;
Declare #t TABLE (EntityID INT, StartDate DATE, EndDate DATE)
INSERT INTO #t VALUES
(3414 ,'02/01/2018','02/02/2018'),
(3414 ,'02/02/2018','02/10/2018');
WITH x AS (
SELECT t.*
, CASE WHEN LAG(EndDate) OVER (PARTITION BY EntityID ORDER BY StartDate) >= StartDate
THEN DATEADD( DAY , 1 , LAG(EndDate) OVER (PARTITION BY EntityID ORDER BY StartDate))
ELSE StartDate END NewStartDate
FROM #t t
)
SELECT EntityID
, NewStartDate
, EndDate
, DATEDIFF(DAY, NewStartDate , EndDate) + 1 AS NumOfDays
FROM X
I want to get last 3 months name from current month. For example current month is December. So, I want get like this October, November and December.
This is my query:
SELECT CONVERT(CHAR, DATENAME(MONTH, IssueDate)) AS MonthName, ItemId
FROM dbo.Issue AS Issue
GROUP BY CONVERT(CHAR, DATENAME(MONTH, IssueDate)), ItemId
HAVING (ItemId = 427)
This returns:
But, my need is:
N.B. When December month close and January month open then October auto excluded as like (November, December and January)
this link is my Database only 2 table (size-243 KB with Zip) on the google drive https://goo.gl/S4m0R5
Add a date diff in a where clause to filter to the last 3 months, and then order by the month number at the end:
SELECT CONVERT(CHAR, DATENAME(MONTH, [IssueDate])) AS MonthName, ItemId
FROM [dbo].[Issue] AS Issue
WHERE datediff(m, [IssueDate], getdate()) between 0 and 2
GROUP BY CONVERT(CHAR, DATENAME(MONTH, [IssueDate])), ItemId, MONTH(IssueDate)
HAVING (ItemId= 427)
order by MONTH(IssueDate);
You can use DATEADD function:
WHERE IssueDate >= dateadd( month, -2, dateadd( day, -datepart( day, getdate() ) + 1, cast( getdate() as date ) ) )
That will give you IssueDate >= '2015-10-01' given today.
That will also work with index you have on IssueDate, if you start doing something like DATEADD / DATEDIFF etc. on IssueDate then the index can only be scanned end-to-end because it needs to processs all rows in the table so renders the index significantly less effective.
DECLARE #t TABLE
(
IssueDate DATETIME,
ItemId INT
)
INSERT INTO #t (IssueDate, ItemId)
VALUES
('20160105', 427),
('20151212', 427),
('20151213', 427),
('20151110', 427),
('20151001', 427),
('20150905', 427)
SELECT DATENAME(MONTH, dt)
FROM (
SELECT DISTINCT TOP(3) DATEADD(MONTH, DATEDIFF(MONTH, 0, IssueDate), 0) AS dt
FROM #t
WHERE ItemId = 427
ORDER BY dt DESC
) t
results -
------------------------------
January
December
November
You can use a recursive CTE to get month names for the last 12 months and then limit it to the last 3 month names in the second part of the query:
;WITH months(MonthNumber) AS
(
SELECT 0
UNION ALL
SELECT MonthNumber+1
FROM months
WHERE MonthNumber < 12
)
SELECT DATENAME(MONTH,DATEADD(MONTH,-MonthNumber,GETDATE())) AS [month]
FROM dbo.Issue AS Issue
CROSS JOIN months m
WHERE m.MonthNumber <3
GROUP BY DATENAME(MONTH,DATEADD(MONTH,-MonthNumber,GETDATE())) , ItemId
HAVING (ItemId = 427)
I have a table, part of which is given below. It contain multiple values (durations) per day. I need two things 1) addition of durations per day. 2) plotting them on calendar in such a way that startdate is first_date from the table and last_date is Last_update from the table. I want to mention 0 for which date there is no duration. I think it will something like below but need help.
;WITH AllDates AS(
SELECT #Fromdate As TheDate
UNION ALL
SELECT TheDate + 1
FROM AllDates
WHERE TheDate + 1 <= #ToDate
)SELECT UserId,
TheDate,
COALESCE(
SUM(
-- When the game starts and ends in the same date
CASE WHEN DATEDIFF(DAY, GameStartTime, GameEndTime) = 0
Here is what I am looking for
Another way to generate the date range you are after would be something like .....
;WITH DateLimits AS
(
SELECT MIN(First_Date) FirstDate
,MAX(Last_Update) LastDate
FROM TableName
),
DateRange AS
(
SELECT TOP (SELECT DATEDIFF(DAY,FirstDate,LastDate ) FROM DateLimits)
DATEADD(DAY
,ROW_NUMBER() OVER (ORDER BY (SELECT NULL))
, (SELECT FirstDate FROM DateLimits)
) AS Dates
FROM master..spt_values a cross join master..spt_values b
)
SELECT * FROM DateRange --<-- you have the desired date range here
-- other query whatever you need.
I have data like below:
StartDate EndDate Duration
----------
41890 41892 3
41898 41900 3
41906 41907 2
41910 41910 1
StartDate and EndDate are respective ID values for any dates from calendar. I want to calculate the sum of duration for consecutive days. Here I want to include the days which are weekends. E.g. in the above data, let's say 41908 and 41909 are weekends, then my required result set should look like below.
I already have another proc that can return me the next working day, i.e. if I pass 41907 or 41908 or 41909 as DateID in that proc, it will return 41910 as the next working day. Basically I want to check if the DateID returned by my proc when I pass the above EndDateID is same as the next StartDateID from above data, then both the rows should be clubbed. Below is the data I want to get.
ID StartDate EndDate Duration
----------
278457 41890 41892 3
278457 41898 41900 3
278457 41906 41910 3
Please let me know in case the requirement is not clear, I can explain further.
My Date Table is like below:
DateId Date Day
----------
41906 09-04-2014 Thursday
41907 09-05-2014 Friday
41908 09-06-2014 Saturdat
41909 09-07-2014 Sunday
41910 09-08-2014 Monday
Here is the SQL Code for setup:
CREATE TABLE Table1
(
StartDate INT,
EndDate INT,
LeaveDuration INT
)
INSERT INTO Table1
VALUES(41890, 41892, 3),
(41898, 41900, 3),
(41906, 41907, 3),
(41910, 41910, 1)
CREATE TABLE DateTable
(
DateID INT,
Date DATETIME,
Day VARCHAR(20)
)
INSERT INTO DateTable
VALUES(41907, '09-05-2014', 'Friday'),
(41908, '09-06-2014', 'Saturday'),
(41909, '09-07-2014', 'Sunday'),
(41910, '09-08-2014', 'Monday'),
(41911, '09-09-2014', 'Tuesday')
This is rather complicated. Here is an approach using window functions.
First, use the date table to enumerate the dates without weekends (you can also take out holidays if you want). Then, expand the periods into one day per row, by using a non-equijoin.
You can then use a trick to identify sequential days. This trick is to generate a sequential number for each id and subtract it from the sequential number for the dates. This is a constant for sequential days. The final step is simply an aggregation.
The resulting query is something like this:
with d as (
select d.*, row_number() over (order by date) as seqnum
from dates d
where day not in ('Saturday', 'Sunday')
)
select t.id, min(t.date) as startdate, max(t.date) as enddate, sum(duration)
from (select t.*, ds.seqnum, ds.date,
(d.seqnum - row_number() over (partition by id order by ds.date) ) as grp
from table t join
d ds
on ds.date between t.startdate and t.enddate
) t
group by t.id, grp;
EDIT:
The following is the version on this SQL Fiddle:
with d as (
select d.*, row_number() over (order by date) as seqnum
from datetable d
where day not in ('Saturday', 'Sunday')
)
select t.id, min(t.date) as startdate, max(t.date) as enddate, sum(duration)
from (select t.*, ds.seqnum, ds.date,
(ds.seqnum - row_number() over (partition by id order by ds.date) ) as grp
from (select t.*, 'abc' as id from table1 t) t join
d ds
on ds.dateid between t.startdate and t.enddate
) t
group by grp;
I believe this is working, but the date table doesn't have all the dates in it.