Please take this as an example where my primary table is
ID Name
-- -------
1 Alpha
2 Beta
3 Beta
4 Beta
5 Charlie
6 Charlie
as there is duplication in Name column. Resultant Table after grouping them by name, with count column is -
Name Count
------- -----
Alpha 1
Beta 3
Charlie 2
SUM 6
Here SUM is taken out as separate row of all the resultant COUNT column, I am trying to get SUM of all the rows from the resultant Count function from primary table but as separate query for SUM unlike separate row
My table has 2 fields Roles and User_Id.
I have already tried Below query
select orl.role ,
SUM (orl.role) as "No of Users"
from org_user_roles orl
group by orl.role
i think this is a string column with numerical values. So need to cast it to int before performing the sum() operation
select orl.role,
sum(orl.user_id::int) as "No of Users"
from org_user_roles orl
group by orl.role
If you want to count rows (users) for each role, use the COUNT aggregate function - not SUM:
select "role", count(*) as "No of Users" from org_user_roles group by "role";
To get the sum of these grouped counts - which is just the overall row count - use:
select count(*) as "Sum" from org_user_roles;
Related
hi im new to sql and trying to understand how to work with data structures. I have a table
fact.userinteraction
interactionuserkey visitdatecode
0 20220404
1 20220404
5 20220402
5 20220128
If the interaction userkey number repeats then, i want a column called number of visits. in this case, for interactionuserkey 5, there are 2 total visits since its repeated twice. for interactionuserkey 0, number of visits =1 and so on. Basically, sum duplicates in column 1 and give total count AS number of visits. How do i do this?
In sql, it's resolved using basic aggregation
select interactionuserkey, count(*)
from your_table
group by interactionuserkey
I am querying a Presto table where I want to calculate what percentage of the total a certain subset of the rows account for.
Consider a table like this:
id
m
1
5
1
7
2
9
3
8
I want to query to report how much of the total measure (m) is contributed by each id. In this example, the total of the measure column is 29 can I find it with a query like...
SELECT SUM("m") FROM t;
output:
sqlite> SELECT SUM("m") FROM t;
29
Then I want to subtotal by id for some of the ids like
SELECT "id", SUM("m") AS "sub_total" FROM t WHERE "id" IN ('1','3') GROUP BY id;
output:
sqlite> SELECT "id", SUM("m") AS "sub_total" FROM t WHERE "id" IN ('1','3') GROUP BY id;
1|12
3|8
Now I want to add a third column where the subtotals are divided by the grand total (29) to get the percentage for each selected id.
I tried:
sqlite>
WITH a AS (
SELECT SUM("m") AS g FROM t )
SELECT "id", SUM("m") AS "sub_total", SUM(m)*100/"a"."g"
FROM a, t
WHERE "t"."id" IN ('1','3') GROUP BY "t"."id";
output:
1|12|41
3|8|27
Which is all good in SQLLite3! But when I translate this to my actual Presto DB (and the right tables and columns), I get this error:
presto error: line 10:5: 'a.g' must be an aggregate expression or appear in GROUP BY clause
I can't understand what I'm missing here or why this would be different in Presto.
When you have a GROUP BY in your query, all expressions that the query is returning must be either:
the expression you are grouping by
or aggregate function
For example if you do GROUP BY id, the resulting query will return one row per id - you cannot just use m, because with id = 1 there are two values: 5 and 7 - so what should be returned? First value, last, sum, average? You need to tell it using aggregate function like sum(m).
Same with a.g - you need to add it to GROUP BY.
WITH a AS (
SELECT SUM("m") AS g FROM t )
SELECT "id", SUM("m") AS "sub_total", SUM(m)*100/"a"."g"
FROM a, t
WHERE "t"."id" IN ('1','3') GROUP BY "t"."id", "a"."g";
There's nothing special about PrestoDB here, it's more SQLite that's less strict, actually most other database engines would complain about your case.
I have some data like this as shown below:
Acc_Id || Row_No
1 1
2 1
2 2
2 3
3 1
3 2
3 3
3 4
and I need a query to get the results as shown below:
Acc_Id || Row_No
1 1
2 3
3 4
Please consider that I'm a beginner in SQL.
I assume you want the Count of the row
SELECT Acc_Id, COUNT(*)
FROM Table
GROUP BY Acc_Id
Try this:
select Acc_Id, MAX(Row_No)
from table
group by Acc_Id
As a beginner then this is your first exposure to aggregation and grouping. You may want to look at the documentation on group by now that this problem has motivated your interest in a solutions. Grouping operates by looking at rows with common column values, that you specify, and collapsing them into a single row which represents the group. In your case values in Acc_Id are the names for your groups.
The other answers are both correct in the the final two columns are going to be equivalent with your data.
select Acc_Id, count(*), max(Row_No)
from T
group by Acc_Id;
If you have gaps in the numbering then they won't be the same. You'll have to decide whether you're actually looking for a count of rows of a maximum of a value within a column. At this point you can also consider a number of other aggregate functions that will be useful to you in the future. (Note that the actual values here are pretty much meaningless in this context.)
select Acc_Id, min(Row_No), sum(Row_No), avg(Row_No)
from T
group by Acc_Id;
I am not good in SQL raw queries. Please help to get Min Max value grouped by the user_id.
Scenario is:
Table has multiple values in column "B" against user_id and i want to out put the column "B" twice as Min/Max in single output. Required output will looks like:
User_id, MaxB, MinB
1 5 2
2 10 3
Consider the Table has 5 entries for both user(1, 2) but the out put prints it as a single row with max and min of B. Thanks in advance. Suggest the link if i am repeating this question as i was unable to find the solution.
Select Max(B) as MAXB, Min(B) as MinB, User_ID
from TableName
group by User_ID
I'm having trouble using COUNT in SQL...The following query returns two rows, but then returns the raps column as 137. So I believe it's counting the total number of operation_id columns in the dataset instead of from the results.
Is there any way to make it count only the columns from the results, so that raps returns as 1 in each of the columns? I would then use PHP to add them together.
//Query
SELECT DISTINCT hrap_id,
operation_id,
COUNT (operation_id) AS raps,
operation_type
FROM view_rappels
WHERE year = '2013' AND crew_id = '4'
GROUP BY hrap_id, operation_type, operation_id
//Results
10.00 702020000.00 137.00 operational
1.00 702020000.00 137.00 operational
You need to put DISTINCT inside of the count function like so
COUNT(DISTINCT operation_id) AS raps