Outline returned by View.GetOutline() method does not quite correspond to the visible drawing - it returns a bit more than the selection outline shown by SolidWorks GUI.
The screenshot below shows the selection outline (light blue dotted rectangle) and diagonal of the outline returned by View.GetOutline() (red line):
Is there a way to get bounding box that corresponds to the actually visible drawing?
Note: Original title of this question was "Is there an alternative to View.GetOutline() which does NOT include Temporary Axes?", however I discovered that View.GetOutline() actually does not include Temporary Axes. The problem was in the View.Position property which defines center bounding box that includes Temporary Axes.
Artem's answer was quite useful so I decided to change the question to correspond to the answer and post a new question for the actual problem.
You can get the bounding box from underlying model via IPartDoc::GetBox/IAssemblyDoc::GetBox API and transform this to a view space via IView::ModelToViewTransform as shown in this example.
You will only need the following portion of code form the DrawBBoxDiagonal function if you do not want to draw the diagonal. The values of vStartPt and vEndPt are the end points of bounding box.
Dim vBox As Variant
Dim swViewTransform As SldWorks.MathTransform
Dim swMathPt As SldWorks.MathPoint
Dim vStartPt As Variant
Dim vEndPt As Variant
vBox = GetViewRefModelBBox(view)
Set swViewTransform = GetViewToSheetTransform(draw, view)
Dim swMathUtils As SldWorks.MathUtility
Set swMathUtils = swApp.GetMathUtility
Dim dPt(2) As Double
dPt(0) = vBox(0): dPt(1) = vBox(1): dPt(2) = vBox(2)
Set swMathPt = swMathUtils.CreatePoint(dPt)
Set swMathPt = swMathPt.MultiplyTransform(swViewTransform)
vStartPt = swMathPt.ArrayData
dPt(0) = vBox(3): dPt(1) = vBox(4): dPt(2) = vBox(5)
Set swMathPt = swMathUtils.CreatePoint(dPt)
Set swMathPt = swMathPt.MultiplyTransform(swViewTransform)
vEndPt = swMathPt.ArrayData
I would also recommend to get precise bounding box via IBody2::GetExtremePoint as shown here
Related
I want to take a screenshot of a RichTextBox using the following code.
The problem is it takes a screenshot of another part of the Form:
Dim memoryImage As Bitmap
Dim myGraphics As Graphics = Me.CreateGraphics()
Dim s As Size = RichTextBox2.Size
memoryImage = New Bitmap(s.Width, s.Height, myGraphics)
Dim memoryGraphics As Graphics = Graphics.FromImage(memoryImage)
memoryGraphics.CopyFromScreen(RichTextBox2.Bounds.X, RichTextBox2.Bounds.Y, 0, 0, s)
memoryImage.Save(audiooutputfolder & name & ".png")
Graphics.CopyFromScreen() requires that you specify screen coordinates.
You can transform local coordinates into screen coordinates using the Control.RectangleToScreen() and Control.PointToScreen() methods.
Other methods do the opposite, see the Docs.
To compute the client area of a Control in screen coordinates, you can use its RectangleToScreen() method and pass the value of the ClientRectangle property:
Dim clientRectToScreen = [Control].RectangleToScreen([Control].ClientRectangle)
To include the non-client area (e.g., the borders of a Control, including the Scrollbars, if any), you need the screen coordinates of its Bounds.
There are different ways to do this. A simple method is to ask the Parent of a Control to get them, passing to the Parent's RectangleToScreen() method the Bounds of a child Control.
If you want to print a Form, which is a Top-Level Control, so it has no Parent, just use its Bounds directly: these measures already express screen coordinates.
It's shown in the ControlToBitmap() method:
Private Function ControlToBitmap(ctrl As Control, clientAreaOnly As Boolean) As Bitmap
If ctrl Is Nothing Then Return Nothing
Dim rect As Rectangle
If clientAreaOnly Then
rect = ctrl.RectangleToScreen(ctrl.ClientRectangle)
Else
rect = If(ctrl.Parent Is Nothing, ctrl.Bounds, ctrl.Parent.RectangleToScreen(ctrl.Bounds))
End If
Dim img As New Bitmap(rect.Width, rect.Height)
Using g As Graphics = Graphics.FromImage(img)
g.CopyFromScreen(rect.Location, Point.Empty, img.Size)
End Using
Return img
End Function
To take a screenshot of a Control, call this method, passing the Control you want to print to a Bitmap and specify whether you just want its content (the client area) or you want to include the non-client area (for example, if the control to print is a Form, you want to include the Caption and borders).
Important: use Path.Combine() to build a path:
Path.Combine(audiooutputfolder, $"{imageName}.png"
if string interpolation is not available ($"{variable} other parts"), you can glue the file extension to the file name:
Path.Combine(audiooutputfolder, imageName & ".png")
' Get the screenshot, client area only
Dim controlImage = ControlToBitmap(RichTextBox2, True)
' Save the image to the specified Path using the default PNG format
controlImage.Save(Path.Combine(audiooutputfolder, $"{imageName}.png"), ImageFormat.Png)
' [...] when done with the bitmap
controlImage.Dispose()
Side note:
If your app is not DpiAware, you may get wrong screen coordinates.
See these notes about this.
I have small problem, does anyone know how to change position of existing dimensions and Notes in Part/Product using short macro.
I will shortly describe what I want to do and what kind of problem I have.
I have simple model (let say rectangle)
Inside this model I have dimensions and annotations created in FTA.
Next step is to drastically change position of this model (base model in point 0,0,0 and I want tochange it position to 150,10000,80 + rotation)
during this change some dimensions and annotations (Theirs position in 3D) are not fully following after geometry.
Because of that I would like to have simple macro to create new position of my dimensions and annotations after part update.
I have performed some simple tests code bellow
What I have noticed, when I set new position of the text:
Theoretically text change position but in 3D it stays in old position.
When edit my text by double click on it and then click OK my text translates to new position which was set in macro earlier. The same situation is when I would like to change frame of the text or content (I had AAA and I would like to have BBB), it's changes only when I open Text editor.
Set part1 = CATIA.ActiveDocument
Set Selection = part1.Selection
Set VisPropertySet = Selection.VisProperties
Selection.Search ("name='Text.1',all")
' get selected annotation here
Dim anAnnotation As Annotation
Set anAnnotation = CATIA.ActiveDocument.Selection.Item(1).Value
' get annotation on the DrawingText interface
Dim txtAnnotation As DrawingText
Set txtAnnotation = anAnnotation.Text.Get2dAnnot()
' get TPS view that contains annotation on the DrawingView interface
Dim vwTPSView As DrawingView
Set vwTPSView = txtAnnotation.Parent.Parent
' get coordinates on a view
Dim dX ' as Double
txtAnnotation.X = 0
txtAnnotation.Y = 30
txtAnnotation.FrameType = catEllipse
part1.Update
End Sub
Generally using Part.Update refreshes the annotation's position and text but you can also use:
Dim anAnnotation As Annotation
'Code here
anAnnotation.ModifyVisu 'This should work for both Texts and Dimensions
But if the above method does not work, you can try reseting the text on the annotation (It will work only for texts, and not for dimensions)
Dim vwTPSView As DrawingView
'Code here
vwTPSView.Text = vwTPSView.Text
Be carefull with this last methos though. If your text has any parameters or variables inside it, replacing the text will clear it.
I use the following VB.NET (VSTO) code to add a shape in MS-Word,
Dim app As Word.Application = Globals.ThisAddIn.Application
Dim doc As Word.Document = app.ActiveDocument
Dim left As Single = CSng(Convert.ToDouble(app.Selection.Information(Word.WdInformation.wdHorizontalPositionRelativeToPage)))
Dim top As Single = CSng(Convert.ToDouble(app.Selection.Information(Word.WdInformation.wdVerticalPositionRelativeToPage)))
Dim shape As Word.Shape = doc.Shapes.AddShape(1, left, top, 225.1F, 224.5F)
shape.Fill.BackColor.RGB = ColorTranslator.ToOle(Color.Transparent)
shape.Fill.Visible = Microsoft.Office.Core.MsoTriState.msoFalse
shape.Fill.Transparency = 0.0F
shape.Line.Transparency = 0.0F
shape.Line.Visible = Microsoft.Office.Core.MsoTriState.msoFalse
What this code does is, it adds a rectangle shape at cursor point and makes it transparent (both background and line).
Now I like to change the absolute positions' type. To explain further, when you select the rectangle shape, then if you select the Ribbon tab Format > Position > More Layout Options... as shown in the image below,
It will open the following dialog,
In the above dialog I like to change Column and Paragraph marked by the red rectangles into the type Margin. How to do this by code?
Word provides a Macro recorder. You may use it to get the code generated for you in the background. Thus, you will find what properties and methods exactly should be used to get the job done. See Record or run a macro for more information.
The solution to this was solved in the link below,
https://social.msdn.microsoft.com/Forums/vstudio/en-US/e69584d7-24fe-4396-9a82-26b7dae02584/word-vsto-change-the-absolute-positions-type?forum=vsto
I am creating an add-in using VB.NET VSTO for MS-Word. In this program I need to retrieve the details such as Location (Left, Top) and Size (Height, Weight) of all the images on the document. I also want to retrieve the page number where the image is located. I use the following code,
Dim i As Integer
For i = 1 To Globals.ThisAddIn.Application.ActiveDocument.InlineShapes.Count
If Globals.ThisAddIn.Application.ActiveDocument.InlineShapes(i).Type = Word.WdInlineShapeType.wdInlineShapePicture Then
strHeight = Globals.ThisAddIn.Application.ActiveDocument.InlineShapes(i).ScaleHeight()
strWidth = Globals.ThisAddIn.Application.ActiveDocument.InlineShapes(i).ScaleWidth()
End If
Next i
However, this can only retrieve the Size (Height, Weight). How to get the Location (Left, Top) and page number of the image?
By its very nature, an InlineShape doesn't have a positionable top and left. It's, well, inline, which means it exists in the text layer of the document and the location floats depending on the text and/or other content before it. If the item is on page 2, and you insert 25 lines of text or another picture before InlineShape(i), said shape will float down to page 3 (or 4 or whatever.)
The height and width ARE accessible, simply by using .Height and .Width. ScaleHeight and ScaleWidth are properties that reflect the size of the object in the document relative to the original size of the object. You probably want to store the height and width as strings, though, since the property returns a single (numeric) value. For height and width:
Dim i As Integer
Dim shp as InlineShape
For i = 1 To Globals.ThisAddIn.Application.ActiveDocument.InlineShapes.Count
shp = Globals.ThisAddIn.Application.ActiveDocument.InlineShapes(i)
If shp.Type = Word.WdInlineShapeType.wdInlineShapePicture Then
strHeight = shp.Height.ToString()
strWidth = shp.Width.ToString()
End If
Next i
To get the page number, you have to reference the range of the InlineShape.
shp.Range.get_Information(Word.WdInformation.wdActiveEndPageNumber)
You can also get the top and left position of the image (although it might not do you any good, depending on why you want it). The get_Information method also has wdHorizontalPositionRelativeToPage and wdVerticalPositionRelativeToPage
I am trying to generate a few hundred basic graphics where the shape text and background color is based on a text string.
For this i have chosen to use PowerPoint, because i feel that the image styling is quite comprehensive for my function. The only program that i know how to do this is Adobe Photoshop, however i do not have that software.
I have got the export image function to work, however the image quality of the exported graphic is terrible
How could i get this done with a better image processor?
As can be seen, i have a powerpoint slide with a textbox to hold the stringvalues (Rectangle 5) and my "shape" which will be styled by the two RGB values in the text string.
the string value has the following format (pipe delimited)
Textbox 4.Name | Rounded Rectangle 7.Color | Rounded Rectangle 3.Color
Code used:
Private Sub btnProcess_Click()
Dim i As Integer
Dim StringsArray As Variant
Dim StringItems As Variant
' Call getlines to break all lines into separate records in stringsarray
StringsArray = getlines()
For i = 0 To UBound(StringsArray)
StringItems = Split(StringsArray(i), "|")
ActivePresentation.Slides("Slide1").Shapes("TextBox 4").TextFrame.TextRange.Text = StringItems(0)
ActivePresentation.Slides("Slide1").Shapes("Rounded Rectangle 7").Fill.ForeColor.RGB = StringItems(1)
ActivePresentation.Slides("Slide1").Shapes("Rounded Rectangle 3").Fill.ForeColor.RGB = StringItems(2)
ActivePresentation.Slides("Slide1").Shapes("Group 6").Export "C:\temp\file.emf", ppShapeFormatEMF, 150, 150, ppRelativeToSlide
Next i
End Sub
Function getlines() As Variant
Dim mylines As Variant
Dim mytext As String
mytext = ActivePresentation.Slides("Slide1").Shapes("Rectangle 5").TextFrame.TextRange.Text
mylines = Split(mytext, vbCr)
getlines = mylines
End Function
The vector graphics based PPT object as seen on the PowerPoint slide is not affected by the scale so at all zoom level the object will not appear distorted.
I could not find a way to output the object graphic as a true Metafile even the ppShapeFormatEMF format does not generate a vector based EMF, just a much larger image.
My best solution at the end, was to increase the base size of the PPT object and export the shape object using the ppShapeFormatPNG format thereby increasing the level of detail of the image.
Kinda Obvious.