Need to write a sql function that takes two different integers with the same length (same amount of digits) as arguments: one lower threshold and one upper threshold.
And the function should return a vector with all whole numbers between the two thresholds - but to reduce the array length, your function is supposed to return a wildcard character instead of the digits where possible.
Example: output of the function for a lower threshold L = 3778 and an upper threshold U = 9423
To further clarify, the line in the example showing 941* has one digit replaced by the wild card character and hence represents all values from 9410 - 9419
The line in the example showing 93* has two digits replaced by the wildcard character and represents all values from 9300 - 9399
And so on.
9423
9422
9421
9420
941*
93*
.
378*
3779
3778
Related
I have a column with numbers with various lengths such as 50055, 1055,155 etc. How can I add a decimal before the last 2nd place of each so that it would be 500.55, 10.55, and 1.55?
I tried using replace by finding the last 2 numbers and replace it with .||last 2 number. That doesn't always work because of a possibility of multiple repetition of the same sequence in the same string.
replace(round(v_num/2),substr(round(v_num/2),-2),'.'||substr(round(v_num/2),-2))
You would divide by 100:
select v_num / 100
You can convert this into a string, if you want.
I have input comprising five character upper-case English letters e.g ABCDE and I need to convert this into two character unique ASCII output.
e.g. ABCDE and ZZZZZ should both give two different outputs
I have converted from ABCDE into hex which gives me 4142434445, but from this can I get to a two character output value I require?
Example:
INPUT1 = ABCDE
Converted to hex = 4142434445
INPUT2 = 4142434445
OUTPUT = ?? Any 2 ASCII Characters
Other examples of INPUT1 =
BIRAL
BRMAL
KLAAX
So you're starting with a 5-digit base-26 number, and you want to squeeze that into some 2-digit scheme with base n?
All possible 1-5 digit base-26 numbers gives you a number space of 26^5 = 11,881,376.
So you want the minimum n where n^2 >= 11,881,376.
Which gives you 3446.
Now it's up to you to go and find a suitable glyph block somewhere in UTF where you can reliably block-out 3446 separate characters to act as your new base/alphabet. And construct a mapping from your 5-char base-26 ABCDE type number onto your 2-char base-3446 wierd-glyph number. Good luck with that.
There's not enough variety in ASCII to do this, since it's only 128 printable characters. Limiting yourself to 2-chars of ASCII means you can only address a number space of 16384.
I'm trying to emulate a function in SQL that a client has produced in Excel. In effect, they have a unique, 10-digit numeric value (VARCHAR) as the primary key in one of their enterprise database systems. Within another database, they require a unique, 5-digit alphanumeric identifier. They want that 5-digit alphanumeric value to be a representation of the 10-digit number. So what they did in excel was to split the 10-digit number into pairs, then convert each of those pairs into a hexadecimal value, then stitch them back together.
The EXCEL equation is:
=IF(VALUE(MID(A2,1,4))>0,DEC2HEX(VALUE(MID(A2,3,2)))&DEC2HEX(VALUE(MID(A2,5,2)))&DEC2HEX(VALUE(MID(A2,7,2)))&DEC2HEX(VALUE(MID(A2,9,2))),DEC2HEX(VALUE(MID(A2,5,2)))&DEC2HEX(VALUE(MID(A2,7,2)))&DEC2HEX((VALUE(MID(A2,9,2)))))
I need the SQL equivalent of this. Of course, should someone out there know a better way to accomplish their goal of "a 5-digit alphanumeric identifier" based off the 10-digit number, I'm all ears.
ADDED 8/2/2011
First of all, thank you to everyone for the replies. Nice to see folks willing to help and even enjoying it! Based on all the responses, I'm apt to tell my client they're intent is sound, only their method is off kilter. I'd also like to recommend a solution. So the challenge remains, just modified slightly:
CHALLENGE: Within SQL, take a 10 digit, unique NUMERIC string and represent it ALPHANUMERICALLY in as few characters as possible. The resulting string must also be unique.
Note that the first 3-4 characters in the 10-digit string are likely to be zeros, and that they could be stripped to shorten the resulting alphanumeric string. Not required, but perhaps helpful.
This problem is inherently impossible. You have a 10 digit numeric value that you want to convert to a 5 digit alphanumeric value. Since there are 10 numeric characters, this means that there are 10^10 = 10 000 000 000 unique values for your 10 digit number. Since there are 36 alphanumeric characters (26 letters + 10 numbers), there are 36^5 = 60 466 176 unique values for your 5 digit number. You cannot map a set of 10 billion elements into a set with around 60 million.
Now, lets take a closer look at what your client's code is doing:
So what they did in excel was to split the 10-digit number into pairs, then convert each of those pairs into a hexadecimal value, then stitch them back together.
This isn't 100% accurate. The excel code never uses the first 2 digits, but performs this operation on the remaining 8. There are two main problems with this algorithm which may not be intuitively obvious:
Two 10 digit numbers can map to the same 5 digit number. Consider the numbers 1000000117 and 1000001701. The last four digits of 1000000117 get mapped to 1 11, where the last four digits of 1000001701 get mapped to 11 1. This causes both to map to 00111.
The 5 digit number may not even end up being 5 digits! For example, 1000001616 gets mapped to 001010.
So, what is a possible solution? Well, if you don't care if that 5 digit number is unique or not, in MySQL you can use something like:
hex(<NUMERIC VALUE> % 0xFFFFF)
The log of 10^10 base 2 is 33.219280948874
> return math.log(10 ^ 10) / math.log(2)
33.219280948874
> = 2 ^ 33.21928
9999993422.9114
So, it takes 34 bits to represent this number. In hex this will take 34/4 = 8.5 characters, much more than 5.
> return math.log(10 ^ 10) / math.log(16)
8.3048202372184
The Excel macro is ignoring the first 4 (or 6) characters of the 10 character string.
You could try encoding in base 36 instead of 16. This will get you to 7 characters or less.
> return math.log(10 ^ 10) / math.log(36)
6.4254860446923
The popular base 64 encoding will get you to 6 characters
> return math.log(10 ^ 10) / math.log(64)
5.5365468248123
Even Ascii85 encoding won't get you down to 5.
> return math.log(10 ^ 10) / math.log(85)
5.1829075929158
You need base 100 to get to 5 characters
> return math.log(10 ^ 10) / math.log(100)
5
There aren't 100 printable ASCII characters, so this is not going to work, as zkhr explained as well, unless you're willing to go beyond ASCII.
I found your question interesting (although I don't claim to know the answer) - I googled a bit for you out of interest and found this which may help you http://dpatrickcaldwell.blogspot.com/2009/05/converting-decimal-to-hexadecimal-with.html
I've found two parameters defined like these:
&TM_PERIOD+4&/&TM_PERIOD(4)&
It's to pass data from a database to a form.
If the format of the data would be DDMMYYYY what are differences between those two parameters?
if TM_PRIOD is in form of DDMMYYYY then
TM_PERIOD(4) equals DDMM
TM_PERIOD+4 equals YYYY
the (4) means 4 characters
the +4 means after the 4th character
TM_PERIOD+1(2) = DM
(2 characters after the first)
These are not bit operations. +n specifies a string offset and (n) specifies the length.
They can be used independently of each other as well, so you can use just +n or just (n).
So:
data: lv_text(20) type c.
lv_text = "Hello".
write: / lv_text+2(3).
would output 'llo', for example.
I am writing a custom totaling method for a grid view. I am totaling fairly large numbers so I'd like to use a decimal to get the total. The problem is I need to control the maximum length of the total number. To solve this problem I started using float but it doesn't seem to support large enough numbers, I get this in the totals column(1.551538E+07). So is there some formating string I can use in .ToString() to guarentee that I never get more then X characters in the total field? Keep in mind I'm totaling integers and decimals.
If you're fine with all numbers displaying in scientific notation, you could go with "E[numberOfDecimalPlaces]" as your format string.
For example, if you want to cap your strings at, say, 12 characters, then, accounting for the one character for the decimal point and five characters needed to display the exponential part, you could do:
Function FormatDecimal(ByVal value As Decimal) As String
If value >= 0D Then
Return value.ToString("E5")
Else
' negative sign eats up another character '
Return value.ToString("E4")
End If
End Function
Here's a simple demo of this function:
Dim d(5) As Decimal
d(0) = 1.203D
d(1) = 0D
d(2) = 1231234789.432412341239873D
d(3) = 33.3218403820498320498320498234D
d(4) = -0.314453908342094D
d(5) = 000032131231285432940D
For Each value As Decimal in d
Console.WriteLine(FormatDecimal(value))
Next
Output:
1.20300E+000
0.00000E+000
1.23123E+009
3.33218E+001
-3.1445E-001
3.21312E+016
You could use Decimal.Round, but I don't understand the exact question, it sounds like you're saying that if the total adds up to 12345.67, you might only want to show 4 digits and would then show 2345 or do you just mean that you want to remove the decimals?