add ordering column in sql oracle - sql

I have to do in sql oracle a time scheduling query. For each employee, I have to show which day he is working or not. Sometimes the person can have a work schedule on two weeks. For example in week 1 he doesn't work Monday, Tuesday and Friday and the week 2 he doesn't work at Monday and Friday.
I already get the query but sometimes the result doesn't start at Monday.
I want to add a weeknumber so I am able to order. Example:
empl date day_nbr Working
1 01/11/2017 3 FULLDAY
1 02/11/2017 4 FULLDAY
1 03/11/2017 5 OFF
1 04/11/2017 6 OFF
1 05/11/2017 7 OFF
1 06/11/2017 1 OFF
1 07/11/2017 2 FULLDAY
1 08/11/2017 3 FULLDAY
1 09/11/2017 4 FULLDAY
1 10/11/2017 5 OFF
1 11/11/2017 6 OFF
1 12/11/2017 7 OFF
1 13/11/2017 1 OFF
1 14/11/2017 2 OFF
2 01/09/2018 6 OFF
2 02/09/2018 7 OFF
2 03/09/2018 1 FULLDAY
2 04/09/2018 2 FULLDAY
2 05/09/2018 3 OFF
2 06/09/2018 4 FULLDAY
2 07/09/2018 5 FULLDAY
For empl=1 you see the week begins at day_nbr 3. I want to add a column weeknumber so I have following result:
empl date day_nbr Working weeknumber
1 01/11/2017 3 FULLDAY 1
1 02/11/2017 4 FULLDAY 1
1 03/11/2017 5 OFF 1
1 04/11/2017 6 OFF 1
1 05/11/2017 7 OFF 1
1 06/11/2017 1 OFF 2
1 07/11/2017 2 FULLDAY 2
1 08/11/2017 3 FULLDAY 2
1 09/11/2017 4 FULLDAY 2
1 10/11/2017 5 OFF 2
1 11/11/2017 6 OFF 2
1 12/11/2017 7 OFF 1
1 13/11/2017 1 OFF 1
1 14/11/2017 2 OFF 1
2 01/09/2018 6 OFF 1
2 02/09/2018 7 OFF 1
2 03/09/2018 1 FULLDAY 1
2 04/09/2018 2 FULLDAY 1
2 05/09/2018 3 OFF 1
2 06/09/2018 4 FULLDAY 1
2 07/09/2018 5 FULLDAY 1
In that way I can order on weeknumber, day_nbr and I will always start at day_nbr 1.
The reason I want to do that is to be able to make a pivot table like this for empl=1
But the problem I get this:

Related

Period and Quarter Sequence

I'm trying to find a way to do a sequence for date periods and quarters(not sure if this is the correct term).
Basically this will help people to navigate dates based on weeks, periods, and quarters once I join this to our sales data. For example, if I just want to know the sales from last week, I could just use WHERE WeekSequence = -1... Another example is, a manager wants to get the sales data for the past quarter, I could just use WHERE QuarterSequence = -1... something like that.
My current table:
WeekStartDate WeekEndDate CurrentWeek Period Quarter WeekSequence
----------------------------------------------------------------------
2020-08-03 2020-08-09 0 2 1 -5
2020-08-10 2020-08-16 0 2 1 -4
2020-08-17 2020-08-23 0 2 1 -3
2020-08-24 2020-08-30 0 2 1 -2
2020-08-31 2020-09-06 0 2 1 -1
2020-09-07 2020-09-13 1 3 1 0
2020-09-14 2020-09-20 0 3 1 1
2020-09-21 2020-09-27 0 3 1 2
2020-09-28 2020-10-04 0 3 1 3
2020-10-05 2020-10-11 0 4 2 4
2020-10-12 2020-10-18 0 4 2 5
What I want it to look like(highlighted):
If I understand correctly, just use window functions:
select t.*,
(period -
max(case when currentweek = 1 then period end) over ()
) as periodsequence,
(quarter -
max(case when currentweek = 1 then quarter end) over ()
) as quartersequence
from t;
You can include this in a view rather than putting it in a table.

Shrinking multiple rows to one row

I want to shrink multiple rows in a data frame to one row.
for example, if I have a dataframe like this,
name year project_name month week worklogs
Ahkam 2019 Proj1 1 1 10
Ahkam 2019 proj2 1 1 14
Ahkam 2019 proj3 1 2 6
Ahkam 2019 proj4 1 2 14
Naser 2019 Proj1 1 1 7
Naser 2019 proj2 1 1 8
Naser 2019 proj3 1 2 5
Naser 2019 proj4 1 2 3
and my output dataframe should be:
name year project_name month week worklogs
Ahkam 2019 NaN 1 1 24
Ahkam 2019 NaN 1 2 20
Naser 2019 NaN 1 1 15
Naser 2019 NaN 1 2 8
The project_name column may be whatever it can be. The worklogs must be added according to grouped columns(name,year,month,week)
Thanks in advance.
Use DataFrameGroupBy.agg:
df = (df.groupby(['name', 'year', 'month', 'week'], as_index=False)
.agg({'project_name':'first', 'worklogs':'sum'}))
print(df)
name year month week project_name worklogs
0 Ahkam 2019 1 1 Proj1 24
1 Ahkam 2019 1 2 proj3 20
2 Naser 2019 1 1 Proj1 15
3 Naser 2019 1 2 proj3 8

Grouping into series based on days since

I need to create a new grouping every time I have a period of more than 60 days since my previous record.
Basically, I need too take the data I have here:
RowNo StartDate StopDate DaysBetween
1 3/21/2017 3/21/2017 14
2 4/4/2017 4/4/2017 14
3 4/18/2017 4/18/2017 14
4 6/23/2017 6/23/2017 66
5 7/5/2017 7/5/2017 12
6 7/19/2017 7/19/2017 14
7 9/27/2017 9/27/2017 70
8 10/24/2017 10/24/2017 27
9 10/31/2017 10/31/2017 7
10 11/14/2017 11/14/2017 14
And turn it into this:
RowNo StartDate StopDate DaysBetween Series
1 3/21/2017 3/21/2017 14 1
2 4/4/2017 4/4/2017 14 1
3 4/18/2017 4/18/2017 14 1
4 6/23/2017 6/23/2017 66 2
5 7/5/2017 7/5/2017 12 2
6 7/19/2017 7/19/2017 14 2
7 9/27/2017 9/27/2017 70 3
8 10/24/2017 10/24/2017 27 3
9 10/31/2017 10/31/2017 7 3
10 11/14/2017 11/14/2017 14 3
Once I have that I'll group by Series and get the min(StartDate) and max(StopDate) for individual durations.
I could do this using a cursor but I'm sure someone much smarter than me has figured out a more elegant solution. Thanks in advance!
You can use the window function sum() over with a conditional FLAG
Example
Select *
,Series= 1+sum(case when [DaysBetween]>60 then 1 else 0 end) over (Order by RowNo)
From YourTable
Returns
RowNo StartDate StopDate DaysBetween Series
1 2017-03-21 2017-03-21 14 1
2 2017-04-04 2017-04-04 14 1
3 2017-04-18 2017-04-18 14 1
4 2017-06-23 2017-06-23 66 2
5 2017-07-05 2017-07-05 12 2
6 2017-07-19 2017-07-19 14 2
7 2017-09-27 2017-09-27 70 3
8 2017-10-24 2017-10-24 27 3
9 2017-10-31 2017-10-31 7 3
10 2017-11-14 2017-11-14 14 3
EDIT - 2008 Version
Select A.*
,B.*
From YourTable A
Cross Apply (
Select Series=1+sum( case when [DaysBetween]>60 then 1 else 0 end)
From YourTable
Where RowNo <= A.RowNo
) B

Get all dates for all date ranges in table using SQL Server

I have table dbo.WorkSchedules(Id, From, To) where I store date ranges for work schedules. I want to create a view that will have all dates for all rows of WorkSchedules. Thanks to this I have 1 view with all dates for all schedules.
On web I only found solutions for 1 row like 2 parameters start and end. My issue is different where I have multiple rows with start and end range.
Example:
WorkSchedules
Id | From | To
---+------------+-----------
1 | 2018-01-01 | 2018-01-05
2 | 2018-01-08 | 2018-01-12
Desired result
1 | 2018-01-01
2 | 2018-01-02
3 | 2018-01-03
4 | 2018-01-04
5 | 2018-01-05
6 | 2018-01-08
7 | 2018-01-09
8 | 2018-01-10
9 | 2018-01-11
10| 2018-01-12
If you are regularly dealing with "jobs" and "schedules" then I propose that you need a permanent calendar table (a table where each row is a unique date). You can create rows for dates dynamically but why do this many times when you can do it once and just re-use?
A calendar table, even of several decades, isn't "big" and when indexed they can be very fast as well. You can also store information about holidays and/or fiscal periods etc.
There are many scripts available to produce these tables, here's an answer with 2 scripts on this site: https://stackoverflow.com/a/5635628/2067753
Assuming you use the second (more comprehensive) script, then you can exclude weekends, or other conditions such as holidays, from query results.
Once you have a permanent Calendar table this style of query may be used:
CREATE TABLE WorkSchedules(
Id INTEGER NOT NULL PRIMARY KEY
,[From] DATE NOT NULL
,[To] DATE NOT NULL
);
INSERT INTO WorkSchedules(Id,[From],[To]) VALUES (1,'2018-01-01','2018-01-05');
INSERT INTO WorkSchedules(Id,[From],[To]) VALUES (2,'2018-01-12','2018-01-12');
with range as (
select min(ws.[From]) as dt_from, max(ws.[To]) dt_to
from WorkSchedules as ws
)
select c.*
from calendar as c
inner join range on c.date between range.dt_from and range.dt_to
where c.KindOfDay = 'BANKDAY'
order by c.date
and the result looks like this (note: "News Years Day" has been excluded)
Date Year Quarter Month Week Day DayOfYear Weekday Fiscal_Year Fiscal_Quarter Fiscal_Month KindOfDay Description
---- --------------------- ------ --------- ------- ------ ----- ----------- --------- ------------- ---------------- -------------- ----------- -------------
1 02.01.2018 00:00:00 2018 1 1 1 2 2 2 2018 1 1 BANKDAY NULL
2 03.01.2018 00:00:00 2018 1 1 1 3 3 3 2018 1 1 BANKDAY NULL
3 04.01.2018 00:00:00 2018 1 1 1 4 4 4 2018 1 1 BANKDAY NULL
4 05.01.2018 00:00:00 2018 1 1 1 5 5 5 2018 1 1 BANKDAY NULL
5 08.01.2018 00:00:00 2018 1 1 2 8 8 1 2018 1 1 BANKDAY NULL
6 09.01.2018 00:00:00 2018 1 1 2 9 9 2 2018 1 1 BANKDAY NULL
7 10.01.2018 00:00:00 2018 1 1 2 10 10 3 2018 1 1 BANKDAY NULL
8 11.01.2018 00:00:00 2018 1 1 2 11 11 4 2018 1 1 BANKDAY NULL
9 12.01.2018 00:00:00 2018 1 1 2 12 12 5 2018 1 1 BANKDAY NULL
Without the where clause the full range is:
Date Year Quarter Month Week Day DayOfYear Weekday Fiscal_Year Fiscal_Quarter Fiscal_Month KindOfDay Description
---- --------------------- ------ --------- ------- ------ ----- ----------- --------- ------------- ---------------- -------------- ----------- ----------------
1 01.01.2018 00:00:00 2018 1 1 1 1 1 1 2018 1 1 HOLIDAY New Year's Day
2 02.01.2018 00:00:00 2018 1 1 1 2 2 2 2018 1 1 BANKDAY NULL
3 03.01.2018 00:00:00 2018 1 1 1 3 3 3 2018 1 1 BANKDAY NULL
4 04.01.2018 00:00:00 2018 1 1 1 4 4 4 2018 1 1 BANKDAY NULL
5 05.01.2018 00:00:00 2018 1 1 1 5 5 5 2018 1 1 BANKDAY NULL
6 06.01.2018 00:00:00 2018 1 1 1 6 6 6 2018 1 1 SATURDAY NULL
7 07.01.2018 00:00:00 2018 1 1 1 7 7 7 2018 1 1 SUNDAY NULL
8 08.01.2018 00:00:00 2018 1 1 2 8 8 1 2018 1 1 BANKDAY NULL
9 09.01.2018 00:00:00 2018 1 1 2 9 9 2 2018 1 1 BANKDAY NULL
10 10.01.2018 00:00:00 2018 1 1 2 10 10 3 2018 1 1 BANKDAY NULL
11 11.01.2018 00:00:00 2018 1 1 2 11 11 4 2018 1 1 BANKDAY NULL
12 12.01.2018 00:00:00 2018 1 1 2 12 12 5 2018 1 1 BANKDAY NULL
and weekends and holidays may be excluded using the column KindOfDay
See this as a demonstration (with build of calendar table) here: http://rextester.com/CTSW63441
Ok, I worked this out for you, thinking you mean that you meant 01/08/2018 as a From date in the second row.
/*WorkSchedules
Id| From | To
1 | 2018-01-01 | 2018-01-05
2 | 2018-01-08 | 2018-01-12
*/
--DROP TABLE #WorkSchedules;
CREATE TABLE #WorkSchedules (
ID int,
[DateFrom] DATE,
[DateTo] DATE
)
INSERT INTO #WorkSchedules
SELECT 1, '2018-01-01', '2018-01-05'
UNION
SELECT 2, '2018-01-08', '2018-01-12'
;WITH CTEDATELIMITS AS (
SELECT [DateFrom], [DateTo]
FROM #WorkSchedules
)
,CTEDATES AS
(
SELECT [DateFrom] as [DateResult] FROM CTEDATELIMITS
UNION ALL
SELECT DATEADD(Day, 1, [DateResult]) FROM CTEDATES
JOIN CTEDATELIMITS ON CTEDATES.[DateResult] >= CTEDATELIMITS.[DateFrom]
AND CTEDATES.dateResult < CTEDATELIMITS.[DateTo]
)
SELECT [DateResult] FROM CTEDATES
ORDER BY [DateResult]
You would use a recursive CTE:
with dates as (
select from, to, from as date
from WorkSchedules
union all
select from, to, dateadd(day, 1, date)
from dates
where date < to
)
select row_number() over (order by date), date
from dates;
Note that from and to are reserved words in SQL. They are lousy names for identifiers. I have not escaped them because I assume they are not the actual names of the columns.

find nonbreaking period with condition

There are quotas for hotels per day in a table. How to get number of days when hotel is daily available?
q_id q_hotel q_date q_value
1 1 2013-02-01 1
2 1 2013-02-02 1
3 1 2013-02-03 1
4 1 2013-02-04 0
5 1 2013-02-05 2
6 1 2013-02-06 3
7 1 2013-02-07 3
8 1 2013-02-08 2
9 1 2013-02-09 0
10 1 2013-02-10 0
11 1 2013-02-11 1
12 1 2013-02-12 1
Wanted output:
q_hotel q_date days_available
1 2013-02-01 3
1 2013-02-02 2
1 2013-02-03 1
1 2013-02-04 0
1 2013-02-05 4
1 2013-02-06 3
1 2013-02-07 2
1 2013-02-08 1
1 2013-02-09 0
1 2013-02-10 0
1 2013-02-11 2
1 2013-02-12 1
For now I can get number of days if there is zero quote after needed date exists - I find closest unavailable day and calculate dates difference.
http://sqlfiddle.com/#!12/1a64c/14
select q_hotel
,q_date
,(select extract(day from (min(B.q_date)-A.q_date)) from Table1 B where B.q_date>A.q_date
and B.q_value=0 and A.q_value<>0)
from Table1 A
But there is a problem when I don't have a zero closing date.
Here is a solution:
select
a.q_date
, a.q_hotel
, case
when
a.q_value = 0
then
0
else
(
select
extract
( day from
min ( b.q_date ) - a.q_date + interval '1 day'
)
from table1 b
where b.q_date >= a.q_date
and b.q_hotel = a.q_hotel
and not exists
(
select 1
from table1 c
where c.q_date = b.q_date + interval '1 day'
and b.q_hotel = a.q_hotel
and q_value <> 0
)
)
end as days_available
from table1 a