extract data from clob column in oracle - sql

Question

I am having data in clob column as below:
:1A:CAD22021828,17
:1B:RECEIVE GENERAL IND
11 BEGUM ST 3-15A2
VILL AP IND 313 416
:1C:/000061071257 CC
RECEIVER GENERAL FOR IND
C/O PNBB MAIN BRANCH
11 BEGUM ST 3-15A2
AA HYD APIND
Now my requirement is to load this into 3 separate columns in target table as below:
1A - CAD22021828,17
1B - RECEIVE GENERAL IND
11 BEGUM ST 3-15A2
VILL AP IND 313 416
1C - /000061071257 CC
RECEIVER GENERAL FOR IND
C/O PNBB MAIN BRANCH
11 BEGUM ST 3-15A2
AA HYD APIND
can someone suggest how I can do this.
This is oracle 11.2
I have tried below code ;
SELECT
REGEXP_SUBSTR(mc_clob,':1A:([[:alnum:]]+\S+)') AS code1A,
REGEXP_SUBSTR(mc_clob,':1B:([[:alnum:]]+\s+)') AS code1B,
REGEXP_SUBSTR(mc_clob,':1C:([[:alnum:]]+\s+)') AS code1c
FROM tableA;

Answer 1

Here is one way to do this using REGEXP_SUBSTR with capture groups:
SELECT
REGEXP_SUBSTR(mc_clob, ':1A:(.*):1B:', 1, 1, 'n', 1) AS code1A,
REGEXP_SUBSTR(mc_clob,':1B:(.*):1C:', 1, 1, 'n', 1) AS code1B,
REGEXP_SUBSTR(mc_clob,':1C:(.*)', 1, 1, 'n', 1) AS code1c
FROM tableA;
Demo
To understand how this works, take the first call to REGEXP_SUBSTR:
REGEXP_SUBSTR(mc_clob, ':1A:(.*):1B:', 1, 1, 'n', 1)
This says to match :1A:(.*):1B:, capturing all content between the :1A: and :1B: markers. The fifth parameter is n, which tells Oracle to let dot match across newlines. That is, (.*) will capture all content between the two markers, including across lines. The sixth parameter is 1, which means that the return value will be the first (and only) capture group. Similar logic applies to the second and third call to REGEXP_SUBSTR.