to_sql add column if not exists (sqlalchemy mysql) - pandas

while appending rows to mysql table with pandas to_sql like
df.to_sql('table_name', engine, if_exists='append')
the appending df may contain some new column, which does not exist in mysql table_name,
so, I get pymysql.err.InternalError fired:
InternalError: (pymysql.err.InternalError) (1054, "Unknown column 'new_columns' in 'field list'")
While trying to catch this exception to add new column to the mysql table I cannot catch pymysql.err.InternalError exception for some reason, so I try to do it in a weird way with BaseException like this:
while True:
try:
df.to_sql(table_name, engine, if_exists='append')
except BaseException as e:
b = e.args
missing_column = b[0].split('(pymysql.err.InternalError) (1054, "Unknown column \'')[1].split(' in \'field list\'")')[0].replace("'",'')
with sql.engine.connect() as con:
con.execute(f'ALTER TABLE {table_name} ADD COLUMN {missing_column} TEXT;')
else: break
This solution ugly and unstable, so I would appreciate your advice!

you can check sql table columns before appending new data to it:
import pandas as pd
target_name = "your_table"
target_cols = pd.read_sql_query(f"select * from {target_name} limit 1;").columns.tolist()
your_cols = df.columns.tolist()
if set(your_cols) - set(target_cols) == set():
# APPEND OPERATION...
else:
# NEW COL OPERATION...

Related

Writing a scalable INSERT statement using cx_Oracle

I am attempting to write a script that will allow me to insert values from an uploaded dataframe into a table inside of an Oracle DB; but my issue lies with
too many columns to hard-code
columns aren't one-to-one
What I'm hoping for is a way to write out the columns, check to see if they sync with the columns of my dataframe and from there use an INSERT VALUES sql statement to input the values from the dataframe to the ODS table.
so far these are the important parts of my script:
import pandas as pd
import cx_Oracle
import config
df = pd.read_excel("Employee_data.xlsx")
conn = None
try:
conn = cx_Oracle.connect(config.username, config.password, config.dsn, encoding=config.encoding)
except cx_Oracle.Error as error:
print(error)
finally:
cursor = conn.cursor
sql = "SELECT * FROM ODSMGR.EMPLOYEE_TABLE"
cursor.execute(sql)
data = cursor.fetchall()
col_names = []
for i in range(0, len(cursor.description)):
col_names.append(cursor.description[i][0])
#instead of using df.columns I use:
rows = [tuple(x) for x in df.values]
which prints my ODS column names, and allows me to conveniently store my rows from the df in an array but I'm at a loss for how to import these to the ODS. I found something like:
cursor.execute("insert into ODSMGR.EMPLOYEE_TABLE(col1,col2) values (:col1, :col2)", {":col1df":df, "col2df:df"})
but that'll mean I'll have to hard-code everything which wouldn't be scalable. I'm hoping I can get some sort of insight to help. It's just difficult since the columns aren't 1-to-1 and that there is some compression/collapsing of columns from the DF to the ODS but any help is appreciated.
NOTE: I've also attempted to use SQLalchemy but I am always given an error "ORA-12505: TNS:listener does not currently know of SID given in connect descriptor" which is really strange given that I am able to connect with cx_Oracle
EDIT 1:
I was able to get a list of columns that share the same name; so after running:
import numpy as np
a = np.intersect1d(df.columns, col_names)
print("common columns:", a)
I was able to get a list of columns that the two datasets share.
I also tried to use this as my engine:
engine = create_engine("oracle+cx_oracle://username:password#ODS-test.domain.com:1521/?ODS-Test")
dtyp = {c:types.VARCHAR(df[c].str.len().max())
for c in df.columns[df.dtypes=='object'].tolist()}
df.to_sql('ODS.EMPLOYEE_TABLE', con = engine, dtype=dtyp, if_exists='append')
which has given me nothing but errors.

snowflake.connector SQL compilation error invalid identifier from pandas dataframe

I'm trying to ingest a df I created from a json response into an existing table (the table is currently empty because I can't seem to get this to work)
The df looks something like the below table:
index
clicks_affiliated
0
3214
1
2221
but I'm seeing the following error:
snowflake.connector.errors.ProgrammingError: 000904 (42000): SQL
compilation error: error line 1 at position 94
invalid identifier '"clicks_affiliated"'
and the column names in snowflake match to the columns in my dataframe.
This is my code:
import pandas as pd
from snowflake.sqlalchemy import URL
from sqlalchemy import create_engine
import snowflake.connector
from snowflake.connector.pandas_tools import write_pandas, pd_writer
from pandas import json_normalize
import requests
df_norm = json_normalize(json_response, 'reports')
#I've tried also adding the below line (and removing it) but I see the same error
df = df_norm.reset_index(drop=True)
def create_db_engine(db_name, schema_name):
engine = URL(
account="ab12345.us-west-2",
user="my_user",
password="my_pw",
database="DB",
schema="PUBLIC",
warehouse="WH1",
role="DEV"
)
return engine
def create_table(out_df, table_name, idx=False):
url = create_db_engine(db_name="DB", schema_name="PUBLIC")
engine = create_engine(url)
connection = engine.connect()
try:
out_df.to_sql(
table_name, connection, if_exists="append", index=idx, method=pd_writer
)
except ConnectionError:
print("Unable to connect to database!")
finally:
connection.close()
engine.dispose()
return True
print(df.head)
create_table(df, "reporting")
So... it turns out I needed to change my columns in my dataframe to uppercase
I've added this after the dataframe creation to do so and it worked:
df.columns = map(lambda x: str(x).upper(), df.columns)

Is there an alternative way for collect() in pyspark? py4j.protocol.Py4JJavaError: An error occurred while calling 0323.collectToPython

Pyspark script crashes when i use collect() or show() in pyspark. My dataframe has only 570 rows, so i don't uderstand what is happening.
I have a Dataframe and i have created a functions that extracts a list with distinct rows from it. It was working fine, then suddenly i had an error:
py4j.protocol.Py4JJavaError: An error occurred while calling
0323.collectToPython
A similar error i have when i try to show() the dataframe.
Is there an alternative method to extract a list with distinct values from a dataframe?
required_list = [(col1,col2), (col1,col2)]
Sorry for not posting the code, but its a large script and its confidential.
Update:
I have a function that extract distinct values from a df:
def extract_dist(df, select_cols):
val = len(select_cols)
list_val = [row[0:val] for row in df.select(*select_cols)).distinct.na.drop().collect()]
return list_val
The function worked fine until i had the error.
I have a main script where i import these function and also another function that calculates a dataframe:
def calculate_df(df_join, v_srs, v_db, v_tbl, sql_context):
cmd = "impala-shel....'create table db.tbl as select * from v_db.v_tbl'"
os.system(cmd)
select_stm = "select * from db.tbl"
df = sql_context(select_stm)
cmd = "impala-shel....'drop table if exists db.tbl'"
os.system(cmd)
join cond = [...]
joined_df = df.join(df_join, join_cond, 'left').select(..)
df1 = joined_df.filer(...)
df2 = joined_df.filer(...)
final_df = df1.union(df2)
final_df.show() # error from show
return final_df
Main script:
import extract_dist
import calculate_df
df_join = ...extract from a hive table
for conn in details:
v_db = conn['database'].upper()
v_tbl = conn['table'].upper()
v_name = conn['descr'].upper()
if v_name in lst:
df = calculate_df(df_join, v_name, v_db, v_tbl, sqlContext)
df = df.filter(...column isin list)
df = df.filter(..).filter(..)
# extract list with distinct rows from df using dist function
df.show() # error from show
dist_list = extract_dist(df, [col1,col2]) # error from collect
for x, y in dist_list:
....
If i don't use show() the the error appears when i run the collect() method.
The same scripts worked before and suddenly failed. It there a memory issue? i have to clear memory?
SOLVED:
I have found the issue. After i created the dataframe from a table i have dropped the table.
cmd = "impala-shel....'drop table if exists db.tbl'"
os.system(cmd)
After i removed the command with drop table the script ran successfully.
I will drop the temporary table at the end of the script, after i finish with the extracted dataframe. I didn't know that if we create a dataframe and after that drop the source table i will have error afterwards.

Postgres 9.5 upsert command in pandas or psycopg2?

Most of the examples I see are people inserting a single row into a database with the ON CONFLICT DO UPDATE syntax.
Does anyone have any examples using SQLAlchemy or pandas.to_sql?
99% of my inserts are using psycopg2 COPY command (so I save a csv or stringio and then bulk insert), and the other 1% are pd.to_sql. All of my logic to check for new rows or dimensions is done in Python.
def find_new_rows(existing, current, id_col):
current[id_col] = current[id_col].astype(int)
x = existing[['datetime', id_col, 'key1']]
y = current[['datetime', id_col, 'key2']]
final = pd.merge(y, x, how='left', on=['datetime', id_col])
final = final[~(final['key2'] == final['key1'])]
final = final.drop(['key1'], axis=1)
current = pd.merge(current, final, how='left', on=['datetime', id_col])
current = current.loc[current['key2_y'] == 1]
current.drop(['key2_x', 'key2_y'], axis=1, inplace=True)
return current
Can someone show me an example of using the new PostgreSQL syntax for upsert with pyscopg2? A common use case is to check for dimension changes (between 50k - 100k rows daily which I compare to existing values) which is CONFLICT DO NOTHING to only add new rows.
Another use case is that I have fact data which changes over time. I only take the most recent value (I currently use a view to select distinct), but it would be better to UPSERT, if possible.
Here is my code for bulk insert & insert on conflict update query for postgresql from pandas dataframe:
Lets say id is unique key for both postgresql table and pandas df and you want to insert and update based on this id.
import pandas as pd
from sqlalchemy import create_engine, text
engine = create_engine(postgresql://username:pass#host:port/dbname)
query = text(f"""
INSERT INTO schema.table(name, title, id)
VALUES {','.join([str(i) for i in list(df.to_records(index=False))])}
ON CONFLICT (id)
DO UPDATE SET name= excluded.name,
title= excluded.title
""")
engine.execute(query)
Make sure that your df columns must be same order with your table.
FYI, this is the solution I am using currently.
It seems to work fine for my purposes. I had to add a line to replace null (NaT) timestamps with None though, because I was getting an error when I was loading each row into the database.
def create_update_query(table):
"""This function creates an upsert query which replaces existing data based on primary key conflicts"""
columns = ', '.join([f'{col}' for col in DATABASE_COLUMNS])
constraint = ', '.join([f'{col}' for col in PRIMARY_KEY])
placeholder = ', '.join([f'%({col})s' for col in DATABASE_COLUMNS])
updates = ', '.join([f'{col} = EXCLUDED.{col}' for col in DATABASE_COLUMNS])
query = f"""INSERT INTO {table} ({columns})
VALUES ({placeholder})
ON CONFLICT ({constraint})
DO UPDATE SET {updates};"""
query.split()
query = ' '.join(query.split())
return query
def load_updates(df, table, connection):
conn = connection.get_conn()
cursor = conn.cursor()
df1 = df.where((pd.notnull(df)), None)
insert_values = df1.to_dict(orient='records')
for row in insert_values:
cursor.execute(create_update_query(table=table), row)
conn.commit()
row_count = len(insert_values)
logging.info(f'Inserted {row_count} rows.')
cursor.close()
del cursor
conn.close()
For my case, I wrote to a temporary table first, then merged the temp table into the actual table I wanted to upsert to. Performing the upsert this way avoids any conflicts where the strings may have single quotes in them.
def upsert_dataframe_to_table(self, table_name: str, df: pd.DataFrame, schema: str, id_col:str):
"""
Takes the given dataframe and inserts it into the table given. The data is inserted unless the key for that
data already exists in the dataframe. If the key already exists, the data for that key is overwritten.
:param table_name: The name of the table to send the data
:param df: The dataframe with the data to send to the table
:param schema: the name of the schema where the table exists
:param id_col: The name of the primary key column
:return: None
"""
engine = create_engine(
f'postgresql://{postgres_configs["username"]}:{postgres_configs["password"]}#{postgres_configs["host"]}'
f':{postgres_configs["port"]}/{postgres_configs["db"]}'
)
df.to_sql('temp_table', engine, if_exists='replace')
updates = ', '.join([f'{col} = EXCLUDED.{col}' for col in df.columns if col != id_col])
columns = ', '.join([f'{col}' for col in df.columns])
query = f'INSERT INTO "{schema}".{table_name} ({columns}) ' \
f'SELECT {columns} FROM temp_table ' \
f'ON CONFLICT ({id_col}) DO ' \
f'UPDATE SET {updates} '
self.cursor.execute(query)
self.cursor.execute('DROP TABLE temp_table')
self.conn.commit()

How to get name of dataframe column in PySpark?

In pandas, this can be done by column.name.
But how to do the same when it's a column of Spark dataframe?
E.g. the calling program has a Spark dataframe: spark_df
>>> spark_df.columns
['admit', 'gre', 'gpa', 'rank']
This program calls my function: my_function(spark_df['rank'])
In my_function, I need the name of the column, i.e. 'rank'.
If it was pandas dataframe, we could use this:
>>> pandas_df['rank'].name
'rank'
You can get the names from the schema by doing
spark_df.schema.names
Printing the schema can be useful to visualize it as well
spark_df.printSchema()
The only way is to go an underlying level to the JVM.
df.col._jc.toString().encode('utf8')
This is also how it is converted to a str in the pyspark code itself.
From pyspark/sql/column.py:
def __repr__(self):
return 'Column<%s>' % self._jc.toString().encode('utf8')
Python
As #numeral correctly said, column._jc.toString() works fine in case of unaliased columns.
In case of aliased columns (i.e. column.alias("whatever") ) the alias can be extracted, even without the usage of regular expressions: str(column).split(" AS ")[1].split("`")[1] .
I don't know Scala syntax, but I'm sure It can be done the same.
If you want the column names of your dataframe, you can use the pyspark.sql class. I'm not sure if the SDK supports explicitly indexing a DF by column name. I received this traceback:
>>> df.columns['High']
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: list indices must be integers, not str
However, calling the columns method on your dataframe, which you have done, will return a list of column names:
df.columns will return ['Date', 'Open', 'High', 'Low', 'Close', 'Volume', 'Adj Close']
If you want the column datatypes, you can call the dtypes method:
df.dtypes will return [('Date', 'timestamp'), ('Open', 'double'), ('High', 'double'), ('Low', 'double'), ('Close', 'double'), ('Volume', 'int'), ('Adj Close', 'double')]
If you want a particular column, you'll need to access it by index:
df.columns[2] will return 'High'
I found the answer is very very simple...
// It is in Java, but it should be same in PySpark
Column col = ds.col("colName"); //the column object
String theNameOftheCol = col.toString();
The variable theNameOftheCol is "colName"
I hope these options may serve more like universal ones. Cases covered:
column not having an alias
column having an alias
column having several consecutive aliases
column names surrounded with backticks
No regex:
str(col).replace("`", "").split("'")[-2].split(" AS ")[-1])
Using regex:
import re
re.search(r"'.*?`?(\w+)`?'", str(col)).group(1)
#table name as an example if you have multiple
loc = '/mnt/tablename' or 'whatever_location/table_name' #incase of external table or any folder
table_name = ['customer','department']
for i in table_name:
print(i) # printing the existing table name
df = spark.read.format('parquet').load(f"{loc}{i.lower()}/") # creating dataframe from the table name
for col in df.dtypes:
print(col[0]) # column_name as per availability
print(col[1]) # datatype information of the respective column
Since none of the answers have been marked as the Answer -
I may be over-simplifying the OPs ask but:
my_list = spark_df.schema.fields
for field in my_list:
print(field.name)