I have two tables like so:
tblOrders: OrderNo (pk), CurrentStepNo (fk)
tblSteps: StepNo (pk), OrderNo (fk), StepName, StepType, StepStart, StepStop
tblOrders contains tons of information about our sales orders, while tblSteps contains tons of information regarding the proper sequential steps it takes to build the material we are selling.
I am trying to construct a query that follows this logic:
"For all orders, select the current step name from the step table. If
the Step Type is equal to 'XO', then select the most recently
completed (where StepStop is not null) regular step (where StepStop is
equal to 'YY')"
I have the following query:
SELECT
tblOrders.*,
tblSteps.StepName
FROM
tblOrders
INNER JOIN tblSteps
ON tblOrders.OrderNo = tblSteps.OrderNo
AND tblOrders.CurrentStepNo = tblSteps.StepNo
Which successfully returns to me the current step name for an in-process order. What I need to achieve is, when the tblOrders.CurrentStepNo is of type 'XO', to find the MAX(tblSteps.StepStop) WHERE tblSteps.StepType = 'YY'. However, I am having trouble putting that logic into my already working query.
Note: I am sorry for the lack of sample data in this example. I would normally post but cannot in this instance. This is also not a homework question.
I have reviewed these references:
Case in Select Statement
https://blogs.msdn.microsoft.com/craigfr/2006/08/23/subqueries-in-case-expressions/
But no luck so far.
I have tried this:
SELECT
tblOrders.*,
CASE
WHEN tblSteps.StepType = 'XO' THEN (-- Some logic here)
ELSE tblSteps.StepName
END AS StepName
FROM
tblOrders
INNER JOIN tblSteps
ON tblOrders.OrderNo = tblSteps.OrderNo
AND tblOrders.CurrentStepNo = tblSteps.StepNo
But am struggling to properly formulate the logic
Join all steps, rank them with ROW_NUMBER, and stay with the best ranked:
select *
from
(
select
o.*,
s.*,
row_number() over
(partition by o.orderno
order by case when s.steptype <> 'XO' and s.stepno = o.currentstepno then 1
when s.steptype <> 'YY' then 2
else 3 end, s.stepstop desc nulls last) as rn
from tblorders o
join tblsteps s on s.orderno = o.orderno
) ranked
where rn = 1
order by orderno;
Related
I’m trying to use a correlated subquery in my sql code and I can't wrap my head around what I'm doing wrong. A brief description about the code and what I'm trying to do:
The code consists of a big query (ALIASED AS A) which result set looks like a list of customer IDs, offer IDs and response status name ("SOLD","SELLING","IRRELEVANT","NO ANSWER" etc.) of each customer to each offer. The customers IDs and the responses in the result set are non-unique, since more than one offer can be made to each customer, and a customer can have different response for different offers.
The goal is to generate a list of distinct customer IDs and to mark each ID with 0 or 1 flag :
if the ID has AT LEAST ONE offer with status name is "SOLD" or "SELLING" the flag should be 1 otherwise 0. Since each customer has an array of different responses, what I'm trying to do is to check if "SOLD" or "SELLING" appears in this array for each customer ID, using correlated subquery in the case statement and aliasing the big underlying query named A with A1 this time:
select distinct
A.customer_ID,
case when 'SOLD' in (select distinct A1.response from A as A1
where A.customer_ID = A1.customer_ID) OR
'SELLING' in (select distinct A1.response from A as A1
where A.customer_ID = A1.customer_ID)
then 1 else 0 end as FLAG
FROM
(select …) A
What I get is a mistake alert saying there is no such object as A or A1.
Thanks in advance for the help!
You can use exists with cte :
with cte as (
<query here>
)
select c.*,
(case when exists (select 1
from cte c1
where c1.customer_ID = c.customer_ID and
c1.response in ('sold', 'selling')
)
then 1 else 0
end) as flag
from cte c;
You can also do aggregation :
select customer_id,
max(case when a.response in ('sold', 'selling') then 1 else 0 end) as flag
from < query here > a;
group by customer_id;
With statement as suggested by Yogesh is a good option. If you have any performance issues with "WITH" statement. you can create a volatile table and use columns from volatile table in your select statement .
create voltaile table as (select response from where response in ('SOLD','SELLING').
SELECT from customer table < and join voltaile table>.
The only disadvantge here is volatile tables cannot be accessed after you disconnect from session.
I need to update the following query so that it only returns one child record (remittance) per parent (claim).
Table Remit_To_Activate contains exactly one date/timestamp per claim, which is what I wanted.
But when I join the full Remittance table to it, since some claims have multiple remittances with the same date/timestamps, the outermost query returns more than 1 row per claim for those claim IDs.
SELECT * FROM REMITTANCE
WHERE BILLED_AMOUNT>0 AND ACTIVE=0
AND REMITTANCE_UUID IN (
SELECT REMITTANCE_UUID FROM Claims_Group2 G2
INNER JOIN Remit_To_Activate t ON (
(t.ClaimID = G2.CLAIM_ID) AND
(t.DATE_OF_LATEST_REGULAR_REMIT = G2.CREATE_DATETIME)
)
where ACTIVE=0 and BILLED_AMOUNT>0
)
I believe the problem would be resolved if I included REMITTANCE_UUID as a column in Remit_To_Activate. That's the REAL issue. This is how I created the Remit_To_Activate table (trying to get the most recent remittance for a claim):
SELECT MAX(create_datetime) as DATE_OF_LATEST_REMIT,
MAX(claim_id) AS ClaimID,
INTO Latest_Remit_To_Activate
FROM Claims_Group2
WHERE BILLED_AMOUNT>0
GROUP BY Claim_ID
ORDER BY Claim_ID
Claims_Group2 contains these fields:
REMITTANCE_UUID,
CLAIM_ID,
BILLED_AMOUNT,
CREATE_DATETIME
Here are the 2 rows that are currently giving me the problem--they're both remitts for the SAME CLAIM, with the SAME TIMESTAMP. I only want one of them in the Remits_To_Activate table, so only ONE remittance will be "activated" per Claim:
enter image description here
You can change your query like this:
SELECT
p.*, latest_remit.DATE_OF_LATEST_REMIT
FROM
Remittance AS p inner join
(SELECT MAX(create_datetime) as DATE_OF_LATEST_REMIT,
claim_id,
FROM Claims_Group2
WHERE BILLED_AMOUNT>0
GROUP BY Claim_ID
ORDER BY Claim_ID) as latest_remit
on latest_remit.claim_id = p.claim_id;
This will give you only one row. Untested (so please run and make changes).
Without having more information on the structure of your database -- especially the structure of Claims_Group2 and REMITTANCE, and the relationship between them, it's not really possible to advise you on how to introduce a remittance UUID into DATE_OF_LATEST_REMIT.
Since you are using SQL Server, however, it is possible to use a window function to introduce a synthetic means to choose among remittances having the same timestamp. For example, it looks like you could approach the problem something like this:
select *
from (
select
r.*,
row_number() over (partition by cg2.claim_id order by cg2.create_datetime desc) as rn
from
remittance r
join claims_group2 cg2
on r.remittance_uuid = cg2.remittance_uuid
where
r.active = 0
and r.billed_amount > 0
and cg2.active = 0
and cg2.billed_amount > 0
) t
where t.rn = 1
Note that that that does not depend on your DATE_OF_LATEST_REMIT table at all, it having been subsumed into the inline view. Note also that this will introduce one extra column into your results, though you could avoid that by enumerating the columns of table remittance in the outer select clause.
It also seems odd to be filtering on two sets of active and billed_amount columns, but that appears to follow from what you were doing in your original queries. In that vein, I urge you to check the results carefully, as lifting the filter conditions on cg2 columns up to the level of the join to remittance yields a result that may return rows that the original query did not (but never more than one per claim_id).
A co-worker offered me this elegant demonstration of a solution. I'd never used "over" or "partition" before. Works great! Thank you John and Gaurasvsa for your input.
if OBJECT_ID('tempdb..#t') is not null
drop table #t
select *, ROW_NUMBER() over (partition by CLAIM_ID order by CLAIM_ID) as ROW_NUM
into #t
from
(
select '2018-08-15 13:07:50.933' as CREATE_DATE, 1 as CLAIM_ID, NEWID() as
REMIT_UUID
union select '2018-08-15 13:07:50.933', 1, NEWID()
union select '2017-12-31 10:00:00.000', 2, NEWID()
) x
select *
from #t
order by CLAIM_ID, ROW_NUM
select CREATE_DATE, MAX(CLAIM_ID), MAX(REMIT_UUID)
from #t
where ROW_NUM = 1
group by CREATE_DATE
I am still new to SQL and getting my head around the whole sub-query aggregation to display some results and was looking for some advice:
The tables might look something like:
Customer: (custID, name, address)
Account: (accountID, reward_balance)
Shop: (shopID, name, address)
Relational tables:
Holds (custID*, accountID*)
With (accountID*, shopID*)
How can I find the store that has the least reward_balance?
(The customer info is not required at this point)
I tried:
SELECT accountID AS ACCOUNT_ID, shopID AS SHOP_ID, MIN(reward_balance) AS LOWEST_BALANCE
FROM Account, Shop, With
WHERE With.accountID = Account.accountID
AND With.shopID=Shop.shopID
GROUP BY
Account.accountID,
Shop.shopID
ORDER BY MIN(reward_balance);
This works in a way that is not intended:
ACCOUNT_ID | SHOP_ID | LOWEST_BALANCE
1 | 1 | 10
2 | 2 | 40
3 | 3 | 100
4 | 4 | 1000
5 | 4 | 5000
As you can see Shop_ID 4 actually has a balance of 6000 (1000+5000) as there are two customers registered with it. I think I need to SUM the lowest balance of the shops based on their balance and display it from low-high.
I have been trying to aggregate the data prior to display but this is where I come unstuck:
SELECT shopID AS SHOP_ID, MIN(reward_balance) AS LOWEST_BALANCE
FROM (SELECT accountID, shopID, SUM(reward_balance)
FROM Account, Shop, With
WHERE
With.accountID = Account.accountID
AND With.shopID=Shop.shopID
GROUP BY
Account.accountID,
Shop.shopID;
When I run something like this statement I get an invalid identifier error.
Error at Command Line : 1 Column : 24
Error report -
SQL Error: ORA-00904: "REWARD_BALANCE": invalid identifier
00904. 00000 - "%s: invalid identifier"
So I figured I might have my joining condition incorrect and the aggregate sorting incorrect, and would really appreciate any general advice.
Thanks for the lengthy read!
Approach this problem one step at time.
We're going to assume (and we should probably check this) that by least reward_balance, that refers to the total of all reward_balance associated with a shop. And we're not just looking for the shop that has the lowest individual reward balance.
First, get all of the individual "reward_balance" for each shop. Looks like the query would need to involve three tables...
SELECT s.shop_id
, a.reward_balance
FROM `shop` s
LEFT
JOIN `with` w
ON w.shop_id = s.shop_id
LEFT
JOIN `account` a
ON a.account_id = w.account_id
That will get us the detail rows, every shop along with the individual reward_balance amounts associated with the shop, if there are any. (We're using outer joins for this query, because we don't see any guarantee that a shops is going to be related to at least one account. Even if it's true for this use case, that's not always true in the more general case.)
Once we have the individual amounts, the next step is to total them for each shop. We can do that using a GROUP BY clause and a SUM() aggregate.
SELECT s.shop_id
, SUM(a.reward_balance) AS tot_reward_balance
FROM `shop` s
LEFT
JOIN `with` w
ON w.shop_id = s.shop_id
LEFT
JOIN `account` a
ON a.account_id = w.account_id
GROUP BY s.shop_id
At this point, with MySQL we could add an ORDER BY clause to arrange the rows in ascending order of tot_reward_balance, and add a LIMIT 1 clause if we only want to return a single row. We can also handle the case when tot_reward_balance is NULL, assigning a zero in place of the NULL.
SELECT s.shop_id
, IFNULL(SUM(a.reward_balance),0) AS tot_reward_balance
FROM `shop` s
LEFT
JOIN `with` w
ON w.shop_id = s.shop_id
LEFT
JOIN `account` a
ON a.account_id = w.account_id
GROUP BY s.shop_id
ORDER BY tot_reward_amount ASC, s.shop_id ASC
LIMIT 1
If there are two (or more) shops with the same least value of tot_reward_amount, this query returns only one of those shops.
Oracle doesn't have the LIMIT clause like MySQL, but we can get equivalent result using analytic function (which is not available in MySQL). We also replace the MySQL IFNULL() function with the Oracle equivalent NVL() function...
SELECT v.shop_id
, v.tot_reward_balance
, ROW_NUMBER() OVER (ORDER BY v.tot_reward_balance ASC, v.shop_id ASC) AS rn
FROM (
SELECT s.shop_id
, NVL(SUM(a.reward_balance),0) AS tot_reward_balance
FROM shop s
LEFT
JOIN with w
ON w.shop_id = s.shop_id
LEFT
JOIN account a
ON a.account_id = w.account_id
GROUP BY s.shop_id
) v
HAVING rn = 1
Like the MySQL query, this returns at most one row, even when two or more shops have the same "least" total of reward_balance.
If we want to return all of the shops that have the lowest tot_reward_balance, we need to take a slightly different approach.
The best approach to building queries is step wise refinement; in this case, start by getting all of the individual reward_amount for each shop. Next step is to aggregate the individual reward_amount into a total. The next steps is to pickout the row(s) with the lowest total reward_amount.
In SQL Server, You can try using a CTE:
;with cte_minvalue as
(
select rank() over (order by Sum_Balance) as RowRank,
ShopId,
Sum_Balance
from (SELECT Shop.shopID, SUM(reward_balance) AS Sum_Balance
FROM
With
JOIN Shop ON With.ShopId = Shop.ShopId
JOIN Account ON With.AccountId = Account.AccountId
GROUP BY
Shop.shopID)ShopSum
)
select ShopId, Sum_Balance from cte_minvalue where RowRank = 1
I am trying to return a set of results and decided to try my luck with CTE, the first table "Vendor", has a list of references, the second table "TVView", has ticket numbers that were created using a reference from the "Vendor" table. There may be one or more tickets using the same ticket number depending on the state of that ticket and I am wanting to return the last entry for each ticket found in "TVView" that matches a selected reference from "Vendor". Also, the "TVView" table has a seed field that is incremented.
I got this to return the right amount of entries (meaning not showing the duplicate tickets but only once) but I cannot figure out how to add an additional layer to go back through and select the last entry for that ticket and return some other fields. I can figure out how to sum which is actually easy, but I really need the Top 1 of each ticket entry in "TVView" regardless if its a duplicate or not while returning all references from "Vendor". Would be nice if SQL supported "Last"
How do you do that?
Here is what I have done so far:
with cteTickets as (
Select s.Mth2, c.Ticket, c.PyRt from Vendor s
Inner join
TVView c on c.Mth1 = s.Mth1 and c.Vendor = s.Vendor
)
Select Mth2, Ticket, PayRt from cteTickets
Where cteTickets.Vendor >='20'
and cteTickets.Vendor <='40'
and cteTickets.Mth2 ='8/15/2014'
Group by cteTickets.Ticket
order by cteTickets.Ticket
Several rdbms's that support Common Table Expressions (CTE) that I am aware of also support analytic functions, including the very useful ROW_NUMBER(), so the following should work in Oracle, TSQL (MSSQL/Sybase), DB2, PostgreSQL.
In the suggestions the intention is to return just the most recent entry for each ticket found in TVView. This is done by using ROW_NUMBER() which is PARTITIONED BY Ticket that instructs row_number to recommence numbering for each change of the Ticket value. The subsequent ORDER BY Mth1 DESC is used to determine which record within each partition is assigned 1, here it will be the most recent date.
The output of row_number() needs to be referenced by a column alias, so using it in a CTE or derived table permits selection of just the most recent records by RN = 1 which you will see used in both options below:
-- using a CTE
WITH
TVLatest
AS (
SELECT
* -- specify the fields
, ROW_NUMBER() OVER (PARTITION BY Ticket
ORDER BY Mth1 DESC) AS RN
FROM TVView
)
SELECT
Mth2
, Ticket
, PayRt
FROM Vendor v
INNER JOIN TVLatest l ON v.Mth1 = l.Mth1
AND v.Vendor = l.Vendor
AND l.RN = 1
WHERE v.Vendor >= '20'
AND v <= '40'
AND v.Mth2 = '2014-08-15'
ORDER BY
v.Ticket
;
-- using a derived table instead
SELECT
Mth2
, Ticket
, PayRt
FROM Vendor v
INNER JOIN (
SELECT
* -- specify the fields
, ROW_NUMBER() OVER (PARTITION BY Ticket
ORDER BY Mth1 DESC) AS RN
FROM TVView
) TVLatest l ON v.Mth1 = l.Mth1
AND v.Vendor = l.Vendor
AND l.RN = 1
WHERE v.Vendor >= '20'
AND v <= '40'
AND v.Mth2 = '2014-08-15'
ORDER BY
v.Ticket
;
please note: "SELECT *" is a convenience or used as an abbreviation if full details are unknown. The queries above may not operate without correctly specifying the field list (eg. 'as is' they would fail in Oracle).
I have a postgres query written for the Spree Commerce store that sorts all of it's products in the following order: In stock (then first available), Backorder (then first available), Sold out (then first available).
In order to chain it with rails scopes I had to put it in the order by clause as opposed to anywhere else. The query itself works, and is fairly performant, but complex. I was curious if anyone with a bit more knowledge could discuss a better way to do it? I'm interested in performance, but also different ways to approach the problem.
ORDER BY (
SELECT
CASE
WHEN tt.count_on_hand > 0
THEN 2
WHEN zz.backorderable = true
THEN 1
ELSE 0
END
FROM (
SELECT
row_number() OVER (dpartition),
z.id,
bool_or(backorderable) OVER (dpartition) as backorderable
FROM (
SELECT DISTINCT ON (spree_variants.id) spree_products.id, spree_stock_items.backorderable as backorderable
FROM spree_products
JOIN "spree_variants" ON "spree_variants"."product_id" = "spree_products"."id" AND "spree_variants"."deleted_at" IS NULL
JOIN "spree_stock_items" ON "spree_stock_items"."variant_id" = "spree_variants"."id" AND "spree_stock_items"."deleted_at" IS NULL
JOIN "spree_stock_locations" ON spree_stock_locations.id=spree_stock_items.stock_location_id
WHERE spree_stock_locations.active = true
) z window dpartition as (PARTITION by id)
) zz
JOIN (
SELECT
row_number() OVER (dpartition),
t.id,
sum(count_on_hand) OVER (dpartition) as count_on_hand
FROM (
SELECT DISTINCT ON (spree_variants.id) spree_products.id, spree_stock_items.count_on_hand as count_on_hand
FROM spree_products
JOIN "spree_variants" ON "spree_variants"."product_id" = "spree_products"."id" AND "spree_variants"."deleted_at" IS NULL
JOIN "spree_stock_items" ON "spree_stock_items"."variant_id" = "spree_variants"."id" AND "spree_stock_items"."deleted_at" IS NULL
) t window dpartition as (PARTITION by id)
) tt ON tt.row_number = 1 AND tt.id = spree_products.id
WHERE zz.row_number = 1 AND zz.id=spree_products.id
) DESC, available_on DESC
The FROM shown above determines whether or not a product is backorderable, and the JOIN shown above determines the stock in inventory. Note that these are very similar queries, except that I need to determine if something is backorderable based on a locations ability to support backorders and its state, WHERE spree_stock_locations.active=true.
Thanks for any advice!