matplotlib histogram with equal bars width - matplotlib

Question

I use a histogram to display the distribution. Everything works fine if the spacing of the bins is uniform. But if the interval is different, then the bar width is appropriate (as expected). Is there a way to set the width of the bar independent of the size of the bins ?
This is what i have
This what i trying to draw
from matplotlib import pyplot as plt
my_bins = [10, 20, 30, 40, 50, 120]
my_data = [5, 5, 6, 8, 9, 15, 25, 27, 33, 45, 46, 48, 49, 111, 113]
fig1 = plt.figure()
ax1 = fig1.add_subplot(121)
ax1.set_xticks(my_bins)
ax1.hist(my_data, my_bins, histtype='bar', rwidth=0.9,)
fig1.show()

Answer 1

I cannot mark your question as a duplicate, but I think my answer to this question might be what you are looking for?
I'm not sure how you'll make sense of the result, but you can use numpy.histogram to calculate the height of your bars, then plot those directly against an arbitrary x-scale.
x = np.random.normal(loc=50, scale=200, size=(2000,))
bins = [0,1,10,20,30,40,50,75,100]
fig = plt.figure()
ax = fig.add_subplot(211)
ax.hist(x, bins=bins, edgecolor='k')
ax = fig.add_subplot(212)
h,e = np.histogram(x, bins=bins)
ax.bar(range(len(bins)-1),h, width=1, edgecolor='k')
EDIT Here's with the adjustment to the x-tick labels so that the correspondence is easier to see.
my_bins = [10, 20, 30, 40, 50, 120]
my_data = [5, 5, 6, 8, 9, 15, 25, 27, 33, 45, 46, 48, 49, 111, 113]
fig = plt.figure()
ax = fig.add_subplot(211)
ax.hist(my_data, bins=my_bins, edgecolor='k')
ax = fig.add_subplot(212)
h,e = np.histogram(my_data, bins=my_bins)
ax.bar(range(len(my_bins)-1),h, width=1, edgecolor='k')
ax.set_xticks(range(len(my_bins)-1))
ax.set_xticklabels(my_bins[:-1])