We are learning subqueries in Oracle SQL. I'm receiving an error "SQL command not properly ended" with an example from my textbook that should work.
I have attempted re-spacing the subquery, but keeping the exact code, this should work
SELECT last_name, salary
FROM employees
WHERE salary > 11000
(SELECT salary
FROM employees
WHERE last_name='Abel');
ERROR at line 4: ORA-00933: SQL command not properly ended
There needs to be something between the 11000 and the following subselect. As an example, it might be that the following was intended:
SELECT last_name, salary
FROM employees
WHERE salary > 11000 AND
salary IN (SELECT salary
FROM employees
WHERE last_name='Abel');
Is this what you want?
SELECT last_name, salary
FROM employees
WHERE salary > 11000 AND
last_name = 'Abel';
This would return employees named "Abel" whose salary exceeds 11,000.
Related
select emp_name, salary
from emp12
where exists (select * from emp12 where salary > 3700)
I am running this query on SQL Server, I don't get any error but the problem is I have mentioned salary > 3700.
In the resulting output, I am get all the salary details including the ones which are below 3700 also, that's what I am not understanding.
How is that possible salary below 3700 is also showing up in the output?
Doing revision for a SQL test I've got coming up and I'm having issues finding a query to meet one of the requirements of the questions. Heres the question:
The HR department needs to find the high-salary and low-salary employees. Modify your query from (7) to display the last name and salary for all employees whose salary is not in the range 5,000 through 12,000
Here's what I've got:
SELECT last_name, salary
FROM employees
WHERE salary BETWEEN 5000 AND 12000;
When I execute the query I get all of the employees who land between those 2 values, I need the employees who land outside of the range of the 2 values. Do I need to use '<' '>'?
Any help would be greatly appreciated :)
SELECT last_name, salary
FROM employees
WHERE salary NOT BETWEEN 5000 AND 12000
I have an Employees table which looks like this:
employee_id employee_name employee_salary
1 Tom 35000
2 Sarah 50000
3 David 45000
4 Rosie 55000
5 Michael 45000
I need to return the employees salary that is higher than the average salary but the below command is having an error saying '1 misuse of aggregate function AVG()'.
SELECT employee_salary
FROM Employees
WHERE employee_salary > AVG(employee_salary);
The output that I'm expecting to get is:
employee_id employee_name employee_salary
2 Sarah 50000
4 Rosie 55000
Please advise, thank you!
I need to write the SQL query to return the number of employees for each department.
I assume you're looking for something like this:
SELECT department_id
,COUNT(employee_id) AS TotalEmployees
FROM Department
LEFT JOIN Employees
ON Employees.department_id = Department.department_id
GROUP BY department_id
Also, I need to return the employees salary that is higher than the average salary
The simplest way to return the salaries that are higher than average as a beginner sql programmer is probably something like this:
SELECT employee_salary
FROM Employees
WHERE employee_salary > (SELECT AVG(employee_salary)
FROM Employees)
As the others said, the other questions just require a bit of research. There are tonnes of resources out there to learn, but it takes time...
I need to write the SQL query to return the number of employees for each
department. However, my below command is not correct:
This is not what you ask for.
You get the join correct, but you ask for:
SELECT COUNT(Employees.employment_id)
The count how often different employment id's exist - which is 1 for an employee in one department, or X with X being the number of entries in the join. As the department_id entry is part of the employee table, this CAN NOT HAPPEN. TOTALLY not asking what you want.
I'm using the LEFT JOIN here because I am returning the result from the
Employees table is this right?
Depends - a normal join should work here. Left is only sensible if the other side can be empty - which I would assume is not possible (there are no rows with Employees.department_id being NULL).
You you want is a count (without anything in the brackets) and a group by department_id. And obviously the department id:
SELECT Department.department_id, count() FROM....
Furthermore, are there any tips to speed up SQL Server's performance?
Just pointing you to https://use-the-index-luke.com/ - indices are a cornerstone for any decent performance.
Ignoring your second question - one per question please.
I have a question about two queries. Will these two queries give the same result? I am trying to find the average salary by department:
Select s1.department, avg(s1.salary)
From
(Select department, salary
From staff
Where salary > 100000) s1
Group by s1.department
vs
select department, avg(salary) as avg_salary
from staff
where salary > 100000
group by department
Yes, it gives the same amounts back.
the bottom query gets data from a sub select which gets its data from the table, whereas the top query gets it straight from the table itself.
There are no additional filters in there. So the result will be the same.
you can test it out however, don't take my word for it.
I will explain the problem I am stuck on. I have a table named empl02 which contains Lastname, salary, and position for all the employees. I am asked to display last,name,salary, position for all employees making more money than the highest paid member of a certain 'position', we will call this position server. I cannot just do something simple like...
SQL> select Lastname,salary,position FROM empl02
2 WHERE
3 SAL > 125000;
Rather, it must be dynamic. I feel the logic is pretty simple I'm just not sure how to translate it into SQL. I am thinking something along the lines of
"SELECT Lastname,salary,position from empl02 where salary > MAX(SALARY) of position(server)" what is a way to translate this task to SQL?
You need to retrieve the "reference" salary as a sub-query:
select lastname, salary, position
from empl02
where salary > (select max(salary)
from empl02
where position = 'manager');