I have a table like this
---------------------------------------------
Id | TransactionId | Amount | Account| crdr |
---------------------------------------------
1 | 1 | 100 | 11111 | 1 |
2 | 2 | 130 | 13133 | 1 |
3 | 1 | 100 | 12111 | 2 |
4 | 2 | 130 | 13233 | 2 |
5 | 2 | 110 | 12122 | 1 |
What I need to display is, show these records as pairs (I have grouped them by transactionid, Amount).
SELECT TransactionId ,Amount , Account, CrDr
FROM Table1 ORDER BY TransactionId ASC,Amount ASC, CrDr ASC
But I want to ignore the records which dont have a pair, as a Example for this above records set result should be like this
---------------------------------------------
TransactionId | Amount | Account| crdr |
---------------------------------------------
1 | 100 | 11111 | 1 |
1 | 100 | 12111 | 2 |
2 | 130 | 13133 | 1 |
2 | 130 | 13233 | 2 |
Can someone suggest a solution for this.
You could use a correlated subquery with a NOT EXISTS condition to ensure that another record exists with the same TransactionId and Amount:
SELECT TransactionId ,Amount , Account, CrDr
FROM Table1 t
WHERE EXISTS (
SELECT 1
FROM Table1 t1
WHERE
t.id <> t1.id
AND t.TransactionId = t1.TransactionId
AND t.Amount = t1.Amount
)
ORDER BY TransactionId ASC,Amount ASC, CrDr ASC
Demo on DB Fiddle:
TransactionId | Amount | Account | CrDr
------------: | -----: | ------: | ---:
1 | 100 | 11111 | 1
1 | 100 | 12111 | 2
2 | 130 | 13133 | 1
2 | 130 | 13233 | 2
Try this:
DECLARE #DataSource TABLE
(
[Id] INT
,[TransactionId] INT
,[Amount] INT
,[Account] INT
,[crdr] INT
);
INSERT INTO #DataSource ([Id], [TransactionId], [Amount], [Account], [crdr])
VALUES (1, 1, 100, 11111, 1)
,(2, 2, 130, 13133, 1)
,(3, 1, 100, 12111, 2)
,(4, 2, 130, 13233, 2)
,(5, 2, 110, 12122, 1);
WITH DataSource AS
(
SELECT *
,COUNT(*) OVER (PARTITION BY [TransactionId], [Amount]) AS [Count]
FROM #DataSource
)
SELECT *
FROM DataSource
WHERE [Count] = 2
ORDER BY TransactionId ASC,Amount ASC, CrDr ASC;
Try this: This this simplest solution of this problem
;with cte
as
(
select TransactionId, Amount
from Table1
group by TransactionId, Amount
having count(*) > 1
)
select *
from Table1 t
inner join cte c on t.TransactionId = c.TransactionId and t.Amount = c.Amount
Related
I have the following SQL table name 'orders':
+--------------+------------+-------------------+------------+
| order_id | item_id | amount | commission |
+--------------+------------+-------------------+------------+
| 111 | 1234 | 23 | 1 |
| 222 | 1234 | 34 | 2 |
| 111 | 2345 | 45 | 3 |
| 111 | 1234 | 23 | 1 |
+--------------+------------+-------------------+------------+
And I'm trying to Select only the rows that the order_id and item_id are NOT the same (remove duplicates only if BOTH has the same value), I tried using "Group_By" as follows:
SELECT * FROM orders GROUP BY order_id,item_id
but this, will remove all duplicates of order_id, and all duplicated of item_id, here is the result:
+--------------+------------+-------------------+------------+
| order_id | item_id | amount | commission |
+--------------+------------+-------------------+------------+
| 111 | 1234 | 23 | 1 |
| 222 | 1234 | 34 | 2 |
+--------------+------------+-------------------+------------+
I've tried using 'DISTINCT' too, but I need to select all columns in the result.
here is the expected result:
+--------------+------------+-------------------+------------+
| order_id | item_id | amount | commission |
+--------------+------------+-------------------+------------+
| 111 | 1234 | 23 | 1 |
| 222 | 1234 | 34 | 2 |
| 111 | 2345 | 45 | 3 |
+--------------+------------+-------------------+------------+
I hope its clear, Thank you.
You can use row_number():
select order_id, item_id, amount, commission
from (
select t.*, row_number() over(partition by order_id, item_id order by commission) rn
from mytable t
) t
where rn = 1
With your sample data, it is not easy to see exactly which partition and order by clause you are looking for, so you might need to adjust them to your exact use case.
Simply:
SELECT DISTINCT * FROM orders
SELECT DISTINCT should do what you want
SELECT DISTINCT order_id, item_id, amount, commission
FROM orders;
If you have more columns, but only care about these being duplicated, then you can use ROW_NUMBER():
SELECT o.*
FROM (SELECT o.*,
ROW_NUMBER() OVER (PARTITION BY order_id, item_id, amount, commission ORDER BY (SELECT NULL)) as seqnum
FROM orders o
) o
WHERE seqnum = 1;
You can try this.
create table MyTable
(order_id int
, item_id int
, amount int
, commission int)
insert into MyTable values
(111, 1234, 23, 1),
(222, 1234, 34, 2),
(111, 2345, 45, 3),
(111, 1234, 23, 1)
select distinct * from MyTable
Live db<>fiddle demo.
I am trying to query a table for data conversion but I am running into issues with the structure. I am guessing I need to Pivot then Unpivot but I am not sure where to begin.
This is my current table
+----+-----------+-------+---------+
| ID | field | value | date |
+----+-----------+-------+---------+
| 1 | Draw1 | 1500 | NULL |
| 1 | Draw1Date | NULL | 4/15/16 |
| 1 | Draw1Fee | 100 | NULL |
| 1 | Draw2 | 2000 | NULL |
| 1 | Draw2Date | NULL | 3/14/17 |
| 1 | Draw2Fee | 100 | NULL |
| 2 | Draw1 | 800 | NULL |
| 2 | Draw1Date | NULL | 4/16/18 |
| 2 | Draw1Fee | 150 | NULL |
| 2 | Draw2 | 760 | NULL |
| 2 | Draw2Date | NULL | 5/6/18 |
| 2 | Draw2Fee | 150 | NULL |
+----+-----------+-------+---------+
Result needed
+----+-------+---------+---------+------+
| ID | Draws | Amount | Date | Fee |
+----+-------+---------+---------+------+
| 1 | Draw1 | 1500 | 4/15/16 | 100 |
| 1 | Draw2 | 2000 | 3/14/17 | 100 |
| 2 | Draw1 | 800 | 4/16/18 | 150 |
| 2 | Draw2 | 760 | 5/6/18 | 150 |
+----+-------+---------+---------+------+
My answer works for provided data. if you are looking for more general solution, for more variety of data, you may try to find another answer. I've not used PIVOT/UNPIVOT.
Test Data:
create table #t (ID int, field varchar(20), [value] int, [date] date)
insert into #t values
(1 ,'Draw1' , 1500 , NULL ),
(1 ,'Draw1Date' , NULL , '4/15/16'),
(1 ,'Draw1Fee' , 100 , NULL ),
(1 ,'Draw2' , 2000 , NULL ),
(1 ,'Draw2Date' , NULL , '3/14/17'),
(1 ,'Draw2Fee' , 100 , NULL ),
(2 ,'Draw1' , 800 , NULL ),
(2 ,'Draw1Date' , NULL , '4/16/18'),
(2 ,'Draw1Fee' , 150 , NULL ),
(2 ,'Draw2' , 760 , NULL ),
(2 ,'Draw2Date' , NULL , '5/6/18' ),
(2 ,'Draw2Fee' , 150 , NULL )
Query:
;with ct as (
select ID, field
from #t
where field in ('Draw1', 'Draw2')
group by ID, field
)
select ct.ID, ct.field
, t1.[value] as Amount, t2.[date] as [Date], t3.[value] as Fee
from ct
inner join #t t1 on t1.ID = ct.ID and t1.field = ct.field
inner join #t t2 on t2.ID = ct.ID and t2.field = ct.field + 'Date'
inner join #t t3 on t3.ID = ct.ID and t3.field = ct.field + 'Fee'
Result:
ID field Amount Date Fee
1 Draw1 1500 2016-04-15 100
1 Draw2 2000 2017-03-14 100
2 Draw1 800 2018-04-16 150
2 Draw2 760 2018-05-06 150
Try this...
SELECT tblAmount.id AS ID,
tblAmount.field AS Draws,
Max(tblAmount.value) AS Amount,
Max(tblDate.[date]) AS [Date],
Max(tblFee.value) AS Fee
FROM tablename tblAmount
INNER JOIN (SELECT id, field, [date]
FROM tablename
WHERE [date] IS NOT NULL AND field LIKE '%Date') tblDate
ON tblAmount.id = tblDate.id
AND tblDate.field LIKE tblAmount.field + '%'
INNER JOIN (SELECT id, field, value
FROM tablename
WHERE value IS NOT NULL AND field LIKE '%Fee') tblFee
ON tblAmount.id = tblFee.id
WHERE tblAmount.value IS NOT NULL
AND tblAmount.field NOT LIKE '%Fee'
AND tblAmount.field NOT LIKE '%Date'
GROUP BY tblAmount.id, tblAmount.field
ORDER BY tblAmount.id, tblAmount.field
Output
+----+-------+--------+------------+-----+
| ID | Draws | Amount | Date | Fee |
+----+-------+--------+------------+-----+
| 1 | Draw1 | 1500 | 2016-04-15 | 100 |
| 1 | Draw2 | 2000 | 2017-03-14 | 100 |
| 2 | Draw1 | 800 | 2018-04-16 | 150 |
| 2 | Draw2 | 760 | 2018-05-06 | 150 |
+----+-------+--------+------------+-----+
Demo: http://www.sqlfiddle.com/#!18/97688/101/0
I would simply do:
select id, left(field, 5),
max(case when len(field) = 5 then value end) as value,
max(case when field like '%date' then value end) as date,
sum(case when field like '%fee' then value end) as fee
from t
group by id, left(field, 5);
If your field is really more complex, do you are looking for date and fee at the end, by anything before, then use cross apply:
select t.id, v.draws,
max(case when t.field = v.draws then value end) as value,
max(case when t.field like '%date' then value end) as date,
sum(case when t.field like '%fee' then value end) as fee
from t cross apply
(values (replace(replace(field, 'date', ''), 'fee', '')) v(draws)
group by id, v.draws;
I have this schema
Item:
| ItemId | Name | Price |
|--------|-------|-------|
| 1 | Item1| 5.00 |
| 2 | Item2| 2.00 |
OrderHeader:
| OrderId| OrderNum| OrderDate |
|--------|---------|------------|
| 1 | ORD1 | 2017-05-10 |
| 2 | ORD2 | 2017-05-12 |
OrderDetails:
|OrderId| ItemId | Total |
--------|--------|---------
| 1 | 1 | 3 |
| 2 | 1 | 2 |
How can I get this result:
|ItemId | OrderId | Paid | Debt |
--------|-----------|----------------
| 1 | 1 | 3 | 2 |
| 1 | 2 | 5 | 0 |
In the result set, the column paid must contains the total of previous payments and plus the new one.
How can I use a Common table expression for example to solve this?
This, you should have provided us:
DECLARE #Item TABLE (Id int, [Name] varchar(15), Price int)
DECLARE #OrderDetails TABLE (OrderId int, ItemId int, Total int)
INSERT INTO #ITEM VALUES (1, 'ITEM1', 5), (2, 'ITEM2', 2)
INSERT INTO #OrderDetails VALUES (1, 1, 3), (2, 1, 2)
This, seems to work, and I think it still has room for improvement:
SELECT OrderId, ItemId, [SUM1], R.Price - [SUM1]
FROM #OrderDetails AS A
LEFT JOIN #Item AS R ON A.ItemId = R.Id
OUTER APPLY (
SELECT SUM(SUB1.TOTAL) AS [SUM1]
FROM #OrderDetails AS SUB1
WHERE SUB1.ItemId = A.ItemId AND SUB1.OrderId <= A.OrderId
) AS B
I have a table like the following:
+----+-----+-----+
| ID | GRP | NR |
+----+-----+-----+
| 1 | 1 | 101 |
| 2 | 1 | 102 |
| 3 | 1 | 103 |
| 4 | 1 | 105 |
| 5 | 1-2 | 106 |
| 6 | 1-2 | 109 |
| 7 | 1-2 | 110 |
| 8 | 2 | 201 |
| 9 | 2 | 202 |
| 10 | 3 | 300 |
| 11 | 3 | 350 |
| 12 | 3 | 351 |
| 13 | 3 | 352 |
+----+-----+-----+
I wanted to create a view which groups this list by GRP and concatenates values in NR.
Is it possible to dynamically detect sequences and shorten them into ranges?
Like 1, 2, 3, 5 would become 1-3, 5.
So the result should look like this:
+-----+--------------------+
| GRP | NRS |
+-----+--------------------+
| 1 | 101 - 103, 105 |
| 1-2 | 106, 109 - 110 |
| 2 | 201 - 202 |
| 3 | 300, 350 - 352 |
+-----+--------------------+
What i got now is simply concatenate values, so the table above would become this:
+-----+--------------------+
| GRP | NRS |
+-----+--------------------+
| 1 | 101, 102, 103, 105 |
| 1-2 | 106, 109, 110 |
| 2 | 201, 202 |
| 3 | 300, 350, 351, 352 |
+-----+--------------------+
Here's the actual statement:
DECLARE #T TABLE
(
ID INT IDENTITY(1, 1)
, GRP VARCHAR(10)
, NR INT
)
INSERT INTO #T
VALUES ('1',101),('1',102),('1',103),('1',105)
,('1-2',106),('1-2',109), ('1-2',110)
,('2',201),('2',202)
,('3',300),('3',350),('3',351),('3',352)
SELECT * FROM #T
;WITH GROUPNUMS (RN, GRP, NR, NRS) AS
(
SELECT 1, GRP, MIN(NR), CAST(MIN(NR) AS VARCHAR(MAX))
FROM #T
GROUP BY GRP
UNION ALL
SELECT CT.RN + 1, T.GRP, T.NR, CT.NRS + ', ' + CAST(T.NR AS VARCHAR(MAX))
FROM #T T
INNER JOIN GROUPNUMS CT ON CT.GRP = T.GRP
WHERE T.NR > CT.NR
)
SELECT NRS.GRP, NRS.NRS
FROM GROUPNUMS NRS
INNER JOIN (
SELECT GRP, MAX(RN) AS MRN
FROM GROUPNUMS
GROUP BY GRP
) R
ON NRS.RN = R.MRN AND NRS.GRP = R.GRP
ORDER BY NRS.GRP
Can anyone tell me if it's easily possible to do something like that?
Would be great if anyone has an idea and would like to share it.
SQLFiddle demo
with TRes
as
(
select T.GRP,T.NR NR,
CASE WHEN T1.NR IS NULL and T2.NR is null
THEN CAST(T.NR as VARCHAR(MAX))
WHEN T1.NR IS NULL and T2.NR IS NOT NULL
THEN '-'+CAST(T.NR as VARCHAR(MAX))
WHEN T1.NR IS NOT NULL and T2.NR IS NULL
THEN CAST(T.NR as VARCHAR(MAX))+'-'
END AS NR_GRP
from T
left join T T1 on T.Grp=T1.Grp and t.Nr+1=t1.Nr
left join T T2 on T.Grp=T2.Grp and t.Nr-1=t2.Nr
WHERE T1.NR IS NULL or T2.NR IS NULL
)
SELECT
GRP,
REPLACE(
substring((SELECT ( ',' + NR_GRP)
FROM TRes t2
WHERE t1.GRP = t2.GRP
ORDER BY
GRP,
NR
FOR XML PATH( '' )
), 2, 10000 )
,'-,-','-')
FROM TRes t1
GROUP BY GRP
Please check my try:
DECLARE #T TABLE
(
ID INT IDENTITY(1, 1)
, GRP VARCHAR(10)
, NR INT
)
INSERT INTO #T
VALUES ('1',101),('1',102),('1',103),('1',105)
,('1-2',106),('1-2',109), ('1-2',110)
,('2',201),('2',202)
,('3',300),('3',350),('3',351),('3',352)
SELECT * FROM #T
;WITH T1 as
(
SELECT GRP, NR, ROW_NUMBER() over(order by GRP, NR) ID FROM #T
)
,T as (
SELECT *, 1 CNT FROM T1 where ID=1
union all
SELECT b.*, (case when T.NR+1=b.NR and T.GRP=b.GRP then t.CNT
else T.CNT+1 end)
from T1 b INNER JOIN T on b.ID=T.ID+1
)
, TN as(
select *,
MIN(NR) over(partition by GRP, CNT) MinVal,
MAX(NR) over(partition by GRP, CNT) MaxVal
From T
)
SELECT GRP, STUFF(
(SELECT distinct ','+(CASE WHEN MinVal=MaxVal THEN CAST(MinVal as nvarchar(10)) ELSE CAST(MinVal as nvarchar(10))+'-'+cast(MaxVal as nvarchar(10)) END)
FROM TN b where b.GRP=a.GRP
FOR XML PATH(''),type).value('.','nvarchar(max)'),1,1,'') AS [ACCOUNT NAMES]
FROM TN a GROUP BY GRP
I need to query some data in the below format in SQL Server:
Id Group Price
1 A 10
2 A 20
Sum 30
1 B 6
2 B 4
Sum 10
1 C 100
2 C 200
Sum 300
I was thinking to do it in the follwoing steps:
Query one group
In other query do sum
Use Union operator to combine this result set
Do step 1-3 for all groups and finally return all sub sets of data using union.
Is there a better way to do this ? May be using some out of box feature ? Please advise.
Edit:
As per suggestions and code sample I tried this code:
Select
Case
when id is null then 'SUM'
else CAST(id as Varchar(10)) end as ID,
Case when [group] is null then 'ALL' else CAST([group] as Varchar(50)) end as [group]
,Price from
(
SELECT Id, [Group],BGAApplicationID,Section, SUM(PrimaryTotalArea) AS price
FROM vwFacilityDetails
where bgaapplicationid=1102
GROUP BY Id, [Group],BGAApplicationID,Section WITH ROLLUP
) a
And Even this code as well:
Select Id, [Group],BGAApplicationID,Section, SUM(PrimaryTotalArea) AS price
From vwFacilityDetails
Where Not ([group] Is Null And id Is Null And BGAApplicationId is null and section is null) and BGAApplicationId=1102
Group By Id, [Group],BGAApplicationID,Section
With Rollup
In results it groups up the data but for every record it shows it 3 times (in both above codes) like:
2879 Existing Facilities Whole School 25.00
2879 Existing Facilities Whole School 25.00
2879 Existing Facilities Whole School 25.00
2879 ALL 25.00
I guess there is some issue in my query, please guide me here as well.
Thanks
SQL Server introduced GROUPING SETS which is what you should be looking to use.
SQL Fiddle
MS SQL Server 2008 Schema Setup:
Create Table vwFacilityDetails (
id int not null,
[group] char(1) not null,
PrimaryTotalArea int not null,
Section int,
bgaapplicationid int
);
Insert Into vwFacilityDetails (id, [group], Section,bgaapplicationid,PrimaryTotalArea) values
(1, 'A', 1,1102,2),
(1, 'A', 1,1102,1),
(1, 'A', 1,1102,7),
(2, 'A', 1,1102,20),
(1, 'B', 1,1102,6),
(2, 'B', 1,1102,4),
(1, 'C', 1,1102,100),
(2, 'C', 1,1102,200);
Query 1:
SELECT CASE WHEN Id is null then 'SUM'
ELSE Right(Id,10) end Id,
[Group],BGAApplicationID,Section,
SUM(PrimaryTotalArea) price
FROM vwFacilityDetails
where bgaapplicationid=1102
GROUP BY GROUPING SETS (
(Id,[Group],BGAApplicationID,Section),
([Group])
)
ORDER BY [GROUP],
ID;
Results:
| ID | GROUP | BGAAPPLICATIONID | SECTION | PRICE |
----------------------------------------------------
| 1 | A | 1102 | 1 | 10 |
| 2 | A | 1102 | 1 | 20 |
| SUM | A | (null) | (null) | 30 |
| 1 | B | 1102 | 1 | 6 |
| 2 | B | 1102 | 1 | 4 |
| SUM | B | (null) | (null) | 10 |
| 1 | C | 1102 | 1 | 100 |
| 2 | C | 1102 | 1 | 200 |
| SUM | C | (null) | (null) | 300 |
Select
id,
[Group],
SUM(price) AS price
From
Test
Group By
[group],
id
With
Rollup
http://sqlfiddle.com/#!3/080cd/8
Select Case when id is null then 'SUM' else CAST(id as Varchar(10)) end as ID
,Case when [group] is null then 'ALL' else CAST([group] as Varchar(10)) end as [group]
,Price from
(
SELECT id, [group], SUM(price) AS Price
FROM IG
GROUP BY [GROUP],ID WITH ROLLUP
) a