How can I make Access treat *1* as a string instead of using wildcard in the SQL
SELECT * FROM TABLE1 WHERE ID IN ("*1*","*2*");?
Sadly, this is a limitation of Access. You can use [*] to search for any single character, so:
TABLE1 WHERE ID IN ("[*]1[*]","[*]2[*]")
Would match any single leading and trailing character with 1 or 2 in the middle. Not what you want, but closer.
In this expression:
WHERE ID IN ("*1*", "*2*")
MS Access does treat the values as strings and not wildcards. The wildcards are only used for LIKE.
If you want them to be treated as wildcards, you need to use LIKE. That would require OR:
WHERE ID LIKE "*1*" OR ID LIKE "*2*"
Or more simply as:
WHERE ID LIKE "*[1-2]*"
Related
I'd like to get productids from url and I've almost finetuned a query to do it but still there is an issue I cannot solve.
The url usually looks like this:
/xp-pen/toll-spe43-deco-pro-small-medium-spe43-tobuy-p665088831/
or
/harry-potter-es-a-tuz-serlege-2019-m19247107/
As you can see there are two types of ids:
in general, ids start with '-p'
ids of some special products start with '-m'
I created this case when statement:
CASE
WHEN MAX(hits.page.pagePath) LIKE '%-p%'
THEN MAX(REGEXP_REPLACE(REGEXP_EXTRACT(
hits.page.pagePath, '-p[0-9]+/'), '\\-|p|/', ''))
WHEN MAX(hits.page.pagePath) LIKE '%-m%'
THEN MAX(REGEXP_REPLACE(REGEXP_EXTRACT(
hits.page.pagePath, '-m[0-9]+/'), '\\-|m|/', ''))
ELSE NULL
END AS productId
It's a little complicated at the first look but I really needed a regexp_replace and a regexp_extract because '-p' or '-m' characters doesn't appear only before the id but it can be multiplied times in a url.
The problem with my code is that there are some special cases when the url looks like this:
/elveszett-profeciak-2019-m17855487/
As you can see the id starts with '-m' but the url also contains '-p'. In this case the result is empty value in the query.
I think it could be solved by modifying the like operator in the when part of the case when statement: LIKE '%-p%' or LIKE '%-m%'
It would be great to have a regexp expression after or instead of the LIKE operator. Something similar to the parameter of '-p[0-9]+/' what I used in regexp_extract function.
So what I would need is to define in the when part of the statement that if the '-p' or '-m' text is followed by numbers in the urls
I'm not sure it's possible to do or not in BQ.
So what I would need is to define in the when part of the statement that if the '-p' or '-m' text is followed by numbers in the urls
I think you want '-p' and '-m' followed by digits. If so, I think this does what you want:
select regexp_extract(url, '-[pm][0-9]+')
from (select '/xp-pen/toll-spe43-deco-pro-small-medium-spe43-tobuy-p665088831/' as url union all
select '/elveszett-profeciak-2019-m17855487/' union all
select '/harry-potter-es-a-tuz-serlege-2019-m19247107/'
) x
Newbie here. Been searching for hours now but I can seem to find the correct answer or properly phrase my search.
I have thousands of rows (orderids) that I want to put on an IN function, I have to run a LIKE at the same time on these values since the columns contains json and there's no dedicated table that only has the order_id value. I am running the query in BigQuery.
Sample Input:
ORD12345
ORD54376
Table I'm trying to Query: transactions_table
Query:
SELECT order_id, transaction_uuid,client_name
FROM transactions_table
WHERE JSON_VALUE(transactions_table,'$.ordernum') LIKE IN ('%ORD12345%','%ORD54376%')
Just doesn't work especially if I have thousands of rows.
Also, how do I add the order id that I am querying so that it appears under an order_id column in the query result?
Desired Output:
Option one
WITH transf as (Select order_id, transaction_uuid,client_name , JSON_VALUE(transactions_table,'$.ordernum') as o_num from transactions_table)
Select * from transf where o_num like '%ORD12345%' or o_num like '%ORD54376%'
Option two
split o_num by "-" as separator , create table of orders like (select 'ORD12345' as num
Union
Select 'ORD54376' aa num) and inner join it with transf.o_num
One method uses OR:
WHERE JSON_VALUE(transactions_table, '$.ordernum') LIKE IN '%ORD12345%' OR
JSON_VALUE(transactions_table, '$.ordernum') LIKE '%ORD54376%'
An alternative method uses regular expressions:
WHERE REGEXP_CONTAINS(JSON_VALUE(transactions_table, '$.ordernum'), 'ORD12345|ORD54376')
According to the documentation, here, the LIKE operator works as described:
Checks if the STRING in the first operand X matches a pattern
specified by the second operand Y. Expressions can contain these
characters:
A percent sign "%" matches any number of characters or
bytes.
An underscore "_" matches a single character or byte.
You can escape "\", "_", or "%" using two backslashes. For example, "\%". If
you are using raw strings, only a single backslash is required. For
example, r"\%".
Thus , the syntax would be like the following:
SELECT
order_id,
transaction_uuid,
client_name
FROM
transactions_table
WHERE
JSON_VALUE(transactions_table,
'$.ordernum') LIKE '%ORD12345%'
OR JSON_VALUE(transactions_table,
'$.ordernum') LIKE '%ORD54376%
Notice that we specify two conditions connected with the OR logical operator.
As a bonus information, when querying large datasets it is a good pratice to select only the columns you desire in your out output ( either in a Temp Table or final view) instead of using *, because BigQuery is columnar, one of the reasons it is faster.
As an alternative for using LIKE, you can use REGEXP_CONTAINS, according to the documentation:
Returns TRUE if value is a partial match for the regular expression, regex.
Using the following syntax:
REGEXP_CONTAINS(value, regex)
However, it will also work if instead of a regex expression you use a STRING between single/double quotes. In addition, you can use the pipe operator (|) to allow the searched components to be logically ordered, when you have more than expression to search, as follows:
where regexp_contains(email,"gary|test")
I hope if helps.
I am trying to filter my sql query with a like condition using underscore in my where clause. However, when i am filtering i want all values with just TS_AW19 and not all values which include TS which is what my query is currently giving me. Could someone assist me with the correct syntax to use for my query below?
SELECT
date,
creative_name,
SUM(revenue)*2 as spend
FROM `crate-media-group-client-data.DV360_ALL.GGLDV360BM_CREATIVE_*`
WHERE advertiser LIKE '%Topshop/Topman%' AND creative_name LIKE '%TS_AW19%' AND date = '2019-09-20'
GROUP BY 1,2
ORDER by creative_name
Note: i am using big query syntax for this query
Underscore (and percent) has a special meaning when used with LIKE, and means a wildcard for any single character. To workaround this, from the BigQuery documentation for LIKE:
You can escape "\", "_", or "%" using two backslashes. For example, "\%". If you are using raw strings, only a single backslash is required. For example, r"\%".
You may try double-escaping the underscore, if you intend for it be literal in your LIKE expression:
SELECT
date,
creative_name,
SUM(revenue)*2 AS spend
FROM `crate-media-group-client-data.DV360_ALL.GGLDV360BM_CREATIVE_*`
WHERE
advertiser LIKE '%Topshop/Topman%' AND
creative_name LIKE '%TS\\_AW19%' AND
date = '2019-09-20'
GROUP BY 1,2
ORDER BY
creative_name;
In REGEX you can do something like [a-c]+, which will match on
aaabbbccc
abcccaabc
cbccaa
b
aaaaaaaaa
In SQL LIKE it seems that one can either do the equivalent of ".*" which is "%", or [a-c]. Is it possible to use the +(at least one) quantifier in SQL to do [a-c]+?
EDIT: Just to clarify, the desired end-query would look something like
SELECT * FROM table WHERE column LIKE '[a-c]+'
which would then match on the list above, but would NOT match on e.g "xxxxxaxxxx"
As a general rule, SQL Server's LIKE patterns are much weaker than regular expressions. For your particular example, you can do:
where col not like '%[^a-c]%'
That is, the column contains no characters that are not a, b, or c.
You can use regex in SQL with combination of LIKE e.g :
SELECT * FROM Table WHERE Field LIKE '%[^a-z0-9 .]%'
This works in SQL
Or in your case
SELECT * FROM Table WHERE Field LIKE '%[^a-c]%'
I seems you want some data from database, That is you don't know exactly, You must show your column and the all character that you want in that filed.
I am working with an Oracle database and would like to write a REGEXP_LIKE expression that finds any number where all digits are the same, such as '999999999' or '777777777' without specifying the length of the field. Also, I would like it to be able to identify characters as well, such as 'aaaaa'.
I was able to get it working when specifying the field length, by using this:
select * from table1
where regexp_like (field1, '^([0-9a-z])\1\1\1\1\1\1\1\1');
But I would like it to be able to do this for any field length.
If a field contains '7777771', for example, I would not want to see it in the results.
Try this:
^([0-9a-z])\1+$
Live demo
You're almost there. You just need to anchor the end of the regex.
^([0-9a-z])\1+$