I want to be able to increment a value when a "separator row" is reached.
As an example; zero is the separator row.
GROUP_ID
--------
1
1
1
0
1
1
0
1
1
1
What I want is:
GROUP_ID
--------
1
1
1
0
2
2
0
3
3
3
Of course outlier scenarios like starting with zero, or consecutive zeros can exist also. I though NTILE might be useful as it has a similar idea of creating buckets.
select START_DATE, END_DATE, DTEDIF, GROUP_ID
FROM (select START_DATE,
END_DATE,
DTEDIF,
(CASE
WHEN DTEDIF <= 24 THEN
1
ELSE
0
END) GROUP_ID
FROM (select START_DATE,
END_DATE,
MONTHS_BETWEEN(END_DATE, START_DATE) as DTEDIF
from (select start_date,
LEAD(start_date, 1) OVER(order by start_date) as END_DATE
from (select sysdate start_date
from dual
union all
select add_months(sysdate, 12) dt
from dual --12
union all
select add_months(sysdate, 22) dt
from dual --10
union all
select add_months(sysdate, 40) dt
from dual --18
union all
select add_months(sysdate, 68) dt
from dual --28
union all
select add_months(sysdate, 70) dt
from dual --18
union all
select add_months(sysdate, 88) dt
from dual --18
union all
select add_months(sysdate, 118) dt
from dual --30
))));
Here is one method: Count the number of zeros before each row:
select t.*,
(case when group_id = 0 then group_id
else sum(case when group_id = 0 then 1 else 0 end) over (order by <ordering column>)
end) as new_group_id
from t;
SQL tables represent unordered sets. So your question requires a separate column to represent the ordering of the data.
You can achieve this by using combination of lag and sum analytical function.
I consider that there is ordering column available with name id.
Select group_id,
Sum(case when coalesce(lag_group_id,0) then 1 else 0 end)
over(order by id) as your_result from
(Select id,
group_id,
lag(group_id) over (order by id) as lag_group_id
from your_table)
Cheers!!
Related
I'm trying to build a query for the following scenario,
Group records by license ID and get min and max dates
For a given license ID, if there are two earliest start dates, then start date of the particular ID has to be updated as latest start date in that grouping.
Since I'm new to sql, I need help to satisfy condition 2. Any help is greatly appreciated. Thanks
Actual data
LicenseID
StartDate
EndDate
100
4/3/2000
3/1/2013
100
4/3/2000
2/2/2017
100
3/1/2013
1/23/2015
100
1/23/2015
2/2/2017
100
2/2/2017
2/9/2018
100
2/2/2017
12/18/2018
100
12/18/2018
2/16/2021
Expected output
LicenseID
StartDate
EndDate
100
12/18/2018
2/16/2021
Here's one option; read comments within code.
Sample data:
SQL> with test (id, start_date, end_date) as
2 (select 100, date '2000-04-03', date '2013-03-01' from dual union all
3 select 100, date '2000-04-03', date '2017-02-02' from dual union all
4 select 100, date '2018-12-18', date '2021-02-16' from dual
5 ),
Query begins here:
6 -- rank start dates per each ID
7 temp as
8 (select id,
9 min(start_date) over (partition by id) min_sd,
10 max(start_date) over (partition by id) max_sd,
11 rank() over (partition by id order by start_date) rnk_sd,
12 --
13 max(end_date) over (partition by id) max_ed
14 from test
15 ),
16 -- count number of the 1st start dates
17 temp2 as
18 (select id,
19 sum(case when rnk_sd = 1 then 1 else 0 end) cnt_sd
20 from temp
21 group by id
22 )
23 -- if number of the 1st start dates is 1, take MIN_SD. Otherwise, take MAX_SD
24 select distinct
25 b.id,
26 case when b.cnt_sd = 1 then a.min_sd else a.max_sd end start_date,
27 a.max_ed end_date
28 from temp2 b join temp a on a.id = b.id;
Result:
ID START_DATE END_DATE
---------- ---------- ----------
100 12/18/2018 02/16/2021
SQL>
This can filter them:
WITH sample_data AS
(
SELECT 100 AS LicenseID, TO_DATE('04/03/2000','MM/DD/YYYY') AS StartDate, TO_DATE('03/01/2013','MM/DD/YYYY') AS EndDate FROM DUAL UNION ALL
SELECT 100, TO_DATE('04/03/2000','MM/DD/YYYY'), TO_DATE('02/02/2017','MM/DD/YYYY') FROM DUAL UNION ALL
SELECT 100, TO_DATE('03/01/2013','MM/DD/YYYY'), TO_DATE('01/23/2015','MM/DD/YYYY') FROM DUAL UNION ALL
SELECT 100, TO_DATE('01/23/2015','MM/DD/YYYY'), TO_DATE('02/02/2017','MM/DD/YYYY') FROM DUAL UNION ALL
SELECT 100, TO_DATE('02/02/2017','MM/DD/YYYY'), TO_DATE('02/09/2018','MM/DD/YYYY') FROM DUAL UNION ALL
SELECT 100, TO_DATE('02/02/2017','MM/DD/YYYY'), TO_DATE('12/18/2018','MM/DD/YYYY') FROM DUAL UNION ALL
SELECT 100, TO_DATE('12/18/2018','MM/DD/YYYY'), TO_DATE('02/16/2021','MM/DD/YYYY') FROM DUAL
)
SELECT dat.licenseID, CASE WHEN dups.licenseID IS NOT NULL THEN MAX(StartDate)
ELSE MIN(StartDate)
END,
CASE WHEN dups.licenseID IS NOT NULL THEN MAX(EndDate)
ELSE MIN(EndDate)
END
FROM sample_data dat
LEFT OUTER JOIN (SELECT COUNT(1), sd.LicenseID
FROM sample_data sd
INNER JOIN (SELECT MIN(StartDate) AS StartDate, LicenseID
FROM sample_data
GROUP BY LicenseID) mins
ON sd.LicenseID = mins.LicenseID AND sd.startDate = mins.StartDate
GROUP BY sd.LicenseID
HAVING COUNT(1) > 1) dups
ON dups.LicenseID = dat.licenseID
GROUP BY dat.licenseID, dups.licenseID;
You can use:
SELECT licenseid,
MAX(startdate) AS startdate,
MAX(enddate) KEEP (DENSE_RANK LAST ORDER BY startdate) AS enddate
FROM table_name
GROUP BY licenseid
HAVING COUNT(*) KEEP (DENSE_RANK FIRST ORDER BY startdate) > 1;
or:
SELECT licenseid,
max_startdate AS startdate,
max_enddate As enddate
FROM (
SELECT licenseid,
RANK()
OVER (PARTITION BY licenseid ORDER BY startdate) AS rnk,
ROW_NUMBER()
OVER (PARTITION BY licenseid, startdate ORDER BY enddate) AS rn,
MAX(startdate)
OVER (PARTITION BY licenseid) AS max_startdate,
MAX(enddate)
KEEP (DENSE_RANK LAST ORDER BY startdate)
OVER (PARTITION BY licenseid) AS max_enddate
FROM table_name t
)
WHERE rnk = 1
AND rn = 2;
Which, for the sample data:
CREATE TABLE table_name (licenseid, startdate, enddate) AS
SELECT 100, DATE'2000-04-03', DATE'2013-03-01' FROM DUAL UNION ALL
SELECT 100, DATE'2000-04-03', DATE'2017-02-02' FROM DUAL UNION ALL
SELECT 100, DATE'2013-03-01', DATE'2015-01-23' FROM DUAL UNION ALL
SELECT 100, DATE'2015-01-23', DATE'2017-02-02' FROM DUAL UNION ALL
SELECT 100, DATE'2017-02-02', DATE'2018-02-09' FROM DUAL UNION ALL
SELECT 100, DATE'2018-02-02', DATE'2018-12-18' FROM DUAL UNION ALL
SELECT 100, DATE'2018-12-18', DATE'2021-02-16' FROM DUAL;
Both output:
LICENSEID
STARTDATE
ENDDATE
100
2018-12-18 00:00:00
2021-02-16 00:00:00
If you do want to perform an UPDATE of that second row then:
MERGE INTO table_name dst
USING (
SELECT ROWID AS rid,
max_startdate,
max_enddate
FROM (
SELECT RANK()
OVER (PARTITION BY licenseid ORDER BY startdate) AS rnk,
ROW_NUMBER()
OVER (PARTITION BY licenseid, startdate ORDER BY enddate) AS rn,
MAX(startdate)
OVER (PARTITION BY licenseid) AS max_startdate,
MAX(enddate)
KEEP (DENSE_RANK LAST ORDER BY startdate)
OVER (PARTITION BY licenseid) AS max_enddate
FROM table_name t
)
WHERE rnk = 1
AND rn = 2
)src
ON (src.rid = dst.ROWID)
WHEN MATCHED THEN
UPDATE
SET startdate = src.max_startdate,
enddate = src.max_enddate;
db<>fiddle here
I am using sql oracle.
I have a table with an emplid and an effdt. I want to add a column in my select that gives the current_flag. I thought this query will do:
select emplid,effdt,
CASE ROW_NUMBER() OVER(PARTITION BY emplid order by effdt desc)
WHEN 1 THEN 'Y'
ELSE 'N'
END CURRENT_FLAG
from job_table
The problem is that I want a 'Y' for the highest effdt of an emplid, but the effdt < sysdate.
Example:
emplid effdt
x 01/01/2014
x 01/01/2015
x 01/01/2016
y 01/01/2014
y 01/01/2015
y 01/01/2016
y 01/01/2020
with my query I have a 'Y'
for the X on 01/01/2014 and
for y on 01/01/2020.
But I want as result:
emplid effdt current_flag
x 01/01/2014 N
x 01/01/2015 N
x 01/01/2016 Y
y 01/01/2014 N
y 01/01/2015 N
y 01/01/2016 Y
y 01/01/2020 N
because 01/01/2020 is not current but in the future.
or maybe an "F" for the value Y on the date 01/01/2020 to show it is in the Future.
I wanted to put an filter effdt < sysdate on my partition by, but I don't know how.
Try this, please. It must working
If I understand task
with tbl as
(SELECT 'x' as id, to_date('01/01/2014', 'dd/mm/yyyy') as dt FROM dual
UNION ALL
SELECT 'x' as id, to_date('01/01/2015', 'dd/mm/yyyy') as dt FROM dual
UNION ALL
SELECT 'y' as id, to_date('01/01/2015', 'dd/mm/yyyy') FROM dual
UNION ALL
SELECT 'y' as id, to_date('01/01/2016', 'dd/mm/yyyy') FROM dual
UNION ALL
SELECT 'y' as id, to_date('01/01/2020', 'dd/mm/yyyy') FROM dual)
select id, dt,
CASE ROW_NUMBER() OVER(PARTITION BY id order by case when dt > sysdate then to_date('01/01/1970', 'dd/mm/yyyy') else dt end desc)
WHEN 1 THEN 'Y'
ELSE 'N'
END flg
from tbl
If I understand task, you can 'F' mark date in "case":
when effdt < sysdate then 'F'
with tbl as
(SELECT 'x' as id, to_date('01/01/2014', 'dd/mm/yyyy') as dt FROM dual
UNION ALL
SELECT 'x' as id, to_date('01/01/2015', 'dd/mm/yyyy') as dt FROM dual
UNION ALL
SELECT 'y' as id, to_date('01/01/2015', 'dd/mm/yyyy') FROM dual
UNION ALL
SELECT 'y' as id, to_date('01/01/2016', 'dd/mm/yyyy') FROM dual
UNION ALL
SELECT 'y' as id, to_date('01/01/2020', 'dd/mm/yyyy') FROM dual)
select id, dt,
CASE WHEN dt > sysdate THEN 'F'
WHEN ROW_NUMBER() OVER (PARTITION BY id order by case when dt > sysdate
then to_date('01/01/1970', 'dd/mm/yyyy') else dt end desc) = 1
THEN 'Y'
ELSE 'N'
END flg
from tbl
x 01.01.2015 Y
x 01.01.2014 N
y 01.01.2016 Y
y 01.01.2015 N
y 01.01.2020 F
I would recommend:
select jt.*,
(case when max(case when effdt < sysdate then effdt end) over (partition by empid) = effdt
then 'Y' else 'N'
end)
from job_table jt;
Here is a db<>fiddle illustrating that this works where Rustam's answer does not.
This assumes that the dates are unique.
If that is possible, you can use row_number(), but it is a little cumbersome:
select jt.*,
(case when row_number() over (partition by empid
order by case when effdt < sysdate then 1 else 2 end, effdt desc
) and
effdt < sysdate
then 'Y' else 'N'
end)
from job_table jt;
I have a table with emplid and end_date columns. I want from all emplids the max end_dates. If at least one end_date is null, I want to have the null value as max. So in this example:
emplid end_date
1 05/04/2019
1 05/10/2019
1 null
2 05/04/2019
2 05/10/2019
I want as result:
emplid end_date
1 null
2 05/10/2019
I tried something like
select emplid,
CASE
WHEN MAX(NVL(end_Date,'01/01/3000'))='01/01/3000' THEN null
ELSE end_date
END as end_dt
from people
group by emplid
then I get a group-by error.
Maybe it is very easy, but I don't figure out how to get properly what I want.
with s(id, dt) as (
select 1, to_date('05/04/2019', 'dd/mm/yyyy') from dual union all
select 1, to_date('05/10/2019', 'dd/mm/yyyy') from dual union all
select 1, null from dual union all
select 2, to_date('05/04/2019', 'dd/mm/yyyy') from dual union all
select 2, to_date('05/10/2019', 'dd/mm/yyyy') from dual)
select id, decode(count(dt), count(*), max(dt)) max_dt
from s
group by id;
ID MAX_DT
---------- -----------------------------
1
2 2019-10-05 00:00:00
I would simply do:
select emplid,
(case when count(*) = count(end_date)
then max(end_date)
end) as max_end_date
from t
group by emplid;
There is no reason to introduce a "magic" maximum value (even if it is correct).
The first expression in the case is simply asking "do the number of non-NULL end-date values match the number of rows".
Try this
SELECT
EMPLID,
CASE WHEN END_DATE='01/01/3000' THEN NULL ELSE END_DATE END AS END_DT
FROM
(
SELECT EMPLID, MAX(END_DATE) AS END_DATE FROM
(
SELECT EMPLID, NVL(END_DATE,'01/01/3000') AS END_DATE FROM PEOPLE
)
GROUP BY EMPLID
);
Case does not go with group by , you have to get the max value using group by first then evaluate the null values. Try below.
select empid, CASE WHEN NVL(eDate,'01-DEC-3000')='01-DEC-3000' THEN null ELSE edate end end_dt from (
select empid, MAX(NVL(eDate,'01-DEC-3000')) eDate
from
(select 1 empid, sysdate-100 edate from dual union all
select 1 empid, sysdate-10 edate from dual union all
select 1 empid, null edate from dual union all
select 2 empid, sysdate-105 edate from dual union all
select 2 empid, sysdate-1 edate from dual ) datad
group by empid);
I have a table that looks like this:
+--------------------+---------+
| Month (date) | amount |
+--------------------+---------+
| 2016-10-01 | 20 |
| 2016-08-01 | 10 |
| 2016-07-01 | 17 |
+--------------------+---------+
I'm looking for a query (sql statement) which satisfies the following conditions:
Give me the value of the previous month.
If there is no value for the previous month lock back in time until one can be found.
If there is just a value for the current month give me this value.
In the example table the row I'm looking for would be this:
+--------------------+---------+
| 2016-08-01 | 10 |
+--------------------+---------+
Has anyone a idea for a non complex select query?
Thanks in advance,
Peter
You may need the following:
SELECT *
FROM ( SELECT *
FROM test
WHERE TRUNC(SYSDATE, 'month') >= month
ORDER BY CASE
WHEN TRUNC(SYSDATE, 'month') = month
THEN 0 /* if current month, ordered last */
ELSE 1 /* previous months are ordered first */
END DESC,
month DESC /* among previous months, the greatest first */
)
WHERE ROWNUM = 1
Another way using MAX
WITH tbl AS (
SELECT TO_DATE('2016-10-01', 'YYYY-MM-DD') AS "month", 20 AS amount FROM dual
UNION
SELECT TO_DATE('2016-08-01', 'YYYY-MM-DD') AS "month", 10 AS amount FROM dual
UNION
SELECT TO_DATE('2016-07-01', 'YYYY-MM-DD') AS "month", 5 AS amount FROM dual
)
SELECT *
FROM tbl
WHERE TRUNC("month", 'MONTH') = NVL((SELECT MAX(t."month")
FROM tbl t
WHERE t."month" < TRUNC(SYSDATE, 'MONTH')),
TRUNC(SYSDATE, 'MONTH'));
I would use row_number():
select t.*
from (select t.*,
row_number() over (order by (case when to_char(dte, 'YYYY-MM') = to_char(sysdate, 'YYYY-MM') then 1 else 2 end) desc,
dte desc
) as seqnum
from t
) t
where seqnum = 1;
Actually, you don't need row_number() for this:
select t.*
from (select t.*
from t
order by (case when to_char(dte, 'YYYY-MM') = to_char(sysdate, 'YYYY-MM') then 1 else 2 end) desc,
dte desc
) t
where rownum = 1;
It's not the nicest query but it should work.
select amount, date from (
select amount, date, row_number over(partition by HERE_PUT_ID order by
case trunc(date, 'month') when trunc(sysdate, 'month') then to_date('00010101', 'yyyymmdd') else trunc(date, 'month') end
desc) r)
where r = 1;
I guess you have some id in table so put id column instead of HERE_PUT_ID if you want query for whole table just delete: partition by HERE_PUT_ID
I added more data for testing, and an "id" column (a more realistic scenario) to show how this would work. If there is no "id" in your data, simply delete any reference to it from the solution.
Notes - month is a reserved Oracle word, don't use it as a column name. The solution assumes the date column contains dates that are already truncated to the beginning of the month. The trick in "order by" in the dense_rank last is to assign a value (ANY value!) when the month is the current month; by default, the value assigned to all other months is NULL, which by default come after any non-null value in an ascending order.
You may want to test the various solutions for efficiency if execution time is important.
with
inputs ( id, mth, amount ) as (
select 1, date '2016-10-01', 20 from dual union all
select 1, date '2016-08-01', 10 from dual union all
select 1, date '2016-07-01', 17 from dual union all
select 2, date '2016-10-01', 30 from dual union all
select 2, date '2016-09-01', 25 from dual union all
select 3, date '2016-10-01', 20 from dual union all
select 4, date '2016-08-01', 45 from dual union all
select 4, date '2016-06-01', 30 from dual
)
-- end of TEST DATA - the solution (SQL query) is below this line
select id,
max(mth) keep(dense_rank last order by
case when mth = trunc(sysdate, 'mm') then 0 end, mth) as mth,
max(amount) keep(dense_rank last order by
case when mth = trunc(sysdate, 'mm') then 0 end, mth) as amount
from inputs
group by id
order by id -- ORDER BY is optional
;
ID MTH AMOUNT
--- ---------- -------
1 2016-08-01 10
2 2016-09-01 25
3 2016-10-01 20
4 2016-08-01 45
You could sort the data in the direction you want to:
with MyData as
(
SELECT to_date('2016-10-01','YYYY-MM-DD') MY_DATE, 20 AMOUNT FROM DUAL UNION
SELECT to_date('2016-08-01','YYYY-MM-DD') MY_DATE, 10 AMOUNT FROM DUAL UNION
SELECT to_date('2016-07-01','YYYY-MM-DD') MY_DATE, 17 AMOUNT FROM DUAL
),
MyResult AS (
SELECT
D.*
FROM MyData D
ORDER BY
DECODE(
12*TO_CHAR(MY_DATE,'YYYY') + TO_CHAR(MY_DATE,'MM'),
12*TO_CHAR(SYSDATE,'YYYY') + TO_CHAR(SYSDATE,'MM'),
-1,
12*TO_CHAR(MY_DATE,'YYYY') + TO_CHAR(MY_DATE,'MM'))
DESC
)
SELECT * FROM MyResult WHERE RowNum = 1
I have a table named x . The data is as follows.
Acccount_num start_dt end_dt
A111326 02/01/2016 02/11/2016
A111326 02/12/2016 03/05/2016
A111326 03/02/2016 03/16/2016
A111331 02/28/2016 02/29/2016
A111331 02/29/2016 03/29/2016
A999999 08/25/2015 08/25/2015
A999999 12/19/2015 12/22/2015
A222222 11/06/2015 11/10/2015
A222222 05/16/2016 05/17/2016
Both A111326 and A111331 should be identified as contiguous data and A999999 and
A222222 should be identified as discontinuous data.In my code I currently use the following query to identify discontinuous data. The A111326 is also erroneously identified as discontinuous data. Please help to modify the below code so that A111326 is not identified as discontinuous data.Thanks in advance for your help.
(SELECT account_num
FROM (SELECT account_num,
(MAX (
END_DT)
OVER (PARTITION BY account_num
ORDER BY START_DT))
START_DT,
(LEAD (
START_DT)
OVER (PARTITION BY account_num
ORDER BY START_DT))
END_DT
FROM x
WHERE (START_DT + 1) <=
(END_DT - 1))
WHERE START_DT < END_DT);
Oracle Setup:
CREATE TABLE accounts ( Account_num, start_dt, end_dt ) AS
SELECT 'A', DATE '2016-02-01', DATE '2016-02-11' FROM DUAL UNION ALL
SELECT 'A', DATE '2016-02-12', DATE '2016-03-05' FROM DUAL UNION ALL
SELECT 'A', DATE '2016-03-02', DATE '2016-03-16' FROM DUAL UNION ALL
SELECT 'B', DATE '2016-02-28', DATE '2016-02-29' FROM DUAL UNION ALL
SELECT 'B', DATE '2016-02-29', DATE '2016-03-29' FROM DUAL UNION ALL
SELECT 'C', DATE '2015-08-25', DATE '2015-08-25' FROM DUAL UNION ALL
SELECT 'C', DATE '2015-12-19', DATE '2015-12-22' FROM DUAL UNION ALL
SELECT 'D', DATE '2015-11-06', DATE '2015-11-10' FROM DUAL UNION ALL
SELECT 'D', DATE '2016-05-16', DATE '2016-05-17' FROM DUAL UNION ALL
SELECT 'E', DATE '2016-01-01', DATE '2016-01-02' FROM DUAL UNION ALL
SELECT 'E', DATE '2016-01-05', DATE '2016-01-06' FROM DUAL UNION ALL
SELECT 'E', DATE '2016-01-03', DATE '2016-01-07' FROM DUAL;
Query:
WITH times ( account_num, dt, lvl ) AS (
SELECT Account_num, start_dt - 1, 1 FROM accounts
UNION ALL
SELECT Account_num, end_dt, -1 FROM accounts
)
, totals ( account_num, dt, total ) AS (
SELECT account_num,
dt,
SUM( lvl ) OVER ( PARTITION BY Account_num ORDER BY dt, lvl DESC )
FROM times
)
SELECT Account_num,
CASE WHEN COUNT( CASE total WHEN 0 THEN 1 END ) > 1
THEN 'N'
ELSE 'Y'
END AS is_contiguous
FROM totals
GROUP BY Account_Num
ORDER BY Account_Num;
Output:
ACCOUNT_NUM IS_CONTIGUOUS
----------- -------------
A Y
B Y
C N
D N
E Y
Alternative Query:
(It's exactly the same method just using UNPIVOT rather than UNION ALL.)
SELECT Account_num,
CASE WHEN COUNT( CASE total WHEN 0 THEN 1 END ) > 1
THEN 'N'
ELSE 'Y'
END AS is_contiguous
FROM (
SELECT Account_num,
SUM( lvl ) OVER ( PARTITION BY Account_Num
ORDER BY CASE lvl WHEN 1 THEN dt - 1 ELSE dt END,
lvl DESC
) AS total
FROM accounts
UNPIVOT ( dt FOR lvl IN ( start_dt AS 1, end_dt AS -1 ) )
)
GROUP BY Account_Num
ORDER BY Account_Num;
WITH cte AS (
SELECT
AccountNumber
,CASE
WHEN
LAG(End_Dt) OVER (PARTITION BY AccountNumber ORDER BY End_Dt) IS NULL THEN 0
WHEN
LAG(End_Dt) OVER (PARTITION BY AccountNumber ORDER BY End_Dt) >= Start_Dt - 1 THEN 0
ELSE 1
END as discontiguous
FROM
#Table
)
SELECT
AccountNumber
,CASE WHEN SUM(discontiguous) > 0 THEN 'discontiguous' ELSE 'contiguous' END
FROM
cte
GROUP BY
AccountNumber;
One of your problems is that your contiguous desired result also includes overlapping date ranges in your example data set. Example A111326 Starts on 3/2/2016 but ends the row before on 3/5/2015 meaning it overlaps by 3 days.