I have a scenario, where 100's of select statements sql's are in one metadata table or some text file.
Need to insert all sql results into one specific table. (master table has col1, col2,col3 .... 200columns )
problem im facing(ORA-00947) is every select statement has different number of columns.
.. i need to generate INSERT PART.
CASE 1 : INSERT INTO (COL1,COL2,COL3) <<this select part comes from file/variable>>
CASE 2 : INSERT INTO (COL1) <<this select part comes from file/variable>>
CASE 3 : INSERT INTO (COL1) <<this select part comes from file/variable>>
have to figure out how many columns are in select part then generate INSERT part.
.
Thought of create as select but problem is some select statement has max(col) without alias so it will fail.
This is too long for a comment.
If you are storing SQL in a table, then you are constructing your query dynamically. So, update the table and list the columns that you want.
You could then construct the inserts as :
insert into master_table (<column list here>)
<select here>;
Both the select and column list would come from the table.
By far the easiest is to create a view for each SELECT statement. Then you can query the USER_TAB_COLUMNS view on the view name and get the column names.
Best regards,
Stew Ashton
Related
Is that applicable to use INSERT inside SELECT statement, in order to insert some data whenever we select. the scenarion is i need to audit the select operations so whenever we run SELECT statemnt we need to insert into a nother table, i have all the code for the select operation all what i need is to find a way to add INSERT statement inside SELECT statement
EX
SELECT *, (
INSERT INTO auditTable(ID, CREATEDINFO) VALUES ( :v0, :v1)
) FROM mainTable;
As suggested in the comments, there may be better ways to do what you are asking, but for the example you have shown, you want to do something like this:
INSERT INTO auditTable(ID, CREATEDINFO)
SELECT *
FROM mainTable;
Note: I'm assuming there are only two rows in mainTable as your query suggests, otherwise you should specify which rows you are selecting rather than using *
I have a table with PK and another column for other id. In some cases i need to insert record with equal values in both columns. For primary key values i'm using sequence, which gives a Field<Long> from Sequences.MY_SEQ.nextval().
How can i extract value from a Field<Long> for guaranteed insert same ids in both columns? Using Field<Long> in insert clause generates 2 different ids in columns.
Here is the solution:
Long id = dsl.select(Sequences.MY_SEQ.nextval()).fetchOne().value1();
Your own solution works, of course, but it will generate two round trips to the database. One for fetching the sequence value and another one for the insert. If that's not a problem, perfect. Otherwise, you can still do it in one single query using INSERT .. SELECT:
In SQL:
(using Oracle syntax. Your SQL syntax may vary...)
INSERT INTO my_table (col1, col2, val)
SELECT t.id, t.id, 'abc'
FROM (
SELECT my_seq.nextval AS id
FROM dual
) t
With jOOQ
Table<?> t = table(select(MY_SEQ.nextval().as("id"))).as("t");
dsl.insertInto(MY_TABLE)
.columns(MY_TABLE.COL1, MY_TABLE.COL2, MY_TABLE.VAL)
.select(
select(t.field("id"), t.field("id"), val("abc"))
.from(t))
.execute();
I want to insert data into one table from another table. In some of the columns I don't have data, so I want to set column to null. I don't know how I should do this?
This is the SQL:
INSERT INTO _21Appoint(
PCUCODE,PID,SEQ,
DATE_SERV,APDATE,
APTYPE,APDIAG,D_UPDATE,CID
) SELECT (
NULL,NULL,NULL,
treatment_date,appointment_date,
typeap_id,appointment_id,NULL,patient_id
) FROM cmu_treatment,cmu_appointment
WHERE cmu_treatment.treatment_id LIKE cmu_appointment.treatment_id;
Your insert is essentially correct. Just don't put the column list in parentheses:
INSERT INTO _21Appoint
(PCUCODE,PID,SEQ,DATE_SERV,APDATE,APTYPE,APDIAG,D_UPDATE,CID)
SELECT NULL,NULL,NULL,treatment_date,appointment_date,typeap_id,appointment_id,NULL,patient_id
FROM cmu_treatment,cmu_appointment
WHERE cmu_treatment.treatment_id LIKE cmu_appointment.treatment_id;
In Postgres (unlike other DBMS) putting a column list in parentheses makes the result a single "record", rather then individual columns. And therefore the select only returns a single column, not multiples and thus it doesn't match the column list for the insert
another option is to simply leave out the columns completely:
INSERT INTO _21Appoint
(DATE_SERV,APDATE,APTYPE,APDIAG,CID)
SELECT treatment_date,appointment_date,typeap_id,appointment_id,patient_id
FROM cmu_treatment,cmu_appointment
WHERE cmu_treatment.treatment_id LIKE cmu_appointment.treatment_id;
I want to select some data using simple sql and insert those data into another table. Both table are same. Data types and column names all are same. Simply those are temporary table of masters table. Using single sql I want to insert those data into another table and in the where condition I check E_ID=? checking part. My another problem is sometime there may be any matching rows in the table. In that time is it may be out sql exception? Another problem is it may be multiple matching rows. That means one E_ID may have multiple rows. As a example in my attachment_master and attachments_temp table has multiple rows for one single ID. How do I solve those problems? I have another problem. My master table data can insert temp table using following code. But I want to change only one column and others are same data. Because I want to change temp table status column.
insert into dates_temp_table SELECT * FROM master_dates_table where e_id=?;
In here all data insert into my dates_temp_table. But I want to add all column data and change only dates_temp_table status column as "Modified". How should I change this code?
You could try this:
insert into table1 ( col1, col2, col3,.... )
SELECT col1, col2, col3, ....
FROM table2 where (you can check any condition here on table1 or table2 or mixed)
For more info have a look here and this similar question
Hope it may help you.
EDit : If I understand your requirement properly then this may be a helpful solution for you:
insert into table1 ( col-1, col-2, col-3,...., col-n, <Your modification col name here> )
SELECT col-1, col-2, col-3,...., col-n, 'modified'
FROM table2 where table1.e_id=<your id value here>
As per your comment in above other answer:
"I send my E_ID. I don't want to matching and get. I send my E_ID and
if that ID available I insert those data into my temp table and change
temp table status as 'Modified' and otherwise don't do anything."
As according to your above statements, If given e_id is there it will copy all the columns values to your table1 and will place a value 'modified' in the 'status' column of your table1
For more info look here
You can use merge statement if I understand your requirement correctly.
Documentation
As I do not have your table structure below is based on assumption, see whether this cater your requirement. I am assuming that e_id is primary key or change as per your table design.
MERGE INTO dates_temp_table trgt
USING (SELECT * FROM master_dates_table WHERE e_id=100) src
ON (trgt.prm_key = src.prm_key)
WHEN NOT MATCHED
THEN
INSERT (trgt.col, trgt.col2, trgt.status)
VALUES (src.col, src.col2, 'Modified');
More information and examples here
insert into tablename( column1, column2, column3,column4 ) SELECT column1,
column2, column3,column4 from anothertablename where tablename.ID=anothertablename.ID
IF multiple values are there then it will return the last result..If not you have narrow your search..
I am trying to find the syntax for inserting the results from an UNPIVOT statement into an existing table in the database?
simplest answer which works for any SELECT including UNPIVOT would be...
INSERT INTO MyTable
SELECT statement
However, this does require that your destination tables columns match your SELECT statement columns.
Although you can get around this limitation with...
INSERT INTO MyTable (column1, column2....)
SELECT statement