I'm having trouble separating the first name from the middle name column in SQL Server 2017 - sql

Question

I created this syntax to separate first name, middle name and last name from a column called invertornames. Just to note that the investor names are in arabic and their middle names are more than 3 words. It worked fine but the first name is also being included in the middle name as you can see below in the image
This is the query I wrote:
SELECT
SUBSTRING(investor_name, CHARINDEX(', ', investor_name) + 2, CASE WHEN CHARINDEX(' ', investor_name, CHARINDEX(', ', investor_name) + 2) = 0 THEN LEN(investor_name) + 1 ELSE CHARINDEX(' ', investor_name, CHARINDEX(', ', investor_name) + 2) END - CHARINDEX(', ', investor_name) - 2)AS FirstName,
RTRIM(LTRIM(REPLACE(REPLACE(investor_name,SUBSTRING(investor_name , 1, CHARINDEX(' ', investor_name) -1),''),REVERSE( LEFT( REVERSE(investor_name), CHARINDEX(' ', REVERSE(investor_name))-1 ) ),''))) AS MiddleName,
RIGHT(investor_name, CHARINDEX(' ', REVERSE(investor_name))) AS LastName
FROM
investornames
If you need any data to try it please let me know.

Answer 1

You may try this. I consider that First word is considered as Firstname, second word is considered as MiddleName and remaining word will considered as LastName.
For the case of arabic names. Software will not automatically detect that for which name calculation start from the front and for which it is taken in reverse. So I guess you need to maintain a flag for same.
In case of arabic name in the portion of cte use reverse to arrange them in left to right order instead of right to left order. And at the end use reverse function again to convert them into their original state.
Hope I am clear about what I am explaining. Sample code is following :-
; with cte as (
select 'Deepak kumar singh' as names
union
select 'Deep'
union
select 'deep kumar'
union
select 'Deepak kumar singh chandel')
SELECT
Reverse(ParseName(Replace(Reverse(names), ' ', '.'), 1)) As [FirstName]
, Reverse(ParseName(Replace(Reverse(names), ' ', '.'), 2)) As [MiddleName]
, case when len( Reverse(ParseName(Replace(Reverse(names), ' ', '.'), 3)))>0 then substring ( names ,
charindex ( Reverse(ParseName(Replace(Reverse(names), ' ', '.'), 2)) + ' ', names) + len(Reverse(ParseName(Replace(Reverse(names), ' ', '.'), 2)) + ' ') + 1
, len(names) - charindex ( Reverse(ParseName(Replace(Reverse(names), ' ', '.'), 2)) + ' ', names) + len(Reverse(ParseName(Replace(Reverse(names), ' ', '.'), 2)) + ' ')) else null end
As [LastName]
FROM (Select names from cte ) As [x]
Result of above query is:
FirstName MiddleName LastName
Deep NULL NULL
deep kumar NULL
Deepak kumar singh
deepak kumar singh chandel
Edit
Updated this ans check this
; with cte as (
select ' شركة عبدالمحسن عبدالعزيزالبابطين ' as names
union
select 'شركة'
union
select 'عبدالمحسن عبدالعزيز'
union
select 'البابطين')
, ct as (
select RTRIM(LTRIM(names)) as Names from cte )
SELECT
Reverse(ParseName(Replace(Reverse(names), ' ', '.'), 1)) As [FirstName]
, Reverse(ParseName(Replace(Reverse(names), ' ', '.'), 2)) As [MiddleName]
, case when len( Reverse(ParseName(Replace(Reverse(names), ' ', '.'), 3)))>0 then substring ( names ,
charindex ( Reverse(ParseName(Replace(Reverse(names), ' ', '.'), 2)) + ' ', names) + len(Reverse(ParseName(Replace(Reverse(names), ' ', '.'), 2)) + ' ') + 1
, len(names) - charindex ( Reverse(ParseName(Replace(Reverse(names), ' ', '.'), 2)) + ' ', names) + len(Reverse(ParseName(Replace(Reverse(names), ' ', '.'), 2)) + ' ')) else null end
As [LastName]
FROM (Select names from ct ) As [x]
Result
FirstName MiddleName LastName
???? ????????? ?????????????????
???? NULL NULL
???????? NULL NULL
????????? ????????? NULL
Here I am expecting on place of ? you'll get your result. BTW I've updated my query, have you tried this one. Just give one more try.