Related
I tried to search posts, but I only found solutions for SQL Server/Access. I need a solution in MySQL (5.X).
I have a table (called history) with 3 columns: hostid, itemname, itemvalue.
If I do a select (select * from history), it will return
+--------+----------+-----------+
| hostid | itemname | itemvalue |
+--------+----------+-----------+
| 1 | A | 10 |
+--------+----------+-----------+
| 1 | B | 3 |
+--------+----------+-----------+
| 2 | A | 9 |
+--------+----------+-----------+
| 2 | C | 40 |
+--------+----------+-----------+
How do I query the database to return something like
+--------+------+-----+-----+
| hostid | A | B | C |
+--------+------+-----+-----+
| 1 | 10 | 3 | 0 |
+--------+------+-----+-----+
| 2 | 9 | 0 | 40 |
+--------+------+-----+-----+
I'm going to add a somewhat longer and more detailed explanation of the steps to take to solve this problem. I apologize if it's too long.
I'll start out with the base you've given and use it to define a couple of terms that I'll use for the rest of this post. This will be the base table:
select * from history;
+--------+----------+-----------+
| hostid | itemname | itemvalue |
+--------+----------+-----------+
| 1 | A | 10 |
| 1 | B | 3 |
| 2 | A | 9 |
| 2 | C | 40 |
+--------+----------+-----------+
This will be our goal, the pretty pivot table:
select * from history_itemvalue_pivot;
+--------+------+------+------+
| hostid | A | B | C |
+--------+------+------+------+
| 1 | 10 | 3 | 0 |
| 2 | 9 | 0 | 40 |
+--------+------+------+------+
Values in the history.hostid column will become y-values in the pivot table. Values in the history.itemname column will become x-values (for obvious reasons).
When I have to solve the problem of creating a pivot table, I tackle it using a three-step process (with an optional fourth step):
select the columns of interest, i.e. y-values and x-values
extend the base table with extra columns -- one for each x-value
group and aggregate the extended table -- one group for each y-value
(optional) prettify the aggregated table
Let's apply these steps to your problem and see what we get:
Step 1: select columns of interest. In the desired result, hostid provides the y-values and itemname provides the x-values.
Step 2: extend the base table with extra columns. We typically need one column per x-value. Recall that our x-value column is itemname:
create view history_extended as (
select
history.*,
case when itemname = "A" then itemvalue end as A,
case when itemname = "B" then itemvalue end as B,
case when itemname = "C" then itemvalue end as C
from history
);
select * from history_extended;
+--------+----------+-----------+------+------+------+
| hostid | itemname | itemvalue | A | B | C |
+--------+----------+-----------+------+------+------+
| 1 | A | 10 | 10 | NULL | NULL |
| 1 | B | 3 | NULL | 3 | NULL |
| 2 | A | 9 | 9 | NULL | NULL |
| 2 | C | 40 | NULL | NULL | 40 |
+--------+----------+-----------+------+------+------+
Note that we didn't change the number of rows -- we just added extra columns. Also note the pattern of NULLs -- a row with itemname = "A" has a non-null value for new column A, and null values for the other new columns.
Step 3: group and aggregate the extended table. We need to group by hostid, since it provides the y-values:
create view history_itemvalue_pivot as (
select
hostid,
sum(A) as A,
sum(B) as B,
sum(C) as C
from history_extended
group by hostid
);
select * from history_itemvalue_pivot;
+--------+------+------+------+
| hostid | A | B | C |
+--------+------+------+------+
| 1 | 10 | 3 | NULL |
| 2 | 9 | NULL | 40 |
+--------+------+------+------+
(Note that we now have one row per y-value.) Okay, we're almost there! We just need to get rid of those ugly NULLs.
Step 4: prettify. We're just going to replace any null values with zeroes so the result set is nicer to look at:
create view history_itemvalue_pivot_pretty as (
select
hostid,
coalesce(A, 0) as A,
coalesce(B, 0) as B,
coalesce(C, 0) as C
from history_itemvalue_pivot
);
select * from history_itemvalue_pivot_pretty;
+--------+------+------+------+
| hostid | A | B | C |
+--------+------+------+------+
| 1 | 10 | 3 | 0 |
| 2 | 9 | 0 | 40 |
+--------+------+------+------+
And we're done -- we've built a nice, pretty pivot table using MySQL.
Considerations when applying this procedure:
what value to use in the extra columns. I used itemvalue in this example
what "neutral" value to use in the extra columns. I used NULL, but it could also be 0 or "", depending on your exact situation
what aggregate function to use when grouping. I used sum, but count and max are also often used (max is often used when building one-row "objects" that had been spread across many rows)
using multiple columns for y-values. This solution isn't limited to using a single column for the y-values -- just plug the extra columns into the group by clause (and don't forget to select them)
Known limitations:
this solution doesn't allow n columns in the pivot table -- each pivot column needs to be manually added when extending the base table. So for 5 or 10 x-values, this solution is nice. For 100, not so nice. There are some solutions with stored procedures generating a query, but they're ugly and difficult to get right. I currently don't know of a good way to solve this problem when the pivot table needs to have lots of columns.
SELECT
hostid,
sum( if( itemname = 'A', itemvalue, 0 ) ) AS A,
sum( if( itemname = 'B', itemvalue, 0 ) ) AS B,
sum( if( itemname = 'C', itemvalue, 0 ) ) AS C
FROM
bob
GROUP BY
hostid;
Another option,especially useful if you have many items you need to pivot is to let mysql build the query for you:
SELECT
GROUP_CONCAT(DISTINCT
CONCAT(
'ifnull(SUM(case when itemname = ''',
itemname,
''' then itemvalue end),0) AS `',
itemname, '`'
)
) INTO #sql
FROM
history;
SET #sql = CONCAT('SELECT hostid, ', #sql, '
FROM history
GROUP BY hostid');
PREPARE stmt FROM #sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
FIDDLE
Added some extra values to see it working
GROUP_CONCAT has a default value of 1000 so if you have a really big query change this parameter before running it
SET SESSION group_concat_max_len = 1000000;
Test:
DROP TABLE IF EXISTS history;
CREATE TABLE history
(hostid INT,
itemname VARCHAR(5),
itemvalue INT);
INSERT INTO history VALUES(1,'A',10),(1,'B',3),(2,'A',9),
(2,'C',40),(2,'D',5),
(3,'A',14),(3,'B',67),(3,'D',8);
hostid A B C D
1 10 3 0 0
2 9 0 40 5
3 14 67 0 8
Taking advantage of Matt Fenwick's idea that helped me to solve the problem (a lot of thanks), let's reduce it to only one query:
select
history.*,
coalesce(sum(case when itemname = "A" then itemvalue end), 0) as A,
coalesce(sum(case when itemname = "B" then itemvalue end), 0) as B,
coalesce(sum(case when itemname = "C" then itemvalue end), 0) as C
from history
group by hostid
I edit Agung Sagita's answer from subquery to join.
I'm not sure about how much difference between this 2 way, but just for another reference.
SELECT hostid, T2.VALUE AS A, T3.VALUE AS B, T4.VALUE AS C
FROM TableTest AS T1
LEFT JOIN TableTest T2 ON T2.hostid=T1.hostid AND T2.ITEMNAME='A'
LEFT JOIN TableTest T3 ON T3.hostid=T1.hostid AND T3.ITEMNAME='B'
LEFT JOIN TableTest T4 ON T4.hostid=T1.hostid AND T4.ITEMNAME='C'
use subquery
SELECT hostid,
(SELECT VALUE FROM TableTest WHERE ITEMNAME='A' AND hostid = t1.hostid) AS A,
(SELECT VALUE FROM TableTest WHERE ITEMNAME='B' AND hostid = t1.hostid) AS B,
(SELECT VALUE FROM TableTest WHERE ITEMNAME='C' AND hostid = t1.hostid) AS C
FROM TableTest AS T1
GROUP BY hostid
but it will be a problem if sub query resulting more than a row, use further aggregate function in the subquery
If you could use MariaDB there is a very very easy solution.
Since MariaDB-10.02 there has been added a new storage engine called CONNECT that can help us to convert the results of another query or table into a pivot table, just like what you want:
You can have a look at the docs.
First of all install the connect storage engine.
Now the pivot column of our table is itemname and the data for each item is located in itemvalue column, so we can have the result pivot table using this query:
create table pivot_table
engine=connect table_type=pivot tabname=history
option_list='PivotCol=itemname,FncCol=itemvalue';
Now we can select what we want from the pivot_table:
select * from pivot_table
More details here
My solution :
select h.hostid, sum(ifnull(h.A,0)) as A, sum(ifnull(h.B,0)) as B, sum(ifnull(h.C,0)) as C from (
select
hostid,
case when itemName = 'A' then itemvalue end as A,
case when itemName = 'B' then itemvalue end as B,
case when itemName = 'C' then itemvalue end as C
from history
) h group by hostid
It produces the expected results in the submitted case.
I make that into Group By hostId then it will show only first row with values,
like:
A B C
1 10
2 3
I figure out one way to make my reports converting rows to columns almost dynamic using simple querys. You can see and test it online here.
The number of columns of query is fixed but the values are dynamic and based on values of rows. You can build it So, I use one query to build the table header and another one to see the values:
SELECT distinct concat('<th>',itemname,'</th>') as column_name_table_header FROM history order by 1;
SELECT
hostid
,(case when itemname = (select distinct itemname from history a order by 1 limit 0,1) then itemvalue else '' end) as col1
,(case when itemname = (select distinct itemname from history a order by 1 limit 1,1) then itemvalue else '' end) as col2
,(case when itemname = (select distinct itemname from history a order by 1 limit 2,1) then itemvalue else '' end) as col3
,(case when itemname = (select distinct itemname from history a order by 1 limit 3,1) then itemvalue else '' end) as col4
FROM history order by 1;
You can summarize it, too:
SELECT
hostid
,sum(case when itemname = (select distinct itemname from history a order by 1 limit 0,1) then itemvalue end) as A
,sum(case when itemname = (select distinct itemname from history a order by 1 limit 1,1) then itemvalue end) as B
,sum(case when itemname = (select distinct itemname from history a order by 1 limit 2,1) then itemvalue end) as C
FROM history group by hostid order by 1;
+--------+------+------+------+
| hostid | A | B | C |
+--------+------+------+------+
| 1 | 10 | 3 | NULL |
| 2 | 9 | NULL | 40 |
+--------+------+------+------+
Results of RexTester:
http://rextester.com/ZSWKS28923
For one real example of use, this report bellow show in columns the hours of departures arrivals of boat/bus with a visual schedule. You will see one additional column not used at the last col without confuse the visualization:
** ticketing system to of sell ticket online and presential
This isn't the exact answer you are looking for but it was a solution that i needed on my project and hope this helps someone. This will list 1 to n row items separated by commas. Group_Concat makes this possible in MySQL.
select
cemetery.cemetery_id as "Cemetery_ID",
GROUP_CONCAT(distinct(names.name)) as "Cemetery_Name",
cemetery.latitude as Latitude,
cemetery.longitude as Longitude,
c.Contact_Info,
d.Direction_Type,
d.Directions
from cemetery
left join cemetery_names on cemetery.cemetery_id = cemetery_names.cemetery_id
left join names on cemetery_names.name_id = names.name_id
left join cemetery_contact on cemetery.cemetery_id = cemetery_contact.cemetery_id
left join
(
select
cemetery_contact.cemetery_id as cID,
group_concat(contacts.name, char(32), phone.number) as Contact_Info
from cemetery_contact
left join contacts on cemetery_contact.contact_id = contacts.contact_id
left join phone on cemetery_contact.contact_id = phone.contact_id
group by cID
)
as c on c.cID = cemetery.cemetery_id
left join
(
select
cemetery_id as dID,
group_concat(direction_type.direction_type) as Direction_Type,
group_concat(directions.value , char(13), char(9)) as Directions
from directions
left join direction_type on directions.type = direction_type.direction_type_id
group by dID
)
as d on d.dID = cemetery.cemetery_id
group by Cemetery_ID
This cemetery has two common names so the names are listed in different rows connected by a single id but two name ids and the query produces something like this
CemeteryID Cemetery_Name Latitude
1 Appleton,Sulpher Springs 35.4276242832293
You can use a couple of LEFT JOINs. Kindly use this code
SELECT t.hostid,
COALESCE(t1.itemvalue, 0) A,
COALESCE(t2.itemvalue, 0) B,
COALESCE(t3.itemvalue, 0) C
FROM history t
LEFT JOIN history t1
ON t1.hostid = t.hostid
AND t1.itemname = 'A'
LEFT JOIN history t2
ON t2.hostid = t.hostid
AND t2.itemname = 'B'
LEFT JOIN history t3
ON t3.hostid = t.hostid
AND t3.itemname = 'C'
GROUP BY t.hostid
I'm sorry to say this and maybe I'm not solving your problem exactly but PostgreSQL is 10 years older than MySQL and is extremely advanced compared to MySQL and there's many ways to achieve this easily. Install PostgreSQL and execute this query
CREATE EXTENSION tablefunc;
then voila! And here's extensive documentation: PostgreSQL: Documentation: 9.1: tablefunc or this query
CREATE EXTENSION hstore;
then again voila! PostgreSQL: Documentation: 9.0: hstore
I have a table like below:
ID | Name | Ratio | Miles
____________________________________
1 | ABC | 45 | 21
1 | ABC | 46 | 24
1 | ABC | 46 | 25
2 | PQR | 41 | 19
2 | PQR | 39 | 17
3 | XYZ | 27 | 13
3 | XYZ | 26 | 11
4 | DEF | 40 | 18
4 | DEF | 40 | 18
4 | DEF | 42 | 20
I want to write a query that will find an ID whose Miles value has been steadily rising.
For instance,
Miles values of Name 'ABC' and 'DEF' are steadily rising.
It's fine if the Miles value drops by up to 5% and rises again.
It should also include this Name.
I tried self join on this table but it gives me Cartesian product.
Can anyone help me with this?
I am using SQL server 2012.
Thanks in advance!
SQL tables represent unordered sets. Let me assume that you have a column that specifies the ordering. Then, you can use lag() and some logic:
select id, name
from (select t.*,
lag(miles) over (partition by id order by orderingcol) as prev_miles
from t
) t
group by id, name
having min(case when prev_miles is null or miles >= prev_miles * 0.95 then 1 else 0 end) = 1;
The having clause is simply determining if all the rows meet your specific condition.
try this:
Note: 5% case is not handled here
create table #tmp(ID INT,Name VARCHAR(50),Ratio INT,Miles INT)
INSERT INTO #tmp
SELECT 1,'ABC',45,21
union all
SELECT 1,'ABC',46,24
union all
SELECT 1,'ABC',46,25
union all
SELECT 2,'PQR',41,19
union all
SELECT 2,'PQR',39,17
union all
SELECT 3,'XYZ',27,13
union all
SELECT 3,'XYZ',26,11
union all
SELECT 4,'DEF',40,18
union all
SELECT 4,'DEF',40,18
union all
SELECT 4,'DEF',42,21
Select *,CASE WHEN Miles<=LEAD(Miles,1,Miles) OVER(partition by ID Order by ID) THEN 1
--NEED ADD 5%condition Here
ELSE 0 END AS nextMiles
into #tmp2
from #tmp
;with cte
AS(
select * , ROW_NUMBER() OVER (partition by ID,nextMiles order by ID) rn from #tmp2
)
SELECT DISTINCT ID,Name FROM cte WHERE rn>1
Drop table #tmp
Drop table #tmp2
I have two tables similar to shown below (just leaving out fields for simplicity).
Table lead :
id | fname | lname | email
---------------------------------------------
1 | John | Doe | jd#test.com
2 | Mike | Johnson | mj#test.com
Table leadcustom :
id | leadid | name | value
-------------------------------------------------
1 | 1 | utm_medium | cpc
2 | 1 | utm_term | fall
3 | 1 | subject | business
4 | 2 | utm_medium | display
5 | 2 | utm_term | summer
6 | 2 | month | may
7 | 2 | color | red
I have a database that captures leads for a wide variety of forms that often have many different form fields. The first table gets the basic info that I know is on each form. The second table captures all other forms fields that were sent over so it can really contain a lot of different fields.
What I am trying to do is to do a join where I can grab all fields from lead table along with utm_medium and utm_term from leadcustom table. I don't need any additional fields even if they were sent over.
Desired results :
id | fname | lname | email | utm_medium | utm_term
---------------------------------------------------------------------------
1 | John | Doe | jd#test.com | cpc | fall
2 | Mike | Johnson | mj#test.com | display | summer
Only way I know I could do this is to grab all lead data and then for each record make more calls to get leadcustom data I am looking for but I know there has to me a more efficient way of getting this data.
I appreciate any help with this and it is not something I can change the way I capture that data and table formats.
If your columns are fixed, you can do this with group by + case + max like this:
select
fname,
lname,
email,
max(case when name = 'utm_medium' then value end) as utm_medium,
max(case when name = 'utm_term' then value end) as utm_term
from
lead l
join leadcustom c
on l.id = c.leadid
group by
fname,
lname,
email
The case will assign value from the leadcustom table when it matches the given name, otherwise it will return null, and max will pick take the assigned value if it exists over the null.
You can test this in SQL Fiddle
The other way to do this is to use pivot operator, but that syntax is slightly more complex -- or at least this is more easy for me.
Unless I interpret your question incorrectly - in which case I'm happy to be corrected - you could achieve your goal with a simple left join where you join on ID of the first table:
select ld.*, ldcust.utm_medium, ldcust.utm_term
from lead ld
left join leadcustom ldcust
on ld.id = ldcust.leadid
You can use a cte or a derived table to solve this:
cte:
;with cte as
(
select leadid, [name], [value]
from leadcustom
where name in('utm_medium', 'display')
)
select id, fname, lname, email, [name], [value]
from lead
inner join cte on(id = leadid)
Derived table:
select id, fname, lname, email, [name], [value]
from lead
inner join
(
select leadid, [name], [value]
from leadcustom
where name in('utm_medium', 'display')
) derived on(id = leadid)
and since suslov used JamesZ's fiddle, I will use it too...
declare #t table (Id int,fname varchar(10),lname varchar(10),email varchar(20))
insert into #t(Id,fname,lname,email)values (1,'john','doe','jd#test.com'),(2,'mike','johnson','mj#test.com')
declare #tt table (id int,leadid int,name varchar(10),value varchar(10))
insert into #tt(id,leadid,name,value)values
(1,1,'utm_medium','cpc'),
(2,1,'utm_term','fall'),
(3,1,'subject','business'),
(4,2,'utm_medium','display'),
(5,2,'utm_term','summer'),
(6,2,'month','may'),(7,2,'color','red')
select Id,fname,lname,
email,
[utm_medium],
[utm_term]
from (
select t.Id,
t.fname,
t.lname,
t.email,
tt.name,
tt.value
from #t t JOIN #tt tt
ON t.Id = tt.leadid)R
PIVOT(MAX(value) for name IN([utm_medium],[utm_term]))P
You can try with pivot and join:
select [id]
, [fname]
, [lname]
, [email]
, [utm_medium]
, [utm_term]
from ( select t2.*
, t1.[name]
, t1.[value]
from [leadcustom] t1
join [lead] t2 on t2.[id] = t1.[leadid]
) t
pivot (
max([value])
for [name] in ([utm_medium], [utm_term])
) pt
pivot rotates the joined table-valued expression, by turning the unique values from [value] column in the expression into [utm_medium] and [utm_term] columns in the output, and performs fake aggregation with max function (it works so because a corresponding column can have multiple values for one unique pivoted column, in this case, [name] for [value]).
SQLFiddle
I have a problems this mornig , I have tried many solutions and nothing gave me the expected result.
I have a table that looks like this :
+----+----------+-------+
| ID | COL2 | DATE |
+----+----------+-------+
| 1 | 1 | 2001 |
| 1 | 2 | 2002 |
| 1 | 3 | 2003 |
| 1 | 4 | 2004 |
| 2 | 1 | 2001 |
| 2 | 2 | 2002 |
| 2 | 3 | 2003 |
| 2 | 4 | 2004 |
+----+----------+-------+
And I have a query that returns a result like this :
I have the unique ID and for this ID I want to take the last date of the ID
+----+----------+-------+
| ID | COL2 | DATE |
+----+----------+-------+
| 1 | 4 | 2004 |
| 2 | 4 | 2004 |
+----+----------+-------+
But I don't have any idea how I can do that.
I tried Join , CROSS APPLY ..
If you have some idea ,
Thank you
Clement FAYARD
declare #t table (ID INT,Col2 INT,Date INT)
insert into #t(ID,Col2,Date)values (1,1,2001)
insert into #t(ID,Col2,Date)values (1,2,2001)
insert into #t(ID,Col2,Date)values (1,3,2001)
insert into #t(ID,Col2,Date)values (1,4,2001)
insert into #t(ID,Col2,Date)values (2,1,2002)
insert into #t(ID,Col2,Date)values (2,2,2002)
insert into #t(ID,Col2,Date)values (2,3,2002)
insert into #t(ID,Col2,Date)values (2,4,2002)
;with cte as(
select
*,
rn = row_number() over(partition by ID order by Col2 desc)
from #t
)
select
ID,
Col2,
Date
from cte
where
rn = 1
SELECT ID,MAX(Col2),MAX(Date) FROM tableName GROUP BY ID
If col2 and date allways the highest value in combination than you can try
SELECT ID, MAX(COL2), MAX(DATE)
FROM Table1
GROUP BY ID
But it is not realy good.
The alternative is a subquery with:
SELECT yourtable.ID, sub1.COL2, sub1.DATE
FROM yourtable
INNER JOIN -- try with CROSS APPLY for performance AND without ON 1=1
(SELECT TOP 1 COL2, DATE
FROM yourtable sub2
WHERE sub2.ID = topquery.ID
ORDER BY COL2, DATE) sub1 ON 1=1
You didn't tell what's the name of your table so I'll assume below it is tbl:
SELECT m.ID, m.COL2, m.DATE
FROM tbl m
LEFT JOIN tbl o ON m.ID = o.ID AND m.DATE < o.DATE
WHERE o.DATE is NULL
ORDER BY m.ID ASC
Explanation:
The query left joins the table tbl aliased as m (for "max") against itself (alias o, for "others") using the column ID; the condition m.DATE < o.DATE will combine all the rows from m with rows from o having a greater value in DATE. The row having the maximum value of DATE for a given value of ID from m has no pair in o (there is no value greater than the maximum value). Because of the LEFT JOIN this row will be combined with a row of NULLs. The WHERE clause selects only these rows that have NULL for o.DATE (i.e. they have the maximum value of m.DATE).
Check the SQL Antipatterns: Avoiding the Pitfalls of Database Programming book for other SQL tips.
In order to do this you MUST exclude COL2 Your query should look like this
SELECT ID, MAX(DATE)
FROM table_name
GROUP BY ID
The above query produces the Maximum Date for each ID.
Having COL2 with that query does not makes sense, unless you want the maximum date for each ID and COL2
In that case you can run:
SELECT ID, COL2, MAX(DATE)
GROUP BY ID, COL2;
When you use aggregation functions(like max()), you must always group by all the other columns you have in the select statement.
I think you are facing this problem because you have some fundemental flaws with the design of the table. Usually ID should be a Primary Key (Which is Unique). In this table you have repeated IDs. I do not understand the business logic behind the table but it seems to have some flaws to me.
How to write a query that will match data and produce and identity for it.
For Example:
RecordID | Name
1 | John
2 | John
3 | Smith
4 | Smith
5 | Smith
6 | Carl
I want a query which will assign an identity after matching exactly on Name.
Expected Output:
RecordID | Name | ID
1 | John | 1X
2 | John | 1X
3 | Smith | 1Y
4 | Smith | 1Y
5 | Smith | 1Y
6 | Carl | 1Z
Note: The ID should be unique for every match. Also, it can be numbers or varchar.
Can somebody help me with this? The main thing is to assign the ID's.
Thanks.
How about this:
with temp as
(
select 1 as id,'John' as name
union
select 2,'John'
union
select 3,'Smith'
union
select 4,'Smith'
union
select 5,'Smith'
union
select 6,'Carl'
)
SELECT *, DENSE_RANK() OVER
(ORDER BY Name) as NewId
FROM TEMP
Order by id
The first part is for testing purposes only.
Please try:
SELECT *,
Rank() over (order by Name ASC)
FROM table
This structure seems to work:
CREATE TABLE #Table
(
Department VARCHAR(100),
Name VARCHAR(100)
);
INSERT INTO #Table VALUES
('Sales','michaeljackson'),
('Sales','michaeljackson'),
('Sales','jim'),
('Sales','jim'),
('Sales','jill'),
('Sales','jill'),
('Sales','jill'),
('Sales','j');
WITH Cte_Rank AS
(
SELECT [Name],
rw = ROW_NUMBER() OVER (ORDER BY [Name])
FROM #Table
GROUP BY [Name]
)
SELECT a.Department,
a.Name,
b.rw
FROM #Table a
INNER JOIN Cte_Rank b
ON a.Name = b.Name;