Current ratio of user is his last inserted ratio in table "Ratio History"
user_id | year | month | ratio
For example if user with ID 1 has two rows
1 | 2019 | 2 | 10
1 | 2019 | 3 | 15
his ratio is 15.
there is some slice from develop table
user_id | year | month | ratio
1 | 2018 | 7 | 10
2 | 2018 | 8 | 20
3 | 2018 | 8 | 30
1 | 2019 | 1 | 40
2 | 2019 | 2 | 50
3 | 2018 | 10 | 60
2 | 2019 | 3 | 70
I need a query which will select grouped rows by user_id and their last ratio.
As a result of the request, the following entries should be selected
user_id | year | month | ratio
1 | 2019 | 1 | 40
2 | 2019 | 3 | 70
3 | 2018 | 10 | 60
I tried use this query
select rh1.user_id, ratio, rh1.year, rh1.month from ratio_history rh1
join (
select user_id, max(year) as maxYear, max(month) as maxMonth
from ratio_history group by user_id
) rh2 on rh1.user_id = rh2.user_id and rh1.year = rh2.maxYear and rh1.month = rh2.maxMonth
but i got only one row
Use distinct on:
select distinct on (user_id) rh.*
from ratio_history rh
order by user_id, year desc, month desc;
distinct on is a very convenient Postgres extension. It returns one row for the key values in parentheses? Which row, it is the first row based on the sort criteria. Note that the sort criteria need to start with the expressions in parentheses.
Related
I have a table of items in the shop, an item may have different entries with same serial number (sn) (but different ids) if the same item was bought again later on with different price (price here is how much did a single item cost the shop)
id | sn | amount | price
----+------+--------+-------
1 | AP01 | 100 | 7
2 | AP01 | 50 | 8
3 | X2P0 | 200 | 12
4 | X2P0 | 30 | 18
5 | STT0 | 20 | 20
6 | PLX1 | 200 | 10
and a table of transactions
id | item_id | price
----+---------+-------
1 | 1 | 10
2 | 1 | 9
3 | 1 | 10
4 | 2 | 11
5 | 3 | 15
6 | 3 | 15
7 | 3 | 15
8 | 4 | 18
9 | 5 | 22
10 | 5 | 22
11 | 5 | 22
12 | 5 | 22
and transaction.item_id references items(id)
I want to group items by serial number (sn), get their sum(amount) and avg(price), and join it with a sold column that counts number of transactions with referenced id
I did the first with
select i.sn, sum(i.amount), avg(i.price) from items i group by i.sn;
sn | sum | avg
------+-----+---------------------
STT0 | 20 | 20.0000000000000000
PLX1 | 200 | 10.0000000000000000
AP01 | 150 | 7.5000000000000000
X2P0 | 230 | 15.0000000000000000
Then when I tried to join it with transactions I got strange results
select i.sn, sum(i.amount), avg(i.price) avg_cost, count(t.item_id) sold, sum(t.price) profit from items i left join transactions t on (i.id=t.item_id) group by i.sn;
sn | sum | avg_cost | sold | profit
------+-----+---------------------+------+--------
STT0 | 80 | 20.0000000000000000 | 4 | 88
PLX1 | 200 | 10.0000000000000000 | 0 | (null)
AP01 | 350 | 7.2500000000000000 | 4 | 40
X2P0 | 630 | 13.5000000000000000 | 4 | 63
As you can see, only the sold and profit columns show correct results, the sum and avg show different results than the expected
I can't separate the statements because I am not sure how can I add the count to the sn group which has the item_id as its id?
select
j.sn,
j.sum,
j.avg,
count(item_id)
from (
select
i.sn,
sum(i.amount),
avg(i.price)
from items i
group by i.sn
) j
left join transactions t
on (j.id???=t.item_id);
There are multiple matches in both tables, so the join multiplies the rows (and eventually produces wron results). I would recommend pre-joining, then aggregating:
select
sn,
sum(amount) total_amount,
avg(price) avg_price,
sum(no_transactions) no_transactions
from (
select
i.*,
(
select count(*)
from transactions t
where t.item_id = i.id
) no_transactions
from items i
) t
group by sn
I have 2 SQL Server tables.
PurchaseOrderReceivingLine (PORL) is a table that contains every receipt from a purchase order. This has hundreds of entries per month.
PartyRelationshipScore (PRS) is a table with a party (supplier) reference number (that is used to join to the PORL table) and a score out of 10 for relationship and price. It also has a date field for when the score is updated so we have a history of the updates.
What I want to achieve is a supplier summary for each month. So I would have Supplier #, TotalValue, LateParts etc. I'm fine with creating the code for that. What I'm struggling with is getting the score for the given month if there are no values for that month.
So, for example I might have a value of 5 on the 1st August. Then it doesn't change until the 1st October when it is increased to 6.
On the grouping, September will have a TotalValue & a LateParts value but because there are no records in September in the PRS table, it will return a NULL value. I need it to get the last value recorded and return that (in this case August's 5). So it will return;
Aug 2019 - 5
Sep 2019 - 5
Oct 2019 - 6
Thanks in advance.
PORL Table
+-------+----------------+-------+-------+
| PORL# | Date (UK) | Value | Party |
+-------+----------------+-------+-------+
| 1 | 1/8/2019 | 100 | 6 |
| 2 | 1/8/2019 | 250 | 6 |
| 3 | 1/9/2019 | 1000 | 6 |
| 4 | 1/10/2019 | 2000 | 6 |
+-------+----------------+-------+-------+
PRS Table
+-------------+------------+-------------------+------------+
| DateChanged (UK) | Party | RelationShipScore | PriceScore |
+-------------+------------+-------------------+------------+
| 1/8/2019 | 6 | 5 | 5 |
| 1/10/2019 | 6 | 6 | 7 |
+------------------+-------+-------------------+------------+
Preferred outcome
+----------+-------+------+------------+-------------------+------------+
| Supplier | Month | Year | TotalValue | RelationshipScore | PriceScore |
+----------+-------+------+------------+-------------------+------------+
| 6 | 8 | 2019 | 350 | 5 | 5 |
| 6 | 9 | 2019 | 1000 | 5 | 5 |
| 6 | 10 | 2019 | 2000 | 6 | 7 |
+----------+-------+------+------------+-------------------+------------+
The relationshipscore & pricescore for month 9 are based on it not changing from month 8.
I think this helps
select Supplier = T.Party
, Month = DATEPART(MONTH,T.[Date])
, Year = DATEPART(YEAR,T.[Date])
, T.TotalValue
, R.RelationShipScore
, R.PriceScore
from ( Select P.[Party],P.[Date],[TotalValue] = sum(P.[Value])
from PurchaseOrderReceivingLine P
group by P.[Party],P.[Date] ) T
outer apply ( select top 1 RelationShipScore , PriceScore
from PartyRelationshipScore
where Party = T.Party
and DateChanged <= T.[Date]
Order by DateChanged desc ) R
I have a table laid out similar to this. I need to select distinct vendor number that has the highest year value and the highest month value
VENDORMONTHLY:
id Vendor Year month More stuff(More columns)
---|---------|-------|-------|---------|
1 | 93000 | 2017 | 3 | sadf |
2 | 93000 | 2017 | 2 | asdf |
5 | 93000 | 2017 | 1 | asdf |
3 | 93000 | 2016 | 12 | fff |
4 | 93000 | 2016 | 11 | ffff |
6 | 40000 | 2017 | 2 | fff |
7 | 40000 | 2017 | 1 | fff |
8 | 40000 | 2016 | 12 | fff |
The result would look like this. I can not for the life of me come up with a query that will give me what I need.
id Vendor Year month More stuff(More columns)
---|---------|-------|-------|---------|
1 | 93000 | 2017 | 3 | sadf |
6 | 40000 | 2017 | 2 | fff |
Any help would be greatly appreciated!
Quick answer, use NOT EXISTS to verify the same id has no other row with a later year or same year but later month:
select v1.*
from VENDORMONTHLY v1
where not exists (select 1 from VENDORMONTHLY v2
where v2.Vendor = v1.Vendor
and (v2.Year > v1.year
or (v2.Year = v1.Year and v2.Month > v1.Month)))
Will return both rows in case of a latest row tie.
Core ANSI SQL-99. Will run on any dbms!
If you are using some database (SQL Server, Oracle, Postgres etc) that support window functions, you can rank ( or row_number if you need only one row per year-month combination per vendor)
select *
from (
select v.*,
rank() over (
partition by vendor order by year desc,
month desc
) rn
from vendormonthly v
) v
where rn = 1;
In SQL server, same can be done in a better way using top with ties:
Select top 1 with ties *
From vendormonthly
Order by rank() over (
partition by vendor
order by year desc, month desc
)
I'm on Teradata. I have an order table like the below.
custID | orderID | month | order_amount
-----------------------------------------
1 | 1 | jan | 10
1 | 2 | jan | 20
1 | 3 | feb | 5
1 | 4 | feb | 7
2 | 5 | mar | 20
2 | 6 | apr | 30
I'd like to add a column to the above table called "Avg order amount per month per customer". Since the table is at an order level, adding this column will cause duplicates like the below, which is ok.
custID | orderID | month | order_amount | avgOrdAmtperMonth
-------------------------------------------------------------
1 | 1 | jan | 10 | 15
1 | 2 | jan | 20 | 15
1 | 3 | feb | 5 | 6
1 | 4 | feb | 7 | 6
2 | 5 | mar | 20 | 20
2 | 6 | apr | 30 | 30
I want the output to have all the columns above, not just the custid and the new column. I'm not sure how to write this because one part of the table is an at order level and the new column needs to be grouped by customer+month. How would I do this?
This is a simple group average:
AVG(order_amount) OVER (PARTITION BY custID, month)
Why not just do the calculation when you query the table?
select t.*,
avg(order_amount) over (partition by custId, month) as avgOrderAmtPerMonth
from t;
You can add this into a view if you want to make it available to multiple downstream queries.
Actually adding the column to the table is a maintenance "nightmare". You have to add triggers to the table and update the value for updates, inserts, and deletes.
I have a table supplier_account which has five coloumns supplier_account_id(pk),supplier_id(fk),voucher_no,debit and credit. I want to get the sum of debit grouped by supplier_id and then subtract the value of credit of the rows in which voucher_no is not null. So for each subsequent rows the value of sum of debit gets reduced. I have tried using 'with' clause.
with debitdetails as(
select supplier_id,sum(debit) as amt
from supplier_account group by supplier_id
)
select acs.supplier_id,s.supplier_name,acs.purchase_voucher_no,acs.purchase_voucher_date,dd.amt-acs.credit as amount
from supplier_account acs
left join supplier s on acs.supplier_id=s.supplier_id
left join debitdetails dd on acs.supplier_id=dd.supplier_id
where voucher_no is not null
But here the debit value will be same for all rows. After subtraction in the first row I want to get the result in second row and subtract the next credit value from that.
I know it is possible by using temporary tables. The problem is I cannot use temporary tables because the procedure is used to generate reports using Jasper Reports.
What you need is an implementation of the running total. The easiest way to do it with a help of a window function:
with debitdetails as(
select id,sum(debit) as amt
from suppliers group by id
)
select s.id, purchase_voucher_no, dd.amt, s.credit,
dd.amt - sum(s.credit) over (partition by s.id order by purchase_voucher_no asc)
from suppliers s
left join debitdetails dd on s.id=dd.id
order by s.id, purchase_voucher_no
SQL Fiddle
Results:
| id | purchase_voucher_no | amt | credit | ?column? |
|----|---------------------|-----|--------|----------|
| 1 | 1 | 43 | 5 | 38 |
| 1 | 2 | 43 | 18 | 20 |
| 1 | 3 | 43 | 8 | 12 |
| 2 | 4 | 60 | 5 | 55 |
| 2 | 5 | 60 | 15 | 40 |
| 2 | 6 | 60 | 30 | 10 |