how to find the total - sql

I have a table A and the output expected is below.
Table A
Id patientId PID
1 123 p1
1 123 p2
1 124 p3
1 124 p4
1 125 p5
2 126 p6
2 126 p7
2 126 p8
2 127 p9
2 127 p10
Count of pid is the count for every patientId how many pids are present and Total count of IDs is the total number of Ids(lets say 5 for Id 1 for example)
Expecting an output like this:
id patientId Count of pid Total count of IDs
1 123 2 5
1 124 2 5
1 125 1 5
2 126 3 5
2 127 2 5
I am not sure how to go beyond this
select Id,patientId,count(PID)
from A
group by 1,2

Because you want to count over two different fields, you need two separate GROUP BY subqueries, which can be JOINed on Id:
SELECT A1."Id",
A1."patientId",
A1.num_pids,
A2.total_ids
FROM (SELECT "Id", "patientId", COUNT(*) AS num_pids
FROM A
GROUP BY "Id", "patientId") A1
JOIN (SELECT "Id", COUNT(*) AS total_ids
FROM A
GROUP BY "Id") A2 ON A2."Id" = A1."Id"
ORDER BY "Id", "patientId"
Output:
Id patientId num_pids total_ids
1 123 2 5
1 124 2 5
1 125 1 5
2 126 3 5
2 127 2 5

select a.Id,a.patientId,count(a.patientId), a2.IdCount
from A a
left join (select Id, count(Id) as "IdCount"
from A
group by Id) a2
on a.Id = a2.Id
group by a.Id,a.patientId, a2.IdCount

I think you just want a window function:
select Id, patientId, count(*),
count(*) over ()
from A
group by 1, 2;
The second count(*) counts the number of rows in the result set, which appears to be what you want.

Related

SQL, label user based on the similarity

Is below case possible in SQL?
Let say I have a table like this:
user_id
product_id
1
123
1
122
1
121
2
124
2
125
2
121
3
123
3
122
3
122
4
123
4
212
4
222
5
124
5
125
5
121
I want to label the user if they have same product_id, regardless the order, so the output looks like this:
user_id
product_id
label
1
123
a
1
122
a
1
121
a
2
124
b
2
125
b
2
121
b
3
123
a
3
121
a
3
122
a
4
123
c
4
212
c
4
222
c
5
124
b
5
125
b
5
121
b
Please advise
You can use the string_agg function to get the list of product_ids for each user (as a single string), then use the dense_rank function on that string to get unique labels for each product_ids list.
select T.user_id, T.product_id, D.label
from table_name T join
(
select user_id,
chr(dense_rank() over (order by user_products) + 96) label
from
(
select user_id,
string_agg(cast(product_id as string), ',' order by product_id) user_products
from table_name
group by user_id
) lbl
) D
on T.user_id = D.user_id
order by T.user_id

SUM a column in SQL, based on DISTINCT values in another column, GROUP BY a third column

I'd appreciate some help on the following SQL problem:
I have a table of 3 columns:
ID Group Value
1 1 5
1 1 5
1 2 10
1 2 10
1 3 20
2 1 5
2 1 5
2 1 5
2 2 10
2 2 10
3 1 5
3 2 10
3 2 10
3 2 10
3 4 50
I need to group by ID, and I would like to SUM the values based on DISTINCT values in Group. So the value for a group is only accounted for once even though it may appear multiple for times for a particular ID.
So for IDs 1, 2 and 3, it should return 35, 15 and 65, respectively.
ID SUM
1 35
2 15
3 65
Note that each Group doesn't necessarily have a unique value
Thanks
the CTE will remove all duplicates, so if there a sdiffrenet values for ID and Group, it will be counted.
The next SELECT wil "GROUP By" ID
For Pstgres you would get
WITH CTE as
(SELECT DISTINCT "ID", "Group", "Value" FROM tablA
)
SELECT "ID", SUM("Value") FROM CTE GROUP BY "ID"
ORDER BY "ID"
ID | sum
-: | --:
1 | 35
2 | 15
3 | 65
db<>fiddle here
Given what we know at the moment this is what I'm thinking...
The CTE/Inline view eliminate duplicates before the sum occurs.
WITH CTE AS (SELECT DISTINCT ID, Group, Value FROM TableName)
SELECT ID, Sum(Value)
FROM CTE
GROUP BY ID
or
SELECT ID, Sum(Value)
FROM (SELECT DISTINCT * FROM TableName) CTE
GROUP BY ID

Issue with SQL Group By and COALESCE on sqlite

I have a table as below in sqlite database. I want to create a line chart showing usage by product groups.
Table: ProductUsageData
UserID ProductName ProductGroup Qty RecordID
1 A1 A 12 1
2 A1 A 12 1
1 A2 A 15 1
3 A1 A 12 2
2 B1 B 12 2
5 B2 B 5 2
1 A1 A 12 3
1 A2 A 15 3
4 A1 A 12 3
3 C1 C 12 3
2 C2 C 15 3
Since I want separate line for each ProductGroup I am using below Query
SELECT
SUM(Qty) as UsedQty,
ProductGroup,
RecordID
FROM ProductUsageData
GROUP BY ProductGroup, RecordID
ORDER BY RecordID ASC;
While I get three records for A (for each RecordID) I get only 1 record each for B & C as they are not used during each RecordID.
Problem is when I am putting one line for each ProductGroup in the chart, the points for B & C are shown as per Qty in the first
My output is like this
A 39 1
A 12 2
B 17 2
A 39 3
C 27 3
So the graph looks like this
instead of
To fix this I changed the query using COALESCE to get 0 Qty if the ProductGroup is not used during each recording.
SELECT
COALESCE(SUM(Qty), 0) as UsedQty,
ProductGroup,
RecordID
FROM ProductUsageData
GROUP BY ProductGroup, RecordID
ORDER BY RecordID ASC;
I was expecting output as below
A 39 1
B 0 1
C 0 1
A 12 2
B 17 2
C 0 2
A 39 3
B 0 3
C 27 3
But I am getting same output as first
Please let me know how can I correct the query to get desired output
A typical solution is to first cross join two queries that select the distinct product groups and record ids from the table; this gives you all possible combinations of productGroup and recordID.
Then, you can bring in the original table with a left join, and aggregate:
select
g.productGroup,
coalesce(sum(p.qty), 0) qty,
r.recordID
from (select distinct productGroup from productUsageData) g
cross join (select distinct recordID from productUsageData) r
left join productUsageData p
on p.productGroup = g.productGroup
and p.recordID = r.recordID
group by r.recordID, g.productGroup
order by r.recordID, g.productGroup
In the real world, you might have separate referential tables for product groups and records ids, which would make the query simpler and more efficient (since it would avoid the need to select distinct in subqueries).
Demo on DB Fiddle:
productGroup | qty | recordID
:----------- | :-- | :-------
A | 39 | 1
B | 0 | 1
C | 0 | 1
A | 12 | 2
B | 17 | 2
C | 0 | 2
A | 39 | 3
B | 0 | 3
C | 27 | 3

SELECT clause with SUM condition

Have this table :
//TEST
NUMBER TOTAL
----------------------------
1 158
2 355
3 455
//TEST1
NUMBER QUANTITY UNITPRICE
--------------------------------------------
1 3 5
1 3 6
1 3 4
2 4 8
3 5 4
I used following query:
SELECT t.NUMBER,sum(t.TOTAL),NVL(SUM(t2.quantity*t2.unitprice),0)
FROM test t INNER JOIN test1 t2 ON t.NUMBER=t2.NUMBER
GROUP BY t.NUMBER;
OUTPUT:
NUMBER SUM(TOTAL) SUM(t2.quantity*t2.unitprice)
-----------------------------------------------------------
1 474 45 <--- only this wrong
2 355 32
It seem like loop for three times so 158*3 in the record.
EXPECTED OUTPUT:
NUMBER SUM(TOTAL) SUM(t2.quantity*t2.unitprice)
-----------------------------------------------------------
1 158 45
2 355 32
You have to understand that the result of your join is something like this:
//TEST1
NUMBER QUANTITY UNITPRICE TOTAL
--------------------------------------------------------------
1 3 5 158
1 3 6 158
1 3 4 158
2 4 8 355
3 5 4 455
It means you don't need to apply a SUM on TOTAL
SELECT t.NUMBER,t.TOTAL,NVL(SUM(t2.quantity*t2.unitprice),0)
FROM test t INNER JOIN test1 t2 ON t.NUMBER=t2.NUMBER
GROUP BY t.NUMBER, t.TOTAL;
Something like this should work using a subquery separating the sums:
select t.num,
sum(t.total),
test1sum
from test t
join (
select num, sum(qty*unitprice) test1sum
from test1
group by num
) t2 on t.num = t2.num
group by t.num, test1sum
SQL Fiddle Demo
In regards to your sample data, you may not even need the additional group by on the test total field. If that table only contains distinct ids, then this would work the same:
select t.num,
t.total,
sum(qty*unitprice)
from test t
join test1 t2 on t.num = t2.num
group by t.num, t.total

Simple data, Complex query on SQL Server

I need to make a query over an SQL Server table but I don't know exactly how.
Consider this table (the real table is much more complex, Ord1 and Ord2 are dates that could be null, but i simplified it to this case):
Data of MyTable
ID MaqID Ord1 Ord2
------------------------
1 144 4 3
2 144 2 1
3 12 2 3
4 144 3 5
5 12 3 1
6 144 4 2
7 12 2 4
8 144 2 3
9 12 1 5
10 12 3 2
I need records for specific MaqID in Specific Order. I get that with this Query:
SELECT * FROM myTable WHERE MaqID=144 ORDER BY MaqID, Order1 DESC, Order2
Wich give me:
ID MaqID Ord1 Ord2
------------------------
6 144 4 2
1 144 4 3
4 144 3 5
2 144 2 1
8 144 2 3
Now, I need a single query that, for each MaqID, return the first ID for each subquery following above order. The result should be:
Expected result
MaqID ID
-----------
144 6
12 5
I have already try distinct conbination of TOP a MAX, but TOP result only one result and i need one for each MaqID, and for Max I have not field to maximize.
To sumarize: I need the first ID for each MaqID from a subquery in a specific order
Any ideas? Thanks!
You can do this using row_number():
select t.*
from (select t.*,
row_number() over (partition by macid Order1 DESC, Order2) as seqnum
from mytable t
) t
where seqnum = 1;