I would like to check if any of my columns in a table have any null values. I am sure there is a quicker way than how I am doing it at the moment. I just want to see if there is a NULL in ANY column however my table has a lot of columns, is there a simple and quick way?
This way I have written so far works but it takes a long time to do for every column (hence the etc etc)
select
sum(case when id is null then 1 else 0 end) as id,
sum(case when name is null then 1 else 0 end) as name,
sum(case when review_count is null then 1 else 0 end) as review_coun,
sum(case when positive_review is null then 1 else 0 end) as
positive_review,
sum(etc etc
from user
I don't know if this will work for your scenario, but it's an option. You can CAST all your columns as a string and then concatenate them together. If you concatenate a NULL value with a string, it will return NULL.
SELECT 'Y'
WHERE EXISTS( -- Check if there are any NULL rows
SELECT
CAST(c1 AS CHAR(1)) ||
CAST(c2 AS CHAR(1)) ||
...
AS MyColumns
WHERE MyColumns IS NULL
)
;
Related
I have zero experience with SQL but am trying to learn how to validate tables. I am trying to see within a table if any of the columns are null.
Currently I have been going with a script that is just counting the number of nulls. I am doing this for each column. Is there a better script that I can use to check all the columns in a table?
select count(id) from schema.table where id is not null
If there are 100 records I would expect all columns to come back with 100 but if one column is null it will show a 0.
You can count each column in a single query by using sum and case:
select
sum(case when Column1 is null then 1 else 0 end) Column1NullCount
, sum(case when Column2 is null then 1 else 0 end) Column2NullCount
-- ...
, sum(case when ColumnN is null then 1 else 0 end) ColumnNNullCount
from MyScheme.MyTable
I have a query which extracts some data from a JSON document and I have a query that based on the number of values returned displays an overall column count. I can't seem to work out how to combine these into a single query? assume that I need to use a sub-query but not sure where to go from here?
SELECT
JSON_EXTRACT_SCALAR(data, '$.cat.name') as cat_name
JSON_EXTRACT_SCALAR(data, '$.dog.name') as dog_name
FROM table
SELECT
CASE WHEN cat_name IS NOT NULL THEN 1 ELSE 0 END +
CASE WHEN dog_name IS NOT NULL THEN 1 ELSE 0 END AS cat_dog_total
FROM table
You can use a subquery to maintain readability:
SELECT (CASE WHEN cat_name IS NOT NULL THEN 1 ELSE 0 END +
CASE WHEN dog_name IS NOT NULL THEN 1 ELSE 0 END
) AS cat_dog_total
from (select JSON_EXTRACT_SCALAR(data, '$.cat.name') as cat_name
JSON_EXTRACT_SCALAR(data, '$.dog.name') as dog_name
from table
) t
Of course, you can substitute in the JSON_EXTRACT_SCALAR() expressions as well, but this is more readable.
I can find the count of non null values by typing each column name, but is there a way to write it without manually typing the column names as I have 100+ columns in my table.
select 'col1Name', count(col1Name) from table where col1Name is null
union
select 'col2Name', count(col2Name) from table where col2Name is null
union ...
select 'col20Name', count(col20Name) from table where col20Name is null
You can use a case operation here
select
sum(case when a is null then 1 else 0 end) A,
sum(case when b is null then 1 else 0 end) B,
sum(case when c is null then 1 else 0 end) C
from T
I've a table in my database for which I need to check if all rows have one field not null.
If there are no row or if there is at least 1 row with the field null => true
If there are rows and they are all with the field not null => False
Is there a way to do this in on simple query? Or I need to check if my table is empty first then if it's not check if I've a row with the field value empty ?
This will count how many NULL values you have in a field;
SELECT
SUM(CASE WHEN FieldName IS NULL THEN 1 ELSE 0 END) NullValues
FROM TableName
Will return 0 if there are no NULL values, and will return the number of NULLS if there are any present.
If you actually want to return a value as 'True' or 'False' then do this;
SELECT CASE
WHEN a.NullValues > 0
THEN 'True'
ELSE 'False'
END CheckField
FROM (
SELECT
SUM(CASE WHEN FieldName IS NULL
THEN 1
ELSE 0
END) NullValues
FROM TableName
) a
Use count(*) and count(field) and compare the two:
select
case when count(*) > 0 and count(*) = count(field) then 1 -- not empty and no nulls
else 0 end as isgood
from mytable;
Oracle SQL has no boolean data type , so I use 1 for true and 0 for false. You can replace this with whatever you like (e.g. 'true' instead of 1 and 'false' instead of 0).
As to turning this into a predicate (correlated to a main query), you'd use something along the lines of:
select ...
from main
where exists
(
select 1
from mytable
where mytable.colx = main.coly
having count(*) > 0 and count(*) = count(field)
);
You can do this with aggregation. However, it is difficult to understand what you are asking for. If you want to check that a field has no NULL values, you can do:
select (case when count(*) > 0 then 1 else 0 end) as HasNullValues
from t
where field is null;
Alternate way I found using max with putting null first:
select case when
max(field) keep (dense_rank first order by datfin desc nulls first) is null then 1
else 0 end as flag
from MYTABLE;
I have a SQL query which displays a list of results. Every row in my database has about
20 columns and not every column is mandatory. I would like the result of the SQL query to be
sorted by the number of filled in columns. The rows with the least empty columns at the top, the ones with the most empty columns at the bottom. Do any of you guys have an idea how to do this?
I thought about adding an extra column to the table which if updated every time the user edits their row, this number would indicate the number of empty columns and I could sort my list with that. This however, sounds like unnecessary troubles, but maybe there is no other way? I'm sure somebody on here will know!
Thanks,
Sander
You can do it in just about any database with a giant case statement:
order by ((case when col1 is not null then 1 else 0 end) +
(case when col2 is not null then 1 else 0 end) +
. . .
(case when col20 is not null then 1 else 0 end)
) desc
You could order by the amount of empty columns:
order by
case when col1 is null then 1 else 0 end +
case when col2 is null then 1 else 0 end +
case when col3 is null then 1 else 0 end +
...
case when col20 is null then 1 else 0 end
(Note the + at the end of the lines: it's only one column with the integer count of empty fields, sorted in ascending order.)