I've got a problem with my SQL task and didn't find any answers yet.
I've got table with this sample data:
ID
Value
Date
1
1
2020-01-01
1
2
2020-03-02
1
1
2020-03-21
1
1
2020-04-14
1
3
2020-05-01
1
1
2020-08-09
1
1
2020-09-12
1
1
2020-10-12
1
3
2020-12-04
All I want to get is:
ID
Value
Date
1
1
2020-01-01
1
2
2020-03-02
1
1
2020-03-21
1
3
2020-05-01
1
1
2020-08-09
1
3
2020-12-04
Some kind of changing value history, but only if the value was changed - when value on new record is the same, get value with min date.
I tried with grouping and row_number, but got no positive results. Any ideas how to do that?
One way to articulate your logic is to say that you want to retain a record when the previous record, as ordered by the date (within a given ID), has a different value than the current record.
WITH cte AS (
SELECT *, LAG(Value) OVER (PARTITION BY ID ORDER BY Date) LagValue
FROM yourTable
)
SELECT ID, Value, Date
FROM cte
WHERE LagValue <> Value OR LagValue IS NULL
ORDER BY Date;
Demo
I have a table called Inventory with the below columns
item warehouse date sequence number value
111 100 2019-09-25 12:29:41.000 1 10
111 100 2019-09-26 12:29:41.000 1 20
222 200 2019-09-21 16:07:10.000 1 5
222 200 2019-09-21 16:07:10.000 2 10
333 300 2020-01-19 12:05:23.000 1 4
333 300 2020-01-20 12:05:23.000 1 5
Expected Output:
item warehouse date sequence number value
111 100 2019-09-26 12:29:41.000 1 20
222 200 2019-09-21 16:07:10.000 2 10
333 300 2020-01-20 12:05:23.000 1 5
Based on item and warehouse, i need to pick latest date and latest sequence number of value.
I tried with below code
select item,warehouse,sequencenumber,sum(value),max(date) as date1
from Inventory t1
where
t1.date IN (select max(date) from Inventory t2
where t1.warehouse=t2.warehouse
and t1.item = t2.item
group by t2.item,t2.warehouse)
group by t1.item,t1.warehouse,t1.sequencenumber
Its working for latest date but not for latest sequence number.
Can you please suggest how to write a query to get my expected output.
You can use row_number() for this:
select *
from (
select
t.*,
row_number() over(
partition by item, warehouse
order by date desc, sequence_number desc, value desc
) rn
from mytable t
) t
where rn = 1
I have a table with some records about fuel consumption. The important columns in the table are: CONSUME_DATE_FROM and CONSUM_DATE_TO.
I want to calculate average fuel consumption per cars on a monthly basis but some rows are not in the same month. For example some have a three month difference between them and the total of gas per litre is aggregated in a single row.
Now I should find records that have difference more than a month between CONSUME_DATE_FROM and CONSUM_DATE_TO, and duplicate them in current or second table per count of month and divide the total gas per litre between related rows.
I've this table with the following data:
ID VehicleId CONSUME_DATE_FROM CONSUM_DATE_TO GAS_PER_LITER
1 100 2018-10-25 2018-12-01 600
2 101 2018-07-19 2018-07-24 100
3 102 2018-12-31 2019-01-01 400
4 103 2018-03-29 2018-05-29 200
5 104 2018-02-05 2018-02-09 50
The expected output table should be as below
ID VehicleId CONSUME_DATE_FROM CONSUM_DATE_TO GAS_PER_LITER
1 100 2018-10-25 2018-12-01 200
1 100 2018-10-25 2018-12-01 200
1 100 2018-10-25 2018-12-01 200
2 101 2018-07-19 2018-07-24 100
3 102 2018-12-31 2019-01-01 200
3 102 2018-12-31 2019-01-01 200
4 103 2018-03-29 2018-05-29 66.66
4 103 2018-03-29 2018-05-29 66.66
4 103 2018-03-29 2018-05-29 66.66
5 104 2018-02-05 2018-02-09 50
Or as below
ID VehicleId CONSUME_DATE_FROM CONSUM_DATE_TO GAS_PER_LITER DATE_RELOAD_GAS
1 100 2018-10-25 2018-12-01 200 2018-10-01
1 100 2018-10-25 2018-12-01 200 2018-11-01
1 100 2018-10-25 2018-12-01 200 2018-12-01
2 101 2018-07-19 2018-07-24 100 2018-07-01
3 102 2018-12-31 2019-01-01 200 2018-12-01
3 102 2018-12-31 2019-01-01 200 2019-01-01
4 103 2018-03-29 2018-05-29 66.66 2018-03-01
4 103 2018-03-29 2018-05-29 66.66 2018-04-01
4 103 2018-03-29 2018-05-29 66.66 2018-05-01
5 104 2018-02-05 2018-02-09 50 2018-02-01
Can someone please help me out with this query?
I'm using oracle database
Your business rule treats the difference between CONSUME_DATE_FROM and CONSUM_DATE_TO as absolute months. So you expect the difference between 2018-10-25 and 2018-12-01 to be three months whereas the difference in days actually equates to about 1.1 months. So we can't use simple date arithmetic to get your desired output, we need to do some additional massaging of the dates.
The query below implements your desired logic by deriving the first day of the month for CONSUME_DATE_FROM and the last day of the month for CONSUME_DATE_TO, then using ceil() to round the difference up to the nearest whole number of months.
This is calculated in a subquery which is used in the main query with the old connect by level trick to multiply a record by level number of times:
with cte as (
select f.*
, ceil(months_between(last_day(CONSUM_DATE_TO)
, trunc(CONSUME_DATE_FROM,'mm'))) as diff
from fuel_consumption f
)
select cte.id
, cte.VehicleId
, cte.CONSUME_DATE_FROM
, cte.CONSUM_DATE_TO
, cte.GAS_PER_LITER/cte.diff as GAS_PER_LITER
, add_months(trunc(cte.CONSUME_DATE_FROM, 'mm'), level-1) as DATE_RELOAD_GAS
from cte
connect by level <= cte.diff
and prior cte.id = cte.id
and prior sys_guid() is not null
;
"what about if add a additional column "DATE_RELOAD_GAS" that display difference date for similar rows"
From your posted sample it seems like DATE_RELOAD_GAS is the first day of the month for each month bounded by CONSUME_DATE_FROM and CONSUM_DATE_TO. I have amended my solution to implement this rule.
By using connect by level structure with considering to_char(c.CONSUME_DATE_FROM + level - 1,'yyyymm') as month I was able to resolve as below :
select ID, VehicleId, myMonth, CONSUME_DATE_FROM, CONSUM_DATE_TO,
trunc(GAS_PER_LITER/max(rn) over (partition by ID order by ID),2) as GAS_PER_LITER,
'01.'||substr(myMonth,5,2)||'.'||substr(myMonth,1,4) as DATE_RELOAD_GAS
from
(
with consumption( ID, VehicleId, CONSUME_DATE_FROM, CONSUM_DATE_TO, GAS_PER_LITER ) as
(
select 1,100,date'2018-10-25',date'2018-12-01',600 from dual union all
select 2,101,date'2018-07-19',date'2018-07-24',100 from dual union all
select 3,102,date'2018-12-31',date'2019-01-01',400 from dual union all
select 4,103,date'2018-03-29',date'2018-05-29',200 from dual union all
select 5,104,date'2018-02-05',date'2018-02-09', 50 from dual
)
select ID, to_char(c.CONSUME_DATE_FROM + level - 1,'yyyymm') myMonth,
VehicleId, c.CONSUME_DATE_FROM, c.CONSUM_DATE_TO, GAS_PER_LITER,
row_number() over (partition by ID order by ID) as rn
from dual join consumption c
on c.ID >= 2
group by ID, to_char(c.CONSUME_DATE_FROM + level - 1,'yyyymm'), VehicleId,
c.CONSUME_DATE_FROM, c.CONSUM_DATE_TO, c.GAS_PER_LITER
connect by level <= c.CONSUM_DATE_TO - c.CONSUME_DATE_FROM + 1
union all
select ID, to_char(c.CONSUME_DATE_FROM + level - 1,'yyyymm') myMonth,
VehicleId, c.CONSUME_DATE_FROM, c.CONSUM_DATE_TO, GAS_PER_LITER,
row_number() over (partition by ID order by ID) as rn
from dual join consumption c
on c.ID = 1
group by ID, to_char(c.CONSUME_DATE_FROM + level - 1,'yyyymm'), VehicleId,
c.CONSUME_DATE_FROM, c.CONSUM_DATE_TO, c.GAS_PER_LITER
connect by level <= c.CONSUM_DATE_TO - c.CONSUME_DATE_FROM + 1
) q
group by ID, VehicleId, myMonth, CONSUME_DATE_FROM, CONSUM_DATE_TO, GAS_PER_LITER, rn
order by ID, myMonth;
I met an interesting issue that if I consider the join condition in the subquery as c.ID >= 1 query hangs on for huge period of time, so splitted into two parts by union all
as c.ID >= 2 and c.ID = 1
Rextester Demo
I am trying to write a sql query (in amazon redshift) that counts the number of times that customer goes from not meeting criteria to meeting criteria, so when a 1 occurs the date after a 0.
I'm stuggling to figure out the logic to do this
ID Snapshot_date Meets Criteria
55 1/1/2018 0
55 1/5/2018 1
55 1/10/2018 1
55 1/15/2018 1
55 1/20/2018 0
55 1/25/2018 1
Use lag to get the previous value,check for the conditions and count.
select id,count(*)
from (select id,snapshot_date
,lag(meets_critetria,1) over(partition by id order by snapshot_date) as prev_m_c
from tbl
) t
where prev_m_c = 0 and meets_criteria = 1
group by id
I have a table which contain _id, underSubheadId, wefDate, price.
Whenever a product is created or price is edited an entry is made in this table also.
What I want is if I enter a date, I get the latest price of all distinct UnderSubheadIds before the date (or on that date if no entry found)
_id underHeadId wefDate price
1 1 2016-11-01 5
2 2 2016-11-01 50
3 1 2016-11-25 500
4 3 2016-11-01 20
5 4 2016-11-11 30
6 5 2016-11-01 40
7 3 2016-11-20 25
8 5 2016-11-15 52
If I enter 2016-11-20 as date I should get
1 5
2 50
3 25
4 30
5 52
I have achieved the result using ROW NUMBER function in SQL SERVER, but I want this result in Sqlite which don't have such function.
Also if a date like 2016-10-25(which have no entries) is entered I want the price of the date which is first.
Like for 1 we will get price as 5 as the nearest and the 1st entry is 2016-11-01.
This is the query for SQL SERVER which is working fine. But I want it for Sqlite which don't have ROW_NUMBER function.
select underSubHeadId,price from(
select underSubHeadId,price, ROW_NUMBER() OVER (Partition By underSubHeadId order by wefDate desc) rn from rates
where wefDate<='2016-11-19') newTable
where newTable.rn=1
Thank You
This is a little tricky, but here is one way:
select t.*
from t
where t.wefDate = (select max(t2.wefDate)
from t t2
where t2.underSubHeadId = t.underSubHeadId and
t2.wefdate <= '2016-11-20'
);
select underHeadId, max(price)
from t
where wefDate <= "2016-11-20"
group by underHead;