Remove Trailing zeros using xsl1.0 or xslt 2.0 - xslt-1.0

Question

I have to sum the values from xml and remove the Trailing zeros from xml.
can you help me to remove this using xsl1.0 or xslt2.0
I have tried with number(.) but its not removing the trailing zeros.
My input is below
<test>
<loop>
<lines>
<linesTotal>2010</linesTotal>
</lines>
<lines>
<linesTotal>20</linesTotal>
</lines>
</loop>
</test>
Expected output is
203
but it results 2030
Please help me!

Answer 1

I can't see why this would be useful (at least not in the given example), and I strongly suspect you don't really want to do this.
But - mainly for fun - here's a method to remove any trailing zeros from the result:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/test">
<output>
<xsl:call-template name="remove-trailing-zeros">
<xsl:with-param name="number" select="sum(loop/lines/linesTotal)"/>
</xsl:call-template>
</output>
</xsl:template>
<xsl:template name="remove-trailing-zeros">
<xsl:param name="number"/>
<xsl:choose>
<xsl:when test="$number and not($number mod 10)">
<xsl:call-template name="remove-trailing-zeros">
<xsl:with-param name="number" select="$number div 10"/>
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$number"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
</xsl:stylesheet>
In XSLT 2.0, you could make this a function instead of a template. Or move the problem to the string domain (as suggested in another answer):
<xsl:template match="/test">
<xsl:param name="sum" select="sum(loop/lines/linesTotal)"/>
<output>
<xsl:value-of select="replace(string($sum), '0+$', '')"/>
</output>
</xsl:template>

Answer 2

You can use replace function using 2.0:
replace(string(2010+30), '0$', '')