Select-Object -Property parameter prevents getting object while in loop - powershell-5.0

Question

Please help me understand why I cannot output the object with Select-Object using -Property parameter while being in loop.
Here is example:
$GPjob = Start-Job -ScriptBlock {Get-Process | Select-Object -First 1}
for ($i = 0 ; $i -lt 200000 ; $i++) {
if (($GPjob.State -eq 'Completed') -and ($GPjob.HasMoreData)) {
"Step 1: $(Get-Date) : `$i=$i"
Receive-Job $GPjob | Select-Object -Property Name
"Step 2: $(Get-Date) : `$i=$i"
}
}
Step 1, Receive-Job and Step 2 lines should be executed one by one inside one of the $i cycles. So I should see all three outputs at once. But actually, I don't see output from Receive-Job and Step 2 until entire loop is over.
But if I don't use -Property parameter for Receive-Job, everything goes as expected: I see all three outputs at once.

Answer 1

This way comes out faster, but I can't explain why. Maybe it's how Out-Default works. I got the same results with &{ for () } and foreach-object. In the ise debugger, if I put a breakpoint on the receive-job line, the output comes out right after I step past the "Step 2" line.
Receive-Job $GPjob | Select-Object -ExpandProperty Name

Answer 2

I still didn't find the answer, but I found a workaround.
Format-Table fixes this mistery. So the next code works just as expected:
$GPjob = Start-Job -ScriptBlock {Get-Process | Select-Object -First 1}
for ($i = 0 ; $i -lt 200000 ; $i++) {
if (($GPjob.State -eq 'Completed') -and ($GPjob.HasMoreData)) {
"Step 1: $(Get-Date) : `$i=$i"
Receive-Job $GPjob | Select-Object -Property Name | ft
"Step 2: $(Get-Date) : `$i=$i"
}
}