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I have the following table named customerOrders.
ID user order
1 1 2
2 1 3
3 1 1
4 2 1
5 1 5
6 2 4
7 3 1
8 6 2
9 2 2
10 2 3
I want to return to users with most orders. Currently, I have the following QUERY:
SELECT user, COUNT(user) AS UsersWithMostOrders
FROM customerOrders
GROUP BY user
ORDER BY UsersWithMostOrders DESC;
This returns me all the values grouped by total orders like.
user UsersWithMostOrders
1 4
2 4
3 1
6 1
I only want to return the users with most orders. In my case that would be user 1 and 2 since both of them have 4 orders. If I use TOP 1 or LIMIT, it will only return the first user. If I use TOP 2, it will only work in this scenario, it will return invalid data when top two users have different count of orders.
Required Result
user UsersWithMostOrders
1 4
2 4
You can use TOP 1 WITH TIES:
SELECT TOP 1 WITH TIES
[user], COUNT(*) AS UsersWithMostOrders
FROM customerOrders
GROUP BY [user]
ORDER BY UsersWithMostOrders DESC;
See the demo.
Results:
> user | UsersWithMostOrders
> ---: | ------------------:
> 1 | 4
> 2 | 4
Option 1
Should work with most versions of SQL.
select *
from (
select *,
rank() over(order by numOrders desc) as rrank
from (
select `user`, count(*) as numOrders
from customerOrders
group by `user`
) summed
) ranked
where rrank = 1
Play around with the code here
Option 2
If your version of SQL allows window functions (with), here is a much more readable solution which does the same thing
with summed as (
select `user`, count(*) as numOrders
from customerOrders
group by `user`
),
ranked as (
select *,
rank() over(order by numOrders desc) as rrank
from summed
)
select *
from ranked
where rrank = 1
Play around with the code here
You can use a CTE to attain this Req:
;WITH CTE AS(
SELECT [user], COUNT(user) AS UsersWithMostOrders
FROM #T
GROUP BY [user])
SELECT M.* from CTE M
INNER JOIN ( SELECT
MAX(UsersWithMostOrders) AS MaximumOrders FROM CTE) S ON
M.UsersWithMostOrders=S.MaximumOrders
Below Oracle Query can help:
WITH test_table AS
(
SELECT user, COUNT(order) AS total_order , DENSE_RANK() OVER (ORDER BY
total_order desc) AS rank_orders FROM customerOrders
GROUP BY user
)
select * from test_table where rank_orders = 1
Here are two tables:
LocationId Address City State Zip
1 2100, 1st St Austin TX 76819
2 2200, 2nd St Austin TX 76829
3 2300, 3rd St Austin TX 76839
4 2400, 4th St Austin TX 76849
5 2500, 5th St Austin TX 76859
6 2600, 6th St Austin TX 76869
TripId PassengerId FromLocationId ToLocationId
1 746896 1 2
2 746896 2 1
3 234456 1 3
4 234456 3 1
5 234456 1 4
6 234456 4 1
7 234456 1 6
8 234456 6 1
9 746896 1 2
10 746896 2 1
11 746896 1 2
12 746896 2 1
I want TOP 5 locations which each passenger has traveled to (does not matter if its from or to location). I can get it using a UNION, but was wondering if there was a better way to do this.
My Solution:
select top 5 *
from
(select count(l.LocationId) as cnt, l.LocationId, l.Address1, l.Address2, l.City, St.State , l.Zip
from
Trip t
join LOCATION l on t.FromLocationId = l.LocationId
where t.PassengerId = 746896
group by count(l.LocationId) as cnt, l.LocationId, l.Address1, l.Address2, l.City, St.State , l.Zip
UNION
select count(l.LocationId) as cnt, l.LocationId, l.Address1, l.Address2, l.City, St.State , l.Zip
from
Trip t
join LOCATION l on t.ToLocationId = l.LocationId
where t.PassengerId = 746896
group by count(l.LocationId) as cnt, l.LocationId, l.Address1, l.Address2, l.City, St.State , l.Zip
) as tbl
order by cnt desc
This will give you top 5 location.
SELECT TOP 5 tmp.fromlocationid AS locationid,
Count(tmp.fromlocationid) AS Times
FROM (SELECT fromlocationid
FROM trip
UNION ALL
SELECT tolocationid
FROM trip) tmp
GROUP BY tmp.fromlocationid
Method 1: This will give you top 5 location of each passenger.
WITH cte AS
( SELECT passengerid,
locationid,
Count(locationid) AS Times,
Row_number() OVER(partition BY passengerid ORDER BY passengerid ASC) AS RowNum
FROM (SELECT tripid, passengerid, fromlocationid AS locationid
FROM trip
UNION ALL
SELECT tripid, passengerid, tolocationid AS locationid
FROM trip) tmp
GROUP BY passengerid, locationid )
SELECT *
FROM cte
WHERE rownum <= 5
ORDER BY passengerid, Times DESC
Method 2: Same result without Union Operator (Top 5 location of each passenger)
WITH cte AS
( SELECT passengerid,
locationid,
Count(locationid) AS Times,
Row_number() OVER(partition BY passengerid ORDER BY passengerid ASC) AS RowNum
FROM trip
UNPIVOT ( locationid
FOR subject IN (fromlocationid, tolocationid) ) u
GROUP BY passengerid, locationid )
SELECT *
FROM cte
WHERE rownum <= 5
ORDER BY passengerid, times DESC
If you also want to get the location details, you can simply join the location table.
SELECT cte.* , location.*
FROM cte
INNER JOIN location ON location.locationid = cte.locationid
WHERE rownum <= 5
ORDER BY passengerid, times DESC
Reference
- https://stackoverflow.com/a/19056083/6327676
YOou'll need to replace the SELECT *'s with the columns you need, however, something like this should work:
WITH Visits AS (
SELECT *,
COUNT(*) OVER (PARTITION BY t.PassengerID, L.LocationID) AS Visits
FROM Trip T
JOIN [Location] L ON T.FromLocationId = L.LocationId),
Rankings AS (
SELECT *,
DENSE_RANK() OVER (PARTITION BY V.PassengerID ORDER BY Visits DESC) AS Ranking
FROM Visits V)
SELECT *
FROM Rankings
WHERE Ranking <= 5;
Further simplified solution
select top 3 * from
(
Select distinct count(locationId) as cnt, locationId from trip
unpivot
(
locationId
for direction in (fromLocationId, toLocationId)
)u
where passengerId IN (746896, 234456)
group by direction, locationId
)as tbl2
order by cnt desc;
Solution combining columns
The main issue for me is avoiding union to combine the two columns.
The UNPIVOT command can do this.
select top 3 * from (
select count(locationId) cnt, locationId
from
(
Select valu as locationId, passengerId from trip
unpivot
(
valu
for loc in (fromLocationId, toLocationId)
)u
)united
where passengerId IN (746896, 234456)
group by locationId
) as tbl
order by cnt desc;
http://sqlfiddle.com/#!18/cec8b/136
If you want to get the counts by direction:
select top 3 * from (
select count(locationId) cnt, locationId, direction
from
(
Select valu as locationId, direction, passengerId from trip
unpivot
(
valu
for direction in (fromLocationId, toLocationId)
)u
)united
where passengerId IN (746896, 234456)
group by locationId, direction
) as tbl
order by cnt desc;
http://sqlfiddle.com/#!18/cec8b/139
Same Results as you ( minus some minor descriptions )
select top 3 * from
(
select distinct * from (
select count(locationId) cnt, locationId
from
(
Select valu as locationId, direction, passengerId from trip
unpivot
(
valu
for direction in (fromLocationId, toLocationId)
)u
)united
where passengerId IN (746896, 234456)
group by locationId, direction
) as tbl
)as tbl2
order by cnt desc;
You can do this without union all:
select top (5) t.passengerid, v.locationid, count(*)
from trip t cross apply
(values (fromlocationid), (tolocationid)) v(locationid) join
location l
on v.locationid = l.locationid
where t.PassengerId = 746896
group by t.passengerid, v.locationid
order by count(*) desc;
If you want an answer for all passengers, it would be a similar idea, using row_number(), but your query suggests you want the answer only for one customer at a time.
You can include additional fields from location as well.
Here is a SQL Fiddle.
If I have a table like this:
Id StateId Name
1 1 a
2 2 b
3 1 c
4 1 d
5 3 e
6 2 f
I want to select like below:
Id StateId Name
4 1 d
5 3 e
6 2 f
For example, Ids 1,3,4 have stateid 1. So select row with max Id, i.e, 4.
; WITH CTE AS
(
SELECT *, ROW_NUMBER() OVER(PARTITION BY STATEID ORDER BY ID DESC) AS RN
)SELECT ID, STATEID, NAME FROM CTE WHERE RN = 1
You can use ROW_NUMBER() + TOP 1 WITH TIES:
SELECT TOP 1 WITH TIES
Id,
StateId,
[Name]
FROM YourTable
ORDER BY ROW_NUMBER() OVER (PARTITION BY StateId ORDER BY Id DESC)
Output:
Id StateId Name
4 1 d
6 2 f
5 3 e
Disclaimer: I gave this answer before the OP had specified an actual database, and hence avoided using window functions. For a possibly more appropriate answer, see the reply by #Tanjim above.
Here is an option using joins which should work across most RDBMS.
SELECT t1.*
FROM yourTable t1
INNER JOIN
(
SELECT StateId, MAX(Id) AS Id
FROM yourTable
GROUP BY StateId
) t2
ON t1.StateId = t2.StateId AND
t1.Id = t2.Id
The following using a subquery, to find the maximum Id for each of the states. The WHERE clause then only includes rows with ids from that subquery.
SELECT
[Id], [StateID], [Name]
FROM
TABLENAME S1
WHERE
Id IN (SELECT MAX(Id) FROM TABLENAME S2 WHERE S2.StateID = S1.StateID)
how to get around this error :
Unable to use an aggregate or a subquery in an expression used in the
GROUP BY list of a GROUP BY clause.
here is my query :
select Id, name,dayA,monthA,yearA,
sum(x) as x,
(select SUM(x) group by month) as total,
from table_A
group by Id,name,monthA,dAyA,yearA, SUM(x)
in other words :
sample data :
id name dayA monthA yearA x
===========================
1 name1 2 3 2016 4
2 name2 2 3 2016 3
3 name1 2 3 2016 2
Expected result :
id name dayA monthA yearA x total
===================================
1 name1 2 3 2016 4 6
2 name2 2 3 2016 3 3
3 name1 2 3 2016 2 6
Thanks in advance
you're query has more problem.
(select SUM(x) group by month) as total, is it from the same table, not likely since column month is not mention inyour group by. When using sub query in a query, you must guaranteed that i will only return one record.
Based on your sample data and expected results...
create table table_A(
id int,
name varchar(25),
dayA int,
monthA int,
yearA int,
x int
)
insert into table_A
values (1,'name1',2,3,2016,4),
(2,'name2',2,3,2016,3),
(2,'name1',2,3,2016,2)
select ta.id, ta.name, ta.dayA, ta.monthA, ta.yearA, ta.x, total.Total from table_A as ta
left join
(select name, sum(x) as Total from table_A group by name) total on ta.name = total.name
group by
ta.id, ta.name, ta.dayA, ta.monthA, ta.yearA, ta.x, total.name, total.Total
May be this is what you want:
select table_A.*, TotalSums.total
from table_A
left join (select name, monthA, dayA, yearA, sum(x) as total from table_A group by name, monthA, dayA, yearA) as TotalSums
on table_A.name = TotalSums.name
and table_A.monthA = TotalSums.monthA
and table_A.dayA = TotalSums.dayA
and table_A.yearA = TotalSums.yearA
order by id
i think this is what you're looking for
select Id, main.name,dayA,main.monthA,main.yearA,
sum(x) as x,
,max(total.total) as total
from table_A as main
join (select SUM(x) total ,name ,monthA,yearA from table_A group by name,monthA,yearA) as total
on main.name = total.name
and main.monthA = total.monthA
and main.yearA = total.yearA
group by Id,main.name,monthA,dAyA,yearA
I have a table_1:
id custno
1 1
2 2
3 3
and a table_2:
id custno qty descr
1 1 10 a
2 1 7 b
3 2 4 c
4 3 7 d
5 1 5 e
6 1 5 f
When I run this query to show the minimum order quantities from every customer:
SELECT DISTINCT table_1.custno,table_2.qty,table_2.descr
FROM table_1
LEFT OUTER JOIN table_2
ON table_1.custno = table_2.custno AND qty = (SELECT MIN(qty) FROM table_2
WHERE table_2.custno = table_1.custno )
Then I get this result:
custno qty descr
1 5 e
1 5 f
2 4 c
3 7 d
Customer 1 appears twice each time with the same minimum qty (& a different description) but I only want to see customer 1 appear once. I don't care if that is the record with 'e' as a description or 'f' as a description.
First of all... I'm not sure why you need to include table_1 in the queries to begin with:
select custno, min(qty) as min_qty
from table_2
group by custno;
But just in case there is other information that you need that wasn't included in the question:
select table_1.custno, ifnull(min(qty),0) as min_qty
from table_1
left outer join table_2
on table_1.custno = table_2.custno
group by table_1.custno;
"Generic" SQL way:
SELECT table_1.custno,table_2.qty,table_2.descr
FROM table_1, table_2
WHERE table_2.id = (SELECT TOP 1 id
FROM table_2
WHERE custno = table_1.custno
ORDER BY qty )
SQL 2008 way (probably faster):
SELECT custno, qty, descr
FROM
(SELECT
custno,
qty,
descr,
ROW_NUMBER() OVER (PARTITION BY custno ORDER BY qty) RowNum
FROM table_2
) A
WHERE RowNum = 1
If you use SQL-Server you could use ROW_NUMBER and a CTE:
WITH CTE AS
(
SELECT table_1.custno,table_2.qty,table_2.descr,
RN = ROW_NUMBER() OVER ( PARTITION BY table_1.custno
Order By table_2.qty ASC)
FROM table_1
LEFT OUTER JOIN table_2
ON table_1.custno = table_2.custno
)
SELECT custno, qty,descr
FROM CTE
WHERE RN = 1
Demolink