Multiple Rows into One Row multiple columns - sql

Question

We need to list all numbers as a flat data set, how can we do that?
Table Name: Telephone
ID TYPE NUMBER
==================================
123 MN 042153939
123 HN 2242116
123 MN 1234567890
123 HN 12345678
Create Table Telephone
(
ID Integer,
Type char(3),
Number Varchar(20)
);
insert into Telephone values
(123, 'MN', '042153939'),
(123, 'HN', '2242116'),
(123, 'MN', '1234567890'),
(123, 'HN', '12345678');
I want SQL to return data in this format
ID MN#1 Mn#2 HN#1 HN#2
================================================
123 042153939 1234567890 2242116 12345678

Answer 1

Dynamic approach
Init
DROP TABLE IF EXISTS #Telephone;
CREATE TABLE #Telephone(ID INT,Type CHAR(3),Number VARCHAR(20));
INSERT INTO #Telephone (ID,Type,Number) VALUES
(123, 'MN', '042153939'),
(123, 'HN', '2242116'),
(123, 'MN', '1234567890'),
(123, 'HN', '12345678');
The code
DECLARE #ColumnList NVARCHAR(MAX);
SELECT #ColumnList = STUFF((SELECT ',[' + RTRIM(t.[Type]) + '#'
+ CONVERT(NVARCHAR(255),ROW_NUMBER()OVER(PARTITION BY t.[Type] ORDER BY t.ID)) + ']'
FROM #Telephone t FOR XML PATH(''),TYPE).value('(./text())[1]','NVARCHAR(MAX)'),1,1,'')
;
DECLARE #sql NVARCHAR(MAX) = '';
SET #sql = N'
SELECT ID,' + #ColumnList + N'
FROM (
SELECT t.ID,t.Number, RTRIM(t.[Type]) + ''#'' + CONVERT(NVARCHAR(255),ROW_NUMBER()OVER(PARTITION BY t.[Type] ORDER BY t.ID)) AS [Type]
FROM #Telephone t
) a
PIVOT(MAX(a.Number) FOR a.Type IN (' + #ColumnList + N')) p
'
;
--PRINT #sql
IF #sql IS NOT NULL EXEC(#sql);

Answer 2

try pivoting like below :
SELECT first_column AS <first_column_alias>,
[pivot_value1], [pivot_value2], ... [pivot_value_n]
FROM
(<source_table>) AS <source_table_alias>
PIVOT
(
aggregate_function(<aggregate_column>)
FOR <pivot_column> IN ([pivot_value1], [pivot_value2], ... [pivot_value_n])
) AS <pivot_table_alias>;

Answer 3

We can try using a pivot query with the help of ROW_NUMBER():
WITH cte AS (
SELECT *, ROW_NUMBER() OVER (ORDER BY TYPE DESC, NUMBER) rn
FROM Telephone
)
SELECT
ID,
MAX(CASE WHEN rn = 1 THEN NUMBER END) AS [MN#1],
MAX(CASE WHEN rn = 2 THEN NUMBER END) AS [MN#2],
MAX(CASE WHEN rn = 3 THEN NUMBER END) AS [HN#3],
MAX(CASE WHEN rn = 4 THEN NUMBER END) AS [HN#4]
FROM cte
GROUP BY ID;

Answer 4

You may try this. with row_number() and pivot.
For more info about pivot you may find this link PIVOT.
; with cte as (
select row_number() over (partition by type order by id ) as Slno, * from Telephone
)
, ct as (
select id, type + '#' + cast(slno as varchar(5)) as Type, values from cte
)
select * from (
select * from ct
) as d
pivot
( max(values) for type in ( [MN#1],[Mn#2],[HN#1],[HN#2] )
) as p