once more I need some assistance. I have one table called Data and contains cars with color and type.
I have one table called "output" and I want the color number appearing per "CARid" (when type='new') and the total colors per ID.
I tried to do it with "case" but it seems impossible to do it in one sql code. Do I need a temp table and then join?
data
carID color type
1 red new
2 blue old
3 red new
2 green new
2 blue new
1 red old
4 empty empty
output
CarID NColor ColorTotal
1 1 2
2 2 3
3 1 1
4 0 0
Some basic aggregation and a case expression should return what I think you are after. But no idea where CarID 4 comes from, it isn't in your sample data.
select CarID
, NColor = sum(case when type = 'new' then 1 end)
, ColorTotal = count(*)
from Data
group by CarID
Related
I have a table with following structure
Id
Division
Details
1
A
some text
2
A
some text
3
B
some text
4
B
some text
5
B
some text
I need to add a new column of integer type named "Order" with some data as described below:
Id
Division
Details
Order
1
A
some text
1
2
A
some text
2
3
B
some text
1
4
B
some text
2
5
B
some text
3
As we can see integer data in "Order" column sequence has to be reset if "Division" data changes. There's are thousand of rows in the table, with more than 100 different divisions.
How can I achieve this?
You can use row_number():
select t.*,
row_number() over(partition by division order by id) rn
from mytable t
I have 2 tables I am combining and that works but I think I designed the second table wrong as I have a column for each item of what really is a multiple choice question. The query is this:
select Count(n.ID) as MemCount, u.Pay1Click, u.PayMailCC, u.PayMailCheck, u.PayPhoneACH, u.PayPhoneCC, u.PayWuFoo
from name as n inner join
UD_Demo_ORG as u on n.ID = u.ID
where n.MEMBER_TYPE like 'ORG_%' and n.CATEGORY not like '%_2' and
(u.Pay1Click = '1' or u.PayMailCC = '1' or u.PayMailCheck = '1' or u.PayPhoneACH = '1' or u.PayPhoneCC = '1' or u.PayWuFoo = '1')
group by u.Pay1Click, u.PayMailCC, u.PayMailCheck, u.PayPhoneACH, u.PayPhoneCC, u.PayWuFoo
The results come up like this:
Count Pay1Click PayMailCC PayMailCheck PayPhoneACH PayPhoneCC PayWuFoo
8 0 0 0 0 0 1
25 0 0 0 0 1 0
8 0 0 0 1 0 0
99 0 0 1 0 0 0
11 0 1 0 0 0 0
So the question is, how can I get this to 2 columns, Count and then the headers of the next 6 headers so the results look like this:
Count PaymentType
8 PayWuFoo
25 PayPhoneCC
8 PayPhoneACH
99 PayMailCheck
11 PayMailCC
Thanks.
Try this one
Select Count,
CASE WHEN Pay1Click=1 THEN 'Pay1Click'
PayMailCC=1 THEN ' PayMailCC'
PayMailCheck=1 THEN 'PayMailCheck'
PayPhoneACH=1 THEN 'PayPhoneACH'
PayPhoneCC=1 THEN 'PayPhoneCC'
PayWuFoo=1 THEN 'PayWuFoo'
END as PaymentType
FROM ......
I think indeed you made a mistake in the structure of the second table. Instead of creating a row for each multiple choice question, i would suggest transforming all those columns to a 'answer' column, so you would have the actual name of the alternative as the record in that column.
But for this, you have to change the structure of your tables, and change the way the table is populated. you should get the name of the alternative checked and put it into your table.
More on this, you could care for repetitive data in your table, so writing over and over again the same string could make your table grow larger.
if there are other things implied to the answer, other informations in the UD_Demo_ORG table, then you can normalize the table, creating a payment_dimension table or something like this, give your alternatives an ID such as
ID PaymentType OtherInfo(description, etc)...
1 PayWuFoo ...
2 PayPhoneCC ...
3 PayPhoneACH ...
4 PayMailCheck ...
5 PayMailCC ...
This is called a dimension table, and then in your records, you would have the ID of the payment type, and not the information you don't need.
So instead of a big result set, maybe you could simplify by much your query and have just
Count PaymentId
8 1
25 2
8 3
99 4
11 5
as a result set. it would make the query faster too, and if you need other information, you can then join the table and get it.
BUT if the only field you would have is the name, perhaps you could use the paymentType as the "id" in this case... just consider it. It is scalable if you separate to a dimension table.
Some references for further reading:
http://beginnersbook.com/2015/05/normalization-in-dbms/ "Normalization in DBMS"
http://searchdatamanagement.techtarget.com/answer/What-are-the-differences-between-fact-tables-and-dimension-tables-in-star-schemas "Differences between fact tables and dimensions tables"
I have this sort of structure
ID STATUS
1 FIRSTSTAT
2 FIRSTSTAT
3 FIRSTSTAT
1 SECSTAT
3 SECSTAT
3 THIRDSTAT
3 FOURTHSTAT
3 FIFTHSTAT
I want to get the 3 back because he has all following status (FIRSTSTAT, SECSTAT, THIRDSTAT). Do you have an idea how I could make that?
It should be done by explicitely giving the statuses because other statuses exist so SELECT FROM WHERE = 'THIRDSTAT' is not ok since it should have all three statuses, not only one of them.
So I guess it should be done calculating the SUM or something like that.
I tried the following but of course, it does not work :
SELECT
FROM
WHERE
AND
AND
If the number of different status values is known to always be 3:
select id
from tablename
where status in ('FIRSTSTAT', 'SECSTAT', 'THIRDSTAT')
group by id
having count(distinct status) = 3
i have a table name conversion and i have these below mentioned columns in it i want to multiply Length\width row elements l*w of 'dimension' values and display them in another new table
Please let me know if anything changes for the same logic in ms access
probably it is simple but i dont know exact query to solve the problem waiting for your solutions
ID area length/width dimensions **new column(L*W) here**
1 1 l 3 3*5=15
2 1 w 5
3 2 l 4
4 2 w 8
5 3 l 6
6 3 w 10
7 4 l 12
8 4 w 13
9 4 W 10
waiting for your reply
You could query the table twice: once for lengths and once for widths and then join by area and multiply the values:
select length.area, length.dimension * width.dimension
from
(select area, dimension from conversion where lenwidth = 'l') length
inner join
(select area, dimension from conversion where lenwidth = 'w') width
on length.area = width.area;
Two remarks:
I suppose that it is a typo that you have two width entries for area 4? Otherwise you would have to decide which value to take in above select statement.
It would not be a good idea to keep the old table and have a new table holding the results. What if you change a value? You would have to remember to change the result accordingly every time. So either ditch the old table or use a view instead of a new table.
Try this
select *,
dimensions*(lead(dimensions) over(order by id)) product
from table1;
Or if you want for the set of area then
select *,
case when length_width='l' and (lead(length_width) over(order by id))='w'
then dimensions*(lead(dimensions) over(order by id))
else 0
end as product
from table1;
fiddle
I have 3 tables:
'CouponType' table:
AutoID Code Name
1 CouT001 SunCoupon
2 CouT002 GdFriCoupon
3 CouT003 1for1Coupon
'CouponIssued' table:
AutoID CouponNo CouponType_AutoID
1 Co001 1
2 Co002 1
3 Co003 1
4 Co004 2
5 Co005 2
6 Co006 2
'CouponUsed' table:
AutoID Coupon_AutoID
1 2
2 3
3 5
I am trying to join 3 tables together using this query below but apparently I am not getting right values for CouponIssued column:
select CouponType.AutoID, Code, Name, Count(CouponIssued.CouponType_AutoID), count(CouponUsed.Coupon_AutoID)
from (CouponType left join CouponIssued
on (CouponType.AutoID = CouponIssued.CouponType_AutoID))
left join CouponUsed
on (couponUsed.Coupon_AutoID = CouponIssued.AutoID)
group by CouponType.AutoID, code, name
order by code
The expected result should be like:
**Auto ID Code Name Issued used**
1 CouT001 SunCoupon 3 2
2 CouT002 GdFriCoupon 3 1
3 CouT003 1for1Coupon 0 0
Thanks!
SELECT t.AutoID
,t.Code
,t.Name
,count(i.CouponType_AutoID) AS issued
,count(u.Coupon_AutoID) AS used
FROM CouponType t
LEFT JOIN CouponIssued i ON i.CouponType_AutoID = t.AutoID
LEFT JOIN CouponUsed u ON u.Coupon_AutoID = i.AutoID
GROUP BY 1,2,3;
You might consider using less confusing names for your table columns. I have made very good experiences with using the same name for the same data across tables (as far as sensible).
In your example, AutoID is used for three different columns, two of which appear a second time in another table under a different name. This would still make sense if Coupon_AutoID was named CouponIssued_AutoID instead.
change count(Coupon.CouponType_AutoID) to count(CouponIssued.CouponType_AutoID) and count(Coupon.Coupon_AutoID) to count(CouponUsed.Coupon_AutoID)