Quantity of data per month - sql

Question

I have to calculate the number of cars a day - of every month
I tried to do this using the Datediff formula
But I can't add the segmentation of each month either.
Attached script table:
create table TABLE_A(Code FLOAT,DateIn datetime,dateOut datetime,Garage varchar(30)
)
insert into Table_A (Code,DateIn,dateOut,Garage) values
('1','2018-06-07 00:00:00.000','2018-12-19 00:00:00.000','X'),
('2','2018-05-30 00:00:00.000','2018-12-19 00:00:00.000','Y'),
('3','2018-08-08 00:00:00.000','2018-11-18 00:00:00.000','Z'),
('4','2018-12-30 00:00:00.000','2018-12-30 00:00:00.000','Y'),
('5','2018-09-16 00:00:00.000','2018-10-19 00:00:00.000','Y'),
('6','2018-05-08 00:00:00.000','2018-08-28 00:00:00.000','Z'),
('7','2018-01-29 00:00:00.000','2018-07-31 00:00:00.000','Z'),
('8','2018-05-24 00:00:00.000','2018-09-10 00:00:00.000','X'),
('9','2018-05-02 00:00:00.000','2018-06-30 00:00:00.000','Y'),
('10','2018-07-05 00:00:00.000','2018-12-09 00:00:00.00','Z')
And this is the structure of the query result that should be:(Columns:Year,month,Garage-Number of vehicles per day by month)
Year month X Y Z
2018 1
2018 2
2018 3
2018 4
2018 5
2018 6
2018 7
2018 8
2018 9
2018 10
2018 11
2018 12
Thanks for the help.

Answer 1

You can first generate the list of months and year and then can left join your table to that -
WITH MONTHS AS (SELECT 1 MNTHS
UNION ALL
SELECT 2
UNION ALL
SELECT 3
UNION ALL
SELECT 4
UNION ALL
SELECT 5
UNION ALL
SELECT 6
UNION ALL
SELECT 7
UNION ALL
SELECT 8
UNION ALL
SELECT 9
UNION ALL
SELECT 10
UNION ALL
SELECT 11
UNION ALL
SELECT 12),
YEAR AS (SELECT 2018 YEAR)
SELECT YEAR,
MNTHS,
SUM(CASE WHEN Garage = 'X' THEN 1 ELSE 0 END) AS X,
SUM(CASE WHEN Garage = 'Y' THEN 1 ELSE 0 END) AS Y,
SUM(CASE WHEN Garage = 'Z' THEN 1 ELSE 0 END) AS Z
FROM (SELECT * FROM MONTHS M CROSS JOIN YEAR Y) YEARS
LEFT JOIN TABLE_A T ON YEARS.MNTHS = MONTH(T.DateIn)
AND YEARS.YEAR = YEAR(T.DateIn)
GROUP BY YEAR(DateIn),
MONTH(DateIn),
MNTHS,
YEAR
ORDER BY YEAR,
MNTHS
Here is the fiddle

Answer 2

The following query should do what you want, the Recursive CTE part is used to figure out dates between each DayIn and DayOut. Once we have the complete list of dates, in the main query we do a conditional aggregation to find out the DISTINCT number of cars in the garage each month,
CREATE TABLE TABLE_A (Code FLOAT,DateIn DATETIME,dateOut DATETIME,Garage VARCHAR(30))
INSERT INTO Table_A (Code,DateIn,dateOut,Garage) VALUES
('1','2018-06-07 00:00:00.000','2018-12-19 00:00:00.000','X'),
('2','2018-05-30 00:00:00.000','2018-12-19 00:00:00.000','Y'),
('3','2018-08-08 00:00:00.000','2018-11-18 00:00:00.000','Z'),
('4','2018-12-30 00:00:00.000','2018-12-30 00:00:00.000','Y'),
('5','2018-09-16 00:00:00.000','2018-10-19 00:00:00.000','Y'),
('6','2018-05-08 00:00:00.000','2018-08-28 00:00:00.000','Z'),
('7','2018-01-29 00:00:00.000','2018-07-31 00:00:00.000','Z'),
('8','2018-05-24 00:00:00.000','2018-09-10 00:00:00.000','X'),
('9','2018-05-02 00:00:00.000','2018-06-30 00:00:00.000','Y'),
('10','2018-07-05 00:00:00.000','2018-12-09 00:00:00.00','Z')
/** Main Query Starts Here **/
;WITH CTE ([Code],[DateIn],[DateOut],[Garage]) AS (
SELECT [Code], [DateIn], [DateOut], [Garage]
FROM TABLE_A WHERE [DateIn] <= [DateOut]
UNION ALL
SELECT [Code], DATEADD(DAY, 1, [DateIn]), [DateOut], [Garage]
FROM CTE
WHERE [DateIn] < [DateOut])
SELECT
YEAR([DateIn]) AS [Year]
,MONTH([DateIn]) AS [Month]
,COUNT( DISTINCT CASE WHEN [Garage] = 'X' THEN T.t1 ELSE NULL END) AS X
,COUNT( DISTINCT CASE WHEN [Garage] = 'Y' THEN T.t1 ELSE NULL END) AS Y
,COUNT( DISTINCT CASE WHEN [Garage] = 'Z' THEN T.t1 ELSE NULL END) AS Z
FROM CTE
CROSS APPLY (VALUES (CONVERT(VARCHAR(4),YEAR([DateIn])) + CONVERT(VARCHAR(2),MONTH([DateIn])) + CONVERT(VARCHAR(20),[Code]))) AS T(t1)
GROUP BY YEAR([DateIn]), MONTH([DateIn])
ORDER BY [Year], [Month]
OPTION (MAXRECURSION 0)
The result is as below,
Year Month X Y Z
2018 1 0 0 1
2018 2 0 0 1
2018 3 0 0 1
2018 4 0 0 1
2018 5 1 2 2
2018 6 2 2 2
2018 7 2 1 3
2018 8 2 1 3
2018 9 2 2 2
2018 10 1 2 2
2018 11 1 1 2
2018 12 1 2 1

Answer 3

You can generate the dates using a recursive subquery.
Then you have multiple ways to calculate the summary data. One simple method uses apply:
with dates as (
select convert(date, '2018-01-01') as dte, 1 as lev
union all
select dateadd(month, 1, dte), lev + 1
from dates
where lev < 12
)
select year(d.dte), month(d.dte), s.*
from dates d outer apply
(select sum(case when a.Garage = 'X' then 1 else 0 end) as x,
sum(case when a.Garage = 'Y' then 1 else 0 end) as y,
sum(case when a.Garage = 'Z' then 1 else 0 end) as z
from table_a a
where a.datein <= d.dte and a.dateout >= d.dte
) s;
Your question is a little vague on the exact calculation. This calculates the number of cars in each garage on the first of each month.
Here is a db<>fiddle.
EDIT:
Your revised question is more complicated, but since I started answering:
with dates as (
select convert(date, '2018-01-01') as dte, 1 as lev
union all
select dateadd(month, 1, dte), lev + 1
from dates
where lev < 12
)
select year(d.dte), month(d.dte),
sum(case when a.Garage = 'X'
then datediff(day,
(case when a.datein < d.dte then d.dte else datein end),
(case when a.dateout >= dateadd(month, 1, d.dte) then eomonth(d.dte) else dateout end)
) + 1
else 0
end) as x_cardays,
sum(case when a.Garage = 'Y'
then datediff(day,
(case when a.datein < d.dte then d.dte else datein end),
(case when a.dateout >= dateadd(month, 1, d.dte) then eomonth(d.dte) else dateout end)
) + 1
else 0
end) as y_cardays,
sum(case when a.Garage = 'Z'
then datediff(day,
(case when a.datein < d.dte then d.dte else datein end),
(case when a.dateout >= dateadd(month, 1, d.dte) then eomonth(d.dte) else dateout end)
) + 1
else 0
end) as z_cardays
from (select d.*, day(eomonth(dte)) as days_in_month
from dates d
) d left join
table_a a
on a.datein < dateadd(month, 1, d.dte) and a.dateout >= d.dte
group by d.dte
order by d.dte;
Overlaps with dates are a bit tricky, but you definitely want to do this with dates.
Note this doesn't calculate the average per day. You can divide by d.days_in_month if you want the average.
Here is a revised db<>fiddle.

Answer 4

This below script will only work if all your DateIn and DateOut for a particular record is in a single year like 2018.
Leap year Year is not considered but can be implemented.
WITH Month_Wise_Day AS
(
-- Listing/selecting 12 month manually here
-- With number of day for that month
SELECT 1 M, 31 ND UNION ALL
SELECT 2 M, 28 UNION ALL SELECT 3 M,31 UNION ALL SELECT 4 M,30 UNION ALL SELECT 5 M,31 UNION ALL
SELECT 6 M,30 UNION ALL SELECT 7 M,31 UNION ALL SELECT 8 M,31 UNION ALL SELECT 9 M,30 UNION ALL
SELECT 10 M,31 UNION ALL SELECT 11 M,30 UNION ALL SELECT 12 M,31
)
SELECT A.Year, A.Month,
SUM(CASE WHEN A.Garage = 'X' THEN A.No_of_days ELSE 0 END) AS X,
SUM(CASE WHEN A.Garage = 'Y' THEN A.No_of_days ELSE 0 END) AS Y,
SUM(CASE WHEN A.Garage = 'Z' THEN A.No_of_days ELSE 0 END) AS Z
FROM
(
SELECT A.*,
B.M AS Month,
YEAR(A.DateIn) AS Year,
CASE
WHEN MONTH(A.DateIn) = MONTH(A.DateOut) THEN DATEDIFF(DD,DateIn,DateOut) +1
WHEN B.M = MONTH(DateIn) THEN B.ND - DAY(DateIn)+1
WHEN B.M = MONTH(DateOut) THEN DAY(DateOut)
ELSE ND
END No_of_days
FROM TABLE_A A
INNER JOIN Month_Wise_Day B ON B.M BETWEEN MONTH(DateIn) AND MONTH (DateOut)
)A
GROUP BY A.Year, A.Month