I have a table similar to this
Can I get help writing up a query which will join col1, col2 & col3 and give me a result as below
I've spent an hour trying to figure it out with my mediocre skills and have got to some point.
select col1, count(*)
from tableName
group by col1
But I can't figure out how to join all three cols.
try this one
select
col,
count(*)
from
(select
id,
col1 as col
from
<table_name>
union all
select
id,
col2
from
<table_name>
union all
select
id,
col3
from
<table_name>)
group by
col
You need to group by col of the union of the 3 columns:
select t.col, count(*)
from (
select col1 col from tablename
union all
select col2 from tablename
union all
select col3 from tablename
) t
group by t.col
You should use UNION to group values from all columns to one column. After that, you can count values
SELECT
col,
count(*) as cnt
FROM
(SELECT col1 as col FROM table1
UNION ALL
SELECT col2 as col FROM table1
UNION ALL
SELECT col2 as col FROM table1) as t
GROUP BY col
Related
Here is a mock table
MYTABLE ROWS
PKEY 1,2,3,4,5,6
COL1 a,b,b,c,d,d
COL2 55,44,33,88,22,33
I want to know which rows have duplicated COL1 values:
select col1, count(*)
from MYTABLE
group by col1
having count(*) > 1
This returns :
b,2
d,2
I now want all the rows that contain b and d. Normally, I would use where in stmt, but with the count column, not certain what type of statement I should use?
maybe you need
select * from MYTABLE
where col1 in
(
select col1
from MYTABLE
group by col1
having count(*) > 1
)
Use a CTE and a windowed aggregate:
WITH CTE AS(
SELECT Pkey,
Col1,
Col2,
COUNT(1) OVER (PARTITION BY Col1) AS C
FROM dbo.YourTable)
SELECT PKey,
Col1,
Col2
FROM CTE
WHERE C > 1;
Lots of ways to solve this here's another
select * from MYTABLE
join
(
select col1 ,count(*)
from MYTABLE
group by col1
having count(*) > 1
) s on s.col1 = mytable.col1;
I want to be able to select two distinct from col1 and col2 ordered by id.
I'm struggling to do this because when I write the following SQL query...
SELECT DISTINCT col1, col2
FROM table
ORDER BY id
I can't ORDER BY id because it's not in the SELECT statement but if I put id in the SELECT statement it will take the DISTINCT id, col1 and col2. Which is basically the whole table as it is since the id column is unique.
How do I do this?
You can use aggregation, and put an aggregate function in the order by clause:
select col1, col2 from mytable group by col1, col2 order by min(id) limit 10
This is one way to do it:
select A.col1, A.col2
from
(select id, col1, col2
from Tablet
order by id) A
left join
(select min(id) id2, col1, col2
from Tablet
GROUP BY COL1, COL2) B
on A.COL1 = B.COL1 AND A.COL2=b.COL2
where A.id = B.id2
LIMIT 4;
Here is the DEMO
I have the following sql at the begnging.
select col1, col2 from table1
union
select col1, col2 from table2
Now I want to able to do a count the total number of rows in the union set from above, and order by col2. How should I do this?
with a as (
select col1, col2 from table1
union
select col1, col2 from table2
)
select *,count(1) over()
from a
order by col2
;
I have found many answers on selecting non-distinct rows where they group by a singular column, for example, e-mail. However, there seems to have been issue in our system where we are getting some duplicate data whereby everything is the same except the identity column.
SELECT DISTINCT
COLUMN1,
COLUMN2,
COLUMN3,
...
COLUMN14
FROM TABLE1
How can I get the non-distinct rows from the query above? Ideally it would include the identity column as currently that is obviously missing from the distinct query.
select COLUMN1,COLUMN2,COLUMN3
from TABLE_NAME
group by COLUMN1,COLUMN2,COLUMN3
having COUNT(*) > 1
With _cte (col1, col2, col3, id) As
(
Select cOl1, col2, col3, Count(*)
From mySchema.myTable
Group By Col1, Col2, Col3
Having Count(*) > 1
)
Select t.*
From _Cte As c
Join mySchema.myTable As t
On c.col1 = t.col1
And c.col2 = t.col2
And c.col3 = t.col3
SELECT * FROM
(
SELECT *, ROW_NUMBER() OVER (PARTITION BY COL 1, COL 2, .... COL N ORDER BY COL M
) RN
FROM TABLE_NAME
)T
WHERE T.RN>1
I have 12 tables in SQL Server with the exact same columns that I would like to combine into one brand new table. I don't want any data/rows deleted.
Thanks
Use union all:
insert into NewTable(col1, col2)
select col1, col2
from(
select col1, col2 from Table1
union all
select col1, col2 from Table2
union all
select col1, col2 from Table3
.....
)t
You can create new table while selecting like:
select col1, col2
into NewTable
from(
select col1, col2 from Table1
union all
select col1, col2 from Table2
union all
select col1, col2 from Table3
.....
)t