SQL append in middle of column data in update query - sql

Question

When we do data refresh we need to append \\prod01\\Test\Load server name with \\prod01.qa.com\\Test\Load
How do I write update query for this. There can be different server names all I need to do is write update script to append server name with qa.com
This is my query that gives all results that have server location.
select * from AppSetting where Value like '%\\%\%' or Value like '%//%/%';
My Prod data looks like this
Value
\\prod01\Images\Load
\\prod01prod6253\Images\Load
\\server05ser\Images\Delete
\\pgdg1076\Email
\\pgdg1076ythg\Test\Load
http://prod7/delta/
My QA data should looks like this after update query
Value
\\prod01.qa.com\Images\Load
\\prod01prod6253.qa.com\Images\Load
\\server05ser.qa.com\Images\Delete
\\pgdg1076.qa.com\Email
\\pgdg1076ythg.qa.com\Test\Load
http://prod7.qa.com/delta/
This is the update query I have. Can I write a generic query
UPDATE eroom.AppSetting
SET Location = REPLACE(Location, '\\prod01\', '\\prod01.qa.tbc.com\')
WHERE Location like '%\\prod01\%';
UPDATE eroom.AppSetting
SET Location = REPLACE(Location, '\\server05ser\', '\\server05ser.qa.tbc.com\')
WHERE Location like '%\\server05ser\%';

Answer 1

I'm posting this as a new answer, as the OP moved the goal posts quite a bit. Instead, I now use CHARINDEX to find the location of each slash (forward or back). As fortunately the injection needs to happen before the 3rd slash, we can use that to our advantage:
SELECT STUFF(V.Value,CI3.I,0,'.qa.tbc.com') AS NewValue,*
FROM (VALUES('\\prod01\Images\Load'),
('\\prod01prod6253\Images\Load'),
('\\server05ser\Images\Delete'),
('\\pgdg1076\Email'),
('\\pgdg1076ythg\Test\Load'),
('http://prod7/delta/'))V([value])
CROSS APPLY (VALUES(CASE WHEN V.[value] LIKE '%/%' THEN '/' ELSE '\' END)) L(C) --So I don't have to keep checking what character I need
CROSS APPLY (VALUES(CHARINDEX(L.C,V.[value]))) CI1(I)
CROSS APPLY (VALUES(CHARINDEX(L.C,V.[value],CI1.I+1))) CI2(I)
CROSS APPLY (VALUES(CHARINDEX(L.C,V.[value],CI2.I+1))) CI3(I);

Answer 2

This is one method. I put the expressions for the PATINDEX and CHARINDEX in the FROM, as I find it far easier to read, and means less repetition:
SELECT V.[value],
ISNULL(STUFF(V.Value,ISNULL(CI.fs,CI.bs),0,'.qa.tbc.com'),V.[value]) AS NewValue
FROM (VALUES('\\prod01\Images\Load'),
('\\prod05\Images\Delete'),
('\\prod10\Email'),
('//http://prod7/delta/'))V([value])
CROSS APPLY (VALUES(NULLIF(PATINDEX('%prod[0-9]%',V.value),0)))PI(I)
CROSS APPLY (VALUES(NULLIF(CHARINDEX('/',V.[value],PI.I),0),NULLIF(CHARINDEX('\',V.[value],PI.I),0))) CI(fs,bs);

Answer 3

This answers the original version of the question.
The simplest way might be with stuff() and a case expression:
select (case when location like '\\prod[0-9][0-9]\*'
then stuff(location, 9, 0, '.qa.tbc.com'
else location
end)
The "prod" portion looks to be fixed length, so you don't need to search for a pattern.