Which date function use to convert date format
YYYYMMDD TO DDMMYYYY
I am using db2 database please help me
assuming you column_with_date is a valid date column and if you have DB2 9.7, you could use
date(to_date(column_with_date,'DDMMYYYY'))
Assuming that your column's data type is VARCHAR, convert it to date and then format it to DDMMYYYY:
varchar_format((to_date(col, 'YYYYMMDD'), 'DDMMYYYY')
replace col with your column's name.
Or use substr() and concatenation:
substr(col, 7, 2) || substr(col, 5, 2) || substr(col, 1, 4)
You can use:
to_char(datecol,'DDMMYYYY')
just to display as DDMMYYYY
a date column doesn't have a format( not stored with a format within a DB table)
2 ways to do it that I can think of, already mentioned above but giving a real command so you can try it.
db2 "select to_char(current_date,'DDMMYYYY') from sysibm.sysdummy1"
or
db2 "select varchar_format(current_date,'DDMMYYYY') from sysibm.sysdummy1"
Related
One column is formatted like this: dd/mm/yyyy
The other is formatted like this: yyyymmdd
How do I create a select statement which lets me compare these two columns? They are both varchar.
I'm running a db2 database.
I DB2, you can use TO_DATE() to convert both string dates to TIMESTAMP datatypes (note that TO_DATE is a synonym for the TIMESTAMP_FORMAT scalar function).
You can then safely compare them:
to_date(col1, 'dd/mm/yyyy') = to_date(col2, 'yyyymmdd')
I solved it like this.
I used substr:
substr(COLUMN_NAME, 7,4) || substr(COLUMN_NAME,4,2) || sub-str(COLUMN_NAME,1,2)
Posted on behalf of the question asker
I have this column called 'Date' that contains dates formatted this way: '20150101'.
I tried using sql substring, but when I run the query using 'date' function in sql, it doesn't work on the date format I have.
Here is the query I made:
SELECT (DATE ((SUBSTR(JOUR, 1, 4),
SUBSTR(JOUR, 5, 2),
SUBSTR(JOUR, 7, 2)))) As date
FROM TABLE
Any idea? I couldn't find anything similar to this date format! I found one that uses the convert function but it's not in StandardSQL or BigQuery
What about PARSE_DATE ?
SELECT PARSE_DATE("%Y%m%d", "20190101") as parsed;
For your table:
SELECT PARSE_DATE ("%Y%m%d", JOUR) As mydatecolumn from TABLE
I have a INSERT + SELECT statement. One column is a VARCHAR but must be filled with a date with 'yyyyMMdd' format in 3 different dialect.
With SQL server and Oracle there's no problem, but in Db2 I didn't find anything to do this stuff.
In SQLServer is CONVERT(VARCHAR,S.DT_NASCITA,112)
In Oracle is TO_CHAR(S.DT_NASCITA,'YYYYMMDD')
Any1 can help me pls ?
ty in advice !
Fix in a very bad way. This way work in all distro, seems
SELECT SUBSTR(CHAR(CURRENT DATE, ISO),1,4) || SUBSTR(CHAR(CURRENT DATE, ISO),6,2) || SUBSTR(CHAR(CURRENT DATE, ISO),9,2) FROM SYSIBM.SYSDUMMY1
I am using ORACLE and I want to convert VARCHAR type into Time using following SQL Query
SELECT CUSTOMER_SERVICE_QUOTE_MEAS.ITEM_CREATE_TM,
TO_char(
CUSTOMER_SERVICE_QUOTE_MEAS.ITEM_CREATE_TM,
'hh24:mi:ss')
AS TIME_CHANGE
FROM FDC.CUSTOMER_SERVICE_QUOTE_MEAS CUSTOMER_SERVICE_QUOTE_MEAS
This results in 6/1/2013 11:32:02 AM but I don't want the date part here. I need only time portion 11:32:02, How it can be done ?
The field CUSTOMER_SERVICE_QUOTE_MEAS.ITEM_CREATE_TM has the data which look like this 113202.
Any help will be appreciated, Thanks.
Is the datatype of the item_create_tm column a NUMBER? The to_char is expecting a date column. To replicate the error:
SELECT to_char(113202, 'hh24:mi:ss') FROM dual;
It generates this error.
ORA-01481: invalid number format model
01481. 00000 - "invalid number format model"
*Cause: The user is attempting to either convert a number to a string
via TO_CHAR or a string to a number via TO_NUMBER and has
supplied an invalid number format model parameter.
*Action: Consult your manual.
You could either transform it to a date first and then to a formatted char.
SELECT to_char(to_date(113202, 'hh24miss'), 'hh24:mi:ss') FROM dual;
Output
11:32:02
Or substring the number to a char with : separators.
SELECT substr(113202, 1, 2) || ':' || substr(113202, 3, 2) || ':' || substr(113202, 5, 2) FROM dual;
Output
11:32:02
you can wrap dates with to_char and a format something like this:
select to_char( mydate, 'hh24:mi:ss' ) as mytime from mytable;
I'm using oracle 11g sql developer
I have a varchar2 column with dates as 0523 (mmDD).
I want to convert them to a date column and have them look like 23-05 (dd-mm)..
Any ideas?
Well, you can do string operations directly to get the format you want:
substring(c, 3, 2)||'-'||substring(c, 1, 2)
To convert to a date, you can use:
to_date('2012'||c, 'YYYYMMDD')
To convert a date back to the form you want:
to_char(<date>, 'DD-MM')