How to calculate total hours from multiple in time and out time from below? - sql

Question

first punch as in time,
second punch as out time
if possible avoid duplicate punch on same time within a minute
I need to get all in time ,outtime in a row with total hours
like below any format.
I tried below query but can't get my expected output
WITH Level1
AS (
SELECT A.emp_reader_id,
DT
,A.EventCatId
,A.Belongs_to
,ROW_NUMBER() OVER ( PARTITION BY A.Belongs_to,A.emp_reader_id ORDER BY DT ) AS RowNum
FROM dbo.trnevents A
)
,
LEVEL2
AS (-- find the last and next event type for each row
SELECT A.emp_reader_id,A.DT , A.EventCatId ,COALESCE(LastVal.EventCatId, 10) AS LastEvent,
COALESCE(NextVal.EventCatId, 10) AS NextEvent ,A.Belongs_to
FROM Level1 A
LEFT JOIN Level1 LastVal
ON A.emp_reader_id = LastVal.emp_reader_id and A.Belongs_to=LastVal.Belongs_to
AND A.RowNum - 1 = LastVal.RowNum
LEFT JOIN Level1 NextVal
ON A.emp_reader_id = NextVal.emp_reader_id and A.Belongs_to=NextVal.Belongs_to
AND A.RowNum + 1 = NextVal.RowNum
)
select * from level2 where emp_reader_id=92 order by dt desc
Expected output:

Answer 1

Try this below script. I considered all DT with Sam Minutes as single entry for the calculation.
WITH CTE AS
(
SELECT MAX(emp_reader_id) emp_reader_id,
CAST(DT AS DATE) Date_for_Group,
LEFT(CAST(DT AS VARCHAR),16) Time_For_Group,
ROW_NUMBER() OVER(PARTITION BY CAST(DT AS DATE) ORDER BY LEFT(CAST(DT AS VARCHAR),16)) RN,
CASE
WHEN ROW_NUMBER() OVER(PARTITION BY CAST(DT AS DATE) ORDER BY LEFT(CAST(DT AS VARCHAR),16))%2 = 0 THEN 'OUT'
ELSE 'IN'
END In_Out
FROM your_table
GROUP BY CAST(DT AS DATE),LEFT(CAST(DT AS VARCHAR),16)
)
SELECT A.emp_reader_id,A.Date_for_Group,
SUM(DATEDIFF(Minute,CAST(A.Time_For_Group AS DATETIME),CAST(B.Time_For_Group AS DATETIME)))/60 Hr,
SUM(DATEDIFF(Minute,CAST(A.Time_For_Group AS DATETIME),CAST(B.Time_For_Group AS DATETIME)))%60 Min
FROM CTE A
INNER JOIN CTE B
ON A.emp_reader_id = B.emp_reader_id
AND A.RN = B.RN -1
AND A.Date_for_Group = B.Date_for_Group
WHERE A.In_Out = 'IN'
GROUP BY A.emp_reader_id,A.Date_for_Group

Answer 2

first assign rownumber to datetime column then start the same result set with rownumber+1
Then Inner join them on rownumbers. After that select min an max from timein and out columns and group by on date to get total workhours of that day. hope it helps.
select empid
,date
,min(timein) as timein,max (timeout) timeout,convert(nvarchar(20),datediff(hh,min (timein),max(timeout))%24)
+':'+
convert(nvarchar(20),datediff(mi,min (timein),max(timeout))%60) as totalhrs
from(
Select a.empid,cast(a.dt as date) date,b.dt as timein,a.dt as timeout from(
SELECT DT
,[empid]
, id
,row_number() over(order by dt) as inn
FROM [test1].[dbo].[Table_2]
)a
inner join(
SELECT distinct DT
,[empid]
, id
,rank() over(order by dt)+1 as out
FROM [test1].[dbo].[Table_2])b
on FORMAT(a.dt,'hh:mm') <> FORMAT(b.dt,'hh:mm')
and cast(a.dt as date)=cast(b.dt as date)
and a.inn=b.out)b
group by b.empid,b.date