I want to know the SQL Query to find how many times a particular number is repeating(total count) in a column which is of int type.
Example: Coumn_iD = PostalCode
Postalcode
8696
2314
9645
3268
4288
2222
in the above case count of 8 = 4, Query for 2 should return 7
Like that, any help would be appreciated.
You can compute the number of occurrences of the particularSymbol on each row in the table as LENGTH(columnName) - LENGTH(REPLACE(columnName, particularNumber, "")) and then simply sum those over the whole table:
SELECT SUM(LENGTH(columnName) - LENGTH(REPLACE(columnName, particularNumber, '')))
FROM tableName
First count the number of occurrences for each row (the nested SELECT statement), then sum up that count to get one aggregate number.
DECLARE #my_num INT
SET #my_num = 2
SELECT SUM(count_per_row)
FROM
(
SELECT len(Postalcode) - len(replace(Postalcode,#my_num,'')) as count_per_row
FROM table)
If you don't need to generalize it, then just replace #my_num in the SELECT block with your number of interest (and get rid of the SELECT statement).
You didn't mention the database system you are using.
In Postgres you can create one row for each character in the postalcode and then group by that:
with test_data (postalcode) as (
values ('8696'),('2314'),('9645'),('3268'),('4288'),('2222')
)
select c, count(*)
from test_data, unnest(string_to_array(postalcode, null)) as t(c)
group by c
order by c
Ivo solution is probably the best. However, because the postal codes are only 4 digits, you might find this easier to follow:
select sum(case when postalcode like '2222' then 4
when postalcode like '%2%2%2%' then 3
when postalcode like '%2%2%' then 2
when postalcode like '%2%' then 1
else 0
end) as num_2s
from t;
Related
Let’s say I have a table
Name age
A Null
B Null
B 7
C 9
C 8
How can I write a sql query to return
Name
C
Meaning that only names where there is no null value in age are returned? Specifically using Postgres
Thoughts so far:
I think doing select name from table where age is not null, returns B and C because B has one age that isn’t null. So then, I thought about grouping by name but aggregation seems to remove bulls. Any help appreciated!
Depending on what dbms you are using, you can use ISNULL:
SELECT name FROM table
GROUP BY name
HAVING SUM(ISNULL(age)) = 0
Do a GROUP BY. COUNT(age) counts non-null values. COUNT(*) counts all rows.
SELECT name
FROM table
GROUP BY name
HAVING COUNT(age) = COUNT(*)
Or do an EXCEPT query:
SELECT name FROM table
EXCEPT
SELECT name FROM table WHERE age IS NULL
Is it possible to get only the countrys who just played in the pre round
Country Round
Germany Pre Round
Germany Quater final
Spain Pre Round
Portugal Pre Round
And I just want to get the countrys which only played in the pre round. So the result should look like this:
Country
Spain
Portugal
You can group by country and set the conditions in the having clause:
select country
from tablename
group by country
having count(*) = 1 and max(round) = 'Pre Round'
You can try the below using not exists
select country from c
where not exists
(select 1 from c as c1 where c.country=c1.country and roundval<>'Pre Round')
Two more for fun. The first is kind of a variation on #forpas', assigning a numeric value to each round, representing the progression through the rounds, and then getting the highest for the country (which would be simpler if the rounds were stored separately with a round number):
select country
from your_table
group by country
having max(case round
when 'Pre Round' then 1
when 'Quater final' then 2
when 'Semi final' then 3
when 'Final' then 4
end) = 1;
If you wanted to find countries that were in the quarters but not semis then you just need to change to = 2, etc.
The second is overkill here, but could be useful to look for more complicated combinations in other types of data:
select country
from your_table
pivot (
count(*) for round in (
'Pre Round' as pre, 'Quater final' as quarter, 'Semi final' as semi, 'Final' as final
)
)
where pre = 1 and quarter = 0 and semi = 0 and final = 0;
Obviously in your example you wouldn't ever have quarter as 0 and then either semi or final as 1 - you can't get to those rounds without playing the quarters; but for other data you might want a mix.
You could use a inner join on subquery for country wih round 're Round' and check for distinct count
select m.Contry
from my_table m
inner join (
select Country
from my_table
where round ='Pre Round'
) t on t.country = m.country
group by m.Country
having count(distinct m.round ) = 1
I am looking for the AVERAGE (overall) of the MINIMUM number (grouped by person).
My table looks like this:
Rank Name
1 Amy
2 Amy
3 Amy
2 Bart
1 Charlie
2 David
5 David
1 Ed
2 Frank
4 Frank
5 Frank
I want to know the AVERAGE of the lowest scores. For these people, the lowest scores are:
Rank Name
1 Amy
2 Bart
1 Charlie
2 David
1 Ed
2 Frank
Giving me a final answer of 1.5 - because three people have a MIN(Rank) of 1 and the other three have a MIN(Rank) of 2. That's what I'm looking for - a single number.
My real data has a couple hundred rows, so it's not terribly big. But I can't figure out how to do this in a single, simple statement. Thank you for any help.
Try this:
;WITH MinScores
AS
(
SELECT
"Rank",
Name,
ROW_NUMBER() OVER(PARTITION BY Name ORDER BY "Rank") row_num
FROM Table1
)
SELECT
CAST(SUM("Rank") AS DECIMAL(10, 2)) /
COUNT("Rank")
FROM MinScores
WHERE row_num = 1;
SQL Fiddle Demo
Selecting the set of minimum values is straightforward. The cast() is necessary to avoid integer division later. You could also avoid integer division by casting to float instead of decimal. (But you should be aware that floats are "useful approximations".)
select name, cast(min(rank) as decimal) as min_rank
from Table1
group by name
Now you can use the minimums as a common table expression, and select from it.
with minimums as (
select name, cast(min(rank) as decimal) as min_rank
from Table1
group by name
)
select avg(min_rank) avg_min_rank
from minimums
If you happen to need to do the same thing on a platform that doesn't support common table expressions, you can a) create a view of minimums, and select from that view, or b) use the minimums as a derived table.
You might try using a derived table to get the minimums, then get the average minimum in the outer query, as in:
-- Get the avg min rank as a decimal
select avg(MinRank * 1.0) as AvgRank
from (
-- Get everyone's min rank
select min([Rank]) as MinRank
from MyTable
group by Name
) as a
I think the easiest one will be
for max
select name , max_rank = max(rank)
from table
group by name;
for average
select name , avg_rank = avg(rank)
from table
cgroup by name;
I've been stuck for quite a while now trying to get this query to work.
Here's the setup:
I have a [Notes] table that contains a nonunique (Number) column and a nonunique (Result) column. I'm looking to create a SELECT statement that will display each distinct (Number) value where the count of the {(Number), (Result)} tuple where Result = 'NA' is > 25.
Number | Result
100 | 'NA'
100 | 'TT'
101 | 'NA'
102 | 'AM'
100 | 'TT'
200 | 'NA'
200 | 'NA'
201 | 'NA'
Basically, have an autodialer that calls a number and returns a code depending on the results of the call. We want to ignore numbers that have had an 'NA'(no answer) code returned more than 25 times.
My basic attempts so far have been similar to:
SELECT DISTINCT n1.Number
FROM Notes n1
WHERE (SELECT COUNT(*) FROM Notes n2
WHERE n1.Number = n2.Number and n1.Result = 'NA') > 25
I know this query isn't correct, but in general I'm not sure how to relate the DISTINCT n1.Number from the initial select to the Number used in the subquery COUNT. Most examples I see aren't actually doing this by adding a condition to the COUNT returned. I haven't had to touch too much SQL in the past half decade, so I'm quite rusty.
you can do it like this :
SELECT Number
FROM Notes
WHERE Result = 'NA'
GROUP BY Number
HAVING COUNT(Result) > 25
Try this:
SELECT Number
FROM (
SELECT Number, Count(Result) as CountNA
FROM Notes
WHERE Result = 'NA'
GROUP BY Number
)
WHERE CountNA > 25
EDIT: depending on SQL product, you may need to give the derived table a table correlation name e.g.
SELECT DT1.Number
FROM (
SELECT Number, Count(Result) as CountNA
FROM Notes
WHERE Result = 'NA'
GROUP
BY Number
) AS DT1 (Number, CountNA)
WHERE DT1.CountNA > 25;
I have a table in my database:
Name | Element
1 2
1 3
4 2
4 3
4 5
I need to make a query that for a number of arguments will select the value of Name that has on the right side these and only these values.
E.g.:
arguments are 2 and 3, the query should return only 1 and not 4 (because 4 also has 5). For arguments 2,3,5 it should return 4.
My query looks like this:
SELECT name FROM aggregations WHERE (element=2 and name in (select name from aggregations where element=3))
What do i have to add to this query to make it not return 4?
A simple way to do it:
SELECT name
FROM aggregations
WHERE element IN (2,3)
GROUP BY name
HAVING COUNT(element) = 2
If you want to add more, you'll need to change both the IN (2,3) part and the HAVING part:
SELECT name
FROM aggregations
WHERE element IN (2,3,5)
GROUP BY name
HAVING COUNT(element) = 3
A more robust way would be to check for everything that isn't not in your set:
SELECT name
FROM aggregations
WHERE NOT EXISTS (
SELECT DISTINCT a.element
FROM aggregations a
WHERE a.element NOT IN (2,3,5)
AND a.name = aggregations.name
)
GROUP BY name
HAVING COUNT(element) = 3
It's not very efficient, though.
Create a temporary table, fill it with your values and query like this:
SELECT name
FROM (
SELECT DISTINCT name
FROM aggregations
) n
WHERE NOT EXISTS
(
SELECT 1
FROM (
SELECT element
FROM aggregations aii
WHERE aii.name = n.name
) ai
FULL OUTER JOIN
temptable tt
ON tt.element = ai.element
WHERE ai.element IS NULL OR tt.element IS NULL
)
This is more efficient than using COUNT(*), since it will stop checking a name as soon as it finds the first row that doesn't have a match (either in aggregations or in temptable)
This isn't tested, but usually I would do this with a query in my where clause for a small amount of data. Note that this is not efficient for large record counts.
SELECT ag1.Name FROM aggregations ag1
WHERE ag1.Element IN (2,3)
AND 0 = (select COUNT(ag2.Name)
FROM aggregatsions ag2
WHERE ag1.Name = ag2.Name
AND ag2.Element NOT IN (2,3)
)
GROUP BY ag1.name;
This says "Give me all of the names that have the elements I want, but have no records with elements I don't want"